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how to remove a sequence from string in ftl

I am working on a project where I need to put away some part of string, not to be visible on front page.
I am working with ftl.
Example:
there is a string like:
<#assign valueToShow= "#99#testing,#777#test">
I need to show the values without part #digits#.
The final result need to be like this:
"testing,test"
How can I do that in FTL?
Thanks...

valueToShow?replace("#[0-9]+#", "", "r"), where 3rd "r" parameter means that what you replace is a regular expression.

The string class offers an easy way to do this:
String valueToShow = rawString.replaceFirst("#\\d+#", "")

Getting file extension from http url using Java

Now I know about FilenameUtils.getExtension() from apache.
But in my case I'm processing extensions from http(s) urls, so in case I have something like
https://your_url/logo.svg?position=5
this method is gonna return svg?position=5
Is there the best way to handle this situation? I mean without writing this logic by myself.

You can use the URL library from JAVA. It has a lot of utility in this cases. You should do something like this:
String url = "https://your_url/logo.svg?position=5";
URL fileIneed = new URL(url);
Then, you have a lot of getter methods for the "fileIneed" variable. In your case the "getPath()" will retrieve this:
fileIneed.getPath() ---> "/logo.svg"
And then use the Apache library that you are using, and you will have the "svg" String.
FilenameUtils.getExtension(fileIneed.getPath()) ---> "svg"
JAVA URL library docs >>>
https://docs.oracle.com/javase/7/docs/api/java/net/URL.html

If you want a brandname® solution, then consider using the Apache method after stripping off the query string, if it exists:
String url = "https://your_url/logo.svg?position=5";
url = url.replaceAll("\\?.*$", "");
String ext = FilenameUtils.getExtension(url);
System.out.println(ext);
If you want a one-liner which does not even require an external library, then consider this option using String#replaceAll:
String url = "https://your_url/logo.svg?position=5";
String ext = url.replaceAll(".*/[^.]+\\.([^?]+)\\??.*", "$1");
System.out.println(ext);
svg
Here is an explanation of the regex pattern used above:
.*/ match everything up to, and including, the LAST path separator
[^.]+ then match any number of non dots, i.e. match the filename
\. match a dot
([^?]+) match AND capture any non ? character, which is the extension
\??.* match an optional ? followed by the rest of the query string, if present

Trying to replace part of a string starts with /x2D

In JMeter, I used a Regular Expression Extractor to extract part of an HTML response. I then passed that to a BeanShell Post Processor. However, having trouble replacing \x2D to -. Is there a way to do this or perhaps do I need to extract the response as
String yourvar = vars.get("accessToken");
String anotherVar = yourvar.replace("data.access_token = '","");
String finalAccessToken = anotherVar.replace("\x2D","-");
vars.put("finalAccessToken",finalAccessToken);
It is not liking the "\x2D" part. It works if I find \x2D but the original string only has .

You need to escape your target String parameter.
final String finalAccessToken = anotherVar.replace("\\x2D", "-");
If it's not what you're asking for, add more info to the question. That's all what I was able to understand.

It is recommended to use JMeter's built-in test elements where possible. In particular your case you might be interested in __strReplace() custom JMeter Function
Install Custom JMeter Functions bundle using JMeter Plugins Manager
Use the following expression to make the replacement:
${__strReplace(${anotherVar},\\\x2D,-,)}
If you want to go for scripting - make sure to use JSR223 PostProcessor and Groovy language. Be aware that you will still need to escape backslash with another backslash like:
String finalAccessToken = anotherVar.replace("\\x2D","-");

Modifying xml via regex in java

I have the following XML String:
<asd1:content></asd1:content>
The namespace prefix asd1 could be different at different places in the XML file.
I want to modify it to :
<asd1:content>*</asd1:content>
I am trying to do it via regex as follows:
myString.replaceAll("<.*:content></.*:content>","replacement text");
The problem is that I don,t want to lose the namespace prefix. What should I do?

Please note that you've 2 typos:
cotent instead of content
replaceAlll instead of replaceAll
If you still need a regex, you can use:
String resultString = subjectString.replaceAll("(?ism)<(.*?):content></(.*?)\\.content>", "<$1:content>*</$2.content>");

How to change the width and height of an html file using java

I wanted to change width="xyz" , where (xyz) can be any particular value to width="300". I researched on regular expressions and this was the one I am using a syntax with regular expression
String holder = "width=\"340\"";
String replacer="width=\"[0-9]*\"";
theWeb.replaceAll(replacer,holder);
where theWeb is the string
. But this was not getting replaced. Any help would be appreciated.

Your regex is correct. One thing you might be forgetting is that in Java all string methods do not affect the current string - they only return a new string with the appropriate transformation. Try this instead:
String replacement = 'width="340"';
String regex = 'width="[0-9]*"';
String newWeb = theWeb.replaceAll(regex, replacement); // newWeb holds new text

Better use JSoup for manipulating and extracting data, etc. from Html
See this link for more details:
http://jsoup.org/