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Trying to replace part of a string starts with /x2D

In JMeter, I used a Regular Expression Extractor to extract part of an HTML response. I then passed that to a BeanShell Post Processor. However, having trouble replacing \x2D to -. Is there a way to do this or perhaps do I need to extract the response as
String yourvar = vars.get("accessToken");
String anotherVar = yourvar.replace("data.access_token = '","");
String finalAccessToken = anotherVar.replace("\x2D","-");
vars.put("finalAccessToken",finalAccessToken);
It is not liking the "\x2D" part. It works if I find \x2D but the original string only has .

You need to escape your target String parameter.
final String finalAccessToken = anotherVar.replace("\\x2D", "-");
If it's not what you're asking for, add more info to the question. That's all what I was able to understand.

It is recommended to use JMeter's built-in test elements where possible. In particular your case you might be interested in __strReplace() custom JMeter Function
Install Custom JMeter Functions bundle using JMeter Plugins Manager
Use the following expression to make the replacement:
${__strReplace(${anotherVar},\\\x2D,-,)}
If you want to go for scripting - make sure to use JSR223 PostProcessor and Groovy language. Be aware that you will still need to escape backslash with another backslash like:
String finalAccessToken = anotherVar.replace("\\x2D","-");

Replace and modify String using regex in java

I have a part of HTML from a website in the below String format:
srcset=" /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#200w.jpg?20170808 200w, /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#338w.jpg?20170808 338w, /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#445w.jpg?20170808 445w, tesla_theme/assets/img/homepage/mobile/homepage-models--touch#542w.jpg?20170808 542w, /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#750w.jpg?20170808 750w"
I want to add http://tesla.com in front of all the urls in the srcset element like http://tesla_theme/assets/img/homepage/mobile/homepage-models--touch#750w.jpg?20170808 750w
I believe this could be done using regex, but I am not sure.
How do I do this using Java if I have multiple srcset elements in a html string variable, and I want to replace all of the srcset url.'s and add the server url in front?
Note: The /tesla_theme will not be consistent, so I cannot use replaceAll, instead, i will have to use regex.

You can simply use String Class replace method as below, It will replace all "/_tesla" in the given String. No special regex required unless you have a kind of pattern instead of "/tesla"
String srcset=" /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#200w.jpg?20170808 200w, /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#338w.jpg?20170808 338w, /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#445w.jpg?20170808 445w, tesla_theme/assets/img/homepage/mobile/homepage-models--touch#542w.jpg?20170808 542w, /tesla_theme/assets/img/homepage/mobile/homepage-models--touch#750w.jpg?20170808 750w";
String requiredSrcSet = srcset.replace("/tesla_", "http://tesla_");

How do I split the rest of the URL from the last path of it

I have this file URL: http://xxx.xxx.xx.xx/resources/upload/2014/09/02/new sample.pdf which will be converted to http://xxx.xxx.xx.xx/resources/upload/2014/09/02/new%20sample.pdf later.
Now I can get the last path by:
public static String getLastPathFromUrl(String url) {
return url.replaceFirst(".*/([^/?]+).*", "$1");
}
which will give me new sample.pdf
but how do I get the remaining of the URL: http://xxx.xxx.xx.xx/resources/upload/2014/09/02/
?

Easier way to get last path from URL would be to use String.split function, like this:-
String url = "http://xxx.xxx.xx.xx/resources/upload/2014/09/02/new sample.pdf";
String[] urlArray = url.split("/");
String lastPath = urlArray[urlArray.length-1];
This converts your url into an Array which can then be used in many ways. There are various ways to get url-lastPath, one way could be to join the above generated Array using this answer. Or use lastIndexOf() and substring like this:-
String restOfUrl = url.substring(0,url.lastIndexOf("/"));
PS:- Although you can learn something by doing this but I think your best solution would be to replace space by %20 in the complete url String, that would be the fastest and make more sense.

I am not sure if I understood it correctly but when you say
I have this file URL: URL/new sample.pdf which will be converted to URL/new%20sample.pdf later.
It looks like you are trying to replace "space" with %20 in URL or said in simple words trying to take care of unwanted characters in URL. If that is what you need use pre-built
URLEncoder.encode(String url,String enc), You can us ÜTF-8 as encoding.
http://docs.oracle.com/javase/7/docs/api/java/net/URLEncoder.html
If you really need to split it, assuming that you interested in URL after http://, remove http:// and take store remaining URL in string variable called say remainingURL. then use
List myList = new ArrayList(Arrays.asList(remainingURL.split("/")));
You can iterate on myList to get rest of URL fragments.

I've found it:
File file=new File("http://xxx.xxx.xx.xx/resources/upload/2014/09/02/new sample.pdf");
System.out.println(file.getPath().replaceAll(file.getName(),""));
Output:
http://xxx.xxx.xx.xx/resources/upload/2014/09/02/

Spring solution:
List<String> pathSegments = UriComponentsBuilder.fromUriString(url).build().getPathSegments();
String lastPath = pathSegments.get(pathSegments.size()-1);

How to change the width and height of an html file using java

I wanted to change width="xyz" , where (xyz) can be any particular value to width="300". I researched on regular expressions and this was the one I am using a syntax with regular expression
String holder = "width=\"340\"";
String replacer="width=\"[0-9]*\"";
theWeb.replaceAll(replacer,holder);
where theWeb is the string
. But this was not getting replaced. Any help would be appreciated.

Your regex is correct. One thing you might be forgetting is that in Java all string methods do not affect the current string - they only return a new string with the appropriate transformation. Try this instead:
String replacement = 'width="340"';
String regex = 'width="[0-9]*"';
String newWeb = theWeb.replaceAll(regex, replacement); // newWeb holds new text

Better use JSoup for manipulating and extracting data, etc. from Html
See this link for more details:
http://jsoup.org/

Java: Carriage returns populating a var in js code?

I am not sure if this is possible, but I'm trying to find a front-end solution to this situation:
I am setting a JavaScript variable to a dynamic tag, populated by backend Java code:
var myString = '#myDynamicContent#';
However, there are some situations, in which the content from the output contains a carriage return; which breaks the code:
var mystring = '<div>
Carriage Return happened above and below.
</div>';
Is there anyway I can resolve this problem on the front-end? Or is it too late in the script to do something about it, because the dynamic tag will run before any JavaScript runs (thus the script is broken by that point)?

I'm sure my JS could be cleaned up (just thought this was a fun problem), but you could search out the comment in the JS.
Lets say your JS looks like this (noticed I added a tag to the comment so we know we're going after the correct one, and there is a div to just for testing):
<script id="testScript">
/*<captureMe><div>
Carriage Return happened above and below.
</div>
*/
var foo = 'bar';
</script>
<div id='test'>What do I see:</div>
Just use this to grab the comment:
var something = $("#testScript").html();
var newSomething = '';
newSomething = something.substr(something.indexOf("/*<captureMe>")+13);
newSomething = newSomething.substr(0, newSomething.indexOf("*/"));
$('#test').append('<br>'+newSomething); // just proving we captured the output, will not render returns or newline as expected by HTML
Technically, it works :), scripting-scripting...
Charbs

JavaScript supports strings that can span multiple lines by putting a backslash (\) at the end of the line, for example:
var myString = 'foo\
bar';
So you should be able to do a Java replace when you write in your server-side variable:
var myString = '#myDynamicContent.replaceAll("\\n", "\\\\n")#';

Replace the \n and/or \r with \\n and/or \\r respectively ... but it has to be done in the server-side language (in your case Java); it can't be done in JavaScript.

Building off of #Charbs' answer, you could avoid the JavaScript comments if you give your script tag a different mime type, so the browser won't try to evaluate it as JavaScript:
<script id="testScript" type="text/notjs" style="display:none">#myDynamicContent#</script>
And then just grab it like this (using jQuery):
var myString = $('#testScript').text();

To me it looks like you're doing token replacement instead of using a template engine. If you like token replacement you might Snippetory too, as it creates similar code. However it has a number of additional features. Using
var myString = '{v:myDynamicContent enc="string"}'
would create
var mystring = '<div>\r\n Carriage Return happened above and below.\r\n </div>'
And thus solve your problem. But you would have to change your code behind, too.