i want to crop the circles i detected using hough transform, i succeded to detect the circles but i didnt understand how to crop them.
here is the code i used for hough transform:
for( int i=0;i<circles.cols();i++){
Point center = new Point( Math.round(circles.get(0,i)[0]),
Math.round(circles.get(0, i)[1]));
System.out.println("X============="+i+":"+circles.get(0,i)[0]);
System.out.println("Y============="+i+":"+circles.get(0,i)[1]);
int radius = (int) Math.round(circles.get(0, i)[2]);
//System.out.println("--Rayon--:"+radius);
Imgproc.circle( image, center, radius, new Scalar(0,0,255),3);//radius, color) `
You can crop an image like this:
Mat initialImage = ...
Rect crop = new Rect(new Point(column,row),new Size(width,height)); // crop area begins at Point(column,row) with Size(width,height)
Mat croppedImage = new Mat(initialImage,crop);
Related
I am able to detect and draw a bounding rectangle around a region of interest like so:
Now I need to find the "x" value of the bottom horizontal line of the green bounding rectangle. My main aim is to find the "x" value of the base of the battery, and the "x" value of the blue strip of paper, so that I can calculate the distance between them.
There are only 2 values, rect.tl() and rect.br(), that I can see be used to draw the bounding rectangle Imgproc.rectangle(sourceMat, rect.tl(), rect.br(), green, 3);. I'm under the assumption that the "x" value from the bottom right point of the bounding rectangle will be the x co-ordinate of the pixel point.
How do i get the 'x' value from rect.br()
When i print out rect.br() like so Log.e("BR", rect.br().toString()); i get this:
E/BR: {793.0, 1686.0}
private Bitmap findRoi(Bitmap sourceBitmap) {
Bitmap roiBitmap = null;
Scalar green = new Scalar(0, 255, 0, 255);
Mat sourceMat = new Mat(sourceBitmap.getWidth(), sourceBitmap.getHeight(), CvType.CV_8UC3);
Utils.bitmapToMat(sourceBitmap, sourceMat);
Mat roiTmp = sourceMat.clone();
final Mat hsvMat = new Mat();
sourceMat.copyTo(hsvMat);
// convert mat to HSV format for Core.inRange()
Imgproc.cvtColor(hsvMat, hsvMat, Imgproc.COLOR_RGB2HSV);
Scalar lowerb = new Scalar(85, 50, 40); // lower color border for BLUE
Scalar upperb = new Scalar(135, 255, 255); // upper color border for BLUE
Core.inRange(hsvMat, lowerb, upperb, roiTmp); // select only blue pixels
// find contours
List<MatOfPoint> contours = new ArrayList<>();
List<RotatedRect> boundingRects = new ArrayList<>();
Imgproc.findContours(roiTmp, contours, new Mat(), Imgproc.RETR_LIST, Imgproc.CHAIN_APPROX_SIMPLE);
// find appropriate bounding rectangles
for (MatOfPoint contour : contours) {
MatOfPoint2f areaPoints = new MatOfPoint2f(contour.toArray());
RotatedRect boundingRect = Imgproc.minAreaRect(areaPoints);
double rectangleArea = boundingRect.size.area();
// test min ROI area in pixels
if (rectangleArea > 40001) {//400000
Point rotated_rect_points[] = new Point[4];
boundingRect.points(rotated_rect_points);
Rect rect = Imgproc.boundingRect(new MatOfPoint(rotated_rect_points));
// test horizontal ROI orientation
if (rect.width > rect.height) {
Imgproc.rectangle(sourceMat, rect.tl(), rect.br(), green, 3);
}
}
}
roiBitmap = Bitmap.createBitmap(sourceMat.cols(), sourceMat.rows(), Bitmap.Config.ARGB_8888);
Utils.matToBitmap(sourceMat, roiBitmap);
return roiBitmap;
}
I don't know a lot about Java but AFAIK it must be similar to c++, so whether you know about it or not,I try my code in c++. Suppose that you are working on the below rectangle:
For having the above Rect in OpenCV:
Rect r = Rect(20,20,30,20); // Rect(x,y,width,height)
And we could access the below-right x with using the br() like the below.
int x2=r.br().x ;
Below pic will tell you the whole story.
double degPi = degrees * Math.PI / 180;
double a = Math.cos(degPi)*tImgCover.getScaledHeight();
double b = Math.sin(degPi)*tImgCover.getScaledWidth();
double c = -Math.sin(degPi) * tImgCover.getScaledHeight();
double d = Math.cos(degPi)* tImgCover.getScaledWidth();
double e = absX;
double f = absY;
contentByte.addImage(imgae, a, b, c, d, e, f);/*add image*/
How to rotate around the image center by itext?
If we have an Image image and coordinates x, y, we can draw the image without rotation with its lower left corner at the given coordinates like this
contentByte.addImage(image, image.getWidth(), 0, 0, image.getHeight(), x, y);
A bitmap image from the resources has a size of 1x1 with the coordinate origin at its lower left. Thus, this operation stretches the image to its correct size and moves it so its lower left is at the given coordinates.
If we want to draw the same image as if the one drawn above was rotated around its center by an angle rotate, therefore, we can do this by moving the 1x1 image so that the origin is in its center, stretch it to its correct size, rotate it, and then move the origin (which still is at the center of the rotated image) to the center of the unrotated image. These operations are easier to express using AffineTransform instances (from package com.itextpdf.awt.geom) instead number tupels. Thus:
// Draw image as if the previous image was rotated around its center
// Image starts out being 1x1 with origin in lower left
// Move origin to center of image
AffineTransform A = AffineTransform.getTranslateInstance(-0.5, -0.5);
// Stretch it to its dimensions
AffineTransform B = AffineTransform.getScaleInstance(image.getWidth(), image.getHeight());
// Rotate it
AffineTransform C = AffineTransform.getRotateInstance(rotate);
// Move it to have the same center as above
AffineTransform D = AffineTransform.getTranslateInstance(x + image.getWidth()/2, y + image.getHeight()/2);
// Concatenate
AffineTransform M = (AffineTransform) A.clone();
M.preConcatenate(B);
M.preConcatenate(C);
M.preConcatenate(D);
//Draw
contentByte.addImage(image, M);
(AddRotatedImage.java test method testAddRotatedImage)
For example drawing both images using
int x = 200;
int y = 300;
float rotate = (float) Math.PI / 3;
results in something like this:
With a Flip
The OP asked in a comment
how to add rotate and flip image？
For this you simply insert a mirroring affine transformation into the sequence of transformations above.
Unfortunately the OP did not mention which he meant a horizontal or a vertical flip. But as changing the rotation angle accordingly transforms one in the other, that isn't really necessary, either.
// Draw image as if the previous image was flipped and rotated around its center
// Image starts out being 1x1 with origin in lower left
// Move origin to center of image
AffineTransform A = AffineTransform.getTranslateInstance(-0.5, -0.5);
// Flip it horizontally
AffineTransform B = new AffineTransform(-1, 0, 0, 1, 0, 0);
// Stretch it to its dimensions
AffineTransform C = AffineTransform.getScaleInstance(image.getWidth(), image.getHeight());
// Rotate it
AffineTransform D = AffineTransform.getRotateInstance(rotate);
// Move it to have the same center as above
AffineTransform E = AffineTransform.getTranslateInstance(x + image.getWidth()/2, y + image.getHeight()/2);
// Concatenate
AffineTransform M = (AffineTransform) A.clone();
M.preConcatenate(B);
M.preConcatenate(C);
M.preConcatenate(D);
M.preConcatenate(E);
//Draw
contentByte.addImage(image, M);
(AddRotatedImage.java test method testAddRotatedFlippedImage)
The result with the same image as above:
With Interpolation
The OP asked in a yet another comment
How anti aliasing ?
The iText Image class knows an Interpolation property. By setting it to true (before adding the image to the document, obviously),
image.setInterpolation(true);
low resolution images are subject to interpolation when drawn.
E.g. using a 2x2 image with differently colored pixels instead of the image of Willi, you get the following results, first without interpolation, then with interpolation:
Confer the AddRotatedImage.java test testAddRotatedInterpolatedImage which adds this image:
Beware: iText Image property Interpolation effectively sets the Interpolate entry in the PDF image dictionary. The PDF specification notes in this context:
NOTE A conforming Reader may choose to not implement this feature of PDF, or may use any specific implementation of interpolation that it wishes.
Thus, on some viewers interpolation may occur differently than in your viewer, maybe even not at all. If you need a specific kind of interpolation on every viewer, upscale the image with the desired amount of interpolation / anti-aliasing before loading it into an iText Image.
public static BufferedImage rotateClockwise90( BufferedImage inputImage ){
int width = inputImage.getWidth();
int height = inputImage.getHeight();
BufferedImage returnImage = new BufferedImage( height, width , inputImage.getType() );
for( int x = 0; x < width; x++ ) {
for( int y = 0; y < height; y++ ) {
returnImage.setRGB( height-y-1, x, inputImage.getRGB( x, y ) );
}
}
return returnImage;
}
I have detected a area (rectangle) in my image with openCv and i have stored the 4 points of rectangle with their coordinates.
I would to crop the original image in this area.
I have:
Mat image_original;
Point p1,p2,p3,p4;
Mat image_output;
How i do this?
Thanks!
Mat image_original;
Point p1,p2,p3,p4;
Rect rectCrop = new Rect(p1.x, p1.y , (p4.x-p1.x+1), (p4.y-p1.y+1));
Mat image_output= image_original.submat(rectCrop);
This is the code for croping image as per your requirement.I assumed that Point p1 is the top-left corner of the crop rectangle and Point p4 is the bottom-right corner of the crop rectangle as you have not mentioned anything about their positions.
I have square area for detection and I replace square area with image but now I have a problem because the image is too large for the square area. So I'd like to resize the image in order to has the same size with the square area.
How I can resize the image? You can look at my GIF below this post
My Code:
Core.rectangle(rgbaInnerWindow, new Point(pt.x-radius,pt.y-radius), new Point(pt.x+radius,pt.y+radius), new Scalar(255));
Mat mask = new Mat(rgbaInnerWindow.size(), CvType.CV_8UC1);
Mat dst = new Mat();
Imgproc.resize(img1, dst, mask.size());
dst.copyTo(rgbaInnerWindow);
I am aware of BufferedImage.getSubimage However, it cant deal with cropping images that are smaller than the cropping size throwing the exception:
java.awt.image.RasterFormatException: (y + height) is outside raster
I want to be able to crop either a PNG/JPG/GIF to a certain size however if the image is smaller than the cropping area centre itself on a white background. Is there a call to do this? Or do I need to create an image manually to centre the image on if so, how would I go about this?
Thanks
You cannot crop an image larger, only smaller. So, you start with the goal dimension,let's say 100x100. And your BufferedImage (bi), let's say 150x50.
Create a rectangle of your goal:
Rectangle goal = new Rectangle(100, 100);
Then intersect it with the dimensions of your image:
Rectangle clip = goal.intersection(new Rectangle(bi.getWidth(), bi.getHeight());
Now, clip corresponds to the portion of bi that will fit within your goal. In this case 100 x50.
Now get the subImage using the value of clip.
BufferedImage clippedImg = bi.subImage(clip,1, clip.y, clip.width, clip.height);
Create a new BufferedImage (bi2), the size of goal:
BufferedImage bi2 = new BufferedImage(goal.width, goal.height);
Fill it with white (or whatever bg color you choose):
Graphics2D big2 = bi2.getGraphics();
big2.setColor(Color.white);
big2.fillRect(0, 0, goal.width, goal.height);
and draw the clipped image onto it.
int x = goal.width - (clip.width / 2);
int y = goal.height - (clip.height / 2);
big2.drawImage(x, y, clippedImg, null);