I have created a server-client project where the server keeps listening and prints the information. However, when i shutdown the client, the server remains open. The problem is that I need to insert this into another application, and, if the server does not close at first, the application will not open unless i kill the process in that port (but this is not an option to me). What should I do to properly close the server once the client disconnects?
Here is the code:
Server:
public class Server {
public static void main(String[] args) {
Connection conn = new Connection();
new Thread(conn).start();
}
private static class Connection implements Runnable {
#Override
public void run() {
try (ServerSocket serverSocket = new ServerSocket(5005)) {
Socket socket = serverSocket.accept();
listener(socket);
} catch (IOException ex) {
ex.printStackTrace();
}
}
private void listener(Socket socket) throws IOException {
DataOutputStream outputStream = new DataOutputStream(socket.getOutputStream());
DataInputStream inputStream = new DataInputStream(socket.getInputStream());
boolean alive = true;
while (alive) {
try {
outputStream.writeUTF(new Scanner(System.in).nextLine());
System.out.println(inputStream.readUTF());
} catch (IOException ex) {
ex.printStackTrace();
alive = false;
}
}
}
}
}
Client:
public class Client {
public static void main(String[] args) {
try (Socket socket = new Socket("localhost", 5005)) {
DataInputStream inputStream = new DataInputStream(socket.getInputStream());
DataOutputStream outputStream = new DataOutputStream(socket.getOutputStream());
while (socket.isConnected()) {
System.out.println("Incoming data: " + inputStream.readUTF());
outputStream.writeUTF(new Scanner(System.in).nextLine());
outputStream.flush();
}
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
Since now, thank you very much!
The thing that force the system wait and not close is this line at your Server.java :
outputStream.writeUTF(new Scanner(System.in).nextLine());
Once it starts waiting the user input, it waits forever along the life time of the instance although your client is disconnected.
So what you can do ? You can create another thread that makes periodic "ENTER" inputs (if you insist using new Scanner(System.in)) for example input per 5 seconds. After the enter, or any other meaningful input, if you decide this is not from your client, don't write it to the client and wait user input again (if your client still connected !). If your client is not connected, just finish your loop.
Please check Java Robot class and this example
Related
hey I'm writing a simple code with a server socket and multiple clients which the server gets every client's username and stores them in a hashmap.the server accepts a socket client and the client enters the username but again the server accept the same socket client and it wants its username and the code stops here.i want it to work for multiple clients not just one.
server class:
public class Server implements Serializable{
// [..]
public void serverConnect() throws IOException, ClassNotFoundException
{
listener = new ServerSocket(9090);
System.out.println("Server is running...");
while (true)
{
System.out.println("Waiting ...");
socket=listener.accept();
for (Socket socket:socketList.keySet())
{
if (this.socket==socket)
{
checkSocket=false;
}
}
if (checkSocket)
{
socketList.put(socket,socketNumber);
System.out.println("Client is connected");
inputReader = new InputStreamReader(socket.getInputStream());
reader = new BufferedReader(inputReader);
user = reader.readLine();
Server.userList.add(user);
socketNumber++;
}
checkSocket=true;
}
}
}
client class:
public class Client {
public Client() {
}
public void clientConnect() throws UnknownHostException, IOException {
System.out.println("enter your username");
Scanner scanner = new Scanner(System.in);
String msg = scanner.nextLine();
Socket socket = new Socket("localhost", 9090);
PrintWriter writer = new PrintWriter(socket.getOutputStream(), true);
writer.println(msg);
}
}
In principle you have the workings of single thread server (which means it can accept only one client connection at a time). The main issue is that you have over-complicated how you receive a connection.
You can simplify your current code by dealing by moving the client connection socket and readers into the local scope and dealing with the socket directly.
public void serverConnect() throws IOException {
listener = new ServerSocket(9090);
System.out.println("Server is running...");
while (true) {
System.out.println("Waiting ...");
Socket socket = listener.accept();
try (BufferedReader reader = new BufferedReader(new InputStreamReader(socket.getInputStream()))) {
String user = reader.readLine();
Server.userList.add(user);
} catch (IOException ignore) {
} finally {
socket.close();
}
}
}
As you can see you don't need to keep hold of the socket beyond reading the value sent. If you are only expecting the one line of data from the client, you should also close the socket otherwise the client can hold the server hostage by not sending any data until the socket timeout is reached.
Further to this you also want to wrap the code inside the while loop with a try/catch block to prevent an exception terminating the server.
As I mentioned in the opening paragraph this code works as a single threaded server and it can only respond to a single request at a time. If you want to accept and process multiple requests you will need to spawn a new thread to handle the response. I would recommend constructing your code as below but for the sake of brevity you could do something like below:
public void serverConnect() throws IOException {
int MAX_WORKERS = 100;
ExecutorService service = Executors.newFixedThreadPool(MAX_WORKERS);
ServerSocket listener = new ServerSocket(9090);
System.out.println("Server is running...");
while (true) {
System.out.println("Waiting ...");
Socket socket = listener.accept();
service.submit(() -> {
System.out.println("Client is connected");
try {
try (BufferedReader reader = new BufferedReader(new InputStreamReader(socket.getInputStream()))) {
String user = reader.readLine();
Server.userList.add(user);
} finally {
socket.close();
}
} catch (Throwable ignore) {
}
});
}
}
So all that is happening above is that we are creating a thread pool of 100 threads using the ExecutorService. This means in theory we can accept 100 concurrent connections.
When a connection is accepted, we submit the socket and worker code to a thread which means that the main thread can return to listening for a new connections.
I want to implement a Server which listens endless on a specific port to receive data from many clients (never in parallel, only serial). The first thing I tried is to run the server and then launch a few clients in serial (one after the other).
This sounded very easy to implement, but I actually got into the problem, that the code works only when I run it in debug mode with at least one breakpoint in the server code (but the same fault as when running it normally without a breakpoint), very strange to me.
However here is the server code:
public class TaskExecutionServer {
public TaskExecutionServer(final int port) {
new Thread() {
#Override
public void run() {
try {
int counter = 0;
ServerSocket serverSocket = new ServerSocket(port);
while(true) {
System.out.println("Waiting for client...");
Socket socket = serverSocket.accept();
System.out.println("Accepted");
InputStream inputStream = socket.getInputStream();
ObjectInputStream objectStream = new ObjectInputStream(inputStream);
while(inputStream.available() > 0 ) {
String to = (String)objectStream.readObject();
System.out.println(to);
System.out.println(++counter);
}
objectStream.close();
inputStream.close();
System.out.println("Closing socket");
socket.close();
}
} catch (Exception e) {
e.printStackTrace();
}
}
}.start();
}
public static void main(String args[]) {
new TaskExecutionServer(2003);
}
}
And here the client code:
public class TaskSenderClient {
public static void main(String args[]){
try{
Socket s = new Socket("localhost",2003);
OutputStream os = s.getOutputStream();
ObjectOutputStream oos = new ObjectOutputStream(os);
oos.writeObject("test");
oos.close();
os.close();
s.close();
}catch(Exception e){
System.out.println("Client exception");
e.printStackTrace();
}
}
}
this is the console output when running in debug mode with breakpoint in the server code row System.out.println("Accepted");:
Waiting for client...
Accepted
test
1
Closing socket
Waiting for client...
Accepted
test
2
Closing socket
Waiting for client...
Accepted
test
3
Closing socket
Waiting for client...
And the output when running in normal mode / without breakpoints in debug-mode:
Waiting for client...
Accepted
test
1
Closing socket
Waiting for client...
Accepted
Closing socket
Waiting for client...
Accepted
Closing socket
Waiting for client...
I don't get any exception... Can someone help? It's my first attempt to re-use a socket connection in java.
EDIT: Checking inputStream.available returns different values
I just added a System.out.println(inputStream.available()); before the while in server code. This prints
always 7 in debug-mode with breakpoint
7 (in first run) and 0 (in all other attemps) afterwards in non-debug mode / without breakpoints
EDIT 2: First wait until inputStream.available != 0
This solution also works for me. However, I removed this code snippet here, because checking of available() seems not to be the correct way for that! -> see the solution!
EDIT 3: New server code, which uses NonEmptyInputStream which checks per PushbackInputStream for non-empty streams:
As this uses the EOFException it seems not to be an optimal solution to me, so I also removed this code snippet (instead see solution below). The usage of exceptions in "correct" code is discussed in the comments below...
InputStream.available() can return 0 if there is no data yet, meaning the client didn't send some yet or at least it is not arrived yet. If you add a breakpoint the client has more time to send the data.
You can either add logic like your client first sends how many objects it writes, the server reads the amount and then reads that many objects before it stops reading.
Another possibility would be to insert a PushbackInputStream between the ObjectInputStream and the InputStream and then do a read() on the PushbackInputStream, check the result for -1 which means end-of-stream and if it was not -1, use unread() to push the read byte back into the stream before using the ObjectInputStream methods.
Here you have an example of your originally posted class rewritten with the last pattern:
public class TaskExecutionServer {
public TaskExecutionServer(final int port) {
new Thread() {
#Override
public void run() {
try {
int counter = 0;
ServerSocket serverSocket = new ServerSocket(port);
while(true) {
System.out.println("Waiting for client...");
Socket socket = serverSocket.accept();
System.out.println("Accepted");
InputStream inputStream = socket.getInputStream();
PushbackInputStream pushbackInputStream = new PushbackInputStream(inputStream);
ObjectInputStream objectStream = new ObjectInputStream(pushbackInputStream);
for(int i; (i = pushbackInputStream.read()) != -1;) {
pushbackInputStream.unread(i);
String to = (String) objectStream.readObject();
System.out.println(to);
System.out.println(++counter);
}
objectStream.close();
pushbackInputStream.close();
inputStream.close();
System.out.println("Closing socket");
socket.close();
}
} catch (Exception e) {
e.printStackTrace();
}
}
}.start();
}
public static void main(String args[]) {
new TaskExecutionServer(2003);
}
}
or here again with try-with-resources which is preferable over manually closing AutoClosables.
public class TaskExecutionServer {
public TaskExecutionServer(final int port) {
new Thread() {
#Override
public void run() {
try (ServerSocket serverSocket = new ServerSocket(port)) {
int counter = 0;
while(true) {
System.out.println("Waiting for client...");
try (Socket socket = serverSocket.accept();
InputStream inputStream = socket.getInputStream();
PushbackInputStream pushbackInputStream = new PushbackInputStream(inputStream);
ObjectInputStream objectStream = new ObjectInputStream(pushbackInputStream)) {
System.out.println("Accepted");
for(int i; (i = pushbackInputStream.read()) != -1;) {
pushbackInputStream.unread(i);
String to = (String) objectStream.readObject();
System.out.println(to);
System.out.println(++counter);
}
System.out.println("Closing socket");
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
}.start();
}
public static void main(String args[]) {
new TaskExecutionServer(2003);
}
}
available() is not a valid test for end of stream. See the Javadoc. You should read from the object stream until EOFException is caught.
I'm trying to make a connection between a server and multiple clients, but it doesn't work even for one. All I want to do is to send from the client an object using the ObjectOutputStream class. The connection is made successfully at the beginning but when I try to send the object to the server it fails.
This is the client part which is written in the main method of a class:
Socket socket;
OutputStream out;
ObjectOutputStream fout;
boolean connected=false;
if (!connected) {
try {
socket = new Socket("localhost", 8000);
out = socket.getOutputStream();
fout = new ObjectOutputStream(out);
fout.flush();
connected = true;
fout.writeObject(ac1);//ac is an object of Plane class
} catch (Exception ex) {
System.out.println(ex.toString());
}
}
This is the server:
public class server {
static class ServerThread implements Runnable {
Socket client = null;
public ServerThread(Socket c) {
this.client = c;
}
public void run() {
try {
System.out.println("Connected to client : "+client.getInetAddress().getHostName());
Plane ac=null;
InputStream in=client.getInputStream();
ObjectInputStream fin=new ObjectInputStream(in);
while(client.isConnected()){
ac = (Plane)fin.readObject();
System.out.println(ac.toString());
}
client.close();
} catch (Exception e) {
// System.err.println(e.getMessage());
e.printStackTrace();
}
}
}
public static void main(String args[]) {
try {
ServerSocket server = new ServerSocket(8000);
while (true) {
Socket p = server.accept();
new Thread(new ServerThread(p)).start();
}
} catch (Exception ex) {
System.err.println("Error : " + ex.getMessage());
}
}
}
Could anyone tell me what is the problem?
Your client never closes the socket, and presumably exits, so the connection is reset. So close the socket.
NB isConnected() is not a valid loop condition. It will never become false. Your loop should terminate when EOFExceprion is caught.
I'm new in Java Sockets, I have seen so many examples but I can't understand how to pass an argument from server to client and vice versa. My destination is to pass an Object that's why I'm using Object I/O Stream.
I have to classes Server and Player.
public class Server extends Thread{
public static final int TEST = 165;
ServerSocket serverSocket;
InetAddress address;
Player playerWhite;
public Server() {
start();
}
#Override
public void run() {
try
{
address = InetAddress.getLocalHost();
serverSocket = new ServerSocket(6000);
playerWhite = new Player();
System.out.println("server waits for players");
playerWhite.socket = serverSocket.accept();
playerWhite.start();
sendTestMessage(playerWhite);
}
catch (IOException ex)
{
Logger.getLogger(Server.class.getName()).log(Level.SEVERE, null, ex);
}
}
public void sendTestMessage(Player player) throws IOException
{
ObjectOutputStream testToClient = new ObjectOutputStream(player.socket.getOutputStream());
testToClient.write(TEST);
testToClient.flush();
}
And the Player class:
public class Player extends Thread {
Socket socket;
Player() throws IOException
{
socket = new Socket(InetAddress.getLocalHost(), 6000);
}
#Override
public void run() {
try {
listenTestStream();
}
catch (IOException | ClassNotFoundException ex)
{
Logger.getLogger(CheckerPlayer.class.getName()).log(Level.SEVERE, null, ex);
}
}
public void listenTestStream() throws IOException, ClassNotFoundException
{
ObjectInputStream ois = new ObjectInputStream(socket.getInputStream());
int message = ois.readInt();
//To test
System.out.println("Server listened: " + message);
}
I execute it as create a Server object in the other class.
When I have testing this application I saw that sometimes client is faster than Server. Is it possible to make him "wait" for server response?
Thanks for your response.
EDIT 1: PROBLEM SOLUTION:
From outside we should create:
Player player = new Player(); // (class player extends from Thread)
player.start();
and delete the Player variable - is not necessary, we need only Socket so:
Server:
Socket playerWhiteSocket
public void run() {
try
{
serverSocket = new ServerSocket(PORT);
playerWhiteSocket = serverSocket.accept();
sendMessage(playerWhiteSocket, "Hello");
}
catch(IOException | ClassNotFoundException ex)
{}
public void sendMessage(Socket socket, String message) throws IOException
{
ObjectOutputStream testToClient = new ObjectOutputStream(socket.getOutputStream());
testToClient.writeObject(message);
testToClient.flush();
}
In Player class we need get method:
public String receiveMessage() throws IOException, ClassNotFoundException
{
//socket is a variable get from Player class socket = new Socket("severHost", PORT);
ObjectInputStream messageFromServer = new ObjectInputStream(socket.getInputStream());
String message = (String) messageFromServer.readObject();
return message;
}
I would recomment doing this public void start(){
try {
ServerSocket = new ServerSocket(this.port,10,this.localAddress);
// set timeout if you want
//this.clientServerSocket.setSoTimeout(timeout);
// infinity loop
while(true)
{
//wait for a client connection
Socket socket = ServerSocket.accept();
// start thread for every new client
Thread t = new Thread(new AcceptClients(this.socket));
t.start();
System.out.println(L"new client connected");
// call garbage collector and hope for the best
System.gc();
}
} catch (IOException e) {
System.out.println("IO Error");
e.printStackTrace();
}
}
and then in another class
public class AcceptClients implements Runnable{
// socket
private Socket socket;
public AcceptClients (Socket socket){
this.socket = socket;
}
#Override
public void run() {
// what happens if a client connect
}
}
I always use this and it works fine
Suggested changes.
Create ServerSocket only once. If you have done it, you won't get "Address already in use" error
After creating Server Socket, you thread should be in while (true) loop to accept connection from client.
Once you create a client socket, pass that socket to thread.
Now Player is used to send communication from server to client socket. So You need one more class like PlayerClient which create a socket to Server IP and Port. Now PlayerClient should create one more thread to handle IO operations like you have done from server. In this case, creating a socket is not in while loop from client side. It create a socket to server once. Now you can run this PlayerClient program from multiple machines.
If you are just sending just primitive type, use DataOutputStream & DataInputStream instead of ObjectStreams
This code will become like this
try
{
address = InetAddress.getLocalHost();
serverSocket = new ServerSocket(6000);
System.out.println("server waits for players");
while ( true){
Socket socket = serverSocket.accept();
Player playerWhite = new Player(socket);
sendTestMessage(socket);// Move this method to Player thread and change the signature of this method accordingly to accept a socket
}
}
catch (IOException ex)
{
Logger.getLogger(Server.class.getName()).log(Level.SEVERE, null, ex);
}
Player.java
Player(Socket socket) throws IOException
{
this.socket = socket;
start();
}
Have a look at this chat example for better understanding.
Yep it is.
It should work if you put it in a endlees loop like that:
try
{
while(true){
address = InetAddress.getLocalHost();
serverSocket = new ServerSocket(6000);
playerWhite = new Player();
System.out.println("server waits for players");
playerWhite.socket = serverSocket.accept();
playerWhite.start();
sendTestMessage(playerWhite);
}
}
catch (IOException ex)
{
Logger.getLogger(Server.class.getName()).log(Level.SEVERE, null, ex);
}
But I would not recommend to put this in a thread. Instead I would put the connection of a new client in a thread, so multiple clients can connect to the server
I have a chat program. Now the code works for communicate between client and server via command line. But it gives an exception (java.net.SocketException: Socket is closed) while running. Please help me to fix that problem.
In a java chat program,how will the communication be implemented between client and server?
ie.
client<-->server (between server and client)
or
client A<-->server<-->client B (server act as a bridge between two clients)
Is the 2 way communication can be implemented through a single socket?
Are there any other methods ?
How to communicate more than one client simultaneously?
server code
class Server
{
ServerSocket server;
Socket client;
public Server()
{
try
{
server = new ServerSocket(2000);
System.out.println("\tServer Started..........");
while (true)
{
client = server.accept();
Send objsend = new Send(client);
Recive objrecive = new Recive(client);
//client.close();
}
}
catch (Exception e)
{
System.out.println("Exception4 " + e);
}
}
public static void main(String arg[])
{
new Server();
}
}
class Recive implements Runnable
{
Socket client;
public Recive(Socket client1)
{
client=client1;
Thread trsend=new Thread(this);
trsend.start();
}
public void run()
{
ObjectInputStream ois;
Message M=new Message();
try
{
ois = new ObjectInputStream(client.getInputStream());
M = (Message)ois.readObject();
M.display();
ois.close();
}
catch (Exception e)
{
System.out.println("Exception1 " + e);
}
}
}
class Send implements Runnable
{
Socket client;
public Send(Socket client1)
{
client=client1;
Thread trrecive=new Thread(this);
trrecive.start();
}
public void run()
{
Message M=new Message();
InputStreamReader isr=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(isr);
try
{
System.out.println("Me(server)");
M.strmessage=br.readLine();
ObjectOutputStream oos=new ObjectOutputStream(cli ent.getOutputStream());
oos.writeObject((Message)M);
oos.flush();
oos.close();
}
catch (Exception e)
{
System.out.println("Exception " + e);
}
}
}
client code
class Client
{
public static void main(String arg[])
{
try
{
Send objsend=new Send();
Recive objrecive=new Recive();
}
catch(Exception e)
{
System.out.println("Exception "+e);
}
}
}
class Send implements Runnable
{
public Send()
{
Thread trsend=new Thread(this);
trsend.start();
}
public void run()
{
try
{
Message M=new Message();
InputStreamReader isr=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(isr);
while(true)
{
System.out.println("Me(client)");
M.strmessage=br.readLine();
Socket client=new Socket("localhost",2000);
ObjectOutputStream oos=new ObjectOutputStream(client.getOutputStream());
oos.writeObject((Message)M);
oos.flush();
oos.close();
}
}
catch(Exception e)
{
System.out.println("Exception "+e);
}
}
}
class Recive implements Runnable
{
public Recive()
{
Thread trrecive=new Thread(this);
trrecive.start();
}
public void run()
{
try
{
while(true)
{
Socket client=new Socket("localhost",2000);
ObjectInputStream ois=new ObjectInputStream(client.getInputStream());
Message CNE=(Message)ois.readObject();
CNE.display();
ois.close();
}
}
catch(Exception e)
{
System.out.println("Exception "+e);
}
}
}
First of all, don't close the streams in every run().
Secondly, check whether port for server which you are using is free.
This program makes your pc both host and server.
import java.io.IOException;
import java.net.*;
public class ClientServer {
static byte[] buffer = new byte[100];
private static void runClient() throws IOException {
byte buffer[] = new byte[100];
InetAddress address = InetAddress.getLocalHost();
DatagramSocket ds=new DatagramSocket();
int pos = 0;
while (pos<buffer.length) {
int c = System.in.read();
buffer[pos++]=(byte)c;
if ((char)c =='\n')
break;
}
System.out.println("Sending " + pos + " bytes");
ds.send(new DatagramPacket(buffer, pos, address, 3000));
}
private static void runServer() throws IOException {
InetAddress address = InetAddress.getLocalHost();
DatagramSocket ds = new DatagramSocket(3000, address);
DatagramPacket dp = new DatagramPacket(buffer, buffer.length);
ds.receive(dp);
String s=new String(dp.getData(),0,dp.getLength());
System.out.print(s);
}
public static void main(String args[]) throws IOException {
if (args.length == 1) {
runClient();
} else {
runServer();
}
}
}
also follow this link
There could be multiple places where the exception could be thrown. Without a stack trace it is difficult to state so accurately, as to the cause of failure.
But the root cause, is essentially due to the fact that you are closing the InputStream of the socket in your Receiver threads after reading a message, and closing the OutputStream of the socket in your Sender threads after sending a message. Closing either of these streams will automatically close the socket, so you if attempt to perform any further operation on it, a SocketException will be thrown.
If you need to ensure that your server and client do not shutdown in such an abrupt manner, you'll have to keep reading the InputStream (until you get a special message to shutdown, for instance). At the same time, you'll also have to keep writing to the OutputStream. Two-way communication is definitely possible, and the posted code is capable of the same (if the socket remains open).
If you have to handle multiple clients, you'll need multiple reader and writer threads on the server, each listening on an instance of a Socket returned from ServerSocket.accept(); in simpler words, you need a reader-writer pair listening on a distinct socket on the server for each client. At the moment, multiple clients can connect to the Server, as each incoming connection is provided its own client Socket object on the Server, that is provided to individual reader and writer threads. The main Server thread can continue to receive incoming connections and delegate the actual work to the reader-writer pairs.
chat programms normaly have a server through which all communication goes. The reason is that other wise every client needs to know how to reach every other client. And that doesn't work in the general case.
So you'll have a server, every client registers and talks with the server, which will forward messages to other clients.
Mostly communication is done via HTTP cause this is likely to go through firewalls and proxies. You probably want to read up on long polling if you are planning for anything serious.