I'm trying to connect to GDAX using their REST API.
I first want to do something very simple, i.e. getting historic rates.
I tried this:
private static final String GDAX_URL = "https://api.gdax.com";
public String getCandles(final String productId, final int granularity) {
HttpsURLConnection connection = null;
String path = "/products/" + productId + "/candles";
try {
//Create connection
URL url = new URL(GDAX_URL);
connection = (HttpsURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("granularity", String.valueOf(granularity));
connection.setUseCaches(false);
connection.setDoOutput(true);
//Send request
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.writeBytes(path);
wr.close();
//Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
StringBuffer response = new StringBuffer();
String line;
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
System.out.println(response.toString());
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if (connection != null) {
connection.disconnect();
}
}
return null;
}
But I get a 400 code in return "Bad Request – Invalid request format".
My problem is with the passing of the path "/products//candles" and the parameters (e.g. granularity).
I don't understand what should go in the request properties and in the message itself, and in what form.
I managed to make it work like this:
URL url = new URL(GDAX_URL + path + "?granularity="+granularity);
connection = (HttpsURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.setRequestProperty("Content-Type", "application/json");
Not sure how to use the DataOutputStream, so I just removed it. At least it works.
Related
How to call subsequent requests using j_security_check, I have followed below code but it's not working .
String url = "https://myhost/jsp/j_security_check?j_username=myuser&j_password=mypassword";
HttpURLConnection connection = (HttpURLConnection) new
URL(url).openConnection();
if (connection.getResponseCode() == 200) {
String cookie = connection.getHeaderField("Set-Cookie").split(";", 2)[0];
url = "https://myhost/getusers";
connection = (HttpURLConnection) new URL(url).openConnection();
connection.setRequestProperty("Cookie", cookie);
connection.setRequestProperty("Cache-Control", "no-cache");
InputStream input = connection.getInputStream();
try (BufferedReader buffer = new BufferedReader(new InputStreamReader(connection.getInputStream()))) {
String result = buffer.lines().collect(Collectors.joining("\n"));
System.out.println(result);
} catch (Exception e) {
e.printStackTrace();
}
}
Can anyone help me on it.
I'm connecting with two local servers post parameters for redirect link. But not change url and web view after posting the parameters. I get only response.toString() (html string like ...."). How I change redirect link and view.
I found other questions and answers that are not easy to understand.
try {
HttpURLConnection connection = null;
URL url = new URL("http://localhost:9090/myproject/payreq");
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length", ""
+ Integer.toString(postParams.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoInput(true);
connection.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(connection
.getOutputStream());
wr.writeBytes(postParams);
wr.flush();
wr.close();
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
} catch (Exception e) {
e.printStackTrace();
} finally {
if (connection != null) {
connection.disconnect();
}
}
I expect change my project link's 8080 from redirect follow other sites.
If you want to redirect to a different server, completetely on the server side, without the user noticing a change in the browser URL, use forward: redirection:
#Controller
public class MyController {
#RequestMapping("/myurl")
public String redirectWithUsingForwardPrefix(ModelMap model) {
model.addAttribute("attribute", "forwardWithForwardPrefix");
return "forward:/http://localhost:9090/myproject/payreq";
}
}
I added this method to my MainActivity.java
But i'm getting error on the static: Inner classes cannot have static declatarions.
protected static String excutePost(String targetURL, String urlParameters) {
HttpURLConnection connection = null;
try {
//Create connection
URL url = new URL(targetURL);
connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length",
Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoOutput(true);
//Send request
DataOutputStream wr = new DataOutputStream(
connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.close();
//Get Response
java.io.InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new java.io.InputStreamReader(is));
StringBuilder response = new StringBuilder(); // or StringBuffer if not Java 5+
String line;
while((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if(connection != null) {
connection.disconnect();
}
}
}
I can remove the static and then i'm getting no errors.
But where do i call this method from now ? From inside the onCreate ?
Tried but it's not exist when i type excute....in the onCreate it's not exist can't call it.
How do i use this method ? And what should i put as urlParameters ?
The outer class which holds the "excutePost" is an inner class therefore it cannot have static methods in it. What you can do is move the outer class to a separate file and make it non static - this will solve your problem.
I used to use DefaultHttpClient for my networking code, but decided to change to HttpURLConnection.
I have searched for other questions on how to send POST messages (eg How to add parameters to HttpURLConnection using POST), but for some reason my Flask app always gives me error 400.
When I use logcat, it indeed displays that my POST message is "username=asdf&password=asdf". I include the code below. Also, if I initialized the cookieManager in the method that called this method (makeServiceCall), will returning cookieManager keep my session for subsequent calls to makeServiceCall?
public CookieManager makeServiceCall(CookieManager cookieManager, String urlString, int method, List<NameValuePair> db) {
String charset = "UTF-8";
try {
URL url = new URL(urlString);
if (method == POST) {
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
if (db != null) {
try {
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);
urlConnection.setChunkedStreamingMode(0);
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("Accept-Charset", charset);
urlConnection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
OutputStream out = new BufferedOutputStream(urlConnection.getOutputStream());
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(out, charset));
Log.d("log", "> " + getQuery(db));
writer.write(getQuery(db));
writer.flush();
writer.close();
out.close();
//Get Response
InputStream in = urlConnection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(in));
String line;
StringBuffer response = new StringBuffer();
while((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
Log.d("Read attempt: ", "> " + response.toString());
}
finally {
urlConnection.disconnect();
}
}
}
etc.
Flask code:
def login():
error = None
if request.method == 'POST':
if request.form['username'] != app.config['USERNAME']:
error = 'Invalid username'
elif request.form['password'] != app.config['PASSWORD']:
error = 'Invalid password'
else:
session['logged_in'] = True
flash('You were logged in')
return redirect(url_for('show_entries'))
return render_template('login.html', error=error)
I need to send a post request to a https address. I have a function that sends post messages currectly but i cant seem to make it work for https.
public static String serverCall(String link, String data){
HttpURLConnection connection;
OutputStreamWriter request = null;
URL url = null;
String response = null;
String parameters = data;
try
{
url = new URL(link);
connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "text/xml");
connection.setRequestMethod("POST");
request = new OutputStreamWriter(connection.getOutputStream());
request.write(parameters);
request.flush();
request.close();
String line = "";
InputStreamReader isr = new InputStreamReader(connection.getInputStream());
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
// Response from server after process will be stored in response variable.
response = sb.toString();
isr.close();
reader.close();
}
catch(IOException e)
{
// Error
}
return response;
}
i have tryed using HttpsURLConnection insted of HttpURLConnection, i am still getting null from my server.
you should call connect();
....
connection.setRequestMethod("POST");
connection.connect();
....