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Android String format not working

I have a problem with String.format In android I want replace { 0 } with my id.
My this code not working:
String str = "abc&id={0}";
String result = String.format(str, "myId");

I think you should use replace method instead of format.
String str = "abc&id={0}";
str.replace("{0}","myId");

you have 2 ways to do that and you are mixing them :)
1.String format:
String str = "abc&id=%s";//note the format string appender %s
String result = String.format(str, "myId");
or
2.Message Format:
String str = "abc&id={0}"; // note the index here, in this case 0
String result = MessageFormat.format(str, "myId");

You have to set your integer value as a seperate variable.
String str = "abc&id";
int myId = 001;
String result = str+myId;

try this,
String result = String.format("abc&id=%s", "myId");
edit if you want more than one id,
String.format("abc&id=%s.id2=%s", "myId1", "myId2");

The syntax you're looking for is:
String str = "abc&id=%1$d";
String result = String.format(str, id);
$d because it's a decimal.
Other use case:
String.format("More %2$s for %1$s", "Steven", "coffee");
// ==> "More coffee for Steven"
which allows you to repeat an argument any number of times, at any position.

Extract last number after decimal

I am getting a piece of JSON text from a url connection and saving it to a string currently as such:
...//setting up url and connection
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String str = in.readLine();
When I print str, I correctly find the data {"build":{"version_component":"1.0.111"}}
Now I want to extract the 111 from str, but I am having some trouble.
I tried
String afterLastDot = inputLine.substring(inputLine.lastIndexOf(".") + 1);
but I end up with 111"}}
I need a solution that is generic so that if I have String str = {"build":{"version_component":"1.0.111111111"}}; the solution still works and extracts 111111111 (ie, I don't want to hard code extract the last three digits after the decimal point)

If you cannot use a JSON parser then you can this regex based extraction:
String lastNum = str.replaceAll("^.*\\.(\\d+).*", "$1");
RegEx Demo
^.* is greedy match that matches everything until last DOT and 1 or more digits that we put in group #1 to be used in replacement.

Find the start and the end indexes of the String you need and substring(start, end) :
// String str = "{"build":{"version_component":"1.0.111"}};" cannot compile without escaping
String str = "{\"build\":{\"version_component\":\"1.0.111\"}}";
int start = str.lastIndexOf(".")+1;
int end = str.lastIndexOf("\"");
String substring = str.substring(start,end);

just use JSON api
JSONObject obj = new JSONObject(str);
String versionComponent= obj.getJSONObject("build").getString("version_component");
Then just split and take the last element
versionComponent.split("\\.")[2];

Please, your can try the following code :
...
int index = inputLine.lastIndexOf(".")+1 ;
String afterLastDot = inputLine.substring(index, index+3);

With Regular Expressions (Rexp),
You can solve your problem like this ;
Pattern pattern = Pattern.compile("111") ;
Matcher matcher = pattern.matcher(str) ;
while(matcher.find()){
System.out.println(matcher.start()+" "+matcher.end());
System.out.println(str.substring(matcher.start(), matcher.end()));
}

remove all characters between slashes in a URL in java

I have a url for examle:
http://www.abc.com/ABC/ABC-Boots-in-Leather/Prod/product.aspx?iid=34487
i have to convert it into:
http://www.abc.com/product.aspx?iid=34487
I am using a regex expression as :
String u = url.replaceAll("/.*?/","");
But it doesn't remove the text but just removes the slashes.? How should i correct it?

int x = url.indexOf('/');
int y = url.lastIndexOf('/')+1;
String u = url.substring(0, x) + url.substring(y);

String s = "http:www.abc.com/ABC/ABC-Boots-in-Leather/Prod/product.aspx?iid=34487";
String s1 = s.replaceAll("(/(.)*/)","/");
output: http:www.abc.com/product.aspx?iid=34487

Updated to changed question
Probably not simplest solution, but works
String url = "http://www.abc.com/ABC/ABC-Boots-in-Leather/Prod/product.aspx?iid=34487";
String u = "http:/" + url.replaceAll("(http://)|/.*/", "/");
Result:
http://www.abc.com/product.aspx?iid=34487

Usage of the java function 'split()

I would like to split the word in java based on the delimeter'-'when it appeared last.
I am expecting the result as "sweet_memory_in" and "everbodylife#gmail.com". Do we have any inbuilt function in java.
Complete word is sweet_memory_in_everbodylife#gmail.com

String s = "sweet_memory_in_everbodylife#gmail.com";
String first = s.substring(0,s.lastIndexOf("_"));
String second = s.substring(s.lastIndexOf("_")+1 );

try this
String s = "sweet_memory_in_everbodylife#gmail.com";
String s1 = s.substring(0,s.lastIndexOf("_"));
String s2 = s.substring(s.lastIndexOf("_")+1,s.length());

Regex may help. Other way is to get the last index of _ and use substring to split it.

Try out this code :
String data = "sweet_memory_in_everbodylife#gmail.com";
int lastIndex = data.lastIndexOf("_");
String firstSplit = data.substring(0, lastIndex);
String secondSplit = data.substring(lastIndex + 1, data.length());
System.out.println(firstSplit);
System.out.println(secondSplit);

Try this my friend (Javascript Codes):
var str = 'sweet_memory_in_everbodylife#gmail.com';
var arr1 = str.substring(str.lastIndexOf("_")).split("_");
var arr2 = str.split("_"+arr1[1]);
alert(arr2[0] +" --> "+arr1[1]);

how to remove anchor tag and make it text

String k= <html>
<a target="_blank" href="http://www.taxmann.com/directtaxlaws/fileopencontainer.aspx?Page=CIRNO&
amp;id=1999033000019320&path=/Notifications/DirectTaxLaws/HTMLFiles/S.O.193(E)30031999.htm&
amp;aa=">number S.O.I93(E), dated the 30th March, 1999
</html>
I'm getting this HTML in a String and I want to remove the anchor tag so that data is also removed from link.
I just want display it as text not as a link.
how to do this i m trying to do so much not able to do please send me code regarding that i m
creating app for Android this issue i m getting in android on web view.

use JSoup, and jSoup.parse()

You can use the following example (don't remember where i've found it, but it works) using replace method to modify the string before showing it:
k = replace ( k, "<a target=\"_blank\" href=", "");
String replace(String _text, String _searchStr, String _replacementStr) {
// String buffer to store str
StringBuffer sb = new StringBuffer();
// Search for search
int searchStringPos = _text.indexOf(_searchStr);
int startPos = 0;
int searchStringLength = _searchStr.length();
// Iterate to add string
while (searchStringPos != -1) {
sb.append(_text.substring(startPos, searchStringPos)).append(_replacementStr);
startPos = searchStringPos + searchStringLength;
searchStringPos = _text.indexOf(_searchStr, startPos);
}
// Create string
sb.append(_text.substring(startPos,_text.length()));
return sb.toString();
}
To substitute all the target with an empty line:
k = replace ( k, "<a target=\"_blank\" href=\"http://www.taxmann.com/directtaxlaws/fileopencontainer.aspx?Page=CIRNO&id=1999033000019320&path=/Notifications/DirectTaxLaws/HTMLFiles/S.O.193(E)30031999.htm&aa=\">", "");
No escape is needed for slash.