Java - Learning the difficulties with synchronized - java

So my teacher posted some code with examples of synchronized code and non synchronized and he is trying to teach us the differences between putting synchronized on a method and a block of code. I dont see the difference in his code by running the application but perhaps you guys can see it and explain. Ill post the code and if there is something missing with the information that im giving you guys just leave a comment and i will edit as soon as possible. So there are two classes which are related to each other. And these are the following. The commented methods are the one that im supposed to try. So the first method im supposed to run with synchronized public int incCounter() { and without. The rest of the methods im supposed to run without synchronizing public int incCounter() {. But i dont see the difference.
package f6;
public class Counter1Thread extends Thread {
private Counter1 counter;
private int times;
public Counter1Thread(Counter1 counter, String name, int times) {
this.counter = counter;
this.setName(name);
this.times = times;
}
// Testa med Counter1-incCounter a) utan synchronized b) med synchronized
// public synchronized void run() {
// int value;
// System.out.println(getName() + " startar");
// while (times-->0) {
// try {
// Thread.sleep(1000);
// } catch (InterruptedException e) {}
// value = counter.incCounter();
// System.out.println(getName()+": "+value);
// }
// }
// testa med Counter1-incCounter utan synchronized
// public synchronized void run() {
// int value;
// System.out.println(getName() + " startar");
// while (times-->0) {
// try {
// Thread.sleep(1000);
// } catch (InterruptedException e) {}
// synchronized(counter) {
// value = counter.incCounter();
// }
// System.out.println(getName()+": "+value);
// }
// }
// testa med Counter1-incCounter utan synchronized
// public void run() {
// int value;
// System.out.println(getName() + " startar");
// while (times-->0) {
// try {
// Thread.sleep(1000);
// } catch (InterruptedException e) {}
// synchronized(counter) {
// value = counter.incCounter();
// System.out.println(getName()+": "+value);
// }
// }
// }
public static void main(String[] args) {
Counter1 counter = new Counter1();
Counter1Thread ct1 = new Counter1Thread(counter,"A",20);
Counter1Thread ct2 = new Counter1Thread(counter,"B",20);
ct1.start();
ct2.start();
}
}
package f6;
import java.util.Random;
public class Counter1 {
private int counter;
private Random rand = new Random();
public int incCounter() {
counter = counter + 1;
return counter;
}
// public synchronized int incCounter() {
// counter = counter + 1;
// return counter;
// }
}

The synchronized on the run methods don't do anything in these examples. You should ignore these. They are at best an example of randomly and incorrectly placed synchronization statements.
The key differences between the implementations are the differences between the (commented out) examples one and three: Example one has no synchronization around the increment operation, while the third example wraps increment with a synchronized statement:
value = counter.incCounter();
System.out.println(getName()+": "+value);
synchronized (counter) {
value = counter.incCounter();
System.out.println(getName()+": "+value);
}
The third example is the equivalent of the fourth example:
public synchronized int incCounter() {
counter = counter + 1;
return counter;
}
Which is the same as:
public int incCounter() {
synchronized (this) {
counter = counter + 1;
return counter;
}
}
Note that this from this fourth example is the same as counter from the third example.
What you should see is that the un-synchronized example doesn't reliably increment the counter. (You may not see the effect every time you run the test, as the result will depend on the timing of the two threads which are used by the test.)

Related

Synchronization simplification

I'm currently working on threading and synchronization.
I'm trying to print "A" 2 times, "B" 1 time, and "C" 4 times with this program, which basically works but I was wondering if there is a smaller and simpler solution to this, like putting all the classes into one or something similar.
Here is the code.
public class foo {
public static int countA = 0;
public static int countB = 0;
public static int countC = 0;
public static void main(String[] args) {
AThread athread = new AThread(new AClass());
BThread bthread = new BThread(new BClass());
CThread cthread = new CThread(new CClass());
athread.start();
bthread.start();
cthread.start();
}
static class AClass {
public synchronized void printA() throws InterruptedException {
if(countA == 2)
wait();
for(int i=1; i<3; i++) {
System.out.println("A"+i);
countA++;
}
}
}
static class BClass{
public synchronized void printB() throws InterruptedException {
if(countB == 1)
wait();
for(int i=1; i<2; i++) {
System.out.println("B"+i);
countB++;
}
}
}
static class CClass{
public synchronized void printC() throws InterruptedException {
if(countC == 4)
wait();
for(int i=1; i<5; i++) {
System.out.println("C"+i);
countC++;
}
}
}
static class AThread extends Thread {
AClass A = new AClass();
AThread(AClass a){
this.A = a;
}
public void run() {
try {
A.printA();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
static class BThread extends Thread {
BClass B = new BClass();
BThread(BClass b){
this.B = b;
}
public void run() {
try {
B.printB();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
static class CThread extends Thread {
CClass C = new CClass();
CThread(CClass c){
this.C = c;
}
public void run() {
try {
C.printC();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
Even though the task does not require threads, here is a different way of writing the code in the description using java 8 CompletableFuture
CompletableFuture<Void> future = CompletableFuture.runAsync(() -> {
for (int i = 0; i < 2; i++) {
System.out.println("A" + (i + 1));
}
}).thenRunAsync(() -> {
System.out.println("B1");
}).thenRunAsync(() -> {
for (int i = 0; i < 5; i++) {
System.out.println("C" + (i + 1));
}
});
As the first comment says, there is no synchronization at all going on between any of your objects. Perhaps this might become apparent by changing the order in which you start the threads (C first, then B, then A).
For scheduling between Threads to work, you need to :
find an object that is visible to both threads so that both can wait() and notify() on that object.
establish the condition that will cause the waiting to stop and put that in a while()
so you get sort of :
while (countA < 2) AClass.class.wait();
in the B thread (and catch the InterruptedException in the loop, don't propagate)
and in the A thread you put
AClass.class.notify();
after the print loop has exited.
You can (and in industrial settings mostly should) replace AClass.class with a synchronisation object dedicated to the purpose (and which has been made visible to both threads).
The while() is necessary because of what is known as "spurious wakeups" : a wait() will exit if a notify() has caused it to do so, but it can also exit without such a notify() having been issued.
And finally, note that the condition in the while() loop accesses countA field from thread B, while thread A might be updating it. With simple integers this may still be failproof, but with more complex evaluations this is in itself a potential source of race condition errors so those accesses need to be synchronized in turn. Also note that while(countA<2) might never become true if thread A crashes for whatever reason so this is not the most robust way of setting things up as it will cause system hangs.
If all this is more like gibberish than English, you should first try and find a decent tutorial on threading and study that carefully.

Multithreading Application won't run after JUnit Test

Im having problems with my Printer-Counter School Problem. Its supposed to be a multithreading application and runs fine so far. But when I running it the second or third time it wont work anymore.. No error message. Looks like Threads sleep forver or so. Also when I test it with a JUnit test it wont work. But sometimes it does... wich is already strange itself.
public class CounterPrinter {
public static void main(String[] args) throws InterruptedException {
if (args.length != 2) {
System.out.println("Usage: CounterPrinter <min> <max>");
System.exit(1);
}
Storage s = new Storage();
Printer d = new Printer(s, Integer.parseInt(args[1]));
Counter z = new Counter(s, Integer.parseInt(args[0]), Integer.parseInt(args[1]));
z.start();
d.start();
z.join();
d.join();
Thread.sleep(5000);
}
}
public class Printerextends Thread {
private Storage storage;
private Integer ende;
Printer(Storage s, Integer ende) {
this.storage = s;
this.ende = ende;
}
#Override
public void run() {
while (storage.hasValue()) {
try {
System.out.print(speicher.getValue(ende) + " ");
Thread.sleep(50);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
public class Counter extends Thread {
private Storage speicher;
private int max, min;
Counter(Storages, int min, int max) {
this.storage = s;
this.max = max;
this.min = min;
}
#Override
public void run() {
for (int i = min; i <= max; i++) {
try {
storage.setValue(i);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
public class Storage implements StorageIf {
private Integer wert;
private boolean hasValue = false;
#Override
public synchronized Integer getValue(Integer ende) throws InterruptedException {
if(wert.equals(ende)){
hasValue = false;
return wert;
}else {
while (!hasValue()) {
wait();
}
hasValue = false;
notifyAll();
return wert;
}
}
#Override
public synchronized void setValue(Integer wert) throws InterruptedException {
while (hasValue()){
wait();
}
hasValue = true;
this.wert = wert;
notifyAll();
}
#Override
public boolean hasValue() {
return hasValue;
}
}
Hope someone can spot a mistake I made :(
Thanks a lot!!!
The problem is that you conflate 2 states :
there is currently a value available
there will be no more values
Add an hasEnded() method to your Storage class, checking if the end value has been reached. Make sure to synchronize this method, as well as the hasValue() method. Synchronization needs to be done on both read and write access!
Then make Printer's while loop check hasEnded, rather than hasValue.
Finally : get rid of all the sleep() calls.
Your own answer, solving the problem with sleep, is not a real solution. A thread safe program does not depend on a computer's performance to function correctly.
z.start();
z.sleep(100);
d.start();
Putting a delay between starting the tow Threads solved the problem for me. My Computer was probably too fast down the road in Thread z before it even started Thread d. Thats why it hung itself up in 50% of the time.
Thanks to everyone tho :)

My own semaphore in java

I'd like to implement my own semaphore in Java (just for practice, I am aware, that there is Semaphore class)
I have implemented it like that:
public class MySemaphore {
private int value = 1;
public synchronized void take() {
this.value++;
this.notify();
}
public synchronized void release(){
while (this.value == 0) {
try {
wait();
} catch (InterruptedException e) {
}
}
this.value--;
}
}
I am trying to use it in such thread:
public class MyThread extends Thread {
private static MySemaphore semaphore = new MySemaphore();
public void run(){
for (int i = 0; i < 100; i++) {
semaphore.take();
try {
Main.myVariable += 1;
semaphore.release();
} catch (Exception e){
System.out.println("Exception" + e.getMessage());
}
}
}
}
I start and join threads like this:
import java.util.ArrayList;
import java.util.List;
public class Main {
public static int myVariable = 0;
private static int threadsNumber = 100;
public static void main(String[] args) {
List<Thread> allThreads = new ArrayList<>();
for (int i = 0; i < threadsNumber; i++) {
allThreads.add(new Thread(new MyThread()));
}
for (int i = 0; i < threadsNumber; i++) {
allThreads.get(i).start();
}
for (int i = 0; i < threadsNumber; i++) {
try{
allThreads.get(i).join();
} catch (Exception e){
System.out.println(e.getMessage());
System.out.println("********************************");
}
}
System.out.println("Result is " + myVariable);
}
}
I just want to increment a variable 10000 times and receive a result. Without semaphore the result is less than 10000 (like 9923, 9684), which is caused by non-atomicity of incrementation. I want to protect this variable using semaphore.
Unfortunately, the result is still less than or equal to 10000 (but much closer, in 9 out of 10 cases greater than 9990).
Do you have any idea why it happens? Is my semaphore wrong or am doing something wrong with launching threads?
In your MySemaphore class, value is already set to 1. It should be zero because in your release function you are verifying if value equals zero or not. This means that when your program starts, no thread will be able to have the semaphore(because you have set it to 1); doing so, they fall into waiting state. Your program ends when 'threadsNumber' reaches it's limit.In other words, you are not verifying if any thread is in waiting state before the programs ends. This explains why you have a 9/10 as success rate.
My recommendation would be to try setting the value to zero and also verify if there are any threads in waiting state.
Your code be like this:
public class MySemaphore {
private int value = 0; //this is already an error in your code
public synchronized void take() {
this.value++;
this.notify(); // wakes up the first thread that called wait on the shared variable
}
public synchronized void release() throws InterruptedException{
while(this.signals == 0) wait();
this.value--;
}
}

How notify second thread of variable's change

I have two threads. The first changes the value of variable Data. And second one print the value if its value has changed. I am trying to do that second thread just print each time that the variable's value changed, but I don't reach success. Someone can help me?
thread 1
class someservice{
volatile int data;
Boolean Flag = false;
public void mymethod(){
flag = true;
for (Integer i = 1; i < sheet.getRows(); i++) {
data = someMethod(); //this method when called return a new
//value
}
flag = false;
...
}
}
thread 2
Promise p = task {
try {
while (true) {
if (engineService.getFlag()) {
print(someservice.data);
}else{
break;
}
}
} catch(Throwable t) {
...
}
}
Since you mention Promises, I infer you are familiar with future/ promise in +C++11
in java there is a similar approach, with future callable...
public class HW5 {
public static void main(String[] argv) throws InterruptedException, ExecutionException {
FutureTask<Boolean> myFutureTask = new FutureTask<>(new Callable<Boolean>() {
#Override
public Boolean call() throws Exception {
// implement the logic here and return true if everything was
// ok, false otherwise.
Thread.sleep(5000);
System.out.println("dddd");
return System.currentTimeMillis() % 2 == 0;
}
});
ExecutorService executor = Executors.newFixedThreadPool(1);
executor.execute(myFutureTask);
Boolean result = myFutureTask.get();
System.out.println("Done!");
}
}
FutureTask in a class that takes a callable which can return an Object after its job is done... in Order to execute the Future task you can use a Executor service, especifically calling the method execute, since you need to wait for the thread to do the job then is necessary that you call Future.get, that will basically blocks the main thread until the future is done, to verify the result, just read the variable result..
You could use the notify() and notifyAll() methods within thread. Check out this link: https://docs.oracle.com/javase/tutorial/essential/concurrency/guardmeth.html
public synchronized void guardedJoy() {
// This guard only loops once for each special event, which may not
// be the event we're waiting for.
while(!joy) {
try {
wait();
} catch (InterruptedException e) {}
}
System.out.println("Joy and efficiency have been achieved!");
}
public synchronized notifyJoy() {
joy = true;
notifyAll();
}
You have to look up more data about Concurrent programming,I can tell you now some basics,well,not so so basic,but i will do my best:
Here,you have a Monitor,it is an abstract concept,in resume,a Monitor is a
class with all it's
method using"syncronized"
as modifier, it means,
that only
one thread
can access
the method
at once.So,
in the
monitor is
the variable
that you
want to print,
and the"flag",
that tells you if
the variable
was modified.Finally,
you can
see the
most important thing,the"wait()"and"notify()"methods,
those method
stops the thread,or"play"
them again.
You ask
here in
the printValue() method, if your variable was changed, if the variable was'nt change, put the thead to sleep with the wait() method, and when the other
method changeValue() is executed, the value is modified, and the notify() method is called, waking up the thread, so, doing all this, you can guarantee three things:
Safety: meaning that the threads will do that you want
Absence of deadlock: meaning that the thread that is put to sleep, will be awake in the future.
Mutex: meaning that only one thread is executing the critical code, for example, the op. "++" is not atomic, is Subdivided inside in more the one action, create a local var, read the var, sum, and asign, so, if more than one thread are in the game, the value may not be consecutive, example:
i = 0;
i ++;
output: 1;
output: 2;
output: 3;
output: 5;
output: 4;
output: 7;
That could happen, and even so, that will happen in the next code, because there a more than one thread executing. Well, this is the way to program with several threads, more or less
public class Monitor {
private int value = 0;
public static boolean valueHasChanged = false;
public synchronized int changeValue(int newValue){
this.value = newValue;
Monitor.valueHasChanged = true;
this.notify();
return this.value + 1;
}
public synchronized void printValue(){
while(!Monitor.valueHasChanged){
try {
this.wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
System.out.println(this.value);
Monitor.valueHasChanged = false;
}
public static void main(String[] args) {
Monitor ac = new Monitor();
BClass t1 = new BClass(ac);
AClass t2 = new AClass(ac);
t1.start();
t2.start();
}
public int getValue() {
return this.value;
}
}
Now the threads:
public class AClass extends Thread{
private Monitor ac;
public AClass(Monitor ac) {
this.ac = ac;
}
#Override
public void run() {
while(true){
this.ac.printValue();
}
}
}
And finally:
public class BClass extends Thread{
private Monitor ac;
public BClass(Monitor ac) {
this.ac = ac;
}
#Override
public void run() {
int v = 0;
while(true){
this.ac.changeValue(v);
v++; // this sum is not secure, if you want to print an
// ascending order, the code is diferent, I will show in
// above.
}
}
Now, if you want an ordered print:
the monitor will look like:
public class Monitor {
private int value = 0;
public boolean valueHasChanged = false;
private boolean hasPrint = true;
public synchronized void changeValue(int newValue) {
this.value = newValue;
this.valueHasChanged = true;
this.notify();
}
public synchronized void changeValuePlusOne() {
while (!hasPrint) {
try {
this.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
this.value++;
this.valueHasChanged = true;
this.hasPrint = false;
this.notifyAll();
}
public synchronized void printValue() {
while (!this.valueHasChanged) {
try {
this.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(this.value);
this.valueHasChanged = false;
this.hasPrint = true;
this.notifyAll();
}
public static void main(String[] args) {
Monitor ac = new Monitor();
BClass t1 = new BClass(ac);
AClass t2 = new AClass(ac);
t1.start();
t2.start();
}
public int getValue() {
return this.value;
}
}
And the Threads:
public class BClass extends Thread{
private Monitor ac;
public BClass(Monitor ac) {
this.ac = ac;
}
#Override
public void run() {
while(true){
this.ac.changeValuePlusOne();
}
}
}
The other Thread look equals:
public class AClass extends Thread{
private Monitor ac;
public AClass(Monitor ac) {
this.ac = ac;
}
#Override
public void run() {
while(true){
this.ac.printValue();
}
}
}

All threads get locked in wait() state [duplicate]

This question already has answers here:
Notify not getting the thread out of wait state
(3 answers)
Closed 7 years ago.
Basically I have to create 3 classes (2 threaded).
First one holds some cargo (has a minimum capacity (0) and a maximum (200))
Second one supplies the cargo every 500ms.
Third one takes away from cargo every 500ms.
Main program has one cargo class(1), 2 supplier classes(2) and 2 substraction classes(3). Problem I'm having is that one by one, they're falling into a wait(); state and never get out. Eventually all of them get stucked in the wait() state, with the program running, but without them actually doing anything.
First class:
public class Storage {
private int maxCapacity;
private int currentCapacity;
public Storage( int currentCapacity, int maxCapacity ) {
this.currentCapacity = currentCapacity;
this.maxCapacity = maxCapacity;
}
public int getCapacity(){ return this.currentCapacity; }
public void increase( int q ) {
this.currentCapacity += q;
System.out.println("increase" + q + ". Total: " + currentCapacity);
}
public int getMax() { return this.maxCapacity; }
public void decrease( int q ) {
this.currentCapacity -= q;
System.out.println("decrease - " + q + ". Total: " + currentCapacity);
}
}
2nd class (supplier):
public class Supplier implements Runnable {
private int capacity;
private Storage storage;
private volatile boolean run;
public Supplier( int capacity, Storage storage ) {
this.capacity = capacity;
this.storage = storage;
this.run = true;
}
public void kiss_kill() { run = !run; }
public synchronized void add() {
while(storage.getCapacity() + capacity > storage.getMax()) {
try {
System.out.println("wait - supplier");
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
storage.increase(capacity);
notifyAll();
}
public void run() {
synchronized (this) {
while(run) {
add();
Thread.yield(); //would be wait(500), but this just speeds it up
}
}
}
}
3rd class (taker/demander):
public class Taker implements Runnable {
private int capacity;
private Storage storage;
private volatile boolean run;
public Taker( int capacity, Storage storage ) {
this.capacity = capacity;
this.storage = storage;
this.run = true;
}
public void kiss_kill() { run = !run; }
public synchronized void take() {
while(storage.getCapacity() - capacity < 0) {
try {
System.out.println("wait - taker");
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
storage.decrease(capacity);
notifyAll();
}
public void run() {
synchronized (this) {
while(run) {
take();
Thread.yield(); //again, wait(500) should be instead
}
}
}
}
Main is something like this:
public class Main{
public static void main(String... args) {
Storage sk = new Storage(100, 200);
Supplier[] s = { new Supplier(10, sk), new Supplier(15, sk) };
Taker[] p = { new Taker(15, sk), new Taker(20, sk) };
Thread t[] = {
new Thread(s[0]),
new Thread(s[1]),
new Thread(p[0]),
new Thread(p[1]) };
for(Thread th : t) th.start();
try {
Thread.sleep(60000); //program should last for 60s.
} catch (InterruptedException e) {
e.printStackTrace();
}
s[0].kiss_kill(); s[1].kiss_kill(); p[0].kiss_kill(); p[1].kiss_kill();
}
}
Why doesn't notifyAll() release the wait() state of other object? What could I do to fix this?
Sorry, I know it's a long example, I hate posting too many classes like this. Thanks for reading!
I translated the code, so if you spot anything that you're unsure about that I've missed, please tell me and I'll fix it right away!
Doing concurrency is easy:
Anyone can slap synchronized on methods and synchronized () {} around blocks of code. It does not mean it is correct. And then they can continue to slap synchronized on everything until it works until it doesn't.
Doing concurrency correctly is Hard:
You should lock on the data that needs to be consistent not the methods making the changes. And you have to use the same lock instance for everything.
In this case that is the currentCapacity in Storage. That is the only thing that is shared and the only thing that needs to be consistent.
What you are doing now is having the classes lock on instances of themselves which means nothing shared is being protected because there is no shared lock.
Think about it, if you are not locking on the same exact instance which must be final of an object then what are you protecting?
Also what about code that has access to the object that needs to be consistent and does not request a lock on it. Well it just does what it wants. synchronized() {} in calling classes is not how you protect shared data from external manipulation.
Thread safe objects are NOT about the synchronized keyword:
Read up on the java.util.concurrent package it has all the things you need already. Use the correct data structure for your use case.
In this particular case if you use AtomicInteger for your counter, you do not need any error prone manual locking, no need for synchronized anywhere, it is already thread safe.
Immutable Data:
If you work with immutable data exclusively you do not need any of this silly locking semantics that are extremely error prone for even those that understand it and even more so for those that think they understand it.
Here is a working idiomatic example:
This is a good chance to learn what non-deterministic means and how to use the step debugger in your IDE to debug concurrent programs.
Q33700412.java
import java.util.Random;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.atomic.AtomicInteger;
import com.vertigrated.FormattedRuntimeException;
public class Q33700412
{
public static void main(final String[] args)
{
final Storage s = new Storage(100);
final int ap = Runtime.getRuntime().availableProcessors();
final ExecutorService es = Executors.newFixedThreadPool(ap);
for (int i = 0; i < ap; i++)
{
es.execute(new Runnable()
{
final Random r = new Random();
#Override
public void run()
{
while (true)
{
/* this if/else block is NOT thread safe, I did this on purpose
the state can change between s.remainingCapacity() and
the call to s.increase/s.decrease.
This is ok, because the Storage object is internally consistent.
This thread might fail if this happens, this is the educational part.
*/
if (s.remainingCapacity() > 0)
{
if (r.nextBoolean()) { s.increase(r.nextInt(10)); }
else { s.decrease(10); }
System.out.format("Current Capacity is %d", s.getCurrentCapacity());
System.out.println();
}
else
{
System.out.format("Max Capacity %d Reached", s.getMaxCapacity());
System.out.println();
}
try { Thread.sleep(r.nextInt(5000)); }
catch (InterruptedException e) { throw new RuntimeException(e); }
}
}
});
}
es.shutdown();
try
{
Thread.sleep(TimeUnit.MINUTES.toMillis(1));
es.shutdown();
}
catch (InterruptedException e) { System.out.println("Done!"); }
}
public static final class Storage
{
/* AtomicInteger is used so that it can be mutable and final at the same time */
private final AtomicInteger currentCapacity;
private final int maxCapacity;
public Storage(final int maxCapacity) { this(0, maxCapacity); }
public Storage(final int currentCapacity, final int maxCapacity)
{
this.currentCapacity = new AtomicInteger(currentCapacity);
this.maxCapacity = maxCapacity;
}
public int remainingCapacity() { return this.maxCapacity - this.currentCapacity.get(); }
public int getCurrentCapacity() { return this.currentCapacity.get(); }
public void increase(final int q)
{
synchronized (this.currentCapacity)
{
if (this.currentCapacity.get() < this.maxCapacity)
{
this.currentCapacity.addAndGet(q);
}
else
{
throw new FormattedRuntimeException("Max Capacity %d Exceeded!", this.maxCapacity);
}
}
}
public int getMaxCapacity() { return this.maxCapacity; }
public void decrease(final int q)
{
synchronized (this.currentCapacity)
{
if (this.currentCapacity.get() - q >= 0)
{
this.currentCapacity.addAndGet(q * -1);
}
else
{
this.currentCapacity.set(0);
}
}
}
}
}
Notes:
Limit the scope of synchronized blocks to the minimum they need to protect and lock on the object that needs to stay consistent.
The lock object must be marked final or the reference can change and you will be locking on different instances.
The more final the more correct your programs are likely to be the first time.
Jarrod Roberson gave you the "how" half of the answer. Here's the other half--the "why".
Your Supplier object's add() method waits on itself (i.e., on the supplier object), and it notifies itself.
Your Taker object's take() method waits on its self (i.e., on the taker object), and it notifies its self.
The supplier never notifies the taker, and taker never notifies the supplier.
You should do all of your synchronization on the shared object (i.e., on the Storage object.
So I should convert storage into a thread?
No, you don't want Storage to be a thread, you want it to be the lock. Instead of having your Supplier objects and your Taker objects synchronize on themselves, they should all synchronize on the shared Storage object.
E.g., do this:
public void take() {
synchronized(storage) {
while(...) {
try {
storage.wait();
} catch ...
}
...
storage.notifyAll();
}
}
Instead of this:
public synchronized void take() {
while(...) {
try {
wait();
} catch ...
}
...
notifyAll();
}
And do the same for all of your other synchronized methods.

Categories