I've issue in format of java for ISO 8601, I'm using this code
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
//yyyy-MM-dd'T'HH:mm:ss.shh:mm
Date date = Calendar.getInstance().getTime();
String cDate = format.format(date);
Log.d("Date","Date is " + cDate);
My result is:
Date is 2019-04-03T04:37:52+0000
if I'm using this format yyyy-MM-dd'T'HH:mm:ssZ. And the result is:
Date is 2019-04-03T04:49:33.3304:49
if I'm using this format yyyy-MM-dd'T'HH:mm:ss.shh:mm. I've been tried my solutions but not is giving me my desired solution.
My desired solution is 2008-09-15T15:53:00+05:00. I try Offset but it's not working for API level 23, It's only for API level 28.
Here is the format mask you should be using:
yyyy-MM-dd'T'HH:mm:ssXXX
From the documentation for SimpleDateFormat, we can see that X represents the ISO 8601 time zone, which shows the timezone in terms of hours shifted from GMT.
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX");
format.setTimeZone(TimeZone.getTimeZone("Africa/Cairo"));
Date date = Calendar.getInstance().getTime();
String cDate = format.format(date);
System.out.println("Date is " + cDate);
Date is 2019-04-03T06:41:30+02:00
Note that I needed to assign a time zone other than GMT, because GMT just returns Z for the time zone.
Tim was right but his given pattern works for java, Not for that java which is in android.
For Android java use this pattern
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZZZZZ");
Then out put will be
Date is 2019-04-03T08:29:27+00:00
Related
I need to format a String that looks like this:
"2018-07-20 18:53:46.598000 +02:00:00"
into a DateTime object like this:
20/07/2018 (HH with Timezone applied):53:46
My approach has been:
String dateTimePattern = "dd/MM/yyyy HH:mm:ss";
SimpleDateFormat dateTimeFormat = new SimpleDateFormat(dateTimePattern);
Date feUltModDateTime = dateTimeFormat.parse(feUltMod);
feUltMod = feUltModDateTime.toString();
But I'm getting a parse error:
java.text.ParseException: Unparseable date: "2018-07-20 18:53:46.598000 +02:00:00"
java.time
DateTimeFormatter origFormatter
= DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss.SSSSSS XXXXX");
DateTimeFormatter desiredFormatter = DateTimeFormatter.ofPattern("dd/MM/uuuu HH:mm:ss");
ZoneId desiredZone = ZoneId.of("America/Fort_Nelson");
String feUltMod = "2018-07-20 18:53:46.598000 +02:00:00";
OffsetDateTime dateTime = OffsetDateTime.parse(feUltMod, origFormatter);
ZonedDateTime dateTimeWithTimeZoneApplied = dateTime.atZoneSameInstant(desiredZone);
feUltMod = dateTimeWithTimeZoneApplied.format(desiredFormatter);
System.out.println(feUltMod);
Output from this snippet is:
20/07/2018 09:53:46
Generally you need two formatters for converting a date or date-time from one format to another: one that specifies the format to convert from and one that specifies the format to convert to.
into a DateTime object like this
A date-time object doesn’t have a format, so in that respect cannot be “like this”. dateTimeWithTimeZoneApplied in the above snippet is in the specified time zone, so has the hours adjusted. After converting to this time zone I have formatted into a string in the format you mentioned, in case you wanted this (I didn’t find it clear).
I am using and recommending java.time, the modern Java date and time API. The date and time classes you were using, Date and SimpleDateFormat, are long outdated and poorly designed, it’s not worth struggling with them. Also SimpleDateFormat supports only milliseconds so can only work correctly with exactly 3 decimals on the seconds, not with the 6 decimals you have got.
Link: Oracle tutorial: Date Time explaining how to use java.time.
final SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm");
Date df = new Date();
String yourString = sdf.format(df);
Date parsedDate = sdf.parse(yourString);
Timestamp sqlDate = new java.sql.Timestamp(parsedDate.getTime());
The above code will give you current Timestamp.Timestamp will provide better feasibilty
I have this date in this format:
String date = "2018-12-08T07:50:00+01:00";
And I'd like to get the local time in this format (adding the hours over GMT) but I'm not able to do it
date = "2018-12-08 08:50:00";
Other example:
String date = "2018-12-08T07:50:00+04:00";
Result:
date = "2018-12-08 11:50:00";
Any help?
As Sun already said in another answer, you misunderstood: 2018-12-08T07:50:00+01:00 is the same point in time as 2018-12-08 06:50:00 in UTC (roughly the same as GMT), not 08:50. +01:00 means that the time comes from a place where the clocks are 1 hour ahead of UTC, so to get the UTC time 1 hour should be subtracted, not added.
DateTimeFormatter desiredFormatter = DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss");
String date = "2018-12-08T07:50:00+01:00";
OffsetDateTime dateTime = OffsetDateTime.parse(date);
OffsetDateTime dateTimeInUtc = dateTime.withOffsetSameInstant(ZoneOffset.UTC);
date = dateTimeInUtc.format(desiredFormatter);
System.out.println(date);
Output from this snippet is:
2018-12-08 06:50:00
Using your other example, 2018-12-08T07:50:00+04:00, the output is
2018-12-08 03:50:00
I am taking advantage of the fact that your string is in ISO 8601 format. OffsetDateTime parses this format as its default, that is, we don’t need to specify the format in a DateTimeFormatter (as we do for your desired result format).
Link: Wikipedia article: ISO 8601
2018-12-08T07:50:00+01:00, the +01:00 in the end does not mean adding hh:mm, it means the datetime is already local date time, in GMT it is 2018-12-08T06:50:00.
You can use string.replaceAll to remove T and +01:00:
String input = "2018-12-08T07:50:00+01:00";
input = input.replaceAll("T", " ");
input = input.replaceAll("\\+.*", "");
System.out.println(input); // 2018-12-08 07:50:00
or parse and re-format it:
OffsetDateTime offsetDateTime = OffsetDateTime.parse("2018-12-08T07:50:00+01:00");
String time = offsetDateTime.format(DateTimeFormatter.ISO_LOCAL_DATE_TIME).replace("T", " ");
System.out.println(time); // 2018-12-08 07:50:00
I am trying to convert UTC Date to IST. But to my surprise, after converting everything, it is still returning me UTC only. How is it possible?
INPUT:
StartDateTimeUtc='2017-09-15T14:00:00',
EndDateTimeUtc='2017-09-15T15:00:00'
Code:
public static final String DATE_FORMATE_CURRENT = "yyyy-MM-dd'T'HH:mm:ss";
Date meetingStartDate = new SimpleDateFormat(Constants.DATE_FORMATE_CURRENT, Locale.ENGLISH).parse(model.StartDateTimeUtc);
Date meetingEndDate = new SimpleDateFormat(Constants.DATE_FORMATE_CURRENT, Locale.ENGLISH).parse(model.EndDateTimeUtc);
//Convert Date to String
DateFormat df = new SimpleDateFormat(Constants.DATE_FORMATE_CURRENT);
String meetinStartDateString = df.format(meetingStartDate);
String meetingEndDateString = df.format(meetingEndDate);
//Convert String Date to IST
SimpleDateFormat dftwo = new SimpleDateFormat(Constants.DATE_FORMATE_CURRENT);
dftwo.setTimeZone(TimeZone.getTimeZone("Asia/Kolkata"));
Date date = null;
Date datetwo = null;
try {
date = dftwo.parse(meetinStartDateString);
datetwo = dftwo.parse(meetingEndDateString);
} catch (ParseException e) {
e.printStackTrace();
}
dftwo.setTimeZone(TimeZone.getDefault());
String formattedStartDate = dftwo.format(date);
String formattedEndDate = dftwo.format(datetwo);
//Convert String Date back to Date format so that we can pass into Calendar code
Date meetingStartDateFinal = new SimpleDateFormat(Constants.DATE_FORMATE_CURRENT, Locale.ENGLISH).parse(formattedStartDate);
Date meetingEndDateFinal = new SimpleDateFormat(Constants.DATE_FORMATE_CURRENT, Locale.ENGLISH).parse(formattedEndDate);
OUTPUT again in UTC:
Start Date : Fri Sep 15 14:00:00 GMT+05:30 2017
End Date : Fri Sep 15 15:00:00 GMT+05:30 2017
A java.util.Date doesn't have any timezone information. It just contains one value: the number of milliseconds since unix epoch (1970-01-01T00:00Z, or January 1st 1907, at midnight in UTC).
This number of milliseconds is the same, everywhere in the world. What's is different is the corresponding date and time in each timezone. Example: right now, this millis value is 1505481835424, which corresponds, in UTC, to 2017-09-15T13:23:55.424Z. This same value corresponds to 10:23 AM in São Paulo, 18:53 in Kolkata, 14:23 in London and so on. The local date/time is different in each timezone, but the millis value is the same for everyone.
That's why you don't convert a Date itself: the millis value is the same, and there's no need to change it. What you can change is the representation of this date in different timezones.
SimpleDateFormat, by default, uses the JVM default timezone to parse dates. But if you know that the inputs are in a specific zone, you must set in the formatter. So, to parse your inputs, you must do:
String startDateTimeUtc = "2017-09-15T14:00:00";
String endDateTimeUtc = "2017-09-15T15:00:00";
SimpleDateFormat sdf = new SimpleDateFormat( "yyyy-MM-dd'T'HH:mm:ss");
// input is in UTC
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
// parse dates
Date meetingStartDate = sdf.parse(startDateTimeUtc);
Date meetingEndDate = sdf.parse(endDateTimeUtc);
The 2 Date objects above will correspond to 14:00 and 15:00 UTC (which is the same as 19:30 and 20:30 in Kolkata timezone).
But if you just print the Date objects directly (using System.out.println, logging, or even checking their values in a debugger), it'll implicity call the toString() method, which uses the JVM default timezone behind the scenes, resulting in the output you're seeing (Fri Sep 15 14:00:00 GMT+05:30 2017).
If you want to print in a specific format, and in a specific timezone, you'll need another formatter:
// another formatter for output
SimpleDateFormat outputFormat= new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
// output will be in Asia/Kolkata timezone
outputFormat.setTimeZone(TimeZone.getTimeZone("Asia/Kolkata"));
System.out.println(outputFormat.format(meetingStartDate));
System.out.println(outputFormat.format(meetingEndDate));
The output will be:
2017-09-15T19:30:00
2017-09-15T20:30:00
Which corresponds to the same UTC dates in Kolkata timezone.
Just remember: you don't convert the Date's between timezones (because their millis values are "absolute" - they are the same for everyone in the world). You just change the String representation of those dates (the corresponding date/time in a specific timezone).
Java new Date/Time API
The old classes (Date, Calendar and SimpleDateFormat) have lots of problems and design issues, and they're being replaced by the new APIs.
In Android you can use the ThreeTen Backport, a great backport for Java 8's new date/time classes. To make it work, you'll also need the ThreeTenABP (more on how to use it here).
This new API has lots of different date/time types for each situation. In this case, the inputs have date and time, but no timezone information, so first I parse them to a org.threeten.bp.LocalDateTime, using a org.threeten.bp.format.DateTimeFormatter:
// parse the inputs
DateTimeFormatter fmt = DateTimeFormatter.ISO_LOCAL_DATE_TIME;
LocalDateTime startDt = LocalDateTime.parse(startDateTimeUtc, fmt);
LocalDateTime endDt = LocalDateTime.parse(endDateTimeUtc, fmt);
Then I use a org.threeten.bp.ZoneOffset to convert them to UTC, and later a org.threeten.bp.ZoneId to convert this to another timezone. The result will be a org.threeten.bp.ZonedDateTime:
// input is in UTC
ZoneOffset utc = ZoneOffset.UTC;
// convert to Asia/Kolkata
ZoneId zone = ZoneId.of("Asia/Kolkata");
ZonedDateTime start = startDt.atOffset(utc).atZoneSameInstant(zone);
ZonedDateTime end = endDt.atOffset(utc).atZoneSameInstant(zone);
Then I use the same DateTimeFormatter to format the output:
System.out.println(fmt.format(start));
System.out.println(fmt.format(end));
The output is:
2017-09-15T19:30:00
2017-09-15T20:30:00
Note that I don't need to set the timezone in the formatter, because the timezone information is in the objects (they are responsible to do the conversion).
I have the following string "2015-04-02 11:52:00+02" and I need to parse it in Java to a Timestamp.
I tried all sorts of formats including
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss+Z");
but nothing seems to work - I keep getting a ParseException
Can anyone help?
I need something like:
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss+Z");
Timestamp t = new Timestamp(mdyFormat.parse("2015-04-02 11:52:00+02").getTime());
Try This
String str="2009-12-31 23:59:59 +0100";
/\
||
Provide Space while providing timeZone
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss Z");
System.out.println(mdyFormat.parse(str));
Output
Fri Jan 01 04:29:59 IST 2010
java.sql.Timestamp objects don't have time zones - they are instants in time, like java.util.Date
So try this:
SimpleDateFormat mdyFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Timestamp t = new Timestamp(mdyFormat.parse("2015-04-02 11:52:00").getTime());
try "yyyy-MM-dd HH:mm:ssX"
Z stand for timezone in the following format: +0800
X stand for timezone in the following format: +08
Examples here
ISO 8601
Replace that SPACE in the middle with a T and you have a valid standard (ISO 8601) string format that can be parsed directly by either the Joda-Time library or the new java.time package built into Java 8 (inspired by Joda-Time). Search StackOverflow for hundreds of examples.
If using java.time, read my comment on Question about a bug when parsing hours-only offset value.
Example in Joda-Time 2.7.
String inputRaw = "2015-04-02 11:52:00+02";
String input = inputRaw.replace( " ", "T" );
DateTimeZone zone = DateTimeZone.forID( "America/Montreal" ); // Specify desired time zone adjustment.
DateTime dateTime = new DateTime( input, zone );
// Im new to java programming
I have a String object that represents a date/time in this format : "2013-06-09 14:20:00" (yyyy-MM-dd HH:mm:ss)
I want to convert it to a Date object so i can perform calculations on it but im confused on how to do this.
I tried :
String string = "2013-06-09 14:20:00";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(string);
System.out.println(date);
//Prints Mon Dec 31 00:00:00 GMT 2012
Any help appreciated
Ok so I have now updated my code to as follows i'm getting the correct date/time now when I print the date but is this the correct implementation :
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String string = "2013-06-09 14:20:00";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(string);
System.out.println(dateFormat.format(date));
//prints 2013-06-09 14:20:00
Thx to everyone that's answered/commented thus far
The format is wrong. Use this instead:
"yyyy-dd-MM HH:mm:ss"
Indeed your last program version is ok, except you don't need to declare the SimpleDateFormat twice. Simply:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String string = "2013-06-09 14:20:00";
Date date = dateFormat.parse(string);
System.out.println(dateFormat.format(date));
String string = "2013-06-09 14:20:00";
and the DATE object format is "yyyy-dd-MM HH:mm:ss"
You can get Date,Day,month and many more by using Date object which is present in
java.util.Date package , like as follows.
Date d = new Date(string);
This will call constructor of Date object for which you are passing 'string' variable which contains date.
d.getDay(); // retrieve day on that particular day
d.getDate(); // retrieve Date
and many more are avaiable like this.
Using java.util.Date
The answer by zzKozak is correct. Well, almost correct. The example code omits required exception handling. Like this…
java.text.DateFormat dateFormat = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String string = "2013-06-09 14:20:00";
Date date = null;
try {
date = dateFormat.parse(string);
} catch ( ParseException e ) {
e.printStackTrace();
}
System.out.println("date: " + dateFormat.format(date));
Don't Use java.util.Date!
Avoid using java.util.Date & Calendar classes bundled with Java. They are notoriously bad in both design and implementation.
Instead use a competent date-time library. In Java that means either:
The third-party open-source Joda-Time
In the forthcoming Java 8, the new java.time.* classes defined by JSR 310 and inspired by Joda-Time.
Time Zone
Your question and code fail to address the issue of time zones. If you ignore time zones, you'll get defaults. That may cause unexpected behaviors when deployed in production. Better practice is to always specify a time zone.
Formatter
If you replace a space with a 'T' per the standard ISO 8601 format, then you can conveniently feed that string directly to a constructor of a Joda-Time DateTime instance.
If you must use that string as-is, then define a formatter to specify that format. You can find many examples of that here on StackOverflow.com.
Example Code
Here is some example code using Joda-Time 2.3, running in Java 7.
I arbitrarily chose a time zone of Montréal.
// © 2013 Basil Bourque. This source code may be used freely forever by anyone taking full responsibility for doing so.
// import org.joda.time.*;
// import org.joda.time.format.*;
// Specify a time zone rather than rely on default.
// Necessary to handle Daylight Saving Time (DST) and other anomalies.
DateTimeZone timeZone = DateTimeZone.forID( "America/Montreal" );
DateTime dateTime = new DateTime( "2013-06-09T14:20:00", timeZone ); // Or pass DateTimeZone.UTC as time zone for UTC/GMT.
System.out.println( "dateTime: " + dateTime );
When run…
dateTime: 2013-06-09T14:20:00.000-04:00