This question already has answers here:
How can I Convert Calendar.toString() into date using SimpleDateFormat.parse()?
(2 answers)
Closed 2 years ago.
I am building a API Java code that is downloading into a CSV file a list of transactions, disputes and payments made through Paypal for this company I work for. One of the columns from the CSV file is a date related column as you can see below:
transactionData.add(String.valueOf(transaction.getDisputes().get(i).getReceivedDate()));
The issue is that all values for the data column above is coming in the CSV as a XMLGregorianDate:
java.util.GregorianCalendar[time=1589760000000,areFieldsSet=true,areAllFieldsSet=true,lenient=true,zone=sun.util.calendar.ZoneInfo[id="UTC",offset=0,dstSavings=0,useDaylight=false,transitions=0,lastRule=null],firstDayOfWeek=2,minimalDaysInFirstWeek=4,ERA=1,YEAR=2020,MONTH=4,WEEK_OF_YEAR=21,WEEK_OF_MONTH=3,DAY_OF_MONTH=18,DAY_OF_YEAR=139,DAY_OF_WEEK=2,DAY_OF_WEEK_IN_MONTH=3,AM_PM=0,HOUR=0,HOUR_OF_DAY=0,MINUTE=0,SECOND=0,MILLISECOND=0,ZONE_OFFSET=0,DST_OFFSET=0]
What changes should I make to the line above to give me the data in timestamp with timezone i.e. "yyyy-mm-dd hh:mi:ss+/-tz"?
You have two options to specify the date-time output format:
1- Using Java 8 Date and Time API classes under the java.time package (recommended)
final GregorianCalendar gregorianCalendar = transaction.getDisputes().get(i).getReceivedDate();
final String dateTimePattern = "yyyy-MM-dd HH:mm:ss.SSSZ";
ZonedDateTime zonedDateTime = gregorianCalendar.toZonedDateTime();
final DateTimeFormatter dateFormatter = DateTimeFormatter.ofPattern(dateTimePattern);
final String dateFormat1 = dateFormatter.format(zonedDateTime);
transactionData.add(dateFormat1);
2- Using the legacy Date-Time classes such as java.util.Date & java.text.SimpleDateFormat.
final Date receivedDate = gregorianCalendar.getTime();
final SimpleDateFormat simpleDateFormat = new SimpleDateFormat(dateTimePattern);
final String dateFormat2 = simpleDateFormat.format(receivedDate);
transactionData.add(dateFormat2);
GregorianCalendar extends Calendar that has a getTime():Date method : https://docs.oracle.com/javase/7/docs/api/java/util/Calendar.html#getTime()
Related
This question already has answers here:
want current date and time in "dd/MM/yyyy HH:mm:ss.SS" format
(11 answers)
How to convert date in to yyyy-MM-dd Format?
(6 answers)
Closed 2 years ago.
I have a
String s = "2020-02-22"`;
and I want to change it to Date so I can store it in my database which has has a column that does not accept anything but Date.
I tried using the LocalDate class but it's in API 26.
Any help would be appreciated.
Assume that you fetch the date from database and pass it to the below method:
public String formatDate(Date date){
SimpleDateFormat ff = new SimpleDateFormat("yyyy-MM-dd");
return ff.format(date);
}
EDIT : based on input from Basil, you could try Android Desugaring to make use of Java 8+ functionality without the need of minimum API level. This would allow the use of LocalDate instead of the old java.util.Date class.
Using LocalDate you could parse a string to date as:
public LocalDate getDate(String dateString) {
return LocalDate.parse(dateString);
}
This question already has answers here:
display Java.util.Date in a specific format
(11 answers)
want current date and time in "dd/MM/yyyy HH:mm:ss.SS" format
(11 answers)
Closed 2 years ago.
Im getting the following error when I try to convert the following string. Id like the Date to be in the format yyyy-MM-dd'T'HH:mm:ss:SSS but instead the Date seems to be coming out as Sun Mar 01 23:00:01 GMT 2020
String FULL_ISO_DATE_FORMAT = "yyyy-MM-dd'T'HH:mm:ss.SSS";
SimpleDateFormat formatter = new SimpleDateFormat(FULL_ISO_DATE_FORMAT);
Date from = formatter.parse("2020-03-01T23:00:01.000");
Error
feign.FeignException: status 400 reading Controller#searchController(Date,Date,Integer,String); content:
{"status":"fail","data":{"errors":[{"type":"IllegalArgumentException","description":"Invalid value Sun Mar 01 23:00:01 GMT 2020 for filter from. Field needs to be in format: yyyy-MM-dd'T'HH:mm:ss.SSS"}]}]}
Any help would be appreciated. I need to use the Date object as the constructor Im querying is using the Date object. Ideally I'd like to use LocalDateTime but I cant.
Use the LocalDateTime from java-8 date-time API and stop using legacy Date classes
String FULL_ISO_DATE_FORMAT = DateTimeFormatter. ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS");
LocalDateTime dateTime = LocalDateTime.now();
dateTime.format(FULL_ISO_DATE_FORMAT);
Please don't use the old classes Date and SimpleDateFormat. Use the new java.time api that is much more robust and better designed.
You can do the same thing as follows:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS");
LocalDateTime date = LocalDateTime.parse("2020-03-01T23:00:01.000", formatter);
Keep in mind that you can convert it to Date for compatibility like so:
Date legacyDate = Date.from(date.atZone(ZoneId.systemDefault()).toInstant());
This question already has an answer here:
in java I need define date in this format 1999-05-31T13:20:00-05:00 [duplicate]
(1 answer)
Closed 5 years ago.
I want this result on date time: 2008-10-31T15:07:38.6875000-05:00, please help me how i get this result?
I am using following code but unable to get required response.
TimeZone tzone = TimeZone.getTimeZone("UTC");
DateFormat dateformat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm'Z'");
String nowAsISO = dateformat.format(new Date());
You are quite right:
Your format expression is missing seconds :ss, millisecond .SSS (many S for how many digit you want) and the Z timezone tag without '
Using single quote ' in the expression will exclude everything included in them from parsing, ergo you will have it printed like a string.
TimeZone tzone = TimeZone.getTimeZone("UTC");
DateFormat dateformat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSSSZ");
String nowAsISO = dateformat.format(new Date());
You can see every possible pattern here
I want to convert from string to date using Java 8.
I can easily convert using SimpleDateFormat and yyyy-MM-dd format
String startDate2="2017-03-24";
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd");
System.out.println(new java.sql.Date(sdf1.parse(startDate2).getTime()));
output:
2017-03-24
String startDate2="2017-03-24";
SimpleDateFormat sdf1 = new SimpleDateFormat("uuuu-MM-dd");
System.out.println(new java.sql.Date(sdf1.parse(startDate2).getTime()));
But when I use 'uuuu-MM-dd' instead of 'yyyy-MM-dd'
output :
1970-03-24(wrong)
now in Java 8:
String startDate1="2017-03-23";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("uuuu-MM-dd");
But I don't know how I can get the date which would be sql date type same as above correct output.
java.sql.Date has a static valueOf method that takes a Java 8 LocalDate so you can do:
String startDate1 = "2017-03-23";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("uuuu-MM-dd");
LocalDate date = LocalDate.parse(startDate1, formatter);
java.sql.Date sqlDate = java.sql.Date.valueOf(date);
As far as I can see, you have a text in yyyy-MM-dd format and you want it in uuuu-MM-dd format. So you need two formats:
String startDate2="2017-03-24";
SimpleDateFormat sourceFormat = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat targetFormat = new SimpleDateFormat("uuuu-MM-dd");
java.sql.Date date = new java.sql.Date(sourceFormat.parse(startDate2).getTime());
String formattedAsDayOfWeek = targetFormat.format(date);
System.out.println(formattedAsDayOfWeek);
Bottom line is that Date contains a millisecond value. java.sql.Date.toString() uses the yyyy-MM-dd format regardless how you parsed it. java.util.sql.Date uses another format: EEE MMM dd hh:mm:ss zzz yyyy with English Locale.
You can do other formatting with DateFormat -s.
I presume you need the uuuu-MM-dd format for inserting data to the database. What does that logic look like?
You don’t want a java.sql.Date. You want a LocalDate. Your SQL database wants one too.
String startDate2 = "2017-03-24";
LocalDate date = LocalDate.parse(startDate2);
System.out.println(date);
Output is:
2017-03-24
I am exploiting the fact that your string is in ISO 8601 format. The classes of java.time including LocalDate parse this format as their default, that is, without any explicit formatter.
You also note that we don’t need any explicit formatter for formatting back into uuuu-MM-dd format for the output. The toString method implicitly called from System..out.println() produces ISO 8601 format back.
Assuming that you are using a JDBC 4.2 compliant driver (I think we all are now), I am taking the way to pass it on to your SQL database from this question: Insert & fetch java.time.LocalDate objects to/from an SQL database such as H2:
myPreparedStatement.setObject ( 1 , date ); // Automatic detection and conversion of data type.
Refer to the linked question for much more detail.
The java.sql.Date class is poorly designed, a true hack on top of the already poorly designed java.util.Date class. Both classes are long outdated. Don’t use any of them anymore.
One more link: Wikipedia article: ISO 8601
This question already has answers here:
Java / convert ISO-8601 (2010-12-16T13:33:50.513852Z) to Date object
(4 answers)
Closed 6 years ago.
How to convert String to ISODate format using SimpleDateFormat, which means that i want to finally get Date in java.util.Date format.
My string will look like 2017-02-17T09:28:03.000Z, i want to convert it to date formt. I can do this in Joda date format, but since i am using mongoDB, it does not accept joda format.
String startDateString1 = "2017-02-17T04:23:17.452Z";
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
Date startDate = df.parse(startDateString1);
String newDateString = df.format(startDate);
above code is not working.
Your code is not working since Z is a reserved character used to interpret RFC-822 time zones :
RFC 822 time zone: For formatting, the RFC 822 4-digit time zone format is used:
RFC822TimeZone:
Sign TwoDigitHours Minutes
TwoDigitHours:
Digit Digit
Since Java 7, you can use X to interpret ISO-8601 time zones https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html . The following works :
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSX");
However, on my computer,
System.out.println(newDateString);
results in the following output :
2017-02-17T05:23:17.452+01
Alternatively, if you are sure to have only UTC dates, you could escape the Z letter with simple quotes :
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
And here is the displayed result :
2017-02-17T04:23:17.452Z
You can do it in Java 8 like below.
Instant instant = Instant.parse("2017-02-17T09:28:03.000Z");
Date date = Date.from(instant);
You could use javax.xml.bind.DatatypeConverter.parseDateTime("2017-02-17T04:23:17.452Z") which will return a Calendar object. You can call getTime() on it to get a Date object.