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Unable to parse with DateTimeFormatter [duplicate]

This question already has answers here:
How to format LocalDate object to MM/dd/yyyy and have format persist
(4 answers)
Unable to Convert String to localDate with custom pattern [duplicate]
(1 answer)
Closed 1 year ago.
I am trying to parse the date in a specific pattern but every time it is showing date in only format. Here what I am doing. Output is written in comments in front of the line.
String dat = "20-06-2021";
String newFormatLocaleDate = "MMM dd yyyy";
String newFormattedDate = convertToNewFormat(dat,currentFormat,newFormatLocaleDate); //Jun 20 2021
DateTimeFormatter formatter1 = DateTimeFormatter.ofPattern(newFormatLocaleDate);
LocalDate parse1 = java.time.LocalDate.parse(newFormattedDate,formatter1); //2021-06-20
System.out.println("Using parse1 Pattern Only "+parse1); //2021-06-20
Date date1 = java.sql.Date.valueOf(parse1);
System.out.println("Using Date Pattern Only "+date1); //2021-06-20
The pattern in which date is required is given and in the string form it giving the correct value but when I am trying to parse it with LocaleDate it is changing the format for all dates to the above mentioned (yyyy-MM-dd) format irrespective of the newFormatLocaleDate pattern.
Thanks

You should not expect the line
System.out.println("Using parse1 Pattern Only "+parse1);
to output something different than 2021-06-20 it literally is exactly what the docs say what will be out putted.
The output will be in the ISO-8601 format uuuu-MM-dd.
So regardless of the format you used while parsing the LocalDate value the toString method will always output a data in the format uuuu-MM-dd.
If you want a different format use the instance method format.

Please note that you are printing the LocalDate and Date instances (using their toString() implementation), therefore not formatted according to your desired template. If you want to print out your parsed date in a particular format, you need to apply a formatter again, for example like this:
System.out.println(parse1.format(DateTimeFormatter.ofPattern("MMM dd yyyy")))

ParseException - Unparseable date exception in Java [duplicate]

This question already has answers here:
Why can't this SimpleDateFormat parse this date string?
(4 answers)
ParseException when parsing 3 character abbreviated month using SimpleDateFormat
(5 answers)
Closed 2 years ago.
I have oracle database with columns data type "TIMESTAMP(0) WITH TIME ZONE" . Which produces
like 14/11/2019 06:30:00, +03:00 in database .
When I am trying to get this timestamp from java
I got java.text.ParseException: Unparseable date: "28-MAY-12 07.40.03 PM +03:00" . Our project java version is 6 . I tried with
new SimpleDateFormat("dd-MM-yy hh.mm.ss") ,
new SimpleDateFormat("dd-MM-yy hh.mm.ss, Z"),
new SimpleDateFormat("dd-MM-yy hh.mm.ss, z") ,
new SimpleDateFormat("dd/MM/yy hh.mm.ss, z") ,
new SimpleDateFormat("dd/MM/yy hh.mm.ss, Z") ,
new SimpleDateFormat("dd/MM/yy hh.mm.ss")
But none of them worked for me all of throwing java.text.ParseException: Unparseable date error.
In my java side i have date datatype property in my class and i want to retrieve data from oracle database then parse then set to date data type property like below.
serDto.setTarih(new Timestamp(new SimpleDateFormat("dd-MM-yy hh.mm.ss").parse(str).getTime()));
For ex in db timestamp data looks like : 14/11/2019 06:30:00, +03:00 and i want to retrieve as date like above.
Thank you in advance.

A partial solution is changing the pattern so that it parses the name of the month and the am/pm marker. Change MM to MMM and add a:
new SimpleDateFormat("dd-MMM-yy hh.mm.ss a").parse(str)
However this will ignore the time zone information. It will return a date with the expected time (i.e. 07:40:03 PM) in the default local time zone where this code is running, which might be different from the time zone in the input GMT+0300.
There doesn't seem to be a way to parse +03:00 into a time zone with SimpleDateFormat in Java 6, so if you need to parse the time zone this will require more custom code.

parse String to 'yyyy-mm-ddThh:mm:ss.SSSZ' ISODate java [duplicate]

This question already has answers here:
Java / convert ISO-8601 (2010-12-16T13:33:50.513852Z) to Date object
(4 answers)
Closed 6 years ago.
How to convert String to ISODate format using SimpleDateFormat, which means that i want to finally get Date in java.util.Date format.
My string will look like 2017-02-17T09:28:03.000Z, i want to convert it to date formt. I can do this in Joda date format, but since i am using mongoDB, it does not accept joda format.
String startDateString1 = "2017-02-17T04:23:17.452Z";
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
Date startDate = df.parse(startDateString1);
String newDateString = df.format(startDate);
above code is not working.

Your code is not working since Z is a reserved character used to interpret RFC-822 time zones :
RFC 822 time zone: For formatting, the RFC 822 4-digit time zone format is used:
RFC822TimeZone:
Sign TwoDigitHours Minutes
TwoDigitHours:
Digit Digit
Since Java 7, you can use X to interpret ISO-8601 time zones https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html . The following works :
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSX");
However, on my computer,
System.out.println(newDateString);
results in the following output :
2017-02-17T05:23:17.452+01
Alternatively, if you are sure to have only UTC dates, you could escape the Z letter with simple quotes :
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
And here is the displayed result :
2017-02-17T04:23:17.452Z

You can do it in Java 8 like below.
Instant instant = Instant.parse("2017-02-17T09:28:03.000Z");
Date date = Date.from(instant);

You could use javax.xml.bind.DatatypeConverter.parseDateTime("2017-02-17T04:23:17.452Z") which will return a Calendar object. You can call getTime() on it to get a Date object.

Change Time zone and date format [duplicate]

This question already has answers here:
How to set the TimeZone for String parsing in Android
(3 answers)
Closed 6 years ago.
I get from the server is like 2017-01-24T16:16:30.690Z.
This date is in GMT time zone.
I want to convert this time into GMT+6 time zone as well as time format.
My expected result is: 24 January 2017 22:16

See above comments. If you apply those, try:
SimpleDateFormat sdf = new SimpleDateFormat();
sdf.applyPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
sdf.setTimeZone(TimeZone.getTimeZone("GMT"));
Date date = sdf.parse("2017-01-24T16:16:30.690Z", new ParsePosition(0));
sdf.setTimeZone(TimeZone.getTimeZone("GMT+06:00"));
sdf.applyPattern("d MMMM yyyy HH:mm");
String formatted = sdf.format(date);
Worked for me.

JodaTime: How hours are represented

I am working with JodaTime now and have a question about how to parse String into DateTime.
I have got a date String in the format:
"2013-05-14T11:36:08+0000"
I tried to convert it into JodaTime's DateTime object:
DateTimeFormatter fmt = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss");
DateTime dateTime = fmt.parseDateTime("2013-05-14T11:36:08+0000");
It works fine except that if I call
dateTime.getHourOfDay()
It returns me 12 instead of 11.
Surprisingly, if I use the Java's SimpleDateFormat:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
Date date = df.parse("2013-05-14T11:36:08+0000");
The date contains exactly the same result, the hour is 12 instead of 11.
I am based in London. I started to think whether this is because the summer saving time? Or did I make an mistake on how the String should be parsed?
Please help. Many thanks.