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Write from file to ArrayList

For the program to work, it is necessary to write data from the file to the arraylist, but how to make the written element not equal to null in the loop? That is, so that the loop stops its execution as soon as it reads all the lines from the file
public static void readFromFile(String path, String filename) throws IOException {
ArrayList<String> ip = new ArrayList<>();
try {
File file = new File(path + "\\" + filename);
FileReader fr = new FileReader(file);
BufferedReader br = new BufferedReader(fr);
ip.add(br.readLine());
while ((ip.add(br.readLine()) != null)) {
//writing to a variable
}
} catch (IOException e) {
System.out.println(e.getMessage());
}
}

ip.add(...) returns a boolean. This code won't compile, because a boolean is a primitive, and thus can never be null.
Move the add inside the loop:
String line;
while ((line = br.readLine()) != null) {
ip.add(line);
}

Here is the better way to read all lines:
Files.readAllLines(Paths.get("path_to_file"), StandardCharsets.UTF_8)

Simplest way to concatenate multi lines of text in java through File Handling

I tried concatenating 2 lines of text in a given text file and printing the output to the console. My code is very complicated, is there a simpler method to achieve this by using FileHandling basic concepts ?
import java.io.*;
public class ConcatText{
public static void main(String[] args){
BufferedReader br = null;
try{
String currentLine;
br = new BufferedReader(new FileReader("C:\\Users\\123\\Documents\\CS105\\FileHandling\\concat.file.text"));
StringBuffer text1 = new StringBuffer (br.readLine());
StringBuffer text2 = new StringBuffer(br.readLine());
text1.append(text2);
String str = text1.toString();
str = str.trim();
String array[] = str.split(" ");
StringBuffer result = new StringBuffer();
for(int i=0; i<array.length; i++) {
result.append(array[i]);
}
System.out.println(result);
}
catch(IOException e){
e.printStackTrace();
}finally{
try{
if(br != null){
br.close();
}
}catch(IOException e){
e.printStackTrace();
}
}
}
}
The text file is as follows :
GTAGCTAGCTAGC
AGCCACGTA
the output should be as follows (concatenation of the text file Strings) :
GTAGCTAGCTAGCAGCCACGTA

If you are using java 8 or newer, the simplest way would be:
List<String> lines = Files.readAllLines(Paths.get(filePath));
String result = String.join("", lines);
If you are using java 7, at least you can use try with resources to reduce the clutter in the code, like this:
try (BufferedReader br = new BufferedReader(new FileReader(filePath))) {
StringBuffer text1 = new StringBuffer (br.readLine());
StringBuffer text2 = new StringBuffer(br.readLine());
// ...
}catch(IOException e){
e.printStackTrace();
}
This way, resources will be autoclosed and you don't need to call br.close().

Short answer, there is:
public static void main(String[] args) {
//this is called try-with-resources, it handles closing the resources for you
try (BufferedReader reader = new BufferedReader(...)) {
StringBuilder stringBuilder = new StringBuilder();
String line = reader.readLine();
//readLine() will return null when there are no more lines
while (line != null) {
//replace any spaces with empty string
//first argument is regex matching any empty spaces, second is replacement
line = line.replaceAll("\\s+", "");
//append the current line
stringBuilder.append(line);
//read the next line, will be null when there are no more
line = reader.readLine();
}
System.out.println(stringBuilder);
} catch (IOException exc) {
exc.printStackTrace();
}
}
First of all read on try with resources, when you are using it you don't need to close manually resources(files, streams, etc.), it will do it for you. This for example.
You don't need to wrap read lines in StringBuffer, you don't get anything out of it in this case.
Also read about the methods provided by String class starting with the java doc - documentation.

Java Reading in text file and outputting it to new file with removed duplicates

I have a text file with an integer on each line, ordered from least to greatest, and I want to put them in a new text file with any duplicate numbers removed.
I've managed to read in the text file and print the numbers on the screen, but I'm unsure on how to actually write them in a new file, with duplicates removed?
public static void main(String[] args)
{
try
{
FileReader fr = new FileReader("sample.txt");
BufferedReader br = new BufferedReader(fr);
String str;
while ((str = br.readLine()) != null) {
out.println(str + "\n");
}
br.close();
}
catch (IOException e) {
out.println("File not found");
}
}

When reading the file, you could add the numbers to a Set, which is a data structure that doesn't allow duplicate values (just Google for "java collections" for more details)
Then you iterate through this Set, writing the numbers to a FileOutputStream (google for "java io" for more details)

Instead of printing each of the numbers, add them to an Array. After you've added all the integers, you can cycle through the array to remove duplicates (sample code for this can be found fairly easily).
Once you have an array, use BufferedWriter to write to an output file. Example code for how to do this can be found here: https://www.mkyong.com/java/how-to-write-to-file-in-java-bufferedwriter-example/
Alternatively, use a Set, and BufferedWriter should still work in the same way.

assuming the input file is already ordered:
public class Question42475459 {
public static void main(final String[] args) throws IOException {
final String inFile = "sample.txt";
try (final Scanner scanner = new Scanner(new BufferedInputStream(new FileInputStream("")), "UTF-8");
BufferedWriter writer = new BufferedWriter(new FileWriter(inFile + ".out", false))) {
String lastLine = null;
while (scanner.hasNext()) {
final String line = scanner.next();
if (!line.equals(lastLine)) {
writer.write(line);
writer.newLine();
lastLine = line;
}
}
}
}
}

Reading text file into arraylist

I really new to Java so I'm having some trouble figuring this out. So basically I have a text file that looks like this:
1:John:false
2:Bob:false
3:Audrey:false
How can I create an ArrayList from the text file for each line?

Read from a file and add each line into arrayList. See the code for example.
public static void main(String[] args) {
ArrayList<String> arr = new ArrayList<String>();
try (BufferedReader br = new BufferedReader(new FileReader(<your_file_path>)))
{
String sCurrentLine;
while ((sCurrentLine = br.readLine()) != null) {
arr.add(sCurrentLine);
}
} catch (IOException e) {
e.printStackTrace();
}
}

While the answer above me works, here's another way to do it. Make sure to import java.util.Scanner.
public static void main(String[] args) {
ArrayList<String> list = new ArrayList<String>();
Scanner scan = new Scanner("YOURFILE.txt");
while(scan.hasNextLine()){
list.add(scan.nextLine());
}
scan.close();
}

If you know how to read a file line by line, either by using Scanner or by using BufferedReader then reading a text file into ArrayList is not difficult for you. All you need to do is read each line and store that into ArrayList, as shown in following example:
BufferedReader bufReader = new BufferedReader(new
FileReader("file.txt"));
ArrayList<String> listOfLines = new ArrayList<>);
String line = bufReader.readLine(); while (line != null)
{
listOfLines.add(line);
line = bufReader.readLine();
}
bufReader.close();
Just remember to close the BufferedReader once you are done to prevent resource leak, as you don't have try-with-resource statement

This will be help to you.
List<String> list = new ArrayList<String>();
BufferedReader reader = new BufferedReader(new FileReader("list.txt"));
String line;
while ((line = reader.readLine()) != null) {
list.add(line);
}
reader.close();
Then you can access those elements in the arraylist.

java 8 lets you do this
String fileName = "c://lines.txt";
List<String> list = new ArrayList<>();
try (Stream<String> stream = Files.lines(Paths.get(fileName))) {
list = stream
.map(String::toUpperCase)
.collect(Collectors.toList());
} catch (IOException e) {
e.printStackTrace();
}
list.forEach(System.out::println);

Reading a specific set of lines in a file [duplicate]

In Java, is there any method to read a particular line from a file? For example, read line 32 or any other line number.

For small files:
String line32 = Files.readAllLines(Paths.get("file.txt")).get(32)
For large files:
try (Stream<String> lines = Files.lines(Paths.get("file.txt"))) {
line32 = lines.skip(31).findFirst().get();
}

Unless you have previous knowledge about the lines in the file, there's no way to directly access the 32nd line without reading the 31 previous lines.
That's true for all languages and all modern file systems.
So effectively you'll simply read lines until you've found the 32nd one.

Not that I know of, but what you could do is loop through the first 31 lines doing nothing using the readline() function of BufferedReader
FileInputStream fs= new FileInputStream("someFile.txt");
BufferedReader br = new BufferedReader(new InputStreamReader(fs));
for(int i = 0; i < 31; ++i)
br.readLine();
String lineIWant = br.readLine();

Joachim is right on, of course, and an alternate implementation to Chris' (for small files only because it loads the entire file) might be to use commons-io from Apache (though arguably you might not want to introduce a new dependency just for this, if you find it useful for other stuff too though, it could make sense).
For example:
String line32 = (String) FileUtils.readLines(file).get(31);
http://commons.apache.org/io/api-release/org/apache/commons/io/FileUtils.html#readLines(java.io.File, java.lang.String)

You may try indexed-file-reader (Apache License 2.0). The class IndexedFileReader has a method called readLines(int from, int to) which returns a SortedMap whose key is the line number and the value is the line that was read.
Example:
File file = new File("src/test/resources/file.txt");
reader = new IndexedFileReader(file);
lines = reader.readLines(6, 10);
assertNotNull("Null result.", lines);
assertEquals("Incorrect length.", 5, lines.size());
assertTrue("Incorrect value.", lines.get(6).startsWith("[6]"));
assertTrue("Incorrect value.", lines.get(7).startsWith("[7]"));
assertTrue("Incorrect value.", lines.get(8).startsWith("[8]"));
assertTrue("Incorrect value.", lines.get(9).startsWith("[9]"));
assertTrue("Incorrect value.", lines.get(10).startsWith("[10]"));
The above example reads a text file composed of 50 lines in the following format:
[1] The quick brown fox jumped over the lazy dog ODD
[2] The quick brown fox jumped over the lazy dog EVEN
Disclamer: I wrote this library

Although as said in other answers, it is not possible to get to the exact line without knowing the offset (pointer) before. So, I've achieved this by creating an temporary index file which would store the offset values of every line. If the file is small enough, you could just store the indexes (offset) in memory without needing a separate file for it.
The offsets can be calculated by using the RandomAccessFile
RandomAccessFile raf = new RandomAccessFile("myFile.txt","r");
//above 'r' means open in read only mode
ArrayList<Integer> arrayList = new ArrayList<Integer>();
String cur_line = "";
while((cur_line=raf.readLine())!=null)
{
arrayList.add(raf.getFilePointer());
}
//Print the 32 line
//Seeks the file to the particular location from where our '32' line starts
raf.seek(raf.seek(arrayList.get(31));
System.out.println(raf.readLine());
raf.close();
Also visit the Java docs on RandomAccessFile for more information:
Complexity: This is O(n) as it reads the entire file once. Please be aware for the memory requirements. If it's too big to be in memory, then make a temporary file that stores the offsets instead of ArrayList as shown above.
Note: If all you want in '32' line, you just have to call the readLine() also available through other classes '32' times. The above approach is useful if you want to get the a specific line (based on line number of course) multiple times.

Another way.
try (BufferedReader reader = Files.newBufferedReader(
Paths.get("file.txt"), StandardCharsets.UTF_8)) {
List<String> line = reader.lines()
.skip(31)
.limit(1)
.collect(Collectors.toList());
line.stream().forEach(System.out::println);
}

No, unless in that file format the line lengths are pre-determined (e.g. all lines with a fixed length), you'll have to iterate line by line to count them.

In Java 8,
For small files:
String line = Files.readAllLines(Paths.get("file.txt")).get(n);
For large files:
String line;
try (Stream<String> lines = Files.lines(Paths.get("file.txt"))) {
line = lines.skip(n).findFirst().get();
}
In Java 7
String line;
try (BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
for (int i = 0; i < n; i++)
br.readLine();
line = br.readLine();
}
Source: Reading nth line from file

If you are talking about a text file, then there is really no way to do this without reading all the lines that precede it - After all, lines are determined by the presence of a newline, so it has to be read.
Use a stream that supports readline, and just read the first X-1 lines and dump the results, then process the next one.

It works for me:
I have combined the answer of
Reading a simple text file
But instead of return a String I am returning a LinkedList of Strings. Then I can select the line that I want.
public static LinkedList<String> readFromAssets(Context context, String filename) throws IOException {
BufferedReader reader = new BufferedReader(new InputStreamReader(context.getAssets().open(filename)));
LinkedList<String>linkedList = new LinkedList<>();
// do reading, usually loop until end of file reading
StringBuilder sb = new StringBuilder();
String mLine = reader.readLine();
while (mLine != null) {
linkedList.add(mLine);
sb.append(mLine); // process line
mLine = reader.readLine();
}
reader.close();
return linkedList;
}

Use this code:
import java.nio.file.Files;
import java.nio.file.Paths;
public class FileWork
{
public static void main(String[] args) throws IOException {
String line = Files.readAllLines(Paths.get("D:/abc.txt")).get(1);
System.out.println(line);
}
}

You can use LineNumberReader instead of BufferedReader. Go through the api. You can find setLineNumber and getLineNumber methods.

You can also take a look at LineNumberReader, subclass of BufferedReader. Along with the readline method, it also has setter/getter methods to access line number. Very useful to keep track of the number of lines read, while reading data from file.

public String readLine(int line){
FileReader tempFileReader = null;
BufferedReader tempBufferedReader = null;
try { tempFileReader = new FileReader(textFile);
tempBufferedReader = new BufferedReader(tempFileReader);
} catch (Exception e) { }
String returnStr = "ERROR";
for(int i = 0; i < line - 1; i++){
try { tempBufferedReader.readLine(); } catch (Exception e) { }
}
try { returnStr = tempBufferedReader.readLine(); } catch (Exception e) { }
return returnStr;
}

you can use the skip() function to skip the lines from begining.
public static void readFile(String filePath, long lineNum) {
List<String> list = new ArrayList<>();
long totalLines, startLine = 0;
try (Stream<String> lines = Files.lines(Paths.get(filePath))) {
totalLines = Files.lines(Paths.get(filePath)).count();
startLine = totalLines - lineNum;
// Stream<String> line32 = lines.skip(((startLine)+1));
list = lines.skip(startLine).collect(Collectors.toList());
// lines.forEach(list::add);
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
list.forEach(System.out::println);
}

EASY WAY - Reading a line using line number.
Let's say Line number starts from 1 till null .
public class TextFileAssignmentOct {
private void readData(int rowNum, BufferedReader br) throws IOException {
int n=1; //Line number starts from 1
String row;
while((row=br.readLine()) != null) { // Reads every line
if (n == rowNum) { // When Line number matches with which you want to read
System.out.println(row);
}
n++; //This increments Line number
}
}
public static void main(String[] args) throws IOException {
File f = new File("../JavaPractice/FileRead.txt");
FileReader fr = new FileReader(f);
BufferedReader br = new BufferedReader(fr);
TextFileAssignmentOct txf = new TextFileAssignmentOct();
txf.readData(4, br); //Read a Specific Line using Line number and Passing buffered reader
}
}

for a text file you can use an integer with a loop to help you get the number of the line, don't forget to import the classes we are using in this example
File myObj = new File("C:\\Users\\LENOVO\\Desktop\\test.txt");//path of the file
FileReader fr = new FileReader(myObj);
fr.read();
BufferedReader bf = new BufferedReader(fr); //BufferedReader of the FileReader fr
String line = bf.readLine();
int lineNumber = 0;
while (line != null) {
lineNumber = lineNumber + 1;
if(lineNumber == 7)
{
//show line
System.out.println("line: " + lineNumber + " has :" + line);
break;
}
//lecture de la prochaine ligne, reading next
line = bf.readLine();
}

They are all wrong I just wrote this in about 10 seconds.
With this I managed to just call the object.getQuestion("linenumber") in the main method to return whatever line I want.
public class Questions {
File file = new File("Question2Files/triviagame1.txt");
public Questions() {
}
public String getQuestion(int numLine) throws IOException {
BufferedReader br = new BufferedReader(new FileReader(file));
String line = "";
for(int i = 0; i < numLine; i++) {
line = br.readLine();
}
return line; }}