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How to Pass This Test Case?

I'm creating the program that determines the largest and smallest number is a series of numbers entered by the user. I've created several tests cases for my code and they all work out, but it fails the most simple test case. When the user inputs a single number. For instance, if the user sets the terminating value to be 25, then enters -1, and finally enters the terminating the value, the output should be
Largest: -1 and Smallest: -1. However, my code will output Largest: 0 and Smallest: -1 -- I why this happens (because I initialized the max value to be 0 before running the loop), but how can I fix this?
Here's my code...
Scanner scan = new Scanner(System.in);
// Declaration variables
double min;
double max = 0;
System.out.println("Enter terminating number: ");
double terminator = scan.nextDouble();
System.out.println("Enter a number: ");
double num = scan.nextDouble();
min = num;
if (num == terminator) {
System.out.println("There must be one number in the list.");
// break;
} else {
while (num != terminator) {
System.out.println("");
num = scan.nextDouble();
if ((num < min) && (num != terminator)) {
double temp = min;
min = num;
max = temp;
} else if ((num > min) && (num != terminator)) {
max = num;
} else {
max = min;
}
}
System.out.println("Largest: " + max);
System.out.println("Smallest: " + min);
}

Instead of initializing max = 0, do max = num just like you already do with min.
It's not clear why you're initializing max differently from min; when a single number has been entered, it's both the minimum and the maximum. Right now, the only code that modifies max is within the loop that reads numbers beyond the first, so the first number has no effect on it.

My if statements will not take new values

The object is to get the average of the entered values.
It is to stop when a negative number is entered.
I am trying to get the smallest and largest values entered.
The problem I am having is that my if statements will not take the smallest/largest new values entered.
It just gives me the Integer.Max_Value and Integer.Min_Value.
import java.util.Scanner;
public class LargeSmallAverage {
public static void main(String[] args) {
// TODO Auto-generated method stub
double count = 0;
double amtOfNums = 0;
int input = 0;
int smallest = Integer.MAX_VALUE, largest = Integer.MIN_VALUE;
int number;
System.out.println("Enter a series of numbers. Enter a negative number to quit.");
Scanner scan = new Scanner(System.in);
while ((input = scan.nextInt()) > 0) {
count += input;
amtOfNums++;
}
while(input>=0){
for(int counter=1; counter<amtOfNums; counter++){
number=scan.nextInt();
if(number<smallest)
smallest=number;
if(number>largest)
largest=number;
}
}
System.out.println("You entered " + amtOfNums + " numbers averaging " + (count/amtOfNums) + ".");
System.out.println("The smallest number is "+ smallest);
System.out.println("The largest number is " + largest);
}
}

Currently you have two loops. One sums the numbers, and the other finds the largest and smallest numbers. Given your output, it sounds like you should be doing it all in one loop - ideally with more useful variable names too. (Your count is actually a sum, not a count... and there's no need for it to be a double. You could make it a long if you really want to avoid overflow. Yes, you need to perform floating point arithmetic for your average, but you can do that when you take the average... your sum is logically an integer.)
int sum = 0;
int smallest = Integer.MAX_VALUE;
int largest = Integer.MIN_VALUE;
int count = 0;
while ((input = scan.nextInt()) >= 0) {
count++;
sum += input;
// Alternative: smallest = Math.min(smallest, input)
if (input < smallest) {
smallest = input;
}
// Alternative: largest = Math.max(smallest, input)
if (input > largest) {
largest = input;
}
}
// Cast for count is just to force floating point division.
System.out.println("You entered " + count +
" numbers averaging " + (sum / (double) count) + ".");
System.out.println("The smallest number is "+ smallest);
System.out.println("The largest number is " + largest);

There is a problem with your while loop condition: while(input>=0){
here input will be always less than zero due to your previous while statement:while ((input = scan.nextInt()) > 0)
Here while loop exits only when you enter a number which is less than zero.. so input will have that value..

Printing the two highest values from user input

I have an assignment where I have to write a code which lets the user decide an amount of int values to be written in, and then decides what these values should be. There has to be atleast 2 inputs from the user. The program will then compare the values from the input and then print out the two highest values. So far I managed to print out the highest value, but I'm not sure whats wrong with the way I've done it since the output just becomes 0 if I choose to print out 2 numbers and the highest one is entered in first. And I'm also not sure how to keep track of the second highest number either. Would appreciate some help.
import java.util.Scanner;
public class ToStoersteTall{
public static void main(String[] args){
System.out.println("How many numbers? (minimum 2)?:");
Scanner reader = new Scanner(System.in);
if (reader.hasNextInt()) {
int numbers = reader.nextInt();
if (numbers >= 2) {
System.out.println("Enter value #1");
if (reader.hasNextInt()) {
int num1 = reader.nextInt();
System.out.println("Enter value #2");
if (reader.hasNextInt()) {
int num2 = reader.nextInt();
int biggest = 0;
for (int i = 3; i <= tall; i++) {
System.out.println("Enter value #" + i);
int num3 = reader.nextInt();
biggest = num1;
if(biggest < num3){
biggest = num3;
}
}
System.out.println(biggest);
} else {
System.out.println("Please enter an integer");
}
} else {
System.out.println("Please enter an integer");
}
} else {
System.out.println("Please enter an integer equal or higher than 2.");
}
} else {
System.out.print("Vennligst oppgi et heltall større eller lik 2.");
}
}
}

I have an assignment where I have to write a code which lets the user decide an amount of int values to be written in, and then decides what these values should be. There has to be atleast 2 inputs from the user. The program will then compare the values from the input and then print out the two highest values. So far I managed to print out the highest value, but I'm not sure whats wrong with the way I've done it since the output just becomes 0 if I choose to print out 2 numbers and the highest one is entered in first. And I'm also not sure how to keep track of the second highest number either. Would appreciate some help.
A couple things:
good practice to close scanner (and IO-related resources in general)
reduced if-statement blocks bloat for easier readability
you specify 2 guaranteed numbers, so attempt to parse those before looping
can remove system.exit calls or replace system.exit and move bulk of code back into the larger if-else blocks as originally state in OP (but I refer back to the sake of readability)
added check for the first and second numbers input to make sure high1 is highest value, and high2 is second highest value.
keep order while looping and checking values (note: does not use array), if the number is a new high, replace high1 and move high1's value down to high2, or if the number is a second (new) high, replace high2. If values are equal, this logic is excluded and you may want to specify based on your own constraints
import java.io.IOException;
import java.util.Scanner;
public class ToStoersteTall {
public static void main(String[] args) throws IOException {
System.out.println("How many numbers? (minimum 2)?:");
Scanner reader = new Scanner(System.in);
int n = 0;
if (reader.hasNextInt()) {
n = reader.nextInt();
} else {
System.out.println("Vennligst oppgi et heltall større eller lik 2.");
System.exit(-1); // quits execution
}
if (n < 2) {
System.out.println("Please enter an integer equal or higher than 2.");
System.exit(-2);
}
// Since guaranteed 2 numbers, parse and assign now
int high1 = 0, high2 = 0;
System.out.println("Enter value # 1");
if (reader.hasNextInt())
high1 = reader.nextInt();
System.out.println("Enter value # 2");
if (reader.hasNextInt())
high2 = reader.nextInt();
// check to see if a switch to keep correct highest order, swap values if so
if (high1 < high2) {
int t = high2;
high2 = high1;
high1 = t;
}
// loop won't execute if only 2 numbers input, but will if 3 or more specified at start
for (int i = 2; i < n; ++i) {
System.out.println("Enter value #" + (i + 1));
if (reader.hasNextInt()) {
int t = reader.nextInt();
if (t > high1) {
high2 = high1; // throw away high2 value and replace with high1
high1 = t; // replace high1 value with new highest value
} else if (t > high2) {
high2 = t;
}
} else {
System.out.println("Please enter an interger");
}
}
reader.close();
System.out.println("The two highest numbers are: " + high1 + ", " + high2);
}
}

You're already keeping track of the biggest, so why not keep track of the second biggest? Another easy way of solving this problem is to keep all the numbers in a list, sort the list by number size, and grab the two highest entries.

I tried your code and used an array to solve the problem.
import java.util.Scanner;
public class Main {
static int secondHighest(int... nums) {
int high1 = Integer.MIN_VALUE;
int high2 = Integer.MIN_VALUE;
for (int num : nums) {
if (num > high1) {
high2 = high1;
high1 = num;
} else if (num > high2) {
high2 = num;
}
}
return high2;
}
public static void main(String[] args) {
System.out.println("How many numbers? (minimum 2)?:");
Scanner reader = new Scanner(System.in);
if (reader.hasNextInt()) {
int numbers = reader.nextInt();
int[] array = new int[numbers];
if (numbers >= 2) {
System.out.println("Enter value #1");
if (reader.hasNextInt()) {
int num1 = reader.nextInt();
array[0] = num1;
System.out.println("Enter value #2");
if (reader.hasNextInt()) {
int num2 = reader.nextInt();
array[1] = num2;
int biggest = 0;
for (int i = 3; i <= numbers; i++) {
System.out.println("Enter value #" + i);
int num3 = reader.nextInt();
array[i-1] = num3;
}
System.out.println("second largest number is" + secondHighest(array));
int largest = 0;
for(int i =0;i<array.length;i++) {
if(array[i] > largest) {
largest = array[i];
}
}
System.out.println("Largest number in array is : " +largest);
} else {
System.out.println("Please enter an integer");
}
} else {
System.out.println("Please enter an integer");
}
} else {
System.out.println("Please enter an integer equal or higher than 2.");
}
} else {
System.out.print("Vennligst oppgi et heltall større eller lik 2.");
}
}
}
Test
How many numbers? (minimum 2)?:
6
Enter value #1
3
Enter value #2
4
Enter value #3
5
Enter value #4
6
Enter value #5
7
Enter value #6
8
second largest number is7
Largest number in array is : 8

There is a logic error in your program. If numbers is 2, then the for loop never gets executed, and the value of biggest remains zero because it is never updated. Change your declaration of biggest to reflect the current maximum value found so far.
int biggest = num1 > num2 ? num1 : num2;
That way if the for loop never executes then biggest will be the maximum value of the first two numbers.
As for keeping track of the second highest value, you could introduce another variable secondBiggest, initialised in a similar manner to biggest, and then write logic to update this value in your for loop. However, in my opinion, it would be much easier to change your strategy to hold the entered values into an array, then when all inputs have been entered, calculate whichever values you desire from the array. This would lead to a much cleaner solution IMO.
(I have assumed that tall in the for loop is actually meant to be numbers...)
import java.util.Scanner;
public class Foo{
public static void main(String[] args){
System.out.println("How many numbers? (minimum 2)?:");
Scanner reader = new Scanner(System.in);
if(reader.hasNextInt()){
int numbers = reader.nextInt();
if(numbers >= 2){
int[] list = new int[numbers];
for(int i = 0; i < numbers; i++){
System.out.println("Enter value #" + (i + 1));
if(reader.hasNextInt())
list[i] = reader.nextInt();
}//for
int biggest = 0;
int secondBiggest = 0;
// find the values you want
for(int i = 0; i < numbers; i++){
if(list[i] > biggest){
secondBiggest = biggest;
biggest = list[i];
}//if
else if(list[i] > secondBiggest)
secondBiggest = list[i];
}//for
// print your results
System.out.println("The biggest integer is: " + biggest);
System.out.println("The second biggest integer is: " + secondBiggest);
}//if
}//if
}//main
}//class

Java will not add first integer when computing average

I am new to Java, so I apologize if I am simply overlooking something simple. I wrote this code to make a few simple calculations, but when I run it, Java does not seem to be adding my first integer that is input when calculating the average. Everything else seems to be fine, so I would appreciate any help. Thanks.
import java.util.Scanner;
public class IntegerCalc {
public static void main(String[] args){
System.out.println("Enter a list of non-negative integers.");
System.out.println("Enter a negative number to indicate the end of your input.");
Scanner keyboard = new Scanner(System.in);
int min = keyboard.nextInt();
int max = min;
double average = 0;
double numberOfInt= 1;
int next = keyboard.nextInt();
double total = 0;
while (next > 0){
if (next > max)
max = next;
else if (next < min)
min = next;
total = total + next;
numberOfInt++;
next = keyboard.nextInt();
}
average = total/numberOfInt;
System.out.println("The largest integer is " + max);
System.out.println("The smallest integer is " + min);
System.out.println("The average is " + average);
}
}

It looks like your code does sum all the input numbers, but your numberOfInt is off by one.
You should initialize it to
double numberOfInt= 0;
instead of
double numberOfInt= 1;
You only want to increment numberOfInt when you add the current value of next to the total, so the first time you add next to total, numberOfInt should become 1.

What I can see is that inside while loop you have this condition:
if (next > max)
max = next;
else if (next < min)
min = next;
Your first value never goes to total.Your first value will count towards average is only when value of next is equal to first value.To solve this problem you can initialize total with max or min(since they are equal initially):
double total = (double) max;

your int numberOfInt should not be initialized at value 1. Since you increment it by 1 with each iteration of your loop, it's value is off by one. Instead, initialize it at value 0.

Why doesn't my "While Loop" print the computation of finding the average "score"?

I am writing a program that reads a sequence of positive integers input by the user. User will only enter one integer at a time.Then it will compute the average of those integers. The program will end when user enters 0. (0 is not counted in the average).The program will print out the average once the program ends.
Question: My code stops working when I gets to the while loop hence it doesn't compute the input by user, hence prints out nothing. Why doesn't my while loop compute the average from the user's inputs? Appreciate your guidance :)
import java.util.Scanner;
public class AverageOfIntegers {
public static void main(String[] args) {
int integer;
double sum;
sum = 0;
double average;
Scanner input = new Scanner(System.in);
int count; count = 0;
average = 0;
System.out.println("Please enter an integer: ");
integer = input.nextInt();
while (integer != 0) {
count = count + 1;
sum = sum + integer;
average = sum / count;
}
System.out.println("Average = " + average);
}
}

This is because you are never actually summing over more than one integer. The user only ever enters one number. As a result your loop is essentially acting on just the one number. You need to put the input inside the while loop and save a running sum and count there. Something more like this
while (integer != 0) {
count += 1;
sum += integer;
average = sum / count;
integer = input.nextInt();
}

Explanation
First of all, when you define data types, you can set their default value in the definition. Ex:
double sum = 0;
vs
double sum;
sum = 0;
Secondly, sum = sum + integer; is the same as: sum += integer;
Thirdly, count = count + 1; is the same as: count += 1 OR (and better yet), count++;
As for your actual algorithm, there is one problem and one suggestion:
you are not changing integer's value after each loop. So, you can
either do that in the while condition: while ((integer =
input.nextInt()) != 0) { or, at the end of each loop:
while (integer != 0) {
count ++;
sum += integer;
average = sum / count;
integer = input.nextInt();
}
This is a suggestion for technically better code (in my opinion), but it looks better, is more intuitive and requires less calculations to calculate the average after the while loop is done instead of during. That way, you only calculate it once, where needed, vs. every loop, which is not needed.
________________________________________________________________________________
The Code (complete class)
public class AverageOfIntegers {
public static void main(String[] args) {
int integer;
double sum = 0;
double average = 0;
Scanner input = new Scanner(System.in);
int count = 0;
System.out.println("Please enter an integer: ");
// set integer = to the nextInt() while looping so it calculates properly
while ((integer = input.nextInt()) != 0) {
count ++;
sum += integer;
}
average = sum / count; // calculate the average after the while-loop
System.out.println("Average = " + average);
}
}
________________________________________________________________________________
Example input/output:
Please enter an integer:
5
10
15
0
Average = 10.0
So it did 5 + 10 + 15 = 30 (which is the sum), and then the average is 30 / 3 (30 is the sum, 3 is the count), and that gave you Average = 10.0.

You need to move integer = input.nextInt(); inside the loop, so your program will collect inputs in a loop. See the corrected version:
import java.util.Scanner;
public class AverageOfIntegers {
public static void main(String[] args) {
int integer = 0, count = 0;
double sum = 0.0, average = 0.0;
Scanner input = new Scanner(System.in);
System.out.println("Please enter an integer: ");
integer = input.nextInt();
while (integer != 0) {
count = count + 1;
sum = sum + integer;
System.out.println("Please enter an integer: ");
integer = input.nextInt();
}
average = sum / count;
System.out.println("Average = " + average);
}
}

The problem is that the input.nextInt() should be part of the loop. The way you wrote it, the code gooes into an infinite loop whenever the first input is non-zero. Instead, do:
while ((integer = input.nextInt()) != 0) {
count = count + 1;
sum = sum + integer;
average = sum / count;
}

In the loop:
while (integer != 0) {
count = count + 1;
sum = sum + integer;
average = sum / count;
}
This will only stops when integer is 0, but this variable is not changing in the loop, so it will never be 0 if it wasn't already in the first place.
According to what you said you want to do, you should probably repeat the call to integer = input.nextInt(); inside your loop, lke this:
System.out.println("Please enter an integer: ");
integer = input.nextInt();
while (integer != 0) {
count = count + 1;
sum = sum + integer;
System.out.println("Please enter an integer: ");
integer = input.nextInt();
}
average = sum / count;
Also, as others have said, you only need to compute the average once after the loop, so I moved it too.