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Why are interface variables static and final by default in Java?
From the Java interface design FAQ by Philip Shaw:
Interface variables are static because Java interfaces cannot be instantiated in their own right; the value of the variable must be assigned in a static context in which no instance exists. The final modifier ensures the value assigned to the interface variable is a true constant that cannot be re-assigned by program code.
source
public: for the accessibility across all the classes, just like the methods present in the interface
static: as interface cannot have an object, the interfaceName.variableName can be used to reference it or directly the variableName in the class implementing it.
final: to make them constants. If 2 classes implement the same interface and you give both of them the right to change the value, conflict will occur in the current value of the var, which is why only one time initialization is permitted.
Also all these modifiers are implicit for an interface, you dont really need to specify any of them.
Since interface doesn't have a direct object, the only way to access them is by using a class/interface and hence that is why if interface variable exists, it should be static otherwise it wont be accessible at all to outside world. Now since it is static, it can hold only one value and any classes that implements it can change it and hence it will be all mess.
Hence if at all there is an interface variable, it will be implicitly static, final and obviously public!!!
(This is not a philosophical answer but more of a practical one). The requirement for static modifier is obvious which has been answered by others. Basically, since the interfaces cannot be instantiated, the only way to access its fields are to make them a class field -- static.
The reason behind the interface fields automatically becoming final (constant) is to prevent different implementations accidentally changing the value of interface variable which can inadvertently affect the behavior of the other implementations. Imagine the scenario below where an interface property did not explicitly become final by Java:
public interface Actionable {
public static boolean isActionable = false;
public void performAction();
}
public NuclearAction implements Actionable {
public void performAction() {
// Code that depends on isActionable variable
if (isActionable) {
// Launch nuclear weapon!!!
}
}
}
Now, just think what would happen if another class that implements Actionable alters the state of the interface variable:
public CleanAction implements Actionable {
public void performAction() {
// Code that can alter isActionable state since it is not constant
isActionable = true;
}
}
If these classes are loaded within a single JVM by a classloader, then the behavior of NuclearAction can be affected by another class, CleanAction, when its performAction() is invoke after CleanAction's is executed (in the same thread or otherwise), which in this case can be disastrous (semantically that is).
Since we do not know how each implementation of an interface is going to use these variables, they must implicitly be final.
Because anything else is part of the implementation, and interfaces cannot contain any implementation.
public interface A{
int x=65;
}
public interface B{
int x=66;
}
public class D implements A,B {
public static void main(String[] a){
System.out.println(x); // which x?
}
}
Here is the solution.
System.out.println(A.x); // done
I think it is the one reason why interface variable are static.
Don't declare variables inside Interface.
because:
Static : as we can't have objects of interfaces so we should avoid using Object level member variables and should use class level variables i.e. static.
Final : so that we should not have ambiguous values for the variables(Diamond problem - Multiple Inheritance).
And as per the documentation interface is a contract and not an implementation.
reference: Abhishek Jain's answer on quora
static - because Interface cannot have any instance. and final - because we do not need to change it.
Interface : System requirement service.
In interface, variable are by default assign by public,static,final access modifier.
Because :
public : It happen some-times that interface might placed in some other package. So it need to access the variable from anywhere in project.
static : As such incomplete class can not create object. So in project we need to access the variable without object so we can access with the help of interface_filename.variable_name
final : Suppose one interface implements by many class and all classes try to access and update the interface variable. So it leads to inconsistent of changing data and affect every other class. So it need to declare access modifier with final.
Java does not allow abstract variables and/or constructor definitions in interfaces. Solution: Simply hang an abstract class between your interface and your implementation which only extends the abstract class like so:
public interface IMyClass {
void methodA();
String methodB();
Integer methodC();
}
public abstract class myAbstractClass implements IMyClass {
protected String varA, varB;
//Constructor
myAbstractClass(String varA, String varB) {
this.varA = varA;
this.varB = VarB;
}
//Implement (some) interface methods here or leave them for the concrete class
protected void methodA() {
//Do something
}
//Add additional methods here which must be implemented in the concrete class
protected abstract Long methodD();
//Write some completely new methods which can be used by all subclasses
protected Float methodE() {
return 42.0;
}
}
public class myConcreteClass extends myAbstractClass {
//Constructor must now be implemented!
myClass(String varA, String varB) {
super(varA, varB);
}
//All non-private variables from the abstract class are available here
//All methods not implemented in the abstract class must be implemented here
}
You can also use an abstract class without any interface if you are SURE that you don't want to implement it along with other interfaces later. Please note that you can't create an instance of an abstract class you MUST extend it first.
(The "protected" keyword means that only extended classes can access these methods and variables.)
spyro
An Interface is contract between two parties that is invariant, carved in the stone, hence final. See Design by Contract.
In Java, interface doesn't allow you to declare any instance variables. Using a variable declared in an interface as an instance variable will return a compile time error.
You can declare a constant variable, using static final which is different from an instance variable.
Interface can be implemented by any classes and what if that value got changed by one of there implementing class then there will be mislead for other implementing classes. Interface is basically a reference to combine two corelated but different entity.so for that reason the declaring variable inside the interface will implicitly be final and also static because interface can not be instantiate.
Think of a web application where you have interface defined and other classes implement it. As you cannot create an instance of interface to access the variables you need to have a static keyword. Since its static any change in the value will reflect to other instances which has implemented it. So in order to prevent it we define them as final.
Just tried in Eclipse, the variable in interface is default to be final, so you can't change it. Compared with parent class, the variables are definitely changeable. Why? From my point, variable in class is an attribute which will be inherited by children, and children can change it according to their actual need. On the contrary, interface only define behavior, not attribute. The only reason to put in variables in interface is to use them as consts which related to that interface. Though, this is not a good practice according to following excerpt:
"Placing constants in an interface was a popular technique in the early days of Java, but now many consider it a distasteful use of interfaces, since interfaces should deal with the services provided by an object, not its data. As well, the constants used by a class are typically an implementation detail, but placing them in an interface promotes them to the public API of the class."
I also tried either put static or not makes no difference at all. The code is as below:
public interface Addable {
static int count = 6;
public int add(int i);
}
public class Impl implements Addable {
#Override
public int add(int i) {
return i+count;
}
}
public class Test {
public static void main(String... args) {
Impl impl = new Impl();
System.out.println(impl.add(4));
}
}
I feel like all these answers missed the point of the OP's question.
The OP did not ask for confirmation of their statement, they wanted to know WHY their statement is the standard.
Answering the question requires a little bit of information.
First, lets talk about inheretence.
Lets assume there is a class called A with an instance variable named x.
When you create a class A, it inhereits all the properties of the Object class. Without your knowledge when you instantiate A, you are instantiating an Object object as well, and A points to it as it's parent.
Now lets say you make a class B that inherits from A.
When you create a class B, you are also creating a class A and a Object.
B has access to the variable x. that means that B.x is really just the same thing as B.A.x and Java just hides the magic of grabbing A for you.
Not lets talk about interfaces...
An interface is NOT inheretence. If B were to implmement the interface Comparable, B is not making a Comparable instance and calling it a parent. Instead, B is promising to have the things that Comparable has.
Not lets talk a little bit of theory here... An interface is a set of functions you can use to interact with something. It is not the thing itself. For example, you interface with your friends by talking to them, sharing food with them, dancing with them, being near them. You don't inheret from them though - you do not have a copy of them.
Interfaces are similar. There is only one interface and all the objects associate with it. Since the interface exists only one time as a Class (as opposed to an instance of itself) it is not possible for each object that implements the interface to have their own copy of the interface. That means there is only one instance of each variable. That means the variables are shared by all the classes that use the interface (a.k.a. static).
As for why we make them public...
Private would be useless. The functions are abstract and cannot have any code inside them to use teh private variable. It will always be unused. If the variable is marked as protected, then only an inheritor of the class will be able to use the variables. I don't think you can inhereit from interfaces. Public is the only viable option then.
The only design decision left is the 'final'. It is possible that you intend to change the shared variable between multiple instances of a class. (E.G. Maybe you have 5 players playing Monopoly and you want one board to exist so you have all the players meet the interface and a single shared Board - it might be that you want to actually make the board change based on the player functions...) [I recommend against this design]
For multithreaded applicatiosn though, if you don't make the variable static you will have a difficult time later, but I won't stop you. Do it and learn why that hurts <3
So there you go. final public static variables
I understand that in Java static methods are inherited just like instance methods, with the difference that when they are redeclared, the parent implementations are hidden rather than overridden. Fine, this makes sense. However, the Java tutorial notes that
Static methods in interfaces are never inherited.
Why? What's the difference between regular and interface static methods?
Let me clarify what I mean when I say static methods can be inherited:
class Animal {
public static void identify() {
System.out.println("This is an animal");
}
}
class Cat extends Animal {}
public static void main(String[] args) {
Animal.identify();
Cat.identify(); // This compiles, even though it is not redefined in Cat.
}
However,
interface Animal {
public static void identify() {
System.out.println("This is an animal");
}
}
class Cat implements Animal {}
public static void main(String[] args) {
Animal.identify();
Cat.identify(); // This does not compile, because interface static methods do not inherit. (Why?)
}
Here's my guess.
Since Cat can only extend one class if Cat extends Animal then Cat.identify has only one meaning. Cat can implement multiple interfaces each of which can have a static implementation. Therefore, the compiler would not know which one to choose?
However, as pointed out by the author,
Java already has this problem, with default methods. If two interfaces
declare default void identify(), which one is used? It's a compile
error, and you have to implement an overriding method (which could
just be Animal.super.identify()). So Java already resolves this
problem for default methods – why not for static methods?
If I was to guess again, I'd say that with default the implementation is part of Cat's vtable. With static it cannot be. The main function must bind to something. At compile time Cat.identify could be replaced with Animal.identify by the compiler but the code wouldn't match reality if Cat was recompiled but not the class that contains main.
Before Java 8, you couldn't define static methods in an interface. This is heavily discussed in this question. I'm going to refer to this answer (by user #JamesA.Rosen) as to why the Java designers probably didn't want static methods in an interface initially:
There are a few issues at play here. The first is the issue of
declaring a static method without defining it. This is the difference
between
public interface Foo {
public static int bar();
}
and
public interface Foo {
public static int bar() {
...
}
}
Java doesn't allow either, but it could allow the second. The first is
impossible for the reasons that Espo mentions: you don't know which
implementing class is the correct definition.
Java could allow the latter, as long as it treated Interfaces as
first-class Objects. Ruby's Modules, which are approximately
equivalent to Java's Interfaces, allow exactly that:
module Foo
def self.bar
...
end
end
However, since the release of Java 8, you can actually add default and static methods inside an interface.
I'm going to be quoting this source a lot here. This is the initial problem:
Java's interface language feature lets you declare interfaces with
abstract methods and provide implementations of those methods in the
classes that implement the interfaces. You are required to implement
each method, which is burdensome when there are many methods to
implement. Also, after publishing the interface you cannot add new
abstract methods to it without breaking source and binary
compatibility.
This was the solution Java 8 provided default:
Java 8 addresses these problems by evolving the interface to support
default and static methods. A default method is an instance method
defined in an interface whose method header begins with the default
keyword; it also provides a code body. Every class that implements the
interface inherits the interface's default methods and can override
them
And for static:
A static method is a method that's associated with the class in which
it's defined, rather than with any object created from that class.
Every instance of the class shares the static methods of the class.
Java 8 also lets static methods be defined in interfaces where they
can assist default methods.
When you implement an interface that contains a static method, the
static method is still part of the interface and not part of the
implementing class. For this reason, you cannot prefix the method with
the class name. Instead, you must prefix the method with the interface
name
Example:
interface X
{
static void foo()
{
System.out.println("foo");
}
}
class Y implements X
{
}
public class Z
{
public static void main(String[] args)
{
X.foo();
// Y.foo(); // won't compile
}
}
Expression Y.foo() will not compile because foo() is a static member
of interface X and not a static member of class Y.
Static methods in interfaces could create a diamond of death if they were being inherited. So, calling a static method from the appropriate interface is good enough compared to the risk of calling it from a concrete class that may implement multiple interfaces that contain static methods of the same name.
Why are static methods any different?
Static methods are just functions unrelated to the objects. Instead of placing them in utility abstract classes (like calling Collections.sort() ) we move those functions (static methods) to their appropriate interfaces. They could be bound to the inherited objects like the default methods do, but that is not their job.
Static methods provide functionality which is unrelated to the instances of the class.
Example:
interface Floatable {
default void float() {
// implementation
}
static boolean checkIfItCanFloat(Object fl) {
// some physics here
}
}
class Duck implements Floatable { }
So, the point is that a Duck may float but the function that checks if an Object really floats is not something that a Duck can do. It is an irrelevant functionallity that we could pass to our Floatable interface instead of having it sit inside some utility class.
Let's begin with some background ...
Java doesn't support multiple inheritance (the ability to extend more than one class). This is because multiple inheritance is prone to the deadly diamond of death (also known as the diamond problem) which the designers of Java chose to preempt.
If B and C override a method inherited from A, which method does D inherit?
A class can implement multiple interfaces because interface methods are contracted for overriding; if a class C implements two interfaces A and B that declare the same method, then the same method in C will be invoked by clients of either interface (A or B). The introduction of default methods for interfaces in Java 8 was made possible by forcing the implementer to override the default in case of ambiguity. This was an acceptable compromise since default methods are intended to be defensive (to be used if no other implementation is explicitly provided by an implementer). However, since the compiler can’t force you to override a static method (static methods inherently can't be overridden), the introduction of static methods for interfaces in Java came with one restriction: the static methods of an interface are not inherited.
The answer is that static methods belong to a class/interface and there is only one instance for static blocks. that's the reason you can't override any static method.
Even in classes, you may override but only the super class' static method gets executed.
I have an abstract class A
I have about 10 classes that extend A
Class A has one or two static methods and it makes sense that these are static, because they belong to the 10 classes, NOT instances of them. One static method e.g. is called getAllFromX, which gets all all instances of the class from X, whatever that may be, it may be a server, well it actually is, but it doesn't matter. So you see it makes sense these methods are static and are not bound to an instance.
At the same time class A has a NON-static abstract method, each subclass overrides this method (just returns a string). I cannot make it static because static methods cannot be overridden (...).
To summarize: abstract class A has a static method and a abstract non-static method, that is overriden by the subclasses. I cannot make the second method static because it must be overriden. On the otherhand I could make the first method non-static, but it would be very ugly and bad programming style, so I'll leave it that way.
The catch? The static method in class A must get the value the non-static method returns (for the subclass the static method is inherited from, of course).
Is the "easiest" way to use reflection to get this done? I mean...really?
Like e.g., I get the class the static method is in:
Class<?> cl=new Object(){}.getClass().getEnclosingClass(); (a hack I found here, thank god...)
I then use getConstructor to construct an object of this subclass.
And then I use this object to call the non-static method.
Really?? Can it not be done easier? I mean that is if I want to design my program conceptually correct...
Coming from C# I don't like that (and the type erasure thing). It is just ugly. Doable but ugly. And a big stumbling block, at least for beginners. EDIT: after reading it again, I'd add: /rant end. Sorry, but I actually care.
I think what you in fact need is the following:
public class A {
public static Set<A> getAllFromX() {
...
}
}
public class B extends A {
public static Set<B> getAllFromX() {
...
}
}
public class C extends A {
public static Set<C> getAllFromX() {
...
}
}
(Just as the valueOf() and values() methods in enums, which is redefined in every Enum subclass, because static methods can't be inherited)
In this case, each class has its own static method doing whatever it wants. But your question doesn't make much sense because it says:
The static method in class A must get the value the non-static method returns (for the subclass the static method is inherited from, of course).
Indeed, the static method is not inherited by the subclass. Static methods are never inherited. If you define a static method foo() in A, and call
B.foo();
the compiler doesn't refuse to compile it, but it translates it to
A.foo();
So, there's no way to do in foo() something that depends on the class on which foo() is called, since it's always A.
You can always use reflection to invoke a method using class name e.g.
Object objectX = ClassX.class.newInstance();
//get your method passing argument types as second param
Method method = ClassX.class.getDeclaredMethod("methodX", null);
//invoke your method passing arguments as second param
method.invoke(objectX, null);
Since you mentioned your static method doesn't use any instance but you are using reflection to get the instance hence I am really not sure, how does it fit in your requirement though.
I think making it as an implemented method (non-static) in your abstract class is a better choice. That way you implement it once but its available in in all your 10 extending classes.
I think your problem is one of larger design. A different object should be responsible for retrieving instances of A or its subclasses. As you can see, relying on a static method to be replaced by subclasses does not work well. Without knowing more about the problem domain, it's hard to give a good answer, but I would consider something similar to the Abstract Factory pattern.
Broadly speaking: Define an abstract class, AFactory, with a method Collection getInstances(). Extend AFactory for each of the concrete subclasses of A you need to return and implement that logic in the overridden getInstances() method as appropriate. You may also provide a static method on the abstract AFactory, getFactory(Class), to get the appropriate factory subtype at runtime.
Why are interface variables static and final by default in Java?
From the Java interface design FAQ by Philip Shaw:
Interface variables are static because Java interfaces cannot be instantiated in their own right; the value of the variable must be assigned in a static context in which no instance exists. The final modifier ensures the value assigned to the interface variable is a true constant that cannot be re-assigned by program code.
source
public: for the accessibility across all the classes, just like the methods present in the interface
static: as interface cannot have an object, the interfaceName.variableName can be used to reference it or directly the variableName in the class implementing it.
final: to make them constants. If 2 classes implement the same interface and you give both of them the right to change the value, conflict will occur in the current value of the var, which is why only one time initialization is permitted.
Also all these modifiers are implicit for an interface, you dont really need to specify any of them.
Since interface doesn't have a direct object, the only way to access them is by using a class/interface and hence that is why if interface variable exists, it should be static otherwise it wont be accessible at all to outside world. Now since it is static, it can hold only one value and any classes that implements it can change it and hence it will be all mess.
Hence if at all there is an interface variable, it will be implicitly static, final and obviously public!!!
(This is not a philosophical answer but more of a practical one). The requirement for static modifier is obvious which has been answered by others. Basically, since the interfaces cannot be instantiated, the only way to access its fields are to make them a class field -- static.
The reason behind the interface fields automatically becoming final (constant) is to prevent different implementations accidentally changing the value of interface variable which can inadvertently affect the behavior of the other implementations. Imagine the scenario below where an interface property did not explicitly become final by Java:
public interface Actionable {
public static boolean isActionable = false;
public void performAction();
}
public NuclearAction implements Actionable {
public void performAction() {
// Code that depends on isActionable variable
if (isActionable) {
// Launch nuclear weapon!!!
}
}
}
Now, just think what would happen if another class that implements Actionable alters the state of the interface variable:
public CleanAction implements Actionable {
public void performAction() {
// Code that can alter isActionable state since it is not constant
isActionable = true;
}
}
If these classes are loaded within a single JVM by a classloader, then the behavior of NuclearAction can be affected by another class, CleanAction, when its performAction() is invoke after CleanAction's is executed (in the same thread or otherwise), which in this case can be disastrous (semantically that is).
Since we do not know how each implementation of an interface is going to use these variables, they must implicitly be final.
Because anything else is part of the implementation, and interfaces cannot contain any implementation.
public interface A{
int x=65;
}
public interface B{
int x=66;
}
public class D implements A,B {
public static void main(String[] a){
System.out.println(x); // which x?
}
}
Here is the solution.
System.out.println(A.x); // done
I think it is the one reason why interface variable are static.
Don't declare variables inside Interface.
because:
Static : as we can't have objects of interfaces so we should avoid using Object level member variables and should use class level variables i.e. static.
Final : so that we should not have ambiguous values for the variables(Diamond problem - Multiple Inheritance).
And as per the documentation interface is a contract and not an implementation.
reference: Abhishek Jain's answer on quora
static - because Interface cannot have any instance. and final - because we do not need to change it.
Interface : System requirement service.
In interface, variable are by default assign by public,static,final access modifier.
Because :
public : It happen some-times that interface might placed in some other package. So it need to access the variable from anywhere in project.
static : As such incomplete class can not create object. So in project we need to access the variable without object so we can access with the help of interface_filename.variable_name
final : Suppose one interface implements by many class and all classes try to access and update the interface variable. So it leads to inconsistent of changing data and affect every other class. So it need to declare access modifier with final.
Java does not allow abstract variables and/or constructor definitions in interfaces. Solution: Simply hang an abstract class between your interface and your implementation which only extends the abstract class like so:
public interface IMyClass {
void methodA();
String methodB();
Integer methodC();
}
public abstract class myAbstractClass implements IMyClass {
protected String varA, varB;
//Constructor
myAbstractClass(String varA, String varB) {
this.varA = varA;
this.varB = VarB;
}
//Implement (some) interface methods here or leave them for the concrete class
protected void methodA() {
//Do something
}
//Add additional methods here which must be implemented in the concrete class
protected abstract Long methodD();
//Write some completely new methods which can be used by all subclasses
protected Float methodE() {
return 42.0;
}
}
public class myConcreteClass extends myAbstractClass {
//Constructor must now be implemented!
myClass(String varA, String varB) {
super(varA, varB);
}
//All non-private variables from the abstract class are available here
//All methods not implemented in the abstract class must be implemented here
}
You can also use an abstract class without any interface if you are SURE that you don't want to implement it along with other interfaces later. Please note that you can't create an instance of an abstract class you MUST extend it first.
(The "protected" keyword means that only extended classes can access these methods and variables.)
spyro
An Interface is contract between two parties that is invariant, carved in the stone, hence final. See Design by Contract.
In Java, interface doesn't allow you to declare any instance variables. Using a variable declared in an interface as an instance variable will return a compile time error.
You can declare a constant variable, using static final which is different from an instance variable.
Interface can be implemented by any classes and what if that value got changed by one of there implementing class then there will be mislead for other implementing classes. Interface is basically a reference to combine two corelated but different entity.so for that reason the declaring variable inside the interface will implicitly be final and also static because interface can not be instantiate.
Think of a web application where you have interface defined and other classes implement it. As you cannot create an instance of interface to access the variables you need to have a static keyword. Since its static any change in the value will reflect to other instances which has implemented it. So in order to prevent it we define them as final.
Just tried in Eclipse, the variable in interface is default to be final, so you can't change it. Compared with parent class, the variables are definitely changeable. Why? From my point, variable in class is an attribute which will be inherited by children, and children can change it according to their actual need. On the contrary, interface only define behavior, not attribute. The only reason to put in variables in interface is to use them as consts which related to that interface. Though, this is not a good practice according to following excerpt:
"Placing constants in an interface was a popular technique in the early days of Java, but now many consider it a distasteful use of interfaces, since interfaces should deal with the services provided by an object, not its data. As well, the constants used by a class are typically an implementation detail, but placing them in an interface promotes them to the public API of the class."
I also tried either put static or not makes no difference at all. The code is as below:
public interface Addable {
static int count = 6;
public int add(int i);
}
public class Impl implements Addable {
#Override
public int add(int i) {
return i+count;
}
}
public class Test {
public static void main(String... args) {
Impl impl = new Impl();
System.out.println(impl.add(4));
}
}
I feel like all these answers missed the point of the OP's question.
The OP did not ask for confirmation of their statement, they wanted to know WHY their statement is the standard.
Answering the question requires a little bit of information.
First, lets talk about inheretence.
Lets assume there is a class called A with an instance variable named x.
When you create a class A, it inhereits all the properties of the Object class. Without your knowledge when you instantiate A, you are instantiating an Object object as well, and A points to it as it's parent.
Now lets say you make a class B that inherits from A.
When you create a class B, you are also creating a class A and a Object.
B has access to the variable x. that means that B.x is really just the same thing as B.A.x and Java just hides the magic of grabbing A for you.
Not lets talk about interfaces...
An interface is NOT inheretence. If B were to implmement the interface Comparable, B is not making a Comparable instance and calling it a parent. Instead, B is promising to have the things that Comparable has.
Not lets talk a little bit of theory here... An interface is a set of functions you can use to interact with something. It is not the thing itself. For example, you interface with your friends by talking to them, sharing food with them, dancing with them, being near them. You don't inheret from them though - you do not have a copy of them.
Interfaces are similar. There is only one interface and all the objects associate with it. Since the interface exists only one time as a Class (as opposed to an instance of itself) it is not possible for each object that implements the interface to have their own copy of the interface. That means there is only one instance of each variable. That means the variables are shared by all the classes that use the interface (a.k.a. static).
As for why we make them public...
Private would be useless. The functions are abstract and cannot have any code inside them to use teh private variable. It will always be unused. If the variable is marked as protected, then only an inheritor of the class will be able to use the variables. I don't think you can inhereit from interfaces. Public is the only viable option then.
The only design decision left is the 'final'. It is possible that you intend to change the shared variable between multiple instances of a class. (E.G. Maybe you have 5 players playing Monopoly and you want one board to exist so you have all the players meet the interface and a single shared Board - it might be that you want to actually make the board change based on the player functions...) [I recommend against this design]
For multithreaded applicatiosn though, if you don't make the variable static you will have a difficult time later, but I won't stop you. Do it and learn why that hurts <3
So there you go. final public static variables
I have just found a static nested interface in our code-base.
class Foo {
public static interface Bar {
/* snip */
}
/* snip */
}
I have never seen this before. The original developer is out of reach. Therefore I have to ask SO:
What are the semantics behind a static interface? What would change, if I remove the static? Why would anyone do this?
The static keyword in the above example is redundant (a nested interface is automatically "static") and can be removed with no effect on semantics; I would recommend it be removed. The same goes for "public" on interface methods and "public final" on interface fields - the modifiers are redundant and just add clutter to the source code.
Either way, the developer is simply declaring an interface named Foo.Bar. There is no further association with the enclosing class, except that code which cannot access Foo will not be able to access Foo.Bar either. (From source code - bytecode or reflection can access Foo.Bar even if Foo is package-private!)
It is acceptable style to create a nested interface this way if you expect it to be used only from the outer class, so that you do not create a new top-level name. For example:
public class Foo {
public interface Bar {
void callback();
}
public static void registerCallback(Bar bar) {...}
}
// ...elsewhere...
Foo.registerCallback(new Foo.Bar() {
public void callback() {...}
});
The question has been answered, but one good reason to use a nested interface is if its function is directly related to the class it is in. A good example of this is a Listener. If you had a class Foo and you wanted other classes to be able to listen for events on it, you could declare an interface named FooListener, which is ok, but it would probably be more clear to declare a nested interface and have those other classes implement Foo.Listener (a nested class Foo.Event isn't bad along with this).
Member interfaces are implicitly static. The static modifier in your example can be removed without changing the semantics of the code. See also the the Java Language Specification 8.5.1. Static Member Type Declarations
An inner interface has to be static in order to be accessed. The interface isn't associated with instances of the class, but with the class itself, so it would be accessed with Foo.Bar, like so:
public class Baz implements Foo.Bar {
...
}
In most ways, this isn't different from a static inner class.
Jesse's answer is close, but I think that there is a better code to demonstrate why an inner interface may be useful. Look at the code below before you read on. Can you find why the inner interface is useful? The answer is that class DoSomethingAlready can be instantiated with any class that implements A and C; not just the concrete class Zoo. Of course, this can be achieved even if AC is not inner, but imagine concatenating longer names (not just A and C), and doing this for other combinations (say, A and B, C and B, etc.) and you easily see how things go out of control. Not to mention that people reviewing your source tree will be overwhelmed by interfaces that are meaningful only in one class.So to summarize, an inner interface enables the construction of custom types and improves their encapsulation.
class ConcreteA implements A {
:
}
class ConcreteB implements B {
:
}
class ConcreteC implements C {
:
}
class Zoo implements A, C {
:
}
class DoSomethingAlready {
interface AC extends A, C { }
private final AC ac;
DoSomethingAlready(AC ac) {
this.ac = ac;
}
}
To answer your question very directly, look at Map.Entry.
Map.Entry
also this may be useful
Static Nested Inerfaces blog Entry
Typically I see static inner classes. Static inner classes cannot reference the containing classes wherease non-static classes can. Unless you're running into some package collisions (there already is an interface called Bar in the same package as Foo) I think I'd make it it's own file. It could also be a design decision to enforce the logical connection between Foo and Bar. Perhaps the author intended Bar to only be used with Foo (though a static inner interface won't enforce this, just a logical connection)
If you will change class Foo into interface Foo the "public" keyword in the above example will be also redundant as well because
interface defined inside another interface will implicitly public
static.
In 1998, Philip Wadler suggested a difference between static interfaces and non-static interfaces.
So far as I can see, the only difference in making an
interface non-static is that it can now include non-static inner
classes; so the change would not render invalid any existing Java
programs.
For example, he proposed a solution to the Expression Problem, which is the mismatch between expression as "how much can your language express" on the one hand and expression as "the terms you are trying to represent in your language" on the other hand.
An example of the difference between static and non-static nested interfaces can be seen in his sample code:
// This code does NOT compile
class LangF<This extends LangF<This>> {
interface Visitor<R> {
public R forNum(int n);
}
interface Exp {
// since Exp is non-static, it can refer to the type bound to This
public <R> R visit(This.Visitor<R> v);
}
}
His suggestion never made it in Java 1.5.0. Hence, all other answers are correct: there is no difference to static and non-static nested interfaces.
In Java, the static interface/class allows the interface/class to be used like a top-level class, that is, it can be declared by other classes. So, you can do:
class Bob
{
void FuncA ()
{
Foo.Bar foobar;
}
}
Without the static, the above would fail to compile. The advantage to this is that you don't need a new source file just to declare the interface. It also visually associates the interface Bar to the class Foo since you have to write Foo.Bar and implies that the Foo class does something with instances of Foo.Bar.
A description of class types in Java.
Static means that any class part of the package(project) can acces it without using a pointer. This can be usefull or hindering depending on the situation.
The perfect example of the usefullnes of "static" methods is the Math class. All methods in Math are static. This means you don't have to go out of your way, make a new instance, declare variables and store them in even more variables, you can just enter your data and get a result.
Static isn't always that usefull. If you're doing case-comparison for instance, you might want to store data in several different ways. You can't create three static methods with identical signatures. You need 3 different instances, non-static, and then you can and compare, caus if it's static, the data won't change along with the input.
Static methods are good for one-time returns and quick calculations or easy obtained data.