How does java calculate the tokens of openai? [closed] - java

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I'm using openai. Openai's gpt3 model call fee is calculated using tokens, but its token calculation method is very strange. I use String.length which is different from the official calculation tool. I don't know how to use python. Does anyone know how to use java? Calculate? Thanks in advance
public static void main(String[] args){
String str = "hello";
byte[] bytes = str.getBytes();
int length = bytes.length;
System.out.println(length);
}

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How to take out the numbers from the String and eliminate those number and store the filtered String and print it in java [closed]

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String txt = "d89%l++5r19o7W *o=1645le9H"
System.out.println(t.replace(/\\d{0,}/g,''));

Because i'm bored...
String txt = "d89%l++5r19o7W *o=1645le9H";
txt = txt.replaceAll("\\d", "")
System.out.println(txt);

This will all numerical charactors from string
System.out.println(string.replaceAll("\\d",""));

Print the shape by getting sides and angle [closed]

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Get four length from the user and also get one internal angle.Using that print what shape is that? I tried this.
Scanner in =new Scanner(System.in);
int l1=in.nextInt();
int l2=in.nextInt();
int l3=in.nextInt();
int l4=in.nextInt();
int L=l1;
int angle=in.nextInt();
if((l1==L)&&(l2==L)&&(l3==L)&&(l4==L))
{
if(angle==90)
System.out.println("SQUARE");
}
I do this for SQUARE check.Now i want to find for IRREGULAR QUADRILATERAL.How can i check for this shape?

how to get values from a Text view android [closed]

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I need to store values from text view for example i am performing the following plus function like 5+6.Now i want to store 5 as value-1 and 6 as value-2.I only have one text view where i am displying like 5+6 in my project.I search a lot about my issue but could not found any proper solution. thanks

try this:
String string =text.getText().toString();
String[] separated = string.split("+");
String firstValue=separated[0];
String secondValue=separated[1];

You can try this and you will able to get the addition of two numbers at once. .
String[] getText = textview.getText().split("\\+");
int total=0;
for(String s:getText){
total+=Integer.parseInt(s);
}
in the end of iteration total will give the final result.From this method it gives the total of any numbers of numbers.

Return a string that matches until another given string [closed]

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I can get it done by implementing the logic to do it. However, I am looking for a single method call rather than implement it myself.
Example:
String sampleStr = "This is a sample string";
String resultStr = sampleStr.singleMethodCall("sample");
//resultStr will be "This is a sample"
I am ok if this can be achieved with a third party API.

You can use standard String functions.
String resultStr = sampleStr.substring(0, sampleStr.indexOf("sample") + 6);
Take the substring from position 0 (the start) until the position of "sample", but add another 6 characters so you also include "sample" and the preceeding space.

Sorting Variables and negated Variables in Java [closed]

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how to sort variables X and negated varibles X' alphabetic which are saved as string in Java?
Example: String string = "B*A'*D*H'"; result must
String sortedString="A'*B*D*H'";

are the variables always separated with * ?
In that case it'd be very simple:
String in = "B*A'*D*H'";
String[] vars = in.split("\\*");
Arrays.sort(vars);
// Java is missing a simple php-like join function ;-(
StringBuilder sorted = new StringBuilder();
for(String s: vars){
sorted.append(s);
sorted.append("*");
}
sorted.deleteCharAt(sorted.length()-1);
and you're done ;-)

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