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I am trying to pass argument from my java GUI to the python algorithm. I have tried many ways but I keep getting unrecognized argument as the error. I am using Process builder to integrate the python code to my java. i need to send fav_movie from java to python.
this is a part of the python code. i am a python beginner so it would be helpful if you could please tell me what is causing this error
def _fuzzy_matching(self, hashmap, fav_movie):
"""
return the closest match via fuzzy ratio.
If no match found, return None
Parameters
----------
hashmap: dict, map movie title name to index of the movie in data
fav_movie: str, name of user input movie
Return
------
index of the closest match
"""
match_tuple = []
# get match
for title, idx in hashmap.items():
ratio = fuzz.ratio(title.lower(), fav_movie.lower())
if ratio >= 60:
match_tuple.append((title, idx, ratio))
# sort
match_tuple = sorted(match_tuple, key=lambda x: x[2])[::-1]
if not match_tuple:
print('Oops! No match is found')
else:
print('Found possible matches in our database: '
'{0}\n'.format([x[0] for x in match_tuple]))
return match_tuple[0][1]
def parse_args():
parser = argparse.ArgumentParser(
prog="Movie Recommender",
description="Run KNN Movie Recommender")
parser.add_argument('--path', nargs='?', default='C:\java programs\qcri 3\ml-latest-small',
help='input data path')
parser.add_argument('--movies_filename', nargs='?', default='movies.csv',
help='provide movies filename')
parser.add_argument('--ratings_filename', nargs='?', default='ratings.csv',
help='provide ratings filename')
parser.add_argument('--movie_name', nargs='?', default='',
help='provide your favourite movie name')
parser.add_argument('--top_n', type=int, default=10,
help='top n movie recommendations')
return parser.parse_args()
if __name__ == '__main__':
# get args
args = parse_args()
data_path = args.path
movies_filename = args.movies_filename
ratings_filename = args.ratings_filename
movie_name = args.movie_name
top_n = args.top_n
# initial recommender system
recommender = KnnRecommender(
os.path.join(data_path, movies_filename),
os.path.join(data_path, ratings_filename))
# set params
recommender.set_filter_params(50, 50)
recommender.set_model_params(20, 'brute', 'cosine', -1)
# make recommendations
recommender.make_recommendations(movie_name, top_n)
this is the error shown:
usage: Movie Recommender [-h] [--path [PATH]]
[--movies_filename [MOVIES_FILENAME]]
[--ratings_filename [RATINGS_FILENAME]]
[--movie_name [MOVIE_NAME]] [--top_n TOP_N]
Movie Recommender: error: unrecognized arguments: toy
this is the java code that accesses the python:
public static void main(String args[]) throws ScriptException, InterruptedException
{
System.out.println("enter movie name");
Scanner s= new Scanner(System.in);
String name= s.nextLine();
ProcessBuilder pb= new ProcessBuilder("python","recomold.py",name);
System.out.println("running file");
Process process = null;
try {
process = pb.start();
inheritIO(process.getInputStream(), System.out);
inheritIO(process.getErrorStream(), System.err);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
int err= process.waitFor();
System.out.println("any errors?"+(err==0 ? "no" : "yes ")+err);
try {
System.out.println("python output "+ output(process.getInputStream()));
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
private static void inheritIO(InputStream src, PrintStream dest) {
new Thread(new Runnable() {
public void run() {
Scanner sc = new Scanner(src);
while (sc.hasNextLine()) {
dest.println(sc.nextLine());
}
}
}).start();
}
private static String output(InputStream inputStream) throws IOException {
StringBuilder sb = new StringBuilder();
BufferedReader br = null;
try{
br= new BufferedReader(new InputStreamReader(inputStream));
String line = null;
while((line=br.readLine())!=null)
{
sb.append(line+"\n");
}
}
finally
{
br.close();
}
return sb.toString();
}
}
It looks like your Python script does not accept a non-option argument as proper input. According to the help text for your Python program, any arguments you provide must come in option/value pair form, like this:
--<option_name> <option_value>
But you're just passing "toy" with no option specifier. So maybe what you want is something like this in your Java code:
ProcessBuilder pb= new ProcessBuilder("python","recomold.py","--movie-name",name);
It seems there are different ways to read and write data of files in Java.
I want to read ASCII data from a file. What are the possible ways and their differences?
My favorite way to read a small file is to use a BufferedReader and a StringBuilder. It is very simple and to the point (though not particularly effective, but good enough for most cases):
BufferedReader br = new BufferedReader(new FileReader("file.txt"));
try {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
} finally {
br.close();
}
Some has pointed out that after Java 7 you should use try-with-resources (i.e. auto close) features:
try(BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
}
When I read strings like this, I usually want to do some string handling per line anyways, so then I go for this implementation.
Though if I want to actually just read a file into a String, I always use Apache Commons IO with the class IOUtils.toString() method. You can have a look at the source here:
http://www.docjar.com/html/api/org/apache/commons/io/IOUtils.java.html
FileInputStream inputStream = new FileInputStream("foo.txt");
try {
String everything = IOUtils.toString(inputStream);
} finally {
inputStream.close();
}
And even simpler with Java 7:
try(FileInputStream inputStream = new FileInputStream("foo.txt")) {
String everything = IOUtils.toString(inputStream);
// do something with everything string
}
ASCII is a TEXT file so you would use Readers for reading. Java also supports reading from a binary file using InputStreams. If the files being read are huge then you would want to use a BufferedReader on top of a FileReader to improve read performance.
Go through this article on how to use a Reader
I'd also recommend you download and read this wonderful (yet free) book called Thinking In Java
In Java 7:
new String(Files.readAllBytes(...))
(docs)
or
Files.readAllLines(...)
(docs)
In Java 8:
Files.lines(..).forEach(...)
(docs)
The easiest way is to use the Scanner class in Java and the FileReader object. Simple example:
Scanner in = new Scanner(new FileReader("filename.txt"));
Scanner has several methods for reading in strings, numbers, etc... You can look for more information on this on the Java documentation page.
For example reading the whole content into a String:
StringBuilder sb = new StringBuilder();
while(in.hasNext()) {
sb.append(in.next());
}
in.close();
outString = sb.toString();
Also if you need a specific encoding you can use this instead of FileReader:
new InputStreamReader(new FileInputStream(fileUtf8), StandardCharsets.UTF_8)
Here is a simple solution:
String content = new String(Files.readAllBytes(Paths.get("sample.txt")));
Or to read as list:
List<String> content = Files.readAllLines(Paths.get("sample.txt"))
Here's another way to do it without using external libraries:
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public String readFile(String filename)
{
String content = null;
File file = new File(filename); // For example, foo.txt
FileReader reader = null;
try {
reader = new FileReader(file);
char[] chars = new char[(int) file.length()];
reader.read(chars);
content = new String(chars);
reader.close();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(reader != null){
reader.close();
}
}
return content;
}
I had to benchmark the different ways. I shall comment on my findings but, in short, the fastest way is to use a plain old BufferedInputStream over a FileInputStream. If many files must be read then three threads will reduce the total execution time to roughly half, but adding more threads will progressively degrade performance until making it take three times longer to complete with twenty threads than with just one thread.
The assumption is that you must read a file and do something meaningful with its contents. In the examples here is reading lines from a log and count the ones which contain values that exceed a certain threshold. So I am assuming that the one-liner Java 8 Files.lines(Paths.get("/path/to/file.txt")).map(line -> line.split(";")) is not an option.
I tested on Java 1.8, Windows 7 and both SSD and HDD drives.
I wrote six different implementations:
rawParse: Use BufferedInputStream over a FileInputStream and then cut lines reading byte by byte. This outperformed any other single-thread approach, but it may be very inconvenient for non-ASCII files.
lineReaderParse: Use a BufferedReader over a FileReader, read line by line, split lines by calling String.split(). This is approximatedly 20% slower that rawParse.
lineReaderParseParallel: This is the same as lineReaderParse, but it uses several threads. This is the fastest option overall in all cases.
nioFilesParse: Use java.nio.files.Files.lines()
nioAsyncParse: Use an AsynchronousFileChannel with a completion handler and a thread pool.
nioMemoryMappedParse: Use a memory-mapped file. This is really a bad idea yielding execution times at least three times longer than any other implementation.
These are the average times for reading 204 files of 4 MB each on an quad-core i7 and SSD drive. The files are generated on the fly to avoid disk caching.
rawParse 11.10 sec
lineReaderParse 13.86 sec
lineReaderParseParallel 6.00 sec
nioFilesParse 13.52 sec
nioAsyncParse 16.06 sec
nioMemoryMappedParse 37.68 sec
I found a difference smaller than I expected between running on an SSD or an HDD drive being the SSD approximately 15% faster. This may be because the files are generated on an unfragmented HDD and they are read sequentially, therefore the spinning drive can perform nearly as an SSD.
I was surprised by the low performance of the nioAsyncParse implementation. Either I have implemented something in the wrong way or the multi-thread implementation using NIO and a completion handler performs the same (or even worse) than a single-thread implementation with the java.io API. Moreover the asynchronous parse with a CompletionHandler is much longer in lines of code and tricky to implement correctly than a straight implementation on old streams.
Now the six implementations followed by a class containing them all plus a parametrizable main() method that allows to play with the number of files, file size and concurrency degree. Note that the size of the files varies plus minus 20%. This is to avoid any effect due to all the files being of exactly the same size.
rawParse
public void rawParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
overrunCount = 0;
final int dl = (int) ';';
StringBuffer lineBuffer = new StringBuffer(1024);
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileInputStream fin = new FileInputStream(fl);
BufferedInputStream bin = new BufferedInputStream(fin);
int character;
while((character=bin.read())!=-1) {
if (character==dl) {
// Here is where something is done with each line
doSomethingWithRawLine(lineBuffer.toString());
lineBuffer.setLength(0);
}
else {
lineBuffer.append((char) character);
}
}
bin.close();
fin.close();
}
}
public final void doSomethingWithRawLine(String line) throws ParseException {
// What to do for each line
int fieldNumber = 0;
final int len = line.length();
StringBuffer fieldBuffer = new StringBuffer(256);
for (int charPos=0; charPos<len; charPos++) {
char c = line.charAt(charPos);
if (c==DL0) {
String fieldValue = fieldBuffer.toString();
if (fieldValue.length()>0) {
switch (fieldNumber) {
case 0:
Date dt = fmt.parse(fieldValue);
fieldNumber++;
break;
case 1:
double d = Double.parseDouble(fieldValue);
fieldNumber++;
break;
case 2:
int t = Integer.parseInt(fieldValue);
fieldNumber++;
break;
case 3:
if (fieldValue.equals("overrun"))
overrunCount++;
break;
}
}
fieldBuffer.setLength(0);
}
else {
fieldBuffer.append(c);
}
}
}
lineReaderParse
public void lineReaderParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
String line;
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null)
doSomethingWithLine(line);
brd.close();
frd.close();
}
}
public final void doSomethingWithLine(String line) throws ParseException {
// Example of what to do for each line
String[] fields = line.split(";");
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
lineReaderParseParallel
public void lineReaderParseParallel(final String targetDir, final int numberOfFiles, final int degreeOfParalelism) throws IOException, ParseException, InterruptedException {
Thread[] pool = new Thread[degreeOfParalelism];
int batchSize = numberOfFiles / degreeOfParalelism;
for (int b=0; b<degreeOfParalelism; b++) {
pool[b] = new LineReaderParseThread(targetDir, b*batchSize, b*batchSize+b*batchSize);
pool[b].start();
}
for (int b=0; b<degreeOfParalelism; b++)
pool[b].join();
}
class LineReaderParseThread extends Thread {
private String targetDir;
private int fileFrom;
private int fileTo;
private DateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
private int overrunCounter = 0;
public LineReaderParseThread(String targetDir, int fileFrom, int fileTo) {
this.targetDir = targetDir;
this.fileFrom = fileFrom;
this.fileTo = fileTo;
}
private void doSomethingWithTheLine(String line) throws ParseException {
String[] fields = line.split(DL);
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCounter++;
}
#Override
public void run() {
String line;
for (int f=fileFrom; f<fileTo; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
try {
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null) {
doSomethingWithTheLine(line);
}
brd.close();
frd.close();
} catch (IOException | ParseException ioe) { }
}
}
}
nioFilesParse
public void nioFilesParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
for (int f=0; f<numberOfFiles; f++) {
Path ph = Paths.get(targetDir+filenamePreffix+String.valueOf(f)+".txt");
Consumer<String> action = new LineConsumer();
Stream<String> lines = Files.lines(ph);
lines.forEach(action);
lines.close();
}
}
class LineConsumer implements Consumer<String> {
#Override
public void accept(String line) {
// What to do for each line
String[] fields = line.split(DL);
if (fields.length>1) {
try {
Date dt = fmt.parse(fields[0]);
}
catch (ParseException e) {
}
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
}
}
nioAsyncParse
public void nioAsyncParse(final String targetDir, final int numberOfFiles, final int numberOfThreads, final int bufferSize) throws IOException, ParseException, InterruptedException {
ScheduledThreadPoolExecutor pool = new ScheduledThreadPoolExecutor(numberOfThreads);
ConcurrentLinkedQueue<ByteBuffer> byteBuffers = new ConcurrentLinkedQueue<ByteBuffer>();
for (int b=0; b<numberOfThreads; b++)
byteBuffers.add(ByteBuffer.allocate(bufferSize));
for (int f=0; f<numberOfFiles; f++) {
consumerThreads.acquire();
String fileName = targetDir+filenamePreffix+String.valueOf(f)+".txt";
AsynchronousFileChannel channel = AsynchronousFileChannel.open(Paths.get(fileName), EnumSet.of(StandardOpenOption.READ), pool);
BufferConsumer consumer = new BufferConsumer(byteBuffers, fileName, bufferSize);
channel.read(consumer.buffer(), 0l, channel, consumer);
}
consumerThreads.acquire(numberOfThreads);
}
class BufferConsumer implements CompletionHandler<Integer, AsynchronousFileChannel> {
private ConcurrentLinkedQueue<ByteBuffer> buffers;
private ByteBuffer bytes;
private String file;
private StringBuffer chars;
private int limit;
private long position;
private DateFormat frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
public BufferConsumer(ConcurrentLinkedQueue<ByteBuffer> byteBuffers, String fileName, int bufferSize) {
buffers = byteBuffers;
bytes = buffers.poll();
if (bytes==null)
bytes = ByteBuffer.allocate(bufferSize);
file = fileName;
chars = new StringBuffer(bufferSize);
frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
limit = bufferSize;
position = 0l;
}
public ByteBuffer buffer() {
return bytes;
}
#Override
public synchronized void completed(Integer result, AsynchronousFileChannel channel) {
if (result!=-1) {
bytes.flip();
final int len = bytes.limit();
int i = 0;
try {
for (i = 0; i < len; i++) {
byte by = bytes.get();
if (by=='\n') {
// ***
// The code used to process the line goes here
chars.setLength(0);
}
else {
chars.append((char) by);
}
}
}
catch (Exception x) {
System.out.println(
"Caught exception " + x.getClass().getName() + " " + x.getMessage() +
" i=" + String.valueOf(i) + ", limit=" + String.valueOf(len) +
", position="+String.valueOf(position));
}
if (len==limit) {
bytes.clear();
position += len;
channel.read(bytes, position, channel, this);
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
#Override
public void failed(Throwable e, AsynchronousFileChannel channel) {
}
};
FULL RUNNABLE IMPLEMENTATION OF ALL CASES
https://github.com/sergiomt/javaiobenchmark/blob/master/FileReadBenchmark.java
Here are the three working and tested methods:
Using BufferedReader
package io;
import java.io.*;
public class ReadFromFile2 {
public static void main(String[] args)throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
BufferedReader br = new BufferedReader(new FileReader(file));
String st;
while((st=br.readLine()) != null){
System.out.println(st);
}
}
}
Using Scanner
package io;
import java.io.File;
import java.util.Scanner;
public class ReadFromFileUsingScanner {
public static void main(String[] args) throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
while(sc.hasNextLine()){
System.out.println(sc.nextLine());
}
}
}
Using FileReader
package io;
import java.io.*;
public class ReadingFromFile {
public static void main(String[] args) throws Exception {
FileReader fr = new FileReader("C:\\Users\\pankaj\\Desktop\\test.java");
int i;
while ((i=fr.read()) != -1){
System.out.print((char) i);
}
}
}
Read the entire file without a loop using the Scanner class
package io;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class ReadingEntireFileWithoutLoop {
public static void main(String[] args) throws FileNotFoundException {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
sc.useDelimiter("\\Z");
System.out.println(sc.next());
}
}
The methods within org.apache.commons.io.FileUtils may also be very handy, e.g.:
/**
* Reads the contents of a file line by line to a List
* of Strings using the default encoding for the VM.
*/
static List readLines(File file)
I documented 15 ways to read a file in Java and then tested them for speed with various file sizes - from 1 KB to 1 GB and here are the top three ways to do this:
java.nio.file.Files.readAllBytes()
Tested to work in Java 7, 8, and 9.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
public class ReadFile_Files_ReadAllBytes {
public static void main(String [] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
byte [] fileBytes = Files.readAllBytes(file.toPath());
char singleChar;
for(byte b : fileBytes) {
singleChar = (char) b;
System.out.print(singleChar);
}
}
}
java.io.BufferedReader.readLine()
Tested to work in Java 7, 8, 9.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class ReadFile_BufferedReader_ReadLine {
public static void main(String [] args) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
FileReader fileReader = new FileReader(fileName);
try (BufferedReader bufferedReader = new BufferedReader(fileReader)) {
String line;
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
}
}
}
}
java.nio.file.Files.lines()
This was tested to work in Java 8 and 9 but won't work in Java 7 because of the lambda expression requirement.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.util.stream.Stream;
public class ReadFile_Files_Lines {
public static void main(String[] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
try (Stream linesStream = Files.lines(file.toPath())) {
linesStream.forEach(line -> {
System.out.println(line);
});
}
}
}
What do you want to do with the text? Is the file small enough to fit into memory? I would try to find the simplest way to handle the file for your needs. The FileUtils library is very handle for this.
for(String line: FileUtils.readLines("my-text-file"))
System.out.println(line);
Below is a one-liner of doing it in the Java 8 way. Assuming text.txt file is in the root of the project directory of the Eclipse.
Files.lines(Paths.get("text.txt")).collect(Collectors.toList());
The most intuitive method is introduced in Java 11 Files.readString
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
public class App {
public static void main(String args[]) throws IOException {
String content = Files.readString(Paths.get("D:\\sandbox\\mvn\\my-app\\my-app.iml"));
System.out.print(content);
}
}
PHP has this luxury for decades! ☺
The buffered stream classes are much more performant in practice, so much so that the NIO.2 API includes methods that specifically return these stream classes, in part to encourage you always to use buffered streams in your application.
Here is an example:
Path path = Paths.get("/myfolder/myfile.ext");
try (BufferedReader reader = Files.newBufferedReader(path)) {
// Read from the stream
String currentLine = null;
while ((currentLine = reader.readLine()) != null)
//do your code here
} catch (IOException e) {
// Handle file I/O exception...
}
You can replace this code
BufferedReader reader = Files.newBufferedReader(path);
with
BufferedReader br = new BufferedReader(new FileReader("/myfolder/myfile.ext"));
I recommend this article to learn the main uses of Java NIO and IO.
Using BufferedReader:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
BufferedReader br;
try {
br = new BufferedReader(new FileReader("/fileToRead.txt"));
try {
String x;
while ( (x = br.readLine()) != null ) {
// Printing out each line in the file
System.out.println(x);
}
}
catch (IOException e) {
e.printStackTrace();
}
}
catch (FileNotFoundException e) {
System.out.println(e);
e.printStackTrace();
}
This is basically the exact same as Jesus Ramos' answer, except with File instead of FileReader plus iteration to step through the contents of the file.
Scanner in = new Scanner(new File("filename.txt"));
while (in.hasNext()) { // Iterates each line in the file
String line = in.nextLine();
// Do something with line
}
in.close(); // Don't forget to close resource leaks
... throws FileNotFoundException
Probably not as fast as with buffered I/O, but quite terse:
String content;
try (Scanner scanner = new Scanner(textFile).useDelimiter("\\Z")) {
content = scanner.next();
}
The \Z pattern tells the Scanner that the delimiter is EOF.
The most simple way to read data from a file in Java is making use of the File class to read the file and the Scanner class to read the content of the file.
public static void main(String args[])throws Exception
{
File f = new File("input.txt");
takeInputIn2DArray(f);
}
public static void takeInputIn2DArray(File f) throws Exception
{
Scanner s = new Scanner(f);
int a[][] = new int[20][20];
for(int i=0; i<20; i++)
{
for(int j=0; j<20; j++)
{
a[i][j] = s.nextInt();
}
}
}
PS: Don't forget to import java.util.*; for Scanner to work.
You can use readAllLines and the join method to get whole file content in one line:
String str = String.join("\n",Files.readAllLines(Paths.get("e:\\text.txt")));
It uses UTF-8 encoding by default, which reads ASCII data correctly.
Also you can use readAllBytes:
String str = new String(Files.readAllBytes(Paths.get("e:\\text.txt")), StandardCharsets.UTF_8);
I think readAllBytes is faster and more precise, because it does not replace new line with \n and also new line may be \r\n. It is depending on your needs which one is suitable.
I don't see it mentioned yet in the other answers so far. But if "Best" means speed, then the new Java I/O (NIO) might provide the fastest preformance, but not always the easiest to figure out for someone learning.
http://download.oracle.com/javase/tutorial/essential/io/file.html
Guava provides a one-liner for this:
import com.google.common.base.Charsets;
import com.google.common.io.Files;
String contents = Files.toString(filePath, Charsets.UTF_8);
Cactoos give you a declarative one-liner:
new TextOf(new File("a.txt")).asString();
This might not be the exact answer to the question. It's just another way of reading a file where you do not explicitly specify the path to your file in your Java code and instead, you read it as a command-line argument.
With the following code,
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class InputReader{
public static void main(String[] args)throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s="";
while((s=br.readLine())!=null){
System.out.println(s);
}
}
}
just go ahead and run it with:
java InputReader < input.txt
This would read the contents of the input.txt and print it to the your console.
You can also make your System.out.println() to write to a specific file through the command line as follows:
java InputReader < input.txt > output.txt
This would read from input.txt and write to output.txt.
For JSF-based Maven web applications, just use ClassLoader and the Resources folder to read in any file you want:
Put any file you want to read in the Resources folder.
Put the Apache Commons IO dependency into your POM:
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-io</artifactId>
<version>1.3.2</version>
</dependency>
Use the code below to read it (e.g. below is reading in a .json file):
String metadata = null;
FileInputStream inputStream;
try {
ClassLoader loader = Thread.currentThread().getContextClassLoader();
inputStream = (FileInputStream) loader
.getResourceAsStream("/metadata.json");
metadata = IOUtils.toString(inputStream);
inputStream.close();
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return metadata;
You can do the same for text files, .properties files, XSD schemas, etc.
try {
File f = new File("filename.txt");
Scanner r = new Scanner(f);
while (r.hasNextLine()) {
String data = r.nextLine();
JOptionPane.showMessageDialog(data);
}
r.close();
} catch (FileNotFoundException ex) {
JOptionPane.showMessageDialog("Error occurred");
ex.printStackTrace();
}
Use Java kiss if this is about simplicity of structure:
import static kiss.API.*;
class App {
void run() {
String line;
try (Close in = inOpen("file.dat")) {
while ((line = readLine()) != null) {
println(line);
}
}
}
}
import java.util.stream.Stream;
import java.nio.file.*;
import java.io.*;
class ReadFile {
public static void main(String[] args) {
String filename = "Test.txt";
try(Stream<String> stream = Files.lines(Paths.get(filename))) {
stream.forEach(System.out:: println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Just use java 8 Stream.
In case you have a large file you can use Apache Commons IO to process the file iteratively without exhausting the available memory.
try (LineIterator it = FileUtils.lineIterator(theFile, "UTF-8")) {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
}
try (Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))) {
stream.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
new File(<path_name>)
Creates a new File instance by converting the given pathname string into an abstract pathname. If the given string is the empty string, then the result is the empty abstract pathname.
Params:
pathname – A pathname string
Throws:
NullPointerException – If the pathname argument is null
Files.lines returns a stream of String
Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))
can throw nullPointerExcetion , FileNotFoundException so, keepint it inside try will take care of Exception in runtime
stream.forEach(System.out::println);
This is used to iterate over the stream and print in console
If you have different use case you can provide your custome function to manipulate the stream of lines
My new favorite approach to simply read a whole text file from a BufferedReader input goes:
String text = input.lines().collect(Collectors.joining(System.lineSeparator())));
This will read the whole file by adding new line (lineSeparator) behind each line. Without the separator it would join all lines together as one.
This appears to have existed since Java 8.
For Android developers ending up here (who use Kotlin):
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val text = myFileUrl.readText() // Not recommended for huge files
println(text)
Other solution:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
val lines = file.readLines() // Not recommended for huge files
lines.forEach(::println)
Another good solution which can be used for huge files as well:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file
.bufferedReader()
.lineSequence()
.forEach(::println)
Or:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file.useLines { lines ->
lines.forEach(::println)
}
Notes:
The vegetables.txt file should be in your classpath (for example, in src/main/resources directory)
The above solutions all treat the file encodings as UTF-8 by default. You can specify your desired encoding as the argument for the functions.
The above solutions do not need any further action like closing the files or readers. They are automatically taken care of by the Kotlin standard library.
It seems there are different ways to read and write data of files in Java.
I want to read ASCII data from a file. What are the possible ways and their differences?
My favorite way to read a small file is to use a BufferedReader and a StringBuilder. It is very simple and to the point (though not particularly effective, but good enough for most cases):
BufferedReader br = new BufferedReader(new FileReader("file.txt"));
try {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
} finally {
br.close();
}
Some has pointed out that after Java 7 you should use try-with-resources (i.e. auto close) features:
try(BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
}
When I read strings like this, I usually want to do some string handling per line anyways, so then I go for this implementation.
Though if I want to actually just read a file into a String, I always use Apache Commons IO with the class IOUtils.toString() method. You can have a look at the source here:
http://www.docjar.com/html/api/org/apache/commons/io/IOUtils.java.html
FileInputStream inputStream = new FileInputStream("foo.txt");
try {
String everything = IOUtils.toString(inputStream);
} finally {
inputStream.close();
}
And even simpler with Java 7:
try(FileInputStream inputStream = new FileInputStream("foo.txt")) {
String everything = IOUtils.toString(inputStream);
// do something with everything string
}
ASCII is a TEXT file so you would use Readers for reading. Java also supports reading from a binary file using InputStreams. If the files being read are huge then you would want to use a BufferedReader on top of a FileReader to improve read performance.
Go through this article on how to use a Reader
I'd also recommend you download and read this wonderful (yet free) book called Thinking In Java
In Java 7:
new String(Files.readAllBytes(...))
(docs)
or
Files.readAllLines(...)
(docs)
In Java 8:
Files.lines(..).forEach(...)
(docs)
The easiest way is to use the Scanner class in Java and the FileReader object. Simple example:
Scanner in = new Scanner(new FileReader("filename.txt"));
Scanner has several methods for reading in strings, numbers, etc... You can look for more information on this on the Java documentation page.
For example reading the whole content into a String:
StringBuilder sb = new StringBuilder();
while(in.hasNext()) {
sb.append(in.next());
}
in.close();
outString = sb.toString();
Also if you need a specific encoding you can use this instead of FileReader:
new InputStreamReader(new FileInputStream(fileUtf8), StandardCharsets.UTF_8)
Here is a simple solution:
String content = new String(Files.readAllBytes(Paths.get("sample.txt")));
Or to read as list:
List<String> content = Files.readAllLines(Paths.get("sample.txt"))
Here's another way to do it without using external libraries:
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public String readFile(String filename)
{
String content = null;
File file = new File(filename); // For example, foo.txt
FileReader reader = null;
try {
reader = new FileReader(file);
char[] chars = new char[(int) file.length()];
reader.read(chars);
content = new String(chars);
reader.close();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(reader != null){
reader.close();
}
}
return content;
}
I had to benchmark the different ways. I shall comment on my findings but, in short, the fastest way is to use a plain old BufferedInputStream over a FileInputStream. If many files must be read then three threads will reduce the total execution time to roughly half, but adding more threads will progressively degrade performance until making it take three times longer to complete with twenty threads than with just one thread.
The assumption is that you must read a file and do something meaningful with its contents. In the examples here is reading lines from a log and count the ones which contain values that exceed a certain threshold. So I am assuming that the one-liner Java 8 Files.lines(Paths.get("/path/to/file.txt")).map(line -> line.split(";")) is not an option.
I tested on Java 1.8, Windows 7 and both SSD and HDD drives.
I wrote six different implementations:
rawParse: Use BufferedInputStream over a FileInputStream and then cut lines reading byte by byte. This outperformed any other single-thread approach, but it may be very inconvenient for non-ASCII files.
lineReaderParse: Use a BufferedReader over a FileReader, read line by line, split lines by calling String.split(). This is approximatedly 20% slower that rawParse.
lineReaderParseParallel: This is the same as lineReaderParse, but it uses several threads. This is the fastest option overall in all cases.
nioFilesParse: Use java.nio.files.Files.lines()
nioAsyncParse: Use an AsynchronousFileChannel with a completion handler and a thread pool.
nioMemoryMappedParse: Use a memory-mapped file. This is really a bad idea yielding execution times at least three times longer than any other implementation.
These are the average times for reading 204 files of 4 MB each on an quad-core i7 and SSD drive. The files are generated on the fly to avoid disk caching.
rawParse 11.10 sec
lineReaderParse 13.86 sec
lineReaderParseParallel 6.00 sec
nioFilesParse 13.52 sec
nioAsyncParse 16.06 sec
nioMemoryMappedParse 37.68 sec
I found a difference smaller than I expected between running on an SSD or an HDD drive being the SSD approximately 15% faster. This may be because the files are generated on an unfragmented HDD and they are read sequentially, therefore the spinning drive can perform nearly as an SSD.
I was surprised by the low performance of the nioAsyncParse implementation. Either I have implemented something in the wrong way or the multi-thread implementation using NIO and a completion handler performs the same (or even worse) than a single-thread implementation with the java.io API. Moreover the asynchronous parse with a CompletionHandler is much longer in lines of code and tricky to implement correctly than a straight implementation on old streams.
Now the six implementations followed by a class containing them all plus a parametrizable main() method that allows to play with the number of files, file size and concurrency degree. Note that the size of the files varies plus minus 20%. This is to avoid any effect due to all the files being of exactly the same size.
rawParse
public void rawParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
overrunCount = 0;
final int dl = (int) ';';
StringBuffer lineBuffer = new StringBuffer(1024);
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileInputStream fin = new FileInputStream(fl);
BufferedInputStream bin = new BufferedInputStream(fin);
int character;
while((character=bin.read())!=-1) {
if (character==dl) {
// Here is where something is done with each line
doSomethingWithRawLine(lineBuffer.toString());
lineBuffer.setLength(0);
}
else {
lineBuffer.append((char) character);
}
}
bin.close();
fin.close();
}
}
public final void doSomethingWithRawLine(String line) throws ParseException {
// What to do for each line
int fieldNumber = 0;
final int len = line.length();
StringBuffer fieldBuffer = new StringBuffer(256);
for (int charPos=0; charPos<len; charPos++) {
char c = line.charAt(charPos);
if (c==DL0) {
String fieldValue = fieldBuffer.toString();
if (fieldValue.length()>0) {
switch (fieldNumber) {
case 0:
Date dt = fmt.parse(fieldValue);
fieldNumber++;
break;
case 1:
double d = Double.parseDouble(fieldValue);
fieldNumber++;
break;
case 2:
int t = Integer.parseInt(fieldValue);
fieldNumber++;
break;
case 3:
if (fieldValue.equals("overrun"))
overrunCount++;
break;
}
}
fieldBuffer.setLength(0);
}
else {
fieldBuffer.append(c);
}
}
}
lineReaderParse
public void lineReaderParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
String line;
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null)
doSomethingWithLine(line);
brd.close();
frd.close();
}
}
public final void doSomethingWithLine(String line) throws ParseException {
// Example of what to do for each line
String[] fields = line.split(";");
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
lineReaderParseParallel
public void lineReaderParseParallel(final String targetDir, final int numberOfFiles, final int degreeOfParalelism) throws IOException, ParseException, InterruptedException {
Thread[] pool = new Thread[degreeOfParalelism];
int batchSize = numberOfFiles / degreeOfParalelism;
for (int b=0; b<degreeOfParalelism; b++) {
pool[b] = new LineReaderParseThread(targetDir, b*batchSize, b*batchSize+b*batchSize);
pool[b].start();
}
for (int b=0; b<degreeOfParalelism; b++)
pool[b].join();
}
class LineReaderParseThread extends Thread {
private String targetDir;
private int fileFrom;
private int fileTo;
private DateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
private int overrunCounter = 0;
public LineReaderParseThread(String targetDir, int fileFrom, int fileTo) {
this.targetDir = targetDir;
this.fileFrom = fileFrom;
this.fileTo = fileTo;
}
private void doSomethingWithTheLine(String line) throws ParseException {
String[] fields = line.split(DL);
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCounter++;
}
#Override
public void run() {
String line;
for (int f=fileFrom; f<fileTo; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
try {
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null) {
doSomethingWithTheLine(line);
}
brd.close();
frd.close();
} catch (IOException | ParseException ioe) { }
}
}
}
nioFilesParse
public void nioFilesParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
for (int f=0; f<numberOfFiles; f++) {
Path ph = Paths.get(targetDir+filenamePreffix+String.valueOf(f)+".txt");
Consumer<String> action = new LineConsumer();
Stream<String> lines = Files.lines(ph);
lines.forEach(action);
lines.close();
}
}
class LineConsumer implements Consumer<String> {
#Override
public void accept(String line) {
// What to do for each line
String[] fields = line.split(DL);
if (fields.length>1) {
try {
Date dt = fmt.parse(fields[0]);
}
catch (ParseException e) {
}
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
}
}
nioAsyncParse
public void nioAsyncParse(final String targetDir, final int numberOfFiles, final int numberOfThreads, final int bufferSize) throws IOException, ParseException, InterruptedException {
ScheduledThreadPoolExecutor pool = new ScheduledThreadPoolExecutor(numberOfThreads);
ConcurrentLinkedQueue<ByteBuffer> byteBuffers = new ConcurrentLinkedQueue<ByteBuffer>();
for (int b=0; b<numberOfThreads; b++)
byteBuffers.add(ByteBuffer.allocate(bufferSize));
for (int f=0; f<numberOfFiles; f++) {
consumerThreads.acquire();
String fileName = targetDir+filenamePreffix+String.valueOf(f)+".txt";
AsynchronousFileChannel channel = AsynchronousFileChannel.open(Paths.get(fileName), EnumSet.of(StandardOpenOption.READ), pool);
BufferConsumer consumer = new BufferConsumer(byteBuffers, fileName, bufferSize);
channel.read(consumer.buffer(), 0l, channel, consumer);
}
consumerThreads.acquire(numberOfThreads);
}
class BufferConsumer implements CompletionHandler<Integer, AsynchronousFileChannel> {
private ConcurrentLinkedQueue<ByteBuffer> buffers;
private ByteBuffer bytes;
private String file;
private StringBuffer chars;
private int limit;
private long position;
private DateFormat frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
public BufferConsumer(ConcurrentLinkedQueue<ByteBuffer> byteBuffers, String fileName, int bufferSize) {
buffers = byteBuffers;
bytes = buffers.poll();
if (bytes==null)
bytes = ByteBuffer.allocate(bufferSize);
file = fileName;
chars = new StringBuffer(bufferSize);
frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
limit = bufferSize;
position = 0l;
}
public ByteBuffer buffer() {
return bytes;
}
#Override
public synchronized void completed(Integer result, AsynchronousFileChannel channel) {
if (result!=-1) {
bytes.flip();
final int len = bytes.limit();
int i = 0;
try {
for (i = 0; i < len; i++) {
byte by = bytes.get();
if (by=='\n') {
// ***
// The code used to process the line goes here
chars.setLength(0);
}
else {
chars.append((char) by);
}
}
}
catch (Exception x) {
System.out.println(
"Caught exception " + x.getClass().getName() + " " + x.getMessage() +
" i=" + String.valueOf(i) + ", limit=" + String.valueOf(len) +
", position="+String.valueOf(position));
}
if (len==limit) {
bytes.clear();
position += len;
channel.read(bytes, position, channel, this);
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
#Override
public void failed(Throwable e, AsynchronousFileChannel channel) {
}
};
FULL RUNNABLE IMPLEMENTATION OF ALL CASES
https://github.com/sergiomt/javaiobenchmark/blob/master/FileReadBenchmark.java
Here are the three working and tested methods:
Using BufferedReader
package io;
import java.io.*;
public class ReadFromFile2 {
public static void main(String[] args)throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
BufferedReader br = new BufferedReader(new FileReader(file));
String st;
while((st=br.readLine()) != null){
System.out.println(st);
}
}
}
Using Scanner
package io;
import java.io.File;
import java.util.Scanner;
public class ReadFromFileUsingScanner {
public static void main(String[] args) throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
while(sc.hasNextLine()){
System.out.println(sc.nextLine());
}
}
}
Using FileReader
package io;
import java.io.*;
public class ReadingFromFile {
public static void main(String[] args) throws Exception {
FileReader fr = new FileReader("C:\\Users\\pankaj\\Desktop\\test.java");
int i;
while ((i=fr.read()) != -1){
System.out.print((char) i);
}
}
}
Read the entire file without a loop using the Scanner class
package io;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class ReadingEntireFileWithoutLoop {
public static void main(String[] args) throws FileNotFoundException {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
sc.useDelimiter("\\Z");
System.out.println(sc.next());
}
}
The methods within org.apache.commons.io.FileUtils may also be very handy, e.g.:
/**
* Reads the contents of a file line by line to a List
* of Strings using the default encoding for the VM.
*/
static List readLines(File file)
I documented 15 ways to read a file in Java and then tested them for speed with various file sizes - from 1 KB to 1 GB and here are the top three ways to do this:
java.nio.file.Files.readAllBytes()
Tested to work in Java 7, 8, and 9.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
public class ReadFile_Files_ReadAllBytes {
public static void main(String [] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
byte [] fileBytes = Files.readAllBytes(file.toPath());
char singleChar;
for(byte b : fileBytes) {
singleChar = (char) b;
System.out.print(singleChar);
}
}
}
java.io.BufferedReader.readLine()
Tested to work in Java 7, 8, 9.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class ReadFile_BufferedReader_ReadLine {
public static void main(String [] args) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
FileReader fileReader = new FileReader(fileName);
try (BufferedReader bufferedReader = new BufferedReader(fileReader)) {
String line;
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
}
}
}
}
java.nio.file.Files.lines()
This was tested to work in Java 8 and 9 but won't work in Java 7 because of the lambda expression requirement.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.util.stream.Stream;
public class ReadFile_Files_Lines {
public static void main(String[] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
try (Stream linesStream = Files.lines(file.toPath())) {
linesStream.forEach(line -> {
System.out.println(line);
});
}
}
}
What do you want to do with the text? Is the file small enough to fit into memory? I would try to find the simplest way to handle the file for your needs. The FileUtils library is very handle for this.
for(String line: FileUtils.readLines("my-text-file"))
System.out.println(line);
Below is a one-liner of doing it in the Java 8 way. Assuming text.txt file is in the root of the project directory of the Eclipse.
Files.lines(Paths.get("text.txt")).collect(Collectors.toList());
The most intuitive method is introduced in Java 11 Files.readString
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
public class App {
public static void main(String args[]) throws IOException {
String content = Files.readString(Paths.get("D:\\sandbox\\mvn\\my-app\\my-app.iml"));
System.out.print(content);
}
}
PHP has this luxury for decades! ☺
The buffered stream classes are much more performant in practice, so much so that the NIO.2 API includes methods that specifically return these stream classes, in part to encourage you always to use buffered streams in your application.
Here is an example:
Path path = Paths.get("/myfolder/myfile.ext");
try (BufferedReader reader = Files.newBufferedReader(path)) {
// Read from the stream
String currentLine = null;
while ((currentLine = reader.readLine()) != null)
//do your code here
} catch (IOException e) {
// Handle file I/O exception...
}
You can replace this code
BufferedReader reader = Files.newBufferedReader(path);
with
BufferedReader br = new BufferedReader(new FileReader("/myfolder/myfile.ext"));
I recommend this article to learn the main uses of Java NIO and IO.
Using BufferedReader:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
BufferedReader br;
try {
br = new BufferedReader(new FileReader("/fileToRead.txt"));
try {
String x;
while ( (x = br.readLine()) != null ) {
// Printing out each line in the file
System.out.println(x);
}
}
catch (IOException e) {
e.printStackTrace();
}
}
catch (FileNotFoundException e) {
System.out.println(e);
e.printStackTrace();
}
This is basically the exact same as Jesus Ramos' answer, except with File instead of FileReader plus iteration to step through the contents of the file.
Scanner in = new Scanner(new File("filename.txt"));
while (in.hasNext()) { // Iterates each line in the file
String line = in.nextLine();
// Do something with line
}
in.close(); // Don't forget to close resource leaks
... throws FileNotFoundException
Probably not as fast as with buffered I/O, but quite terse:
String content;
try (Scanner scanner = new Scanner(textFile).useDelimiter("\\Z")) {
content = scanner.next();
}
The \Z pattern tells the Scanner that the delimiter is EOF.
The most simple way to read data from a file in Java is making use of the File class to read the file and the Scanner class to read the content of the file.
public static void main(String args[])throws Exception
{
File f = new File("input.txt");
takeInputIn2DArray(f);
}
public static void takeInputIn2DArray(File f) throws Exception
{
Scanner s = new Scanner(f);
int a[][] = new int[20][20];
for(int i=0; i<20; i++)
{
for(int j=0; j<20; j++)
{
a[i][j] = s.nextInt();
}
}
}
PS: Don't forget to import java.util.*; for Scanner to work.
You can use readAllLines and the join method to get whole file content in one line:
String str = String.join("\n",Files.readAllLines(Paths.get("e:\\text.txt")));
It uses UTF-8 encoding by default, which reads ASCII data correctly.
Also you can use readAllBytes:
String str = new String(Files.readAllBytes(Paths.get("e:\\text.txt")), StandardCharsets.UTF_8);
I think readAllBytes is faster and more precise, because it does not replace new line with \n and also new line may be \r\n. It is depending on your needs which one is suitable.
I don't see it mentioned yet in the other answers so far. But if "Best" means speed, then the new Java I/O (NIO) might provide the fastest preformance, but not always the easiest to figure out for someone learning.
http://download.oracle.com/javase/tutorial/essential/io/file.html
Guava provides a one-liner for this:
import com.google.common.base.Charsets;
import com.google.common.io.Files;
String contents = Files.toString(filePath, Charsets.UTF_8);
Cactoos give you a declarative one-liner:
new TextOf(new File("a.txt")).asString();
This might not be the exact answer to the question. It's just another way of reading a file where you do not explicitly specify the path to your file in your Java code and instead, you read it as a command-line argument.
With the following code,
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class InputReader{
public static void main(String[] args)throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s="";
while((s=br.readLine())!=null){
System.out.println(s);
}
}
}
just go ahead and run it with:
java InputReader < input.txt
This would read the contents of the input.txt and print it to the your console.
You can also make your System.out.println() to write to a specific file through the command line as follows:
java InputReader < input.txt > output.txt
This would read from input.txt and write to output.txt.
For JSF-based Maven web applications, just use ClassLoader and the Resources folder to read in any file you want:
Put any file you want to read in the Resources folder.
Put the Apache Commons IO dependency into your POM:
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-io</artifactId>
<version>1.3.2</version>
</dependency>
Use the code below to read it (e.g. below is reading in a .json file):
String metadata = null;
FileInputStream inputStream;
try {
ClassLoader loader = Thread.currentThread().getContextClassLoader();
inputStream = (FileInputStream) loader
.getResourceAsStream("/metadata.json");
metadata = IOUtils.toString(inputStream);
inputStream.close();
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return metadata;
You can do the same for text files, .properties files, XSD schemas, etc.
try {
File f = new File("filename.txt");
Scanner r = new Scanner(f);
while (r.hasNextLine()) {
String data = r.nextLine();
JOptionPane.showMessageDialog(data);
}
r.close();
} catch (FileNotFoundException ex) {
JOptionPane.showMessageDialog("Error occurred");
ex.printStackTrace();
}
Use Java kiss if this is about simplicity of structure:
import static kiss.API.*;
class App {
void run() {
String line;
try (Close in = inOpen("file.dat")) {
while ((line = readLine()) != null) {
println(line);
}
}
}
}
import java.util.stream.Stream;
import java.nio.file.*;
import java.io.*;
class ReadFile {
public static void main(String[] args) {
String filename = "Test.txt";
try(Stream<String> stream = Files.lines(Paths.get(filename))) {
stream.forEach(System.out:: println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Just use java 8 Stream.
In case you have a large file you can use Apache Commons IO to process the file iteratively without exhausting the available memory.
try (LineIterator it = FileUtils.lineIterator(theFile, "UTF-8")) {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
}
try (Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))) {
stream.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
new File(<path_name>)
Creates a new File instance by converting the given pathname string into an abstract pathname. If the given string is the empty string, then the result is the empty abstract pathname.
Params:
pathname – A pathname string
Throws:
NullPointerException – If the pathname argument is null
Files.lines returns a stream of String
Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))
can throw nullPointerExcetion , FileNotFoundException so, keepint it inside try will take care of Exception in runtime
stream.forEach(System.out::println);
This is used to iterate over the stream and print in console
If you have different use case you can provide your custome function to manipulate the stream of lines
My new favorite approach to simply read a whole text file from a BufferedReader input goes:
String text = input.lines().collect(Collectors.joining(System.lineSeparator())));
This will read the whole file by adding new line (lineSeparator) behind each line. Without the separator it would join all lines together as one.
This appears to have existed since Java 8.
For Android developers ending up here (who use Kotlin):
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val text = myFileUrl.readText() // Not recommended for huge files
println(text)
Other solution:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
val lines = file.readLines() // Not recommended for huge files
lines.forEach(::println)
Another good solution which can be used for huge files as well:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file
.bufferedReader()
.lineSequence()
.forEach(::println)
Or:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file.useLines { lines ->
lines.forEach(::println)
}
Notes:
The vegetables.txt file should be in your classpath (for example, in src/main/resources directory)
The above solutions all treat the file encodings as UTF-8 by default. You can specify your desired encoding as the argument for the functions.
The above solutions do not need any further action like closing the files or readers. They are automatically taken care of by the Kotlin standard library.
I have a text file with several lines
Category: Type of problem you're having
Description: Overview of the problem
How To Fix: Directions to fix your problem (has carriage
returns, sometimes)
Related Links: Additional Resources
**There are no numbers in my list; it was the only way I could think of to make it neater...*
I've been trying to get my code to recognize all of the information between "How To Fix:" and "Related Links" when it has more than one line. I know from my research that I have to use either (?s) or Pattern.DOTALL, however neither of them seem to be working. I'm fairly new to Regex, so I'm expect is something elementary. Here is my code:
String fileName = System.getProperty("user.home") + "/Desktop/Test.txt";
try {
FileReader fr = new FileReader(fileName);
BufferedReader br = new BufferedReader(fr);
sc1 = new Scanner(br);
String findingRegex = "(Description:.*)";
String recommRegex = "(?<=How To Fix:)(.*)(?=Related Links)";//regex I'm trying to use
Pattern pFinding = Pattern.compile(findingRegex);
Pattern pRecomm = Pattern.compile(recommRegex, Pattern.DOTALL);
while (sc1.hasNextLine()) {
String clean = sc1.nextLine().trim();
String clean2 = clean.replaceAll("\\\\x\\p{XDigit}{2}", "");
Matcher mFinding = pFinding.matcher(clean2);
Matcher mRecomm = pRecomm.matcher(clean2);
while (mFinding.find()) {
System.out.println(mFinding);
}
while (mRecomm.find()){
System.out.println(mRecomm); //nothing prints?
}
}
br.close();
fr.close();
System.out.println("The following data was imported: ");
try {
tbl.displayAll();
} catch (NullPointerException npe) {
System.out.println("You have no data.");
}
} catch (FileNotFoundException fnfe) {
System.out.println("File named Test.txt was not located on your desktop. Program Terminated.");
System.exit(0);
} catch (IOException ioe) {
System.out.println("The import operation failed. Program Terminated");
System.exit(0);
} finally {
sc1.close();
}
Lastly, I tested my Regex here and it worked as expected?
MY SOLUTION:
String findingRegex = "(?<=Description:)(.*)(?=How To Fix)";
String recommRegex = "(?<=How To Fix:)(.*)(?=Related Links)";
Pattern pFinding = Pattern.compile(findingRegex, Pattern.DOTALL);
Pattern pRecomm = Pattern.compile(recommRegex, Pattern.DOTALL);
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null){
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String newFile = sb.toString();
Matcher mFinding = pFinding.matcher(newFile);
Matcher mRecomm = pRecomm.matcher(newFile);
while (mFinding.find()) {
System.out.println(mFinding);
}
while (mRecomm.find()){
System.out.println(mRecomm);
}
Here:
String clean = sc1.nextLine().trim();
You are breaking your input up by line. But then you're trying to match multiple lines. There aren't multiple lines to match, because you only kept the one.
You could read the entire file into memory first, and then match against it. Or you could do something like
StringBuilder sb = new StringBuilder();
int state = 0;
while (sc1.hasNextLine()) {
String line = sc1.nextLine();
if (line.contains("How To Fix:")) {
state = 1;
}
if (state == 1) {
sb.append(line);
}
if (line.contains("Related Links:")) {
state = 0;
}
}
(You'll need to modify this if you need to match more than once per file.)
I am implementing a RPN calculator in Java and need help creating a class to parse the equations into separate tokens.
My input file will have an unknown number of equations similar to the ones shown below:
49+62*61-36
4/64
(53+26)
0*72
21-85+75-85
90*76-50+67
46*89-15
34/83-38
20/76/14+92-15
I have already implemented my own generic stack class to be used in the program, but I am now trying to figure out how to read data from the input file. Any help appreciated.
I've posted the source code for my stack class at PasteBin, in case it may help.
I have also uploaded the Calculator with no filereading to PasteBin to show what I have done already.
I have now managed to get the file read in and the tokens broken up thanks for the help. I am getting an error when it reaches the end of the file and was wondering how to solve that?
Here is the code:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.StringTokenizer;
public class TestClass {
static public void main(String[] args) throws IOException {
File file = new File("testEquations.txt");
String[] lines = new String[10];
try {
FileReader reader = new FileReader(file);
BufferedReader buffReader = new BufferedReader(reader);
int x = 0;
String s;
while((s = buffReader.readLine()) != null){
lines[x] = s;
x++;
}
}
catch(IOException e){
System.exit(0);
}
String OPERATORS = "+-*/()";
for (String st : lines) {
StringTokenizer tokens = new StringTokenizer(st, OPERATORS, true);
while (tokens.hasMoreTokens()) {
String token = tokens.nextToken();
if (OPERATORS.contains(token))
handleOperator(token);
else
handleNumber(token);
}
}
}
private static void handleNumber(String token) {
System.out.println(""+token);
}
private static void handleOperator(String token) {
System.out.println(""+token);
}
}
Also How would I make sure the RPN works line by line? I am getting quite confused by the algorithms I am trying to follow.
Because all of the operators are single characters, you can instruct StringTokenizer to return them along with the numeric tokens.
String OPERATORS = "+-*/()";
String[] lines = ...
for (String line : lines) {
StringTokenizer tokens = new StringTokenizer(line, OPERATORS, true);
while (tokens.hasMoreTOkens()) {
String token = tokens.nextToken();
if (OPERATORS.contains(token))
handleOperator(token);
else
handleNumber(token);
}
}
As your question has now changed completely from it's original version - this is in response to your original one, which was how to use FileReader to get the values from your file.
This will put each line into a separate element of a String array. You should probably use an ArrayList instead, as it's far more flexible, but I have just done this as a quick demo - you can clean it up as you wish, although I notice the code you are using expects a String array as it's input. Perhaps you could read the values initially into an ArrayList, then copy that to an array once you have all the lines - that way you can put as many lines in as you wish and keep your code flexible for changes in the number of lines in your input file.
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public class TestClass {
static public void main(String[] args) {
File file = new File("myfile.txt");
String[] lines = new String[10];
try {
FileReader reader = new FileReader(file);
BufferedReader buffReader = new BufferedReader(reader);
int x = 0;
String s;
while((s = buffReader.readLine()) != null){
lines[x] = s;
x++;
}
}
catch(IOException e){
//handle exception
}
// And just to prove we have the lines right where we want them..
for(String st: lines)
System.out.println(st);
}
}
You mentioned before that you were using the code on this link:
http://www.technical-recipes.com/2011/a-mathematical-expression-parser-in-java/#more-1658
This appears to already deal with operator precedence doesn't it? And with parsing each String from the array and sorting them into numbers or operators? From my quick look it at least it appears to do that.
So it looks like all you need is for your lines to be in a String array, which you then pass to the code you already have. From what I can see anyway.
Obviously this doesn't address the issue of numbers greater than 9, but hopefully it helps with the first half.
:-)
public void actionPerformed(ActionEvent e) {
double sum=0;
int count = 0 ;
try {
String nomFichier = "Fichier.txt";
FileReader fr = new FileReader(nomFichier);
BufferedReader br = new BufferedReader(fr);
String ligneLue;
do {
ligneLue = br.readLine();
if(ligneLue != null) {
StringTokenizer st = new StringTokenizer(ligneLue, ";");
String nom = st.nextToken();
String prenom = st.nextToken();
String age = st.nextToken();
String tele = st.nextToken();
String adress = st.nextToken();
String codePostal = st.nextToken();
String ville = st.nextToken();
String paye = st.nextToken();
double note = Double.parseDouble(st.nextToken());
count++;
}
}
while(ligneLue != null);
br.close();
double mediane = count / 2;
if(mediane % 2 == 0) {
JOptionPane.showMessageDialog(null, "Le mediane dans le fichier est " + mediane);
}
else {
mediane +=1;
JOptionPane.showMessageDialog(null, "Le mediane dans le fichier est " + mediane);
}
}//fin try
catch(FileNotFoundException ex) {
System.out.println(ex.getMessage());
}
catch(IOException ex) {
System.out.println(ex.getMessage());
}
}