I need to format a decimal value into a string where I always display at lease 2 decimals and at most 4.
So for example
"34.49596" would be "34.4959"
"49.3" would be "49.30"
Can this be done using the String.format command?
Or is there an easier/better way to do this in Java.
Yes you can do it with String.format:
String result = String.format("%.2f", 10.0 / 3.0);
// result: "3.33"
result = String.format("%.3f", 2.5);
// result: "2.500"
You want java.text.DecimalFormat.
DecimalFormat df = new DecimalFormat("0.00##");
String result = df.format(34.4959);
Here is a small code snippet that does the job:
double a = 34.51234;
NumberFormat df = DecimalFormat.getInstance();
df.setMinimumFractionDigits(2);
df.setMaximumFractionDigits(4);
df.setRoundingMode(RoundingMode.DOWN);
System.out.println(df.format(a));
java.text.NumberFormat is probably what you want.
NumberFormat and DecimalFormat are definitely what you want. Also, note the NumberFormat.setRoundingMode() method. You can use it to control how rounding or truncation is applied during formatting.
You want java.text.DecimalFormat
Related
I am trying to format prices using DecimalFormat, but this isn't working for all variations.
DecimalFormat df = new DecimalFormat("0.##")
df.format(7.8)
df.format(85.0)
prints
7.80
and
85
but "7.79999" gets formatted as "7.8", not "7.80". I have tried doing things this way
DecimalFormat df = new DecimalFormat("0.00")
to force two dp, but then "85.0" gets formatted as "85.00" not "85"!
Is there a way of capturing all variations, so that prices are printed either as #, ##, or #.##? For example:
5, 55, 5.55, 5.50, 500, 500.40
There is a slight difference between these two formats. The "#.##" means it will print the number with maximum two decimal places whereas "#.00" means it will always display two decimal places and if the decimal places are less than two, it will replace them with zeros. see the example below with output.
public static final DecimalFormat df1 = new DecimalFormat( "#.##" );
public static final DecimalFormat df2 = new DecimalFormat( "#.00" );
System.out.println(df1.format(7.80));
System.out.println(df1.format(85));
System.out.println(df1.format(85.786));
System.out.println(df2.format(7.80));
System.out.println(df2.format(85));
System.out.println(df2.format(85.786));
And the output will be
7.8
85
85.79
7.80
85.00
85.79
This doesn't seem to be solved by a single formatter. I suggest you use "0.00" format and replace ".00" with an empty string.
public static String myFormat(double number) {
DecimalFormat df = new DecimalFormat("0.00");
return df.format(number).replaceAll("\\.00$", "");
}
I don't think it's possible, at least not with Java SE formatters. You need to make a custom formatter. I would do it like this
String res = df.format(number).replace(".00", "");
Use the BigDecimal number class instead:
e.g. if n is a BigDecimal,
then you can use
String s = NumberFormat.getCurrencyInstance().format(n);
By the way, it's best practice to use BigDecimal when working with money.
You can try with:
DecimalFormat df = new DecimalFormat("#.##",new DecimalFormatSymbols(Locale.US));
System.out.println(new java.text.DecimalFormat("#.##").format(5.00));
This will print 5
System.out.println(new java.text.DecimalFormat("#.00").format(500.401));
This will print 500.40
I have this:
if (inKm)
{
text = String.valueOf(MetricConverter.milesToKilometers(Double.valueOf(text)));
}
This yields a result into a JTextField that is a bit too long for my liking. How do I truncate or use decimalformat on the resulting value? When I used decimalformat within this expression it just bugged out the program.
I like to use this since it's so similar to printf()
double doubleValue = 123.4567895;
String.format("%.2f", doubleValue); // returns "123.46"
Edit: This does not truncate, but rounds half-up.
More info on how to use the String.format(), and java.util.Formatter:
http://docs.oracle.com/javase/7/docs/api/java/util/Formatter.html
I want to convert a number to a 2 decimal places (Always show two decimal places) in runtime. I tried some code but it only does, as shown below
20.03034 >> 20.03
20.3 >> 20.3 ( my code only rounds not converts )
however, I want it to do this:
20.03034 >> 20.03
20.3 >> 20.30 (convert it to two decimal places)
My code below:
angle = a variable
angle_screen = a variable
DecimalFormat df = new DecimalFormat("#.##");
angle = Double.valueOf(df.format(angle));
angle_screen.setText(String.valueOf(angle) + tmp);
Any help on how to do this would be great, thanks.
try this new DecimalFormat("#.00");
update:
double angle = 20.3034;
DecimalFormat df = new DecimalFormat("#.00");
String angleFormated = df.format(angle);
System.out.println(angleFormated); //output 20.30
Your code wasn't using the decimalformat correctly
The 0 in the pattern means an obligatory digit, the # means optional digit.
update 2: check bellow answer
If you want 0.2677 formatted as 0.27 you should use new DecimalFormat("0.00"); otherwise it will be .27
DecimalFormat df=new DecimalFormat("0.00");
Use this code to get exact two decimal points.
Even if the value is 0.0 it will give u 0.00 as output.
Instead if you use:
DecimalFormat df=new DecimalFormat("#.00");
It wont convert 0.2659 into 0.27. You will get an answer like .27.
Try this: String.format("%.2f", angle);
Try
DecimalFormat df = new DecimalFormat("#,##0.00");
I want to round all of my numbers to 1 decimal place.
For example
22.0
-6.1
I am using:
DecimalFormat decimalFormat = new DecimalFormat("0.0");
middlePanelTextView.setText(decimalFormat.format(score.getElevationAngle()));
But whole numbers don't have a 0 appended to it.
-18 should be -18.0 etc.
instead my value shows up as -18.
.# represents a significant digit 0 doesn't.
.# represents and optional digit So try "###.#"
http://developer.android.com/reference/java/text/DecimalFormat.html
I'm not sure about the syntax: but the above article should give you all you need.
Try
middlePanelTextView.setText(""+decimalFormat.format(score.getElevationAngle()));
My TextView was cutting off the digits. My fault. Shrank font size.
Try using
DecimalFormat decimalFormat = new DecimalFormat("#.#");
as the constructor parameter instead.
Try using the following code:
DecimalFormat decimalFormat = new DecimalFormat("0.0#");
I am trying to set decimal values,Below is my input string
String rate="1.000000000";
Converting to double:
Double converted=Double.valueOf(rate);
DecimalFormat format=new DecimalFormat("#.########"); //Setting decimal points to 8
System.out.println("ouput"+format.format(rate)); //Giving output as 1.
I dont understand how to do this,Any hints please.
Regards,
Chaitu
Try
DecimalFormat format=new DecimalFormat("#.00000000");
and
System.out.println("ouput"+format.format(converted));
# will not be displayed for 0, use 0 instead:
String rate="1.010000000";
Double converted=Double.valueOf(rate);
DecimalFormat format=new DecimalFormat("0.00000000");
System.out.println("ouput "+format.format(converted));
Firstly, you're passing the string rate to the DecimalFormat.format method. This will fail, you need to pass the converted object in.
When I tested your code with the above changes, I got 1.01 in the output. To format to 8 decimal places, follow Bala Rs comments. i.e. DecimalFormat format = new DecimalFormat("#.00000000");