Sum two dates in Java - java

How can I add two dates in Java?
Example: The sum of "2010-01-14 19:16:17" "0000-10-03 01:10:05"
would result in "2010-11-17 20:26:22".
I know how to do it using Calendar and adding field by field.
Is any other way to sum them all (year/month/day/hour/minute/second) at once?

If you are using the Date object, you can just do:
Date d1 = ...
Date d2 = ...
long sum = d1.getTime() + d2.getTime();
Date sumDate = new Date(sum);
The code uses the .getTime() method that returns the number of milliseconds since the epoch.
Needless to say the Date class has a lot of problems and should be avoided when possible.
Do you want to sum other types instead?
Update: for Calendar, I would do the following (based on javadocs):
Calendar c1 = ...
Calendar c2 = ...
long sum = c1.getTimeInMillis() + c2.getTimeInMillis();
Calendar sumCalendar = (Calendar)c1.clone();
sumCalendar.setTimeInMillis(sum);
UPDATED: As Steve stated, this works if the Date you presented here assumes that the second date is with respect to the Java epoch. If you do want to start with year "0", then you need to account for that (by subtracting your epoch time).

Don't sum the time in millis of the two dates!
Date d1 = new Date();
Date d2 = new Date();
Date dTotal = new Date(d1.getTime() + d2.getTime());
System.out.println(dTotal); // Incorrect! Misses about 1970 years.
Just clone the Calendar and add the datetime parts one by one.
Calendar c1 = Calendar.getInstance();
Calendar c2 = Calendar.getInstance();
Calendar cTotal = (Calendar) c1.clone();
cTotal.add(Calendar.YEAR, c2.get(Calendar.YEAR));
cTotal.add(Calendar.MONTH, c2.get(Calendar.MONTH) + 1); // Months are zero-based!
cTotal.add(Calendar.DATE, c2.get(Calendar.DATE));
cTotal.add(Calendar.HOUR_OF_DAY, c2.get(Calendar.HOUR_OF_DAY));
cTotal.add(Calendar.MINUTE, c2.get(Calendar.MINUTE));
cTotal.add(Calendar.SECOND, c2.get(Calendar.SECOND));
cTotal.add(Calendar.MILLISECOND, c2.get(Calendar.MILLISECOND));
System.out.println(cTotal.getTime()); // Correct!
Needless to say, JodaTime is smarter and cleaner with this.

As always, I would recommend the Java 8 date/time APIs or Joda for date/time work, since they are much more powerful and intuitive.
You can add durations and periods to a DateTime object trivially. You can add minutes/seconds/months equally easily.
However, you can't add two dates directly, since that doesn't really make sense. This is a powerful illustration of why Joda is a help - it stops you doing stuff that you really shouldn't be doing.

tl;dr
LocalDateTime later =
LocalDateTime
.parse (
"2010-01-14 19:16:17"
.replace ( " " , "T" )
)
.plus( Period.parse ( "P10M3D" ) )
.plus( Duration.parse ( "PT1H10M5S" ) )
;
ISO 8601
The representation of a span-of-time using the same format as a moment is creating confusion. A span is not at all the same as a moment.
Instead of using YYYY-MM-DD HH-MM-SS format for a span of time, I suggest using the standard ISO 8601 format of PnYnMnDTnHnMnS. In this format, the P marks the beginning (for "Period" presumably) and the T separates the years-month-days portion from the hours-minutes-seconds portion.
Example values:
PT1H30M → One and a half hours.
P3Y6M4DT12H30M5S → Three years, six months, four days, twelve hours, thirty minutes, and five seconds.
P10M3DT1H10M5S → Your Question’s duration of 0000-10-03 01:10:05.
java.time
The Question and the other Answers use troublesome old date-time classes now outmoded by the java.time framework built into Java 8 and later. See Oracle Tutorial. Much of the java.time functionality has been back-ported to Java 6 & 7 in ThreeTen-Backport and further adapted to Android in ThreeTenABP.
The java.time classes use ISO 8601 formats by default when parsing and generating Strings that represent date-time values.
The Question does not provide any time zone info, so here we use the LocalDateTime class. If we know an offset-from-UTC we would use the OffsetDateTime class, and if even better we knew a time zone, we would use the ZonedDateTime class.
Spans of time in java.time are divided amongst a pair of classes. Years-months-days are represented by the Period class, and hours-minutes-seconds are handled by the Duration class.
Combining these times, we can indeed perform date-time math. Here we add a span of time to an starting date-time to get a resulting date-time. And we do so in very few lines of code. The result is indeed that expected by the Question.
We convert the input strings to canonical ISO 8601 format by replacing the SPACE in the middle with a T.
LocalDateTime ldt = LocalDateTime.parse ( "2010-01-14 19:16:17".replace ( " " , "T" ) );
//"0000-10-03 01:10:05"
Period period = Period.parse ( "P10M3D" );
Duration duration = Duration.parse ( "PT1H10M5S" );
LocalDateTime result = ldt.plus ( period ).plus ( duration );
Compare to the result expected in the Question.
LocalDateTime expectation = LocalDateTime.parse ( "2010-11-17 20:26:22".replace ( " " , "T" ) );
Boolean isSame = result.equals ( expectation );
Dump to console.
System.out.println ( "ldt: " + ldt + " + period: " + period + " + duration: " + duration + " is result: " + result + " compared to expectation: " + expectation + " is the same: " + isSame );
ldt: 2010-01-14T19:16:17 + period: P10M3D + duration: PT1H10M5S is result: 2010-11-17T20:26:22 compared to expectation: 2010-11-17T20:26:22 is the same: true

You want to do getTimeInMillis() on both those Calendars so you'll have two honest-to-goodness long values you can add up. You can then take the sum and stash it in a new Calendar using that Calendar's setTimeInMillis() method.
Whether you want to add two Calendars as shown above or two Dates as shown in notnoop's answer is up to you, of course. The effect is similar, it just depends on what you want to do with the result. A Date is mostly just good for storing and/or converting to a String for printing out or displaying, whereas a Calendar will let you fiddle with the individual time values should you so choose.
As others have mentioned, you're committing some conceptual no-no's in using a Date or Calendar, which are meant to store "real" dates and times, e.g. ones in the 20th or 21st century, as intervals, i.e. time spans. The classes in the standard Java library don't give you really useful tools to handle this, which is why the Joda classes were developed. All the cool kids in date/time processing use those; but on the other hand that involves downloading and managing a 3rd party library.

notnoop answer is definitely correct. However, if you are going to do lots of processing of dates, times and intervals, I suggest that you look at class DateUtils in apache commons lang and at joda-time library.
JDK7 will come with better support for some of the features that joda-time provides. Just saying ... it might be a consideration if your app makes heavy usage of this stuff.

You need to define your EPOCH. The Java epoch (like Unix) is 1 Jan 1970 GMT/UTC. I assume you think you're adding ten months, 3 days and some odd hours from 1 Jan 0000 but you have a epoch offset until 1970. The maths may not necessarily work.
Use Calendar or Joda (as mentioned). If you just simply want to add a number of seconds and days (&c) then feel free to add said # of milliseconds to your first date object.

Use calendar class add method to add two dates in java.
Calendar calendar=Calendar.getInstance();
calendar.add(Calendar.Date,23);
calendar.add(Calendar.Month,13);
calendar.add(Calendar.Year,15);
By using add method in Calendar class we can add day,month,year to the existing date.
click here for complete program.

I am occasionally guilty of this practice too, storing time interval in a date object and using getTime() as suggested by notnoop.
It works. Contrary to certain opinion, it certainly works. I just ignore that the interval could be representative of an unintended date. It is a quick and dirty way for me to add an interval, say, [6 years, 6 months, 6 days, 6 hours, 6 minutes, 6 seconds] to a date.

Related

Java Convert Interval of Days to Dates

I have a dates in format such as:
- dd. - dd.MM.yyyy
Based on this information I want to receive from date and to date.
Naive implementation in pseudo code is:
Split the date into first part and second part
Create a SimpleDateFormat for second part
Take a look, whether the number in the first part is higher than the number in a second part.
If it is:
Decrement month for the first date
Create from date which will contain the dd from the first part, decremented month from the second part and year from the second part.
If it isn't:
Create from date which will contain the dd from the first part and month and year from second part.
This solution would probably work most of the time, but it feels rather awkward. Isn't there any better solution?
I'd suggest you to check the package
org.joda.time
In particular the following classes
DateTime
Period
java.time
The java.time framework is built into Java 8 and later. Much of that functionality is back-ported to Java 6 & 7 and to Android.
I provide some scraps of example code here, but untested – never run. Should get you going in the right direction.
Two tricky parts to this problem:
YearThe Question says to assign the year. That is not the case for a stop date in January with a start date that turns out to be in previous month, December. You want the previous year in such a case. Solution is to let java.time subtract a month and handle the Jan-to-Dec math for you.
Month lengthVarious months have different lengths, different number of days, obviously. Keep mind that you cannot try to put day-of-month 31 on to month of April. If your input data is always clean and valid, and our algorithm below is correct, this should be a non-issue. Nevertheless, I would certainly add some exception-catching code to my example code below to trap any attempt to form an invalid date.
I'll skip the string-splitting part, and assume you have a number (the day-of-month) from the first part, and a string of the date from the second part.
long dayOfMonth = Long.longValue( "31" );
That date is not in standard format, so we must specify a formatting pattern. A LocalDate represents a date-only value without time-of-day and without time zone.
DateTimeFormatter formatter = DateTimeFormatter.ofPattern( "dd.MM.yyyy" );
LocalDate stop = LocalDate.parse( "21.05.2016" , formatter );
We can extract the day-of-month to compare.
LocalDate start = null;
int d = localDate.getDayOfMonth();
Do the comparison.
if( dayOfMonth >=d ) { // If start is in previous month…
start = stop.minusMonths( 1 ).withDayOfMonth( dayOfMonth );
} else if (dayOfMonth < d ) { // If start is in same month…
start = stop.withDayOfMonth( dayOfMonth );
} else {
// FIXME: handle impossible condition as error. The 'if' statements are flawed.
}
By the way, the format of this input data is awkward and, frankly, silly. This kind of precious “cleverness” creates extra work, gives opportunity for confusion and errors, is completely needless without providing any benefits, and drives me nuts. If you have any control of this input data I strongly suggest either of two possible changes.
First, if exchanging data within your app, do not use strings. Use objects. Above you have seen the LocalDate object. You could pass those around. Or even define your own class LocalDateRange to house a pair of LocalDate objects. Or see this Question and especially this Answer that talks about using the Google Guava class Range to hold the pair of LocalDate objects.
Secondly, when you must serialize date-time values to strings, use the standard ISO 8601 formats. Such use is simple as the java.time classes by default use these formats when parsing/generating strings. A date-only value should be in YYYY-MM-DD order. A date range interval is a pair of those strings mated with a slash (SOLIDUS) or alternatively a pair of hyphens when a slash is inappropriate (such as file or folder naming within a Unix-related file system).

Printing Time and Date in both Universal Time and Standard Time

Writing a Java application that takes user input into a Time and Date class, but I am not sure how to take this user input and convert it into Universal and Standard time... I have spent multiple hours surfing the web and stack overflow and have not been able to find a solution.
I have hours, minutes, seconds, year, month, day all in separate integer variables and need to display them in Universal and Standard time.
Thanks for taking a look...
There are two solutions:
first is place all of input in the string and parse it:
String dateStr = ""
//put your input in this string in some format/ example:
//dateSttr = year + "." + month + "." + day + " " + hour + ":" + minute;
//It is better to use StringBuilder
DateFormat inputFormat = new SimpleDateFormat("yyyy.MM.dd hh:mm");
//note that hh is 12h-format and HH is 24h-format
DateFormat outputFormat1 = new SimpleDateFormat("your_outputFormat");
DateFormat outputFormat2 = new SimpleDateFormat("your_another_outputFormat");
Date date = inputFormat.parse(dateStr);
String o1, o2;
o1 = outputFormat1.format(date);
o2 = outputFormat2.format(date);
//o1 and o2 is your result.
For the rules, how this formats is done, see javadoc
The second solution is to get a new date and set your parameters:
Calendar cln = Calendar.getInstance().clear();
//by default you get a calendar with current system time
//now set the fields. for example, day:
cln.set(Calendar.YEAR, 2015);
cln.set(Calendar.MONTH, Calendar.FEBRUARY);
cln.set(Calendar.DAY_OF_MONTH, 17);
cln.set(Calendar.HOUR_OF_DAY, 18);//Calendar.HOUR for 12h-format
cln.set(Calendar.MINUTE, 27);
See more about setting calendar in javadoc
Note, that in the second variant, you might have some fields undefiend.
If #JonSkeet 's assumption and mine is correct, you're starting with either UTC or your local time. Displaying it is just a matter of formatting your output.
For the other type of time, you add or subtract a number of hours, which you can find on the web. The tricky part is that this may push you into the next calendar day, or pull you back into the previous one. To deal with that, I figure you want to either
implement an adder for year, month, day, hour--or
convert those to decimal somethings (Excel uses days, for instance, where as I write this it's 42328.08813), shift the value by the appropriate number of hours, and convert it back.
java.time
The Answer by TEXHIK is correct, but outdated. Also, as others mentioned, I do not know what you mean by "Universal and Standard time". But I'll try to get you part way there.
As of Java 8, the old java.util.Date/.Calendar classes have been supplanted by the new java.time framework. The new classes are inspired by the highly successful Joda-Time framework, intended as its successor, similar in concept but re-architected. Defined by JSR 310. Extended by the ThreeTen-Extra project. See the Tutorial.
The ZonedDateTime class has a factory method taking numbers for year, month, and so on.
Plus you must specify a time zone. If your numbers represent a date-time in UTC, use the ZoneOffset.UTC constant. For other time zones, specify a ZoneId object by using a proper time zone name; never use the 3-4 letter codes such as EST or IST as their are neither standardized nor unique.
ZoneId zoneId = ZoneId.of( "America/Montreal" );
// ZoneId zoneId = ZoneOffset.UTC; // ZoneOffset is a subclass of ZoneId.
ZonedDateTime zdt = ZonedDateTime.of( 2015 , 1 , 2 , 3 , 4 , 5 , 6 , zoneId );
zdt: 2015-01-02T03:04:05.000000006-05:00[America/Montreal]
You can convert to UTC or another time zone.
ZonedDateTime zdt_Kolkata = zdt.withZoneSameInstant ( ZoneId.of("Asia/Kolkata") );
ZonedDateTime zdt_Utc = zdt.withZoneSameInstant ( ZoneOffset.UTC );
zdt_Kolkata: 2015-01-02T13:34:05.000000006+05:30[Asia/Kolkata]
zdt_Utc: 2015-01-02T08:04:05.000000006Z
If working with classes not yet updated for java.time, convert to a java.util.Date. First extract a Instant object, a moment on the timeline always in UTC.
java.util.Date date = java.util.Date.from ( zdt.toInstant () );

Java Built In Date Manipulation and Comparison

I'm looking to create a datetime stamp, then add 10 hours to it, then have a thread check to see if the time has elapsed.
I read through, Time comparison but it seems a bit complicated/convoluted for something so simple. Especially if your time comparison goes across midnight.
My understanding is that java's underlying datetime, is suppose to be a long, if this is true, is there a simple way to add another long to it, such as the number equivalent of 10 hours? Or some other means such as adding two dates?
Note: The solution needs to be part of core java, can't be part of a 3rd party lib.
You can use a Calendar to perform that math,
Calendar cal = Calendar.getInstance();
cal.add(Calendar.HOUR, 10); // Add 10 hours.
Date date2 = cal.getTime(); // Now plus 10 hours.
Date date = new Date(); // Now.
You can use the Date.getTime() method to obtain the underlying timestamp, the timestamp is basically the number of milliseconds elapsed since a defined base instant (1970-01-01 00:00:00 IIRC).
System.currentTimeMillis() allows you the get the "now" instant directly, without any detours using Date, Calendar and the like.
The timestamp can then be manipulated basic math:
timestamp += TimeUnit.MILLISECONDS.convert(10, TimeUnit.HOURS);
Example of adding 10 hours:
long nowInMilliSince1970 = System.currentTimeMillis();
long tenHoursAsMilli = TimeUnit.MILLISECONDS.convert(10L, TimeUnit.MINUTES);
long tenHoursLater = nowInMilliSince1970 + tenHoursAsMilli;
System.out.println("now in milliseconds: \t\t" + nowInMilliSince1970);
System.out.println("10 hours in milliseconds: \t" + tenHoursAsMilli);
System.out.println("10 hours from now: \t\t" + tenHoursLater);
Checking if the timestamp is in the past is as easy as:
if (timestamp < System.currentTimeMillis()) {
System.out.println("timestamp is in the past");
}
Do note that direct timestamp math has no concept of daylight saving and time zones. If you want that, use a Calendar for math - Calendar implements the dirty exceptional rules for that.
Another way of achieving it using just JDK built in stuff is:
long tenHoursFromNow = System.currentTimeMillis() + TimeUnit.HOURS.toMillis(10);
and then in your Thread you would check:
if(System.currentTimeMillis() > tenHoursFromNow)
{
//Do something as the time has elapsed
}
Although I would argue that the use of Calendar and Date is clearer as to what the intention of your code is trying to achieve.
The bundled java.util.Date and .Calendar are notoriously troublesome. They really should be avoided.
You stated a requirement of no added libraries. So see the java.time part of my answer, using the new package newly added to Java 8. But I urge you to reconsider your reluctance to add a library, especially if you cannot move to Java 8 yet; j.u.Date/Calendar really are that bad.
Both libraries handle anomalies such as Daylight Saving Time.
Consider specifying a time zone rather than rely on the JVM's default. Generally best to work in UTC, and then translate to a local time zone for presentation to the user.
java.time
The java.time package is newly added to Java 8. Inspired by Joda-Time but re-architected. Defined by JSR 310. Extended by the threeten-extra project.
ZonedDateTime tenHoursLater = ZonedDateTime.now().plusHours( 10 );
Joda-Time
Using the Joda-Time 2.3 library.
DateTime tenHoursLater = DateTime.now().plusHours( 10 );
For more info on this kind of use of Joda-Time, see my answer to a similar question.

Best way to convert months into Milliseconds

I'm trying to convert a no of months into milliseconds
For example:
6 months = X milliseconds
There's no fixed answer to that, because it depends on which months those are - and indeed which year it is. Also potentially which time zone you're in, if you want to take account of that. (I'm assuming you mean the Gregorian calendar, by the way - different calendar systems have different month lengths.)
You could get some sort of "reasonable approximation" by assuming 365.25 days in a year, and saying that 6 months is half of that, then find out that many days in milliseconds. But it would only be an approximation.
For "how many milliseconds does it take to get from date/time X to 6 months later" you'd use an API (even Calendar would work for this particular case, although I'd recommend Joda Time or java.time in Java 8):
Set your start date/time, in the appropriate calendar and time zone
Fetch the "milliseconds since the Unix epoch" (which is easy enough to retrieve in any API) and remember it
Add 6 months
Fetch the "milliseconds since the Unix epoch" again, and subtract the earlier value from it
If you know exactly from when to when those 6 months reach, you can use a variety of ways to calculate the duration, using java.util.Calendar, JodaTime, or the JDK1.8 time API.
But if you don't have particular dates in mind, you can take an average duration for your month.
No API in the world can change that fact.
For example, the JDK1.8 time API uses this for the duration of a month in seconds: (from java.time.temporal.ChronoUnit)
MONTHS("Months", Duration.ofSeconds(31556952L / 12)),
31,556,952 is the number of a seconds in a year, based on a year that lasts 365.2425 days.
You can use the same number directly and get the same result as with the time API:
long months = 6;
long seconds = months * 31556952L / 12;
long milliseconds = seconds * 1000;
Result:
15,778,476,000
Calendar today = Calendar.getInstance();
Calendar sixMonthsAhead = Calendar.getInstance();
sixMonthsAhead.add(Calendar.MONTH, 6);
long differenceInMilis = sixMonthsAhead.getTimeInMillis() - today.getTimeInMillis();
You could also use...
sixMonthsAhead.add(Calendar.DATE, 180);
// or 183 days because 365 / 2 is approximately 183.
instead of...
sixMonthsAhead.add(Calendar.MONTH, 6);
for a more accurate result. But like Jon has mentioned, it will always vary depending on what day of the year it is.
The answer by Jon Skeet is correct.
Joda-Time
Assuming you could specify a pair of beginning and ending points on a time line, here is some example code using the Joda-Time 2.3 library.
This code grabs the current moment, adjusts to first of the month, and adjusts to first moment of that day. Then it adds 6 months. Joda-Time is smart about adding the months, taking into account leap year and various lengths of months. This span of 6 months is then represented as an Interval instance. From that we calculate the number of milliseconds. Note that count of milliseconds needs to be a long (64-bit) rather than an int (32-bit) we Java programmers more commonly use. Lastly, for fun, we see what this span of time looks like when formatted in the ISO 8601 standard’s "Duration" format.
DateTimeZone dateTimeZone = DateTimeZone.forID( "Europe/Paris" ); // Better to specify a time zone than rely on JVM’s default.
DateTime start = new DateTime( dateTimeZone ).withDayOfMonth( 1 ).withTimeAtStartOfDay();
DateTime stop = start.plusMonths( 6 );
Interval interval = new Interval( start, stop );
long milliseconds = interval.toDurationMillis(); // A long, not an int.
Period period = interval.toPeriod(); // For fun… ISO 8601 standard's Duration format.
Dump to console…
System.out.println("start: " + start );
System.out.println("stop: " + stop );
System.out.println("interval: " + interval );
System.out.println("milliseconds: " + milliseconds );
System.out.println("period: " + period );
When run…
start: 2014-04-01T00:00:00.000+02:00
stop: 2014-10-01T00:00:00.000+02:00
interval: 2014-04-01T00:00:00.000+02:00/2014-10-01T00:00:00.000+02:00
milliseconds: 15811200000
period: P6M

Do we have a TimeSpan sort of class in Java

I was just wondering if there is a need of TimeSpan in java.util so that I can define how much hours,minutes and seconds are there in between these two times.
From this TimeSpan we can have a time interval between two times. like
TimeSpan getTimeSpan( Date before, Date after ){...}
or
long timeSpan = System.currentTimeMillis();
// ... long job
timeSpan = System.currentTimeMillis() - timeSpan;
TimeSpan ts = new TimeSpan(timeSpan);
and with this TimeSpan we can use it in SimpleDateFormat.
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
format.format( timsSpan );
I am not sure if this is already been implemented in Java but yet undiscovered by me.
With JDK 8 date-time libraries in SDK has been enriched and you can use
Duration or Period
Interval from JodaTime will do..
A time interval represents a period of
time between two instants. Intervals
are inclusive of the start instant and
exclusive of the end. The end instant
is always greater than or equal to the
start instant.
Intervals have a fixed millisecond
duration. This is the difference
between the start and end instants.
The duration is represented separately
by ReadableDuration. As a result,
intervals are not comparable. To
compare the length of two intervals,
you should compare their durations.
An interval can also be converted to a
ReadablePeriod. This represents the
difference between the start and end
points in terms of fields such as
years and days.
Interval is thread-safe and immutable.
In Java 8 a proper time library has been added to the standard API (this is based heavily on JodaTime).
In it there are two classes that you can use to indicate a period:
Duration which indicates a seconds or nanoseconds length of a timespan.
Period which indicates a more user-friendly difference, stored as 'x years and y months etc'.
A detailed explanation of the difference between them can be found in the Java tutorial
If you're on on Java 8 (or higher) or simply don't want to import JodaTime (the Author of JodaTime himself suggest migrating to java.time): Java 8 offers that functionality with Periods, see here for a tutorial: https://docs.oracle.com/javase/tutorial/datetime/iso/period.html
Let me quote the Oracle tutorial here:
LocalDate today = LocalDate.now();
LocalDate birthday = LocalDate.of(1960, Month.JANUARY, 1);
Period p = Period.between(birthday, today);
long p2 = ChronoUnit.DAYS.between(birthday, today);
System.out.println("You are " + p.getYears() + " years, " + p.getMonths() +
" months, and " + p.getDays() +
" days old. (" + p2 + " days total)");
The code produces output similar to the following:
You are 53 years, 4 months, and 29 days old. (19508 days total)
If you are looking for an alternative lighter version, have a look at this library that I wrote to use in my own Android app. https://github.com/ashokgelal/samaya
Sorry, I don't have any documentation on its usage, but it is very similar to the counterpart .net Timespan class. Also, there are some unit tests which contains many examples on how to use it.

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