How to validate against schema in JAXB 2.0 without marshalling? - java

I need to validate my JAXB objects before marshalling to an XML file. Prior to JAXB 2.0, one could use a javax.xml.bind.Validator. But that has been deprecated so I'm trying to figure out the proper way of doing this. I'm familiar with validating at marshall time but in my case I just want to know if its valid. I suppose I could marshall to a temp file or memory and throw it away but wondering if there is a more elegant solution.

Firstly, javax.xml.bind.Validator has been deprecated in favour of javax.xml.validation.Schema (javadoc). The idea is that you parse your schema via a javax.xml.validation.SchemaFactory (javadoc), and inject that into the marshaller/unmarshaller.
As for your question regarding validation without marshalling, the problem here is that JAXB actually delegates the validation to Xerces (or whichever SAX processor you're using), and Xerces validates your document as a stream of SAX events. So in order to validate, you need to perform some kind of marshalling.
The lowest-impact implementation of this would be to use a "/dev/null" implementation of a SAX processor. Marshalling to a null OutputStream would still involve XML generation, which is wasteful. So I would suggest:
SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = schemaFactory.newSchema(locationOfMySchema);
Marshaller marshaller = jaxbContext.createMarshaller();
marshaller.setSchema(schema);
marshaller.marshal(objectToMarshal, new DefaultHandler());
DefaultHandler will discard all the events, and the marshal() operation will throw a JAXBException if validation against the schema fails.

You could use a javax.xml.bind.util.JAXBSource (javadoc) and a javax.xml.validation.Validator (javadoc), throw in an implementation of org.xml.sax.ErrorHandler (javadoc) and do the following:
import java.io.File;
import javax.xml.XMLConstants;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.util.JAXBSource;
import javax.xml.validation.*;
public class Demo {
public static void main(String[] args) throws Exception {
Customer customer = new Customer();
customer.setName("Jane Doe");
customer.getPhoneNumbers().add(new PhoneNumber());
customer.getPhoneNumbers().add(new PhoneNumber());
customer.getPhoneNumbers().add(new PhoneNumber());
JAXBContext jc = JAXBContext.newInstance(Customer.class);
JAXBSource source = new JAXBSource(jc, customer);
SchemaFactory sf = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = sf.newSchema(new File("customer.xsd"));
Validator validator = schema.newValidator();
validator.setErrorHandler(new MyErrorHandler());
validator.validate(source);
}
}
For More Information, See My Blog
http://blog.bdoughan.com/2010/11/validate-jaxb-object-model-with-xml.html

This how we did it. I had to find a way to validate the xml file versus an xsd corresponding to the version of the xml since we have many apps using different versions of the xml content.
I didn't really find any good examples on the net and finally finished with this. Hope this will help.
ValidationEventCollector vec = new ValidationEventCollector();
SchemaFactory sf = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
URL xsdURL = getClass().getResource("/xsd/" + xsd);
Schema schema = sf.newSchema(xsdURL);
//You should change your jaxbContext here for your stuff....
Unmarshaller um = (getJAXBContext(NotificationReponseEnum.NOTIFICATION, notificationWrapper.getEnteteNotification().getTypeNotification()))
.createUnmarshaller();
um.setSchema(schema);
try {
StringReader reader = new StringReader(xml);
um.setEventHandler(vec);
um.unmarshal(reader);
} catch (javax.xml.bind.UnmarshalException ex) {
if (vec != null && vec.hasEvents()) {
erreurs = new ArrayList < MessageErreur > ();
for (ValidationEvent ve: vec.getEvents()) {
MessageErreur erreur = new MessageErreur();
String msg = ve.getMessage();
ValidationEventLocator vel = ve.getLocator();
int numLigne = vel.getLineNumber();
int numColonne = vel.getColumnNumber();
erreur.setMessage(msg);
msgErreur.setCode(ve.getSeverity())
erreur.setException(ve.getLinkedException());
erreur.setPosition(numLigne, numColonne);
erreurs.add(erreur);
logger.debug("Erreur de validation xml" + "erreur : " + numLigne + "." + numColonne + ": " + msg);
}
}
}

Related

Java Unmarshalling issue (jaxb) [duplicate]

I am using JAXB to parse xml elements from the SOAP response. I have defined POJO classes for the xml elements. I have tested pojo classes without namespace and prefix its working fine .Though when i am trying to parse with namespaces and prefix facing the following exception.Requirement is to parse the input from SOAPMessage Object
javax.xml.bind.UnmarshalException: unexpected element (uri:"http://schemas.xmlsoap.org/soap/envelope/", local:"Envelope"). Expected elements are <{}Envelope>
Tried to fix by creating #XMLSchema for the package in package-info.java and located this file in package folder.Can any one guide me to move forward?
Referred this posts but didn help me .
EDITED :XMLSchema
#javax.xml.bind.annotation.XmlSchema (
xmlns = { #javax.xml.bind.annotation.XmlNs(prefix = "env",
namespaceURI="http://schemas.xmlsoap.org/soap/envelope/"),
#javax.xml.bind.annotation.XmlNs(prefix="ns3", namespaceURI="http://www.xxxx.com/ncp/oomr/dto/")
}
)
package com.one.two;
Thanks in advance
This can be done without modifying the generated JAXB code using standard SOAPMessage class. I wrote about this here and here
It's a little fiddly but works correctly.
Marshalling
Farm farm = new Farm();
farm.getHorse().add(new Horse());
farm.getHorse().get(0).setName("glue factory");
farm.getHorse().get(0).setHeight(BigInteger.valueOf(123));
Document document = DocumentBuilderFactory.newInstance().newDocumentBuilder().newDocument();
Marshaller marshaller = JAXBContext.newInstance(Farm.class).createMarshaller();
marshaller.marshal(farm, document);
SOAPMessage soapMessage = MessageFactory.newInstance().createMessage();
soapMessage.getSOAPBody().addDocument(document);
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
soapMessage.writeTo(outputStream);
String output = new String(outputStream.toByteArray());
Unmarshalling
String example =
"<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\"><soapenv:Header /><soapenv:Body><ns2:farm xmlns:ns2=\"http://adamish.com/example/farm\"><horse height=\"123\" name=\"glue factory\"/></ns2:farm></soapenv:Body></soapenv:Envelope>";
SOAPMessage message = MessageFactory.newInstance().createMessage(null,
new ByteArrayInputStream(example.getBytes()));
Unmarshaller unmarshaller = JAXBContext.newInstance(Farm.class).createUnmarshaller();
Farm farm = (Farm)unmarshaller.unmarshal(message.getSOAPBody().extractContentAsDocument());
Here is how you can handle your use cae:
If You Need to Map the Envelope Element
package-info
Typically you would use the #XmlSchema as follows. Using the namespace and elementFormDefault properties like I've done means that all data mapped to XML elements unless otherwise mapped will belong to the http://www.xxxx.com/ncp/oomr/dto/ namespace. The information specified in xmlns is for XML schema generation altough some JAXB implementations use this to determine the preferred prefix for a namespace when marshalling (see: http://blog.bdoughan.com/2011/11/jaxb-and-namespace-prefixes.html).
#XmlSchema (
namespace="http://www.xxxx.com/ncp/oomr/dto/",
elementFormDefault=XmlNsForm.QUALIFIED,
xmlns = {
#XmlNs(prefix = "env", namespaceURI="http://schemas.xmlsoap.org/soap/envelope/"),
#XmlNs(prefix="whatever", namespaceURI="http://www.xxxx.com/ncp/oomr/dto/")
}
)
package com.one.two;
import javax.xml.bind.annotation.*;
Envelope
If within the com.one.two you need to map to elements from a namespace other than http://www.xxxx.com/ncp/oomr/dto/ then you need to specify it in the #XmlRootElement and #XmlElement annotations.
package com.one.two;
import javax.xml.bind.annotation.*;
#XmlRootElement(name="Envelope", namespace="http://schemas.xmlsoap.org/soap/envelope/")
#XmlAccessorType(XmlAccessType.FIELD)
public class Envelope {
#XmlElement(name="Body", namespace="http://schemas.xmlsoap.org/soap/envelope/")
private Body body;
}
For More Information
http://blog.bdoughan.com/2010/08/jaxb-namespaces.html
If You Just Want to Map the Body
You can use a StAX parser to parse the message and advance to the payload portion and unmarshal from there:
import javax.xml.bind.*;
import javax.xml.stream.*;
import javax.xml.transform.stream.StreamSource;
public class UnmarshalDemo {
public static void main(String[] args) throws Exception {
XMLInputFactory xif = XMLInputFactory.newFactory();
StreamSource xml = new StreamSource("src/blog/stax/middle/input.xml");
XMLStreamReader xsr = xif.createXMLStreamReader(xml);
xsr.nextTag();
while(!xsr.getLocalName().equals("return")) {
xsr.nextTag();
}
JAXBContext jc = JAXBContext.newInstance(Customer.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
JAXBElement<Customer> jb = unmarshaller.unmarshal(xsr, Customer.class);
xsr.close();
}
}
For More Information
http://blog.bdoughan.com/2012/08/handle-middle-of-xml-document-with-jaxb.html
Just wanted to add onto the existing answers -- while unmarshalling if the XML document is not namespace aware you might receive an error: javax.xml.bind.UnmarshalException: unexpected element (uri:"http://some.url";, local:"someOperation")
If this is the case you can simply use a different method on the unmarshaller:
Unmarshaller unmarshaller = JAXBContext.newInstance(YourObject.class).createUnmarshaller();
JAXBElement<YourObject> element = unmarshaller.unmarshal(message.getSOAPBody().extractContentAsDocument(), YourObject.class);
YourObject yo = element.getValue();

Timestamp tag empty in XML - Java Marshaller

I am not very familiar with Marshaller but I gave a try in a project and the XML was generated fine. But when I apply the XML validation (with the .xsd file) it shows an Error saying that <Timestamp> is empty. I debugged the application and I see that inside my Bean the Timestamp is not empty but when the Marshaller generates the XML it is really empty. In the other hand, other attributes which uses XMLGregorianCalendar are present in the XML. I don't know what is happening.
This is the XML generator function:
public void generateXMLReportFile(String fileOutputDirectory,
String xmlOutputFileName,
CRSOECD crsOECD)
throws JAXBException, FileNotFoundException, IOException
{
String encoding = "UTF-8";
// Schema location to write to generated XML file.
String schemaLocation = "urn:oecd:ties:crs:v1 CrsXML_v1.0.xsd";
// Generate The Report:
JAXBContext context = JAXBContext.newInstance(CRSOECD.class);
StringWriter xml = new StringWriter();
Marshaller marshaller = context.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
marshaller.setProperty(Marshaller.JAXB_ENCODING, encoding);
marshaller.setProperty(Marshaller.JAXB_SCHEMA_LOCATION, schemaLocation);
marshaller.marshal(crsOECD, xml);
try (OutputStream out = new FileOutputStream(fileOutputDirectory + xmlOutputFileName)) {
byte[] bytes = xml.toString().getBytes(encoding);
out.write(bytes, 0, bytes.length);
log.info("XML generated.");
}
}
If I debug, I see that the element which is empty in the XML is not empty in the Bean crsOECD.
Guys I just found the answer. The problem was that my element was tagged like this:
#XmlElement(name = "Timestamp", required = true)
#XmlSchemaType(name = "dateTime")
And I was passing only a Date with no Time.

XMLSchema validation with Catalog.xml file for entity resolving

i have a schema.xsd which includes and modifies xhtml like this:
<xs:redefine schemaLocation="http://www.w3.org/MarkUp/SCHEMA/xhtml11.xsd">
...
</xs:redefine>
Now i have written a Validator, which
reads the schema from xml file
uses a CatalogManager for resolving entities
it works fine as it does not load any files from the net but rather finds xhtml11.xsd as given in my catalog.xml file.
public class XmlTemplateValidator implements TemplateValidator
{
public List<SAXParseException> validate ( String xml ) throws Exception
{
Reader input = new StringReader(xml);
InputSource inputSource = new InputSource(input);
SAXParserFactory factory = SAXParserFactory.newInstance();
factory.setNamespaceAware(true);
factory.setValidating(true);
SAXParser parser = factory.newSAXParser();
parser.setProperty("http://java.sun.com/xml/jaxp/properties/schemaLanguage", "http://www.w3.org/2001/XMLSchema");
XMLReader reader = parser.getXMLReader();
reader.setEntityResolver(new CatalogResolver());
DefaultErrorHandler handler = new DefaultErrorHandler();
reader.setErrorHandler(handler);
reader.parse(inputSource);
return handler.getSaxParseExceptions();
}
}
Now i want exactly the same thing, but i want to give the schema inside my validator (so not let the author say against which schema it should validate, but rather let the validator decide which schema to use.
public class NewXmlTemplateValidator implements TemplateValidator
{
static final String schemaSource = "schema.xsd";
public List<SAXParseException> validate ( String xml ) throws Exception
{
Reader input = new StringReader(xml);
SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
URL schemaUrl = getClass().getResource(schemaSource);
Schema schema = factory.newSchema(schemaUrl);
Validator validator = schema.newValidator();
DefaultErrorHandler handler = new DefaultErrorHandler();
validator.setErrorHandler(handler);
Source source = new StreamSource(input);
validator.validate(source);
return handler.getSaxParseExceptions();
}
}
It works but it does load all xhtml files form the net which takes rather long and is not what i want.
So i want to validate a XML String against a predefined schema with proper entity resolving via a catalog.xml definition.
How can i easily add a CatalogResolver to the second setup?
Add an XMLCatalogResolver in the second example like this:
SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
URL schemaUrl = getClass().getResource(schemaSource);
String catalog = getClass().getResource("/catalog.xml").getFile();
XMLCatalogResolver resolver = new XMLCatalogResolver(new String[] { catalog });
factory.setResourceResolver(resolver);

how can i unmarshall in jaxb and enjoy the schema validation without using an explicit schema file

I am using jaxb for my application configurations
I feel like I am doing something really crooked and I am looking for a way to not need an actual file or this transaction.
As you can see in code I:
1.create a schema into a file from my JaxbContext (from my class annotation actually)
2.set this schema file in order to allow true validation when I unmarshal
JAXBContext context = JAXBContext.newInstance(clazz);
Schema mySchema = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI).newSchema(schemaFile);
jaxbContext.generateSchema(new MySchemaOutputResolver()); // ultimately creates schemaFile
Unmarshaller u = m_context.createUnmarshaller();
u.setSchema(mySchema);
u.unmarshal(...);
do any of you know how I can validate jaxb without needing to create a schema file that sits in my computer?
Do I need to create a schema for validation, it looks redundant when I get it by JaxbContect.generateSchema ?
How do you do this?
Regarding ekeren's solution above, it's not a good idea to use PipedOutputStream/PipedInputStream in a single thread, lest you overflow the buffer and cause a deadlock. ByteArrayOutputStream/ByteArrayInputStream works, but if your JAXB classes generate multiple schemas (in different namespaces) you need multiple StreamSources.
I ended up with this:
JAXBContext jc = JAXBContext.newInstance(Something.class);
final List<ByteArrayOutputStream> outs = new ArrayList<ByteArrayOutputStream>();
jc.generateSchema(new SchemaOutputResolver(){
#Override
public Result createOutput(String namespaceUri, String suggestedFileName) throws IOException {
ByteArrayOutputStream out = new ByteArrayOutputStream();
outs.add(out);
StreamResult streamResult = new StreamResult(out);
streamResult.setSystemId("");
return streamResult;
}});
StreamSource[] sources = new StreamSource[outs.size()];
for (int i=0; i<outs.size(); i++) {
ByteArrayOutputStream out = outs.get(i);
// to examine schema: System.out.append(new String(out.toByteArray()));
sources[i] = new StreamSource(new ByteArrayInputStream(out.toByteArray()),"");
}
SchemaFactory sf = SchemaFactory.newInstance( XMLConstants.W3C_XML_SCHEMA_NS_URI );
m.setSchema(sf.newSchema(sources));
m.marshal(docs, new DefaultHandler()); // performs the schema validation
I had the exact issue and found a solution in the Apache Axis 2 source code:
protected List<DOMResult> generateJaxbSchemas(JAXBContext context) throws IOException {
final List<DOMResult> results = new ArrayList<DOMResult>();
context.generateSchema(new SchemaOutputResolver() {
#Override
public Result createOutput(String ns, String file) throws IOException {
DOMResult result = new DOMResult();
result.setSystemId(file);
results.add(result);
return result;
}
});
return results;
}
and after you've acquired your list of DOMResults that represent the schemas, you will need to transform them into DOMSource objects before you can feed them into a schema generator. This second step might look something like this:
Unmarshaller u = myJAXBContext.createUnmarshaller();
List<DOMSource> dsList = new ArrayList<DOMSource>();
for(DOMResult domresult : myDomList){
dsList.add(new DOMSource(domresult.getNode()));
}
String schemaLang = "http://www.w3.org/2001/XMLSchema";
SchemaFactory sFactory = SchemaFactory.newInstance(schemaLang);
Schema schema = sFactory.newSchema((DOMSource[]) dsList.toArray(new DOMSource[0]));
u.setSchema(schema);
I believe you just need to set a ValidationEventHandler on your unmarshaller. Something like this:
public class JAXBValidator extends ValidationEventCollector {
#Override
public boolean handleEvent(ValidationEvent event) {
if (event.getSeverity() == event.ERROR ||
event.getSeverity() == event.FATAL_ERROR)
{
ValidationEventLocator locator = event.getLocator();
// change RuntimeException to something more appropriate
throw new RuntimeException("XML Validation Exception: " +
event.getMessage() + " at row: " + locator.getLineNumber() +
" column: " + locator.getColumnNumber());
}
return true;
}
}
And in your code:
Unmarshaller u = m_context.createUnmarshaller();
u.setEventHandler(new JAXBValidator());
u.unmarshal(...);
If you use maven using jaxb2-maven-plugin can help you. It generates schemas in generate-resources phase.

Validate an XML File Against Multiple Schema Definitions

I'm trying to validate an XML file against a number of different schemas (apologies for the contrived example):
a.xsd
b.xsd
c.xsd
c.xsd in particular imports b.xsd and b.xsd imports a.xsd, using:
<xs:include schemaLocation="b.xsd"/>
I'm trying to do this via Xerces in the following manner:
XMLSchemaFactory xmlSchemaFactory = new XMLSchemaFactory();
Schema schema = xmlSchemaFactory.newSchema(new StreamSource[] { new StreamSource(this.getClass().getResourceAsStream("a.xsd"), "a.xsd"),
new StreamSource(this.getClass().getResourceAsStream("b.xsd"), "b.xsd"),
new StreamSource(this.getClass().getResourceAsStream("c.xsd"), "c.xsd")});
Validator validator = schema.newValidator();
validator.validate(new StreamSource(new StringReader(xmlContent)));
but this is failing to import all three of the schemas correctly resulting in cannot resolve the name 'blah' to a(n) 'group' component.
I've validated this successfully using Python, but having real problems with Java 6.0 and Xerces 2.8.1. Can anybody suggest what's going wrong here, or an easier approach to validate my XML documents?
So just in case anybody else runs into the same issue here, I needed to load a parent schema (and implicit child schemas) from a unit test - as a resource - to validate an XML String. I used the Xerces XMLSchemFactory to do this along with the Java 6 validator.
In order to load the child schema's correctly via an include I had to write a custom resource resolver. Code can be found here:
https://code.google.com/p/xmlsanity/source/browse/src/com/arc90/xmlsanity/validation/ResourceResolver.java
To use the resolver specify it on the schema factory:
xmlSchemaFactory.setResourceResolver(new ResourceResolver());
and it will use it to resolve your resources via the classpath (in my case from src/main/resources). Any comments are welcome on this...
http://www.kdgregory.com/index.php?page=xml.parsing
section 'Multiple schemas for a single document'
My solution based on that document:
URL xsdUrlA = this.getClass().getResource("a.xsd");
URL xsdUrlB = this.getClass().getResource("b.xsd");
URL xsdUrlC = this.getClass().getResource("c.xsd");
SchemaFactory schemaFactory = schemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
//---
String W3C_XSD_TOP_ELEMENT =
"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?>\n"
+ "<xs:schema xmlns:xs=\"http://www.w3.org/2001/XMLSchema\" elementFormDefault=\"qualified\">\n"
+ "<xs:include schemaLocation=\"" +xsdUrlA.getPath() +"\"/>\n"
+ "<xs:include schemaLocation=\"" +xsdUrlB.getPath() +"\"/>\n"
+ "<xs:include schemaLocation=\"" +xsdUrlC.getPath() +"\"/>\n"
+"</xs:schema>";
Schema schema = schemaFactory.newSchema(new StreamSource(new StringReader(W3C_XSD_TOP_ELEMENT), "xsdTop"));
The schema stuff in Xerces is (a) very, very pedantic, and (b) gives utterly useless error messages when it doesn't like what it finds. It's a frustrating combination.
The schema stuff in python may be a lot more forgiving, and was letting small errors in the schema go past unreported.
Now if, as you say, c.xsd includes b.xsd, and b.xsd includes a.xsd, then there's no need to load all three into the schema factory. Not only is it unnecessary, it will likely confuse Xerces and result in errors, so this may be your problem. Just pass c.xsd to the factory, and let it resolve b.xsd and a.xsd itself, which it should do relative to c.xsd.
From the xerces documentation :
http://xerces.apache.org/xerces2-j/faq-xs.html
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;
...
StreamSource[] schemaDocuments = /* created by your application */;
Source instanceDocument = /* created by your application */;
SchemaFactory sf = SchemaFactory.newInstance(
"http://www.w3.org/XML/XMLSchema/v1.1");
Schema s = sf.newSchema(schemaDocuments);
Validator v = s.newValidator();
v.validate(instanceDocument);
I faced the same problem and after investigating found this solution. It works for me.
Enum to setup the different XSDs:
public enum XsdFile {
// #formatter:off
A("a.xsd"),
B("b.xsd"),
C("c.xsd");
// #formatter:on
private final String value;
private XsdFile(String value) {
this.value = value;
}
public String getValue() {
return this.value;
}
}
Method to validate:
public static void validateXmlAgainstManyXsds() {
final SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
String xmlFile;
xmlFile = "example.xml";
// Use of Enum class in order to get the different XSDs
Source[] sources = new Source[XsdFile.class.getEnumConstants().length];
for (XsdFile xsdFile : XsdFile.class.getEnumConstants()) {
sources[xsdFile.ordinal()] = new StreamSource(xsdFile.getValue());
}
try {
final Schema schema = schemaFactory.newSchema(sources);
final Validator validator = schema.newValidator();
System.out.println("Validating " + xmlFile + " against XSDs " + Arrays.toString(sources));
validator.validate(new StreamSource(new File(xmlFile)));
} catch (Exception exception) {
System.out.println("ERROR: Unable to validate " + xmlFile + " against XSDs " + Arrays.toString(sources)
+ " - " + exception);
}
System.out.println("Validation process completed.");
}
I ended up using this:
import org.apache.xerces.parsers.SAXParser;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import org.xml.sax.helpers.DefaultHandler;
import java.io.IOException;
.
.
.
try {
SAXParser parser = new SAXParser();
parser.setFeature("http://xml.org/sax/features/validation", true);
parser.setFeature("http://apache.org/xml/features/validation/schema", true);
parser.setFeature("http://apache.org/xml/features/validation/schema-full-checking", true);
parser.setProperty("http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation", "http://your_url_schema_location");
Validator handler = new Validator();
parser.setErrorHandler(handler);
parser.parse("file:///" + "/home/user/myfile.xml");
} catch (SAXException e) {
e.printStackTrace();
} catch (IOException ex) {
e.printStackTrace();
}
class Validator extends DefaultHandler {
public boolean validationError = false;
public SAXParseException saxParseException = null;
public void error(SAXParseException exception)
throws SAXException {
validationError = true;
saxParseException = exception;
}
public void fatalError(SAXParseException exception)
throws SAXException {
validationError = true;
saxParseException = exception;
}
public void warning(SAXParseException exception)
throws SAXException {
}
}
Remember to change:
1) The parameter "http://your_url_schema_location" for you xsd file location.
2) The string "/home/user/myfile.xml" for the one pointing to your xml file.
I didn't have to set the variable: -Djavax.xml.validation.SchemaFactory:http://www.w3.org/2001/XMLSchema=org.apache.xerces.jaxp.validation.XMLSchemaFactory
Just in case, anybody still come here to find the solution for validating xml or object against multiple XSDs, I am mentioning it here
//Using **URL** is the most important here. With URL, the relative paths are resolved for include, import inside the xsd file. Just get the parent level xsd here (not all included xsds).
URL xsdUrl = getClass().getClassLoader().getResource("my/parent/schema.xsd");
SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = schemaFactory.newSchema(xsdUrl);
JAXBContext jaxbContext = JAXBContext.newInstance(MyClass.class);
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
unmarshaller.setSchema(schema);
/* If you need to validate object against xsd, uncomment this
ObjectFactory objectFactory = new ObjectFactory();
JAXBElement<MyClass> wrappedObject = objectFactory.createMyClassObject(myClassObject);
marshaller.marshal(wrappedShipmentMessage, new DefaultHandler());
*/
unmarshaller.unmarshal(getClass().getClassLoader().getResource("your/xml/file.xml"));
If all XSDs belong to the same namespace then create a new XSD and import other XSDs into it. Then in java create schema with the new XSD.
Schema schema = xmlSchemaFactory.newSchema(
new StreamSource(this.getClass().getResourceAsStream("/path/to/all_in_one.xsd"));
all_in_one.xsd :
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:ex="http://example.org/schema/"
targetNamespace="http://example.org/schema/"
elementFormDefault="unqualified"
attributeFormDefault="unqualified">
<xs:include schemaLocation="relative/path/to/a.xsd"></xs:include>
<xs:include schemaLocation="relative/path/to/b.xsd"></xs:include>
<xs:include schemaLocation="relative/path/to/c.xsd"></xs:include>
</xs:schema>

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