I would like to wrap an executable jar into a .exe file in order to give it to associate. I used Launch4j and it works. However the others are not able to use it. Error occurs always with Java version.
I found this question:
Running a java program as an exe in Windows without JRE installed
Is there nothing else more easy to use?
EDIT :
I slected prefer JRE rather than preferJDK und JRE window, that was the problem there.
In Launch4j, under JRE > Bundled JRE path, type something like ./runtime. When you wrap your JAR file into an EXE, the EXE will look for a java runtime in the current directory under a subdirectory called "runtime". If you copy a Java runtime directory into the same directory as your wrapped EXE file, it will use it.
In Windows Explorer:
The "runtime" directory is the complete JRE directory, E.G. "jre1.8.0_201", but renamed. Inside there should be a bin folder and a lib folder and some other files.
Currently running OSX El Capitan on a recently set up computer. I'm trying to set up Java's unlimited crypto policy which requires me to modify some files within my current jre, but I can't find the Java folder that is supposed to be located within Library.
I've run /usr/libexec/java_home which shows me /Library/Java/JavaVirtualMachines/jdk1.8.0_91.jdk/Contents/Home however within my Library folder, there is no Java folder, even when I try and navigate through terminal it says Java folder doesn't exist. After trying to reinstall JDK 1.8, still no luck and I'm out of ideas.
This is not the Library folder in your home directory, this is the Library folder in the root file system on your main disk.
So in Terminal the command
cd /Library/Java/JavaVirtualMachines/jdk1.8.0_91.jdk
should work.
For different releases of Java replace jdk1.8.0_91.jdk with the appropriate release.
To list what is in the directory use:
ls /Library/Java/JavaVirtualMachines
Go to Macintosh HD/Library/Java
not to username/Library
I know that windows users prefer .exe (Windows EXEcutables) and mac users prefer .app (AppleScript application) and Java uses .jar (Java ARchive). But is there any reasonable cross-platform executable because to execute JAR you need the CMD or Terminal (at least in the case of a Mac) to run the file by using:
java -jar %FILEPATH%
But is there any other executable I can use?
Should I just have a Mac and a Windows downloads?
Can I make a jar that can be double clicked?
I have searched as far as I can in stock overflow but no simple reasonable answer.
Hope this can help more people than me :)
To be able to start a jar file via double-click, the .jar extension needs to be associated with the Java Runtime executable, javaw.exe under Windows. That is the same mechanism used to open for example .docx files with Microsoft Word.
As far as I know, the JRE installation adds such an association automatically.
In order to tell Java which class to start from the Jar after it was double-clicked, you need a META-INF/MANIFEST.MF in the Jar, like #Elliott Frisch described.
By the way: Mac apps are in fact folders, which Mac OS X shows as one piece (right-click on a Mac app and click Show Package Contents to enter that folder). So the idea is very similar to Jars, although Jars are real files and not folder -- and of course their format is totally different.
So a Jar is the format "executable" on all platforms (having a JRE installed).
An executable JAR file is the most portable cross-platform executable. Macintosh app files are Mach-O format, and not compatible with Windows Portable Executable. The Windows executable format is not compatible with Mac or Linux (ELF). Basically, the only format that will reliably run on Windows, Mac and Linux is a Jar File.
From Setting an Application's Entry Point the Java Tutorials,
If you have an application bundled in a JAR file, you need some way to indicate which class within the JAR file is your application's entry point. You provide this information with the Main-Class header in the manifest, which has the general form:
Main-Class: classname
I can't open or run my .jar file.
I just installed java, but I tried to open the .jar with other programs first, so the double-click defaults to something else and I can't change it back.
java -jar myfile.jar`
Above command returns:
'java' is not recognized as an internal or external command, operable program or batch file.
Is there a way I can still open/run this?
e: OS is Windows 8.
Also, I downloaded the .jar file; didn't create it myself (if that's relevant)
Not sure if it contains an executable (but I think it does).
you can use the command prompt:
javaw.exe -jar yourfile.jar
Hope it works for you.
There are two different types of Java to download: The JDK, which is used to write Java programs, and the RE (runtime environment), which is used to actually run Java programs. Are you sure that you installed the RE instead of the SDK?
Use cmd prompt and type
java -jar exapmple.jar
To run your jar file.
for more information refer to this link it describes how to properly open the jar file.
https://superuser.com/questions/745112/how-do-i-run-a-jar-file-without-installing-java
You may have several JDKs installed in your PC. Some older JDK installers also copy some java files such as java.exe, javaw.exe into C:\Windows\System32 folder.
I had a similar issue, and searched the internet for a solution and none of the suggestions didn’t open by double clicking the .jar file.
In my case the reason is I have multiple JDK & JRE versions installed on my computer. Since I am a software developer working with several different versions for different clients I need to use multiple JDKs in my PC (Windows 10 Pro). So I do not want to change the system variables (i.e. JAVA_HOME, JRE_HOME or PATH), instead I use command prompt to run java in user process whenever I wanted to use a different version.
When installing JDK it registers the .jar file association with latest version we installed in the PC. If you right click on the .jar icon and select properties, it will show that file opens with “Java(TM) Platform SE Binary”. If we look at the registry key: HKEY_CLASSES_ROOT\jarfile\shell\open\command, it will point to latest JDK version.
It is not a good idea (sometimes annoying) to change the registry key every time I want to run an app build from a different version.
So in my situation it is impossible to just double click the .jar file to execute it. But instead I found a work around solution myself.
Scenario:
Multiple JDKs (1.7, 1.8, 9.0, 10.0, 11.0, and 12.0)are installed in the PC, so the latest installed was 12.0.
Problem
Want to double click an executable .jar developed using JDK 1.8 and didn’t work
This is my work around solution:
Create a shortcut for the .jar file that you want to open.
Right click the shortcut icon and select properties -> Shortcut tab
Change the text in the target (for example "D:\Dev\JavaApp1.8.jar")
To
"C:\Program Files\Java\jdk1.8.0\bin\javaw.exe" -jar
"D:\Dev\JavaApp1.8.jar"
Then click ok Double click the shortcut.
It should now open the app.
I was having this same issue for both Windows 8 and Windows Server 2012 configurations.
I had installed the latest version of JDK Java 7 and had set my **JAVA_HOME**system env variable to the jre folder: *C:\Program Files (x86)\Java\jre7*
I also added the bin folder to my **Path** system env variable: *%JAVA_HOME%\bin*
But I was still having problems with double clicking the executable jar files. I found another system env variable OPENDS_JAVA_ARGS that can be used to set the optional properties for javaw.exe. So I added this variable and set it to: -jar
Now I am able to run the executable jar files when double clicking them.
In cmd you can use the following:
c:\your directory\your folder\build>java -jar yourFile.jar
However, you need to create you .jar file on your project if you use Netbeans. How just go to Run ->Clean and Build Project(your project name)
Also make sure you project properties Build->Packing has a yourFile.jar
and check Build JAR after Compiling
check Copy Depentent Libraries
Warning: Make sure your Environmental variables for Java are properly set.
Old way to compile and run a Java File from the command prompt (cmd)
Compiling: c:\>javac Myclass.java
Running: c:\>java com.myPackage.Myclass
I hope this info help.
Go to your java directory,
Copy this path
C:\Program Files\Java\jdk1.8.0_40\bin
Right click on my computer , click properties, then go to "Advanced system settings"
click , Environment variables.
go to "System variables" table, find an entry named "path".
Double click it and go to the end, put a semicolon and paste your path, apply and ok.
It should run now.
first of all, we have to make sure that you have downloaded and installed the JDK.
In order to download it click on the following link
http://www.oracle.com/technetwork/java/javase/downloads/jdk8-downloads-2133151.html
(Do not forget to check "Accept License Agreement", before you choose the version you want to download)
For Windows OS 32-Bit (x86) choose "jdk-8u77-windows-i586.exe"
For Windows OS 64-Bit (x64) choose "jdk-8u77-windows-x64.exe"
Install the file that is going to be downloaded. During the installation, pay attention, because you have to keep the installation path.
When you have done so, the last thing to do, is to define two "Environment Variables".
The first "Environmental Variable" name should be:
JAVA_HOME
and its value should be the installation path
(for example: C:\Program Files\Java\jdk1.8.0_77)
The second "Environmental Variable" name should be:
JRE_HOME and its value should be the installation path
(for example C:\Program Files\Java\jre8)
As soon as you have defined the Environment Variables, you can go to command prompt (cdm) and run from every path your preferred "java.exe" commands. Your command line can now recognize your "java.exe" commands.
:)
P.S.: In order to define "Environment Variable", make a right click on "This PC" and select "properties" from the menu. Then the "System" window will appear and you have to click on "Advanced system settings". As a consequence "System properties" window shows. Select the "Advanced" tab and click on "Environment Variables" button. You can now define the aforementioned variables and you're done
You must create a manifest file and specify your class that has the main method. you can build your jar file with manifest file as a parameter.
jar cfm MyJar.jar Manifest.txt MyPackage/*.class
Manifest-Version: 1.0
Archiver-Version: Plexus Archiver
Created-By: Apache Maven
Built-By: Cakes
Build-Jdk: 1.6.0_04
Main-Class: com.foo.App
An easy way to execute .jar files is to create a batch file.
Let's say you placed your jar file on your Desktop;
#echo OFF
java -jar C:\Users\YourName\Desktop\myjar.jar
Copy this code to a .txt file, modify "YourName" and save as "myjar.bat". Then whenever you double click, the jar file will be executed.
Hope this helps.
Short trick: after I only REMOVED SPACES from names of the folders, where the .jar file was, double-clicked worked and the file executed.
In Netbeans please delete current you create the jar file and on the project explore of Netbeans please clean and build 2 or 3 times and right the project folder in project explore and build the jar file.
I had this problem a while back and the solution was really easy.
Just uninstall the current version of Java, download an older one, then uninstall the older and install the latest again.
For example: Java 8 Update 73 current install Java 7 Update 95.
How it works: Java's registry keys were messed up, and when you install the older version they get fixed.
If the intention of the question is to view the contents of the JAR file, then the following java command would help.. (provided, JDK location is added to the environment variables.)
Windows Command prompt> jar tvf yourJarFile.jar
Example:
jar tvf log4j-extras-1.2.17.jar
Reference: http://docs.oracle.com/javase/tutorial/deployment/jar/view.html
I downloaded the latest JDK 7u10. Once you do that, try running your jar, It should execute.
hi i converted my jar file into an exe using jsmooth but when i install it, it shows an error like java not found.
Please help me, how can I add the jre to my exe wrapper so this problem is solved.
It is trying to get the java installation to run your application, where it might be searching in JAVA_HOME, So if the JAVA_HOME is not set in the machine where you installing your application then try to install the java and set the JAVA_HOME as a pre-requisite of your installation.
I don't believe JSmooth can actually bundle a JRE with the exe. What you can do is tell JSmooth where to expect the JRE when running the exe (as in the same folder the exe is run from). If you do this you simply need to zip the exe and a JRE up, and distribute that.
The end user would unzip this, and the resulting folder would contain your exe and the JRE. Since JSmooth knows where to look relative your exe, it can find the JRE.
i have use it using launch4j
follow the following steps
1-create project directory called e.g:project
2-copy the runnable jar file to it
3-copy the jre directory to it u can rename it or keep name as it e.g i will call myjre
run launch4j program :
1- fill the basic tap with required information .
2- go to JRE tap there is a field called (bundle JRE path ) write "myjre" add min Jar virsion 1,6 it will case you an error if you do not fill this fields
and then click run button to generate exe file , you have to remember to keep the myjre directory with along side with executable exe file
e.g the application directory should contains :
1- [you app name].exe
2-myjre
in this description you can run your application with no care if jre is installed in a machine or not and become portable
Good Luck , feel free to contact me for more details