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How I should use ajax to fire a web service call to export an Excel

updated question:
On server side i have a service as below, if I want to use ajax to fire the call on the client side, how I should do that?
In server:
Java/Spring
#GET
#Produces("application/vnd.ms-excel")
#Path("permissions/all/{userList}")
public Response allPermissionsExcel(#PathParam("userList") String userList) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
HSSFWorkbook wb;
try {
String[] groupList = userList.split(",");
wb = this.excelPermissionsService.getPermissionsExcelWorkbook(groupList);
wb.write(baos);
} catch (IOException e) {
e.printStackTrace();
} finally {
baos.close();
}
byte[] bytes = baos.toByteArray();
ResponseBuilder response = Response.ok(bytes);
response.header("Content-Disposition", "attachment; filename=export.xls");
return response.build();
}
In client:
$scope.exportToExcel = function() {
var promise = usersResource.getExcelPermissions($scope.userList);
promise.$promise.then(function(data) {
//I tried to convert to blob then save it with FileSaver.js, but I got an issue in converting the object to blob.
var blob = new Blob([data],
var blob = new Blob([data],
{type: "application/octet-stream"});
saveAs(blob, "exportThis.xls");
});
};
in the client side, if i use ajax (above code) to fire a call to server, and it returns an object, but nothing prompts up to download, unless I use
window.location = "url here";
to fire the call. But that's a redirect and pops up to download after all javascript ran.
Since I have some loading animations which are applied by $watch, i need to use ajax to fire the call instead of using window.location.
Can anyone help me save the "data" object excel in client side?
Thanks!

You need to use window.open without requesting an ajax
it will just open a new window and then the file will start download without affecting the current page
window.open("permissions/all/1"); // instead of window.location because it will move you to another page
You also can open it by a pop up like this
newwindow=window.open("permissions/all/1","Window name",'height=50,width=150); // this one is better because it will open a small window without hiding the current window
if (window.focus) {newwindow.focus()}
return false;

How to serve .jasper file with HTTP Server?

I am creating HTTP server with Tomee, i am placed jasper report file (.jasper) in webapp directory. if i access http://localhost:8080/test.jasper in browser, the browser will prompt to download the file.
In my java project i'm creating simple code to access that link and then preview the report. I use async-http-client library for request.
DefaultAsyncHttpClient client = new DefaultAsyncHttpClient();
BoundRequestBuilder brb = client.prepareGet("http://localhost:8765/qa/test.jasper");
Future<InputStream> f = brb.execute(new AsyncCompletionHandler<InputStream>() {
#Override
public InputStream onCompleted(Response resp) {
try {
String[][] data = {{"Jakarta"},{"Surabaya"},{"Solo"},{"Denpasar"}};
String[] columnNames = {"City"};
DefaultTableModel dtm = new DefaultTableModel(data, columnNames);
Map<String,Object> params = new HashMap<>();
JasperPrint jPrint = JasperFillManager.fillReport(
resp.getResponseBodyAsStream(),
params,
new JRTableModelDataSource(dtm)
);
JasperViewer jpView = new JasperViewer(jPrint,false);
jpView.setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
jpView.setSize(800, 600);
jpView.setLocationRelativeTo(null);
jpView.setVisible(true);
} catch (JRException ex) {
System.out.println(ex.getMessage());
}
return resp.getResponseBodyAsStream();
}
});
From my code above, i got an error Error loading object from InputStream
normally i can use
InputStream input = MainContext.class.getResourceAsStream(filename);
But i want to replace file input stream with http request (stream too).
How exactly i can serve .jasper file with http server...?

Error loading object from InputStream error came from corrupt InputStream, if i download .jasper file normally via browser and execute the report with JRLoader.loadObjectFromFile(path to file) it doesn't works too, because tomee give corrupt file (the source file not corrupt).
My own solution is read source file as stream, convert it to base64 encode, and serve it via HTTP API protocol.
finput = new FileInputStream(sPath);
byte[] bFile = Base64.getEncoder().encode(IOUtils.toByteArray(finput));
String sFile = new String(bFile);
inside client side, i received it as body string, decode the base64 string, convert it to InputStream and Finally execute the report with InputStream.
byte[] bBody = Base64.getDecoder().decode(sBody);
InputStream mainReport = new ByteArrayInputStream(bBody);
return JasperFillManager.fillReport(mainReport, params);

Java Webdav File Synchronization

I have a cloud storage at strato namely hidrive. It uses the webdav protocol. Note that it's based on HTTP. The client application they provide is poor and buggy so I tried various other tools for synchronization but none just worked the way I need it.
I'm therefore trying to implement it in Java using the Sardine project. Is there any code for hard-copying a local source folder to an external cloud folder? I haven't found anything in that direction.
The following code is supposed to upload the file...
Sardine sardine = SardineFactory.begin("username", "password");
InputStream fis = new FileInputStream(new File("some/file/test.txt"));
sardine.put("https://webdav.hidrive.strato.com/users/username/Backup", fis);
... but throws an exception instead:
Exception in thread "main" com.github.sardine.impl.SardineException: Unexpected response (301 Moved Permanently)
at com.github.sardine.impl.handler.ValidatingResponseHandler.validateResponse(ValidatingResponseHandler.java:48)
at com.github.sardine.impl.handler.VoidResponseHandler.handleResponse(VoidResponseHandler.java:34)
at com.github.sardine.impl.handler.VoidResponseHandler.handleResponse(VoidResponseHandler.java:1)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:218)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:160)
at com.github.sardine.impl.SardineImpl.execute(SardineImpl.java:828)
at com.github.sardine.impl.SardineImpl.put(SardineImpl.java:755)
at com.github.sardine.impl.SardineImpl.put(SardineImpl.java:738)
at com.github.sardine.impl.SardineImpl.put(SardineImpl.java:726)
at com.github.sardine.impl.SardineImpl.put(SardineImpl.java:696)
at com.github.sardine.impl.SardineImpl.put(SardineImpl.java:689)
at com.github.sardine.impl.SardineImpl.put(SardineImpl.java:682)
at com.github.sardine.impl.SardineImpl.put(SardineImpl.java:676)
Printing out the folders in that directory works so the connection/ authentication did succeed:
List<DavResource> resources = sardine.list("https://webdav.hidrive.strato.com/users/username/Backup");
for (DavResource res : resources)
{
System.out.println(res);
}
Please either help me fix my code or link me to some file synchronization library that works for my purpose.

Sardine uses (internally) HttpClient. There is similar question here where you can find an answer Httpclient 4, error 302. How to redirect?.

Try converting the InputStream obj into byte array before you call put(). Something like the below,
byte[] fisByte = IOUtils.toByteArray(fis);
sardine.put("https://webdav.hidrive.strato.com/users/username/Backup", fisByte);
It worked for me. Let me know.

I had to extend the "org.apache.http.impl.client.LaxRedirectStrategy" and also the getRedirect() Method of org.apache.http.impl.client.DefaultRedirectStrategy with a treatment of the needed methods: PUT, MKOL, etc. . By default only GET is redirected.
It looks like this:
private static final String[] REDIRECT_METHODS = new String[] { HttpGet.METHOD_NAME, HttpPost.METHOD_NAME, HttpHead.METHOD_NAME, HttpPut.METHOD_NAME, HttpDelete.METHOD_NAME, HttpMkCol.METHOD_NAME };
isRedirectable-Method
for (final String m : REDIRECT_METHODS) {
if (m.equalsIgnoreCase(method)) {
System.out.println("isRedirectable true");
return true;
}
}
return method.equalsIgnoreCase(HttpPropFind.METHOD_NAME);
getRedirect-Method:
final URI uri = getLocationURI(request, response, context);
final String method = request.getRequestLine().getMethod();
if (method.equalsIgnoreCase(HttpHead.METHOD_NAME)) {
return new HttpHead(uri);
} else if (method.equalsIgnoreCase(HttpGet.METHOD_NAME)) {
return new HttpGet(uri);
} else if (method.equalsIgnoreCase(HttpPut.METHOD_NAME)) {
HttpPut httpPut = new HttpPut(uri);
httpPut.setEntity(((HttpEntityEnclosingRequest) request).getEntity());
return httpPut;
} else if (method.equalsIgnoreCase("MKCOL")) {
return new HttpMkCol(uri);
} else if (method.equalsIgnoreCase("DELETE")) {
return new HttpDelete(uri);
} else {
final int status = response.getStatusLine().getStatusCode();
if (status == HttpStatus.SC_TEMPORARY_REDIRECT) {
return RequestBuilder.copy(request).setUri(uri).build();
} else {
return new HttpGet(uri);
}
}
That worked for me.

Test AJAX file upload

I want to test the file upload in my application. The upload itself is handled as described in section Direct file upload on http://www.playframework.org/documentation/2.0/JavaFileUpload.
I am using the latest Play20 version and build it as described here.
My current code looks like this, but obviously the part is missing which adds a test file to the request:
Test.java
FakeRequest request = fakeRequest(POST, "/measurement/123/file");
// how to append test file to this request?
Result result = routeAndCall(request);
assertOK(result);
Controller.java
public static uploadFile() {
RequestBody body = request().body();
if (body != null) {
RawBuffer rawBuffer = body.asRaw();
if (rawBuffer != null) {
File uploadedFile = rawBuffer.asFile();
// ...
}
}
return ok();
}

My solution for Play 2 Java file upload testing has been to create a UploadFakeRequest extending FakeRequest. Inside the class I have then my own withRawBody method with something like that:
RawBuffer raw = new RawBuffer(1000, data.getBytes()); // No clue what is the correct value here...
AnyContentAsRaw content = new AnyContentAsRaw(raw);
fake = new play.api.test.FakeRequest(POST, fake.path(), new play.api.test.FakeHeaders(Scala.asScala(map)), content, "127.0.0.1");

The signature of the FakeRequest call, as per source code, is:
case class FakeRequest[A](method: String, uri: String, headers: FakeHeaders, body: A) extends Request[A]
You should be able to inspect the body of a POST request that uploads a file to your application and copy that body as a parameter in your testing code. The alternative is to build it as per RFC description on multipart POST.

How to indicate the file name for saving to the browser from a REST service in Jersey?

i am trying to have a REST service return a zip file from the local harddrive .
Following is what i am doing ,
#Path("/interface3/{Ent_id}/{esf_app_id}/{esf_app_ver}")
public class Interface3Mock {
// This method is called if TEXT_PLAIN is request
#GET
#Produces("application/zip")
public Response callInterface3_text(
#PathParam("Ent_id") Integer entitlement_id,
#PathParam("eapp_id") String eapp_id,
#PathParam("eapp_ver") String eapp_ver) {
File f = new File("D:\\Documentation\\Documentation.zip");
String mt = new MimetypesFileTypeMap().getContentType(f);
return Response.ok(f, mt).build();
}
}
Now when i use the browser ie. Internet Explorer and key in the url http://localhost:9788/mockRESTServer/rest/interface3/123456/k123/l345
i see a file download dialog that says "Do you want to save the file l345`.
i want it to ask me for the zip download ie. D:\\Documentation\\Documentation.zip.
But somehow it takes up the last parameter in the request URL.

return Response.ok(f, mt)
.header("Content-Disposition", "attachment; filename=Documentation.zip")
.build();
See How to set response header in JAX-RS so that user sees download popup for Excel?