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I am learning Java now and I am learning about different kinds of collections, so far I learned about LinkedList, ArrayList and Array[].
Now I've been introduced to Hash types of collections, HashSet and HashMap, and I didn't quite understand why there are useful, because the list of commands that they support is quietly limited, also, they are sorted in a random order and I need to Override the equal and HashKey methods in order to make it work right with class.
Now, what I don't understand is the benefits over the hassle of using these types instead of ArrayList of a costume class.
I mean, what Map is doing is connecting 2 objects as 1, but wouldn't it just be better to create a class that contains this 2 objects as parameters, and have getters to modify and use them?
If the benefit is that this Hash objects can only contain 1 object of the same name, wouldn't it just be easier to make the ArrayList check that the type is not already there before adding it?
So far I learned to choose when to use LinkedList, ArrayList or Array[] by the rule of "if it's really simple, use Array[], if it's a bit more complex use ArrayList (for example to hold collection of certain class), and if the list is dynamic with a lot of objects inside that need to change order according to removing or adding a new one in the middle or go back and forth within the list then use LinkedList.
But I couldn't understand when to prefer HashMap or HashSet, and I would be really glad if you could explain it to me.
Let me help you out here...
Hashed collections are the most efficient to add, search and remove data, since they hash the key (in HashMap) or the element (in HashSet) to find the place where they belong in a single step.
The concept of hashing is really simple. It is the process of representing an object as a number that can work as it´s id.
For example, if you have a string in Java like String name = "Jeremy";, and you print its hashcode: System.out.println(name.hashCode());, you will see a big number there (-2079637766), that was created using that string object values (in this string object, it's characters), that way, that number can be used as an Id for that object.
So the Hashed collections like the ones mentioned above, use this number to use it as an array index to find the elements in no-time. But obviously is too big to use it as an array index for a possible small array. So they need to reduce that number so it fits in the range of the array size. (HashMap and HashSet use arrays to store their elements).
The operation that they use to reduce that number is called hashing, and is something like this: Math.abs(-2079637766 % arrayLength);.
It's not like that exactly, it's a bit more complex, but this is to simplify.
Let's say that arrayLength = 16;
The % operator will reduce that big number to a number smaller than 16, so that it can be fit in the array.
That is why a Hashed collection will not allow duplicate, because if you try to add the same object or an equivalent one (like 2 strings with the same characters), it will produce the same hashcode and will override whatever value is in the result index.
In your question, you mentioned that if you are worried about duplicates items in an ArrayList, we can just check if the item is there before inserting it, so this way we don't need to use a HashSet. But that is not a good idea, because if you call the method list.contains(elem); in an ArrayList, it needs to go one by one comparing the elements to see if it's there. If you have 1 million elements in the ArrayList, and you check if an element is there, but it is not there, the ArrayList iterated over 1 million elements, that is not good. But with a HashSet, it would only hashed the object and go directly where it is supposed to be in the array and check, doing it in just 1 step, instead of 1 million. So you see how efficient a HashSet is compared to an ArrayList.
The same happens with a HashMap of size 1 million, that it will only take 1 single step to check if a key is there, and not 1 million.
The same thing happens when you need to add, find and remove an element, with the hashed collections it will do all that in a single step (constant time, doesn't depend on the size of the map), but that varies for other structures.
That's why it is really efficient and widely used.
Main Difference between an ArrayList and a LinkedList:
If you want to find the element at place 500 in an ArrayList of size 1000, you do: list.get(500); and it will do that in a single step, because an ArrayList is implemented with an array, so with that 500, it goes directly where the element is in the array.
But a LinkedList is not implemented with an array, but with objects pointing to each other. This way, they need to go linearly and counting from 0, one by one until they get to the 500, which is not really efficient compared to the 1 single step of the ArrayList.
But when you need to add and remove elements in an ArrayList, sometimes the Array will need to be recreated so more elements fit in it, increasing the overhead.
But that doesn't happen with the LinkedList, since no array has to be recreated, only the objects (nodes) have to be re-referenced, which is done in a single step.
So an ArrayList is good when you won't be deleting or adding a lot of elements on the structure, but you are going to read a lot from it.
If you are going to add and remove a lot of elements, then is better a linked list since it has less work to do with those operations.
Why you need to implement the equals(), hashCode() methods for user-defined classes when you want to use those objects in HashMaps, and implement Comparable interface when you want to use those objects with TreeMaps?
Based on what I mentioned earlier for HashMaps, is possible that 2 different objects produce the same hash, if that happens, Java will not override the previous one or remove it, but it will keep them both in the same index. That is why you need to implement hashCode(), so you make sure that your objects will not have a really simple hashCode that can be easily duplicated.
And the reason why is recommended to override the equals() method is that if there is a collision (2 or more objects sharing the same hash in a HashMap), then how do you tell them apart? Well, asking the equals() method of those 2 objects if they are the same. So if you ask the map if it contains a certain key, and in that index, it finds 3 elements, it asks the equals() methods of those elements if its equals() to the key that was passed, if so, it returns that one. If you don't override the equals() method properly and specify what things you want to check for equality (like the properties name, age, etc.), then some unwanted overrides inside the HashMap will happen and you will not like it.
If you create your own classes, say, Person, and has properties like name, age, lastName and email, you can use those properties in the equals() method and if 2 different objects are passed but have the same values in your selected properties for equality, then you return true to indicate that they are the same, or false otherwise. Like the class String, that if you do s1.equals(s2); if s1 = new String("John"); and s2 = new String("John");, even though they are different objects in Java Heap Memory, the implementation of String.equals method uses the characters to determine if the objects are equals, and it returns true for this example.
To use a TreeMap with user-defined classes, you need to implement the Comparable interface, since the TreeMap will compare and sort the objects based on some properties, you need to specify by which properties your objects will be sorted. Will your objects be sorted by age? By name? By id? Or by any other property that you would like. Then, when you implement the Comparable interface and override the compareTo(UserDefinedClass o) method, you do your logic and return a positive number if the current object is greater than the o object passed, 0 if they are the same and a negative number if the current object is smaller. That way, the TreeMap will know how to sort them, based on the number returned.
First HashSet. In HashSet, you can easily get whether it contains given element. Let's have a set of people in your class and you want to ask whether a guy is in your class. You can make an array list of strings. And if you want to ask if a guy is in your class, you have to iterate through whole the list until you find him, which might be too slow for longer lists. If you use HashSet instead, the operation is much faster. You calculate the hash of the searched string and then you go directly to the hash, so you don't need to pass so many elements to answer your question. Well, you can also make a workaround to make the ArrayList faster to access for this purpose but this is already prepared.
And now HashMap. Now imagine that you also want to store a score for each person. So now you can use HashMap. You enter the name and you get his score in a short time, without the need of iterating through whole the data structure.
Does it make sense?
Concerning your question:
"But I couldn't understand when to prefer HashMap or HashSet, and I
would be really glad if you could explain it to me"
The HashMap implement the Map interface, to be used for mapping a Key (K) to a value (V) in constant time, and where order doesn't matter, so you can put and retrieve those data efficiently if you now the key.
And HashSet implement the Set interface, but is internanly using and HashMap, its role is to be used as a Set, meaning you're not supposed to retrieve an element, you just check that is in the set or not (mostly).
In HashMap, you can have identical value, while you can't in a Set (because its a property of a Set).
Concerning this question :
If the benefit is that this Hash objects can only contain 1 object of the same name, >wouldn't it just be easier to make the ArrayList check that the type is not already >there before adding it?
When dealing with collection, you have may base you choice of a particular one on the data representation but also on the way you want to access and store those data, how do you access it ? Do you need to sort them ? Because each implemenation may have different complexity (https://en.wikipedia.org/wiki/Time_complexity), it become important.
Using the doc,
For ArrayList:
The add operation runs in amortized constant time, that is, adding n elements requires O(n) time. All of the other operations run in linear time (roughly speaking).
For HashMap:
This implementation provides constant-time performance for the basic operations (get and put), assuming the hash function disperses the elements properly among the buckets. Iteration over collection views requires time proportional to the "capacity" of the HashMap instance (the number of buckets) plus its size (the number of key-value mappings). Thus, it's very important not to set the initial capacity too high (or the load factor too low) if iteration performance is important.
So it's about the time complexity.
You may choose even more untypical collection for certain problems :).
This has little to do with Java specifically, and the choice depends mostly on performance requirements, but there's a fundamental difference that must be highlighted. Conceptually, Lists are types of collections that keep the order of insertion and may have duplicates, Sets are more like bags of items that have no specific order and no duplicates. Of course, different implementations may find a way around it (like a TreeSet).
First, let's check the difference between ArrayList and LinkedList. A linked list is a set of nodes, where each node contains a value and a link to the next and previous nodes. This makes inserting an element to a linked list a matter of appending a node to the end of the list, which is a quick operation since the memory does not have to be contiguous, as long as a node keeps a reference to the next node. On the other side, accessing a specific element requires transversing the entire list until finding it.
An array list, as the name implies, wraps an array. Accessing elements in an array by using its index is direct access, but inserting an element implies resizing the array to include the new element, so the memory it occupies is contiguous, making writes a bit heavier in this case.
A HashMap works like a dictionary, where for each key there's a value. The behavior of the insertion will mostly depend on how the hashCode and equals functions of the object used as a key are implemented. If the hashCode of two keys is the same, there's a hash collision, so equals will be used to understand if it's the same key or not. If equals is the same, then it's the same key, so the value is replaced. If not, the new value is added to the collection. Accessing and Writing values depends mostly on calculating the hash of the key followed by direct access to the value, making both operations really quick, O(1).
A set is pretty much like a hash map, without the "values" part, thus, it follows the same rules regarding the implementation of hashCode and equals operations for the added value.
It might be handy to study a bit about the Big-O notation and complexity of algorithms. If you are starting with Java, I'd strongly recommend the book Effective Java, by Joshua Bloch.
Hope it helps you dig further.
Does such a thing exist anywhere? Basically I see java has LinkedHashSet but no type of navigatable hash set?
By its very nature, a hash-based data structure is not ordered. You can write wrappers which supplement it with an additional data structure (this is more or less what LinkedHashMap does). But while it makes some sense to keep a hash set and a list, in order to keep a good ordering, you would need a tree or similar data structure. But the tree can work as a set by itself, so you would essentially be duplicating the information (more than in the case of set plus list, which differ more than two different set implemnentations). So the best solution is to just use TreeSet or another SortedSet if you need order.
It's not a HashSet, but as a descendant of Set you have the TreeSet
This class implements the Set interface, backed by a TreeMap instance. This class guarantees that the sorted set will be in ascending element order
You can traverse the elements using the iterator
public Iterator iterator()
Returns an iterator over the elements in this set. The elements are returned in ascending order
You can use a TreeSet but all the operations in it are lg(n)
You can use a LinkedHashSet, which keeps a linked list on top of hashset, but it only maintains insertion ordering (first inserted will be first element in iterator), you cannot have natural or custom ordering
You could also use TreeSet+HashSet approach but two reference for each element will be kept and while add and remove would still be lg(n) the contains will become expected o(n)
choose wisely :)
I guess there's TreeMap which is...related but definitely not the same :)
If I am going to create a Java Collection, and only want to fill it with elements, and then iterate through it (without knowing the necessary size beforehand), i.e. all I need is Collection<E>.add(E) and Collection<E>.iterator(), which concrete class should I choose? Is there any advantage to using a Set rather than a List, for example? Which one would have the least overhead?
which concrete class should I choose?
I would probably just go with an ArrayList or a LinkedList. Both support the add and iterator methods, and neighter of them have any considerable overhead.
Is there any advantage to using a Set rather than a List, for example?
No, I wouldn't say so. (Unless you rely on the order of the elements, in which case you must use a List, or want to disallow duplicates, in which case you should use a Set.)
(I don't see how any Set implementation could beat a list implementation for add / iterator methods, so I'd probably go with a List even if I don't care about order.)
Which one would have the least overhead?
Sounds like micro benchmarking here, but if I'd be forced to guess, I'd say ArrayList (or perhaps LinkedList in coner cases where ArrayLists need to reallocate memory often :-)
Do not go with a Set. Sets and Lists differ according to their purpose, that you should always consider when choosing the right Collection
a List is there for maintaining elements in the order you added them; and if you insert the same element twice it will be kept twice
a Set is there for holding one specific element exactly once (uniqueness); order is only relevant for specific implementations (like TreeSet), but still elements that are 'the same' would not be added twice
Set is only meaningful if you want to sort your objects and to make sure no duplicate element is 'registered'. Else, an ArrayList is just fine.
However, if you want to add elements while iterating too, an ArrayBlockingQueue is better.
Here are some key points which can help you to choose your collection according to your requirement -
List(ArrayList or LinkedList)
Allowed duplicate values.
Insertion order preserved.
Set
Not allowed duplicate values.
Insertion order is not preserved.
So according to your requirement List seems to be a suitable choice.
Now Between ArrayList and LinkedList -
ArrayList is a random access list. Use if your frequent operation is the retrieval of elements.
LinkedList is the best option if you want to add or remove elements from the list.
I've been using HashMaps since I started programming again in Java without really understanding these Collections thing.
Honestly I am not really sure if using HashMaps all the way would be best for me or for production code. Up until now it didn't matter to me as long as I was able to get the data I need the way I called them in PHP (yes, I admit whatever negative thing you are thinking right now) where $this_is_array['this_is_a_string_index'] provides so much convenience to recall an array of variables.
So now, I have been working with java for more than 3 months and came across the Interfaces I specified above and wondered, why are there so many of these things (not to mention, vectors, abstractList {oh well the list goes on...})?
I mean how are they different from each other?
And more importantly, what is the best Interface to use in my case?
The API is pretty clear about the differences and/or relations between them:
Collection
The root interface in the collection hierarchy. A collection represents a group of objects, known as its elements. Some collections allow duplicate elements and others do not. Some are ordered and others unordered.
http://download.oracle.com/javase/6/docs/api/java/util/Collection.html
List
An ordered collection (also known as a sequence). The user of this interface has precise control over where in the list each element is inserted. The user can access elements by their integer index (position in the list), and search for elements in the list.
http://download.oracle.com/javase/6/docs/api/java/util/List.html
Set
A collection that contains no duplicate elements. More formally, sets contain no pair of elements e1 and e2 such that e1.equals(e2), and at most one null element. As implied by its name, this interface models the mathematical set abstraction.
http://download.oracle.com/javase/6/docs/api/java/util/Set.html
Map
An object that maps keys to values. A map cannot contain duplicate keys; each key can map to at most one value.
http://download.oracle.com/javase/6/docs/api/java/util/Map.html
Is there anything in particular you find confusing about the above? If so, please edit your original question. Thanks.
A short summary of common java collections:
'Map': A 'Map' is a container that allows to store key=>value pair. This enables fast searches using the key to get to its associated value. There are two implementations of this in the java.util package, 'HashMap' and 'TreeMap'. The former is implemented as a hastable, while the latter is implemented as a balanced binary search tree (thus also having the property of having the keys sorted).
'Set': A 'Set' is a container that holds only unique elements. Inserting the same value multiple times will still result in the 'Set' only holding one instance of it. It also provides fast operations to search, remove, add, merge and compute the intersection of two sets. Like 'Map' it has two implementations, 'HashSet' and 'TreeSet'.
'List': The 'List' interface is implemented by the 'Vector', 'ArrayList' and 'LinkedList' classes. A 'List' is basically a collection of elements that preserve their relative order. You can add/remove elements to it and access individual elements at any given position. Unlike a 'Map', 'List' items are indexed by an int that is their position is the 'List' (the first element being at position 0 and the last at 'List.size()'-1). 'Vector' and 'ArrayList' are implemented using an array while 'LinkedList', as the name implies, uses a linked list. One thing to note is, unlike php's associative arrays (which are more like a Map), an array in Java and many other languages actually represents a contiguous block of memory. The elements in an array are basically laid out side by side on adjacent "slots" so to speak. This gives very fast lookup and write times, much faster than associative arrays which are implemented using more complex data structures. But they can't be indexed by anything other than the numeric positions within the array, unlike associative arrays.
To get a really good idea of what each collection is good for and their performance characteristics I would recommend getting a good idea about data structures like arrays, linked lists, binary search trees, hashtables, as well as stacks and queues. There is really no substitute to learning this if you want to be an effective programmer in any language.
You can also read the Java Collections trail to get you started.
In Brief (and only looking at interfaces):
List - a list of values, something like a "resizable array"
Set - a container that does not allow duplicates
Map - a collection of key/value pairs
A Map vs a List.
In a Map, you have key/value pairs. To access a value you need to know the key. There is a relationship that exists between the key and the value that persists and is not arbitrary. They are related somehow. Example: A persons DNA is unique (the key) and a persons name (the value) or a persons SSN (the key) and a persons name (the value) there is a strong relationship.
In a List, all you have are values (a persons name), and to access it you need to know its position in the list (index) to access it. But there is no permanent relationship between the position of the value in the list and its index, it is arbitrary.
■ List — An ordered collection of elements that allows duplicate entries
Concrete Classes:
ArrayList — Standard resizable list.
LinkedList — Can easily add/remove from beginning or end.
Vector — Older thread-safe version of ArrayList.
Stack — Older last-in, first-out class.
■ Set — Does not allow duplicates
Concrete Classes:
HashSet—Uses hashcode() to find unordered elements.
TreeSet—Sorted and navigable. Does not allow null values.
■ Queue — Orders elements for processing
Concrete Classes:
LinkedList — Can easily add/remove from beginning or end.
ArrayDeque—First-in, first-out or last-in, first-out. Does not allow null values.
■ Map — Maps unique keys to values
Concrete Classes:
HashMap — Uses hashcode() to find keys.
TreeMap — Sorted map. Does not allow null keys.
Hashtable — Older version of hashmap. Does not allow null keys or values.
That is a question that ultimately has a very complex answer--there are entire college classes dedicated to data structures. The short answer is that they all have trade-offs in memory usage and the speed of various operations.
What would be really healthy is some time with a nice book on data structures--I can almost guarantee that your code will improve significantly if you get a nice understanding of data structures.
That said, I can give you some quick, temporary advice from my experience with Java. For most simple internal things, ArrayList is generally preferred. For passing collections of data about, simple arrays are generally used. HashMap is only really used for cases when there is some logical reason to have special keys corresponding to values--I haven't seen anyone use them as a general data structure for everything. Other structures are more complicated and tend to be used in special cases.
As you already know, they are containers for objects. Reading their respective APIs will help you understand their differences.
Since others have described what are their differences about their usage, I will point you to this link which describes complexity of various data structures.
This list is programming language agnostic, and, as always, real world implementations will vary.
It is useful to understand complexity of various operations for each of these structures, since in the real world, it will matter if you're constantly searching for an object in your 1,000,000 element linked list that's not sorted. Performance will not be optimal.
List Vs Set Vs Map
1) Duplicity: List allows duplicate elements. Any number of duplicate elements can be inserted into the list without affecting the same existing values and their indexes.
Set doesn’t allow duplicates. Set and all of the classes which implements Set interface should have unique elements.
Map stored the elements as key & value pair. Map doesn’t allow duplicate keys while it allows duplicate values.
2) Null values: List allows any number of null values.
Set allows single null value at most.
Map can have single null key at most and any number of null values.
3) Order: List and all of its implementation classes maintains the insertion order.
Set doesn’t maintain any order; still few of its classes sort the elements in an order such as LinkedHashSet maintains the elements in insertion order.
Similar to Set Map also doesn’t stores the elements in an order, however few of its classes does the same. For e.g. TreeMap sorts the map in the ascending order of keys and LinkedHashMap sorts the elements in the insertion order, the order in which the elements got added to the LinkedHashMap.enter code here
List Vs Set Vs Map
1) Duplicity: List allows duplicate elements. Any number of duplicate elements can be inserted into the list without affecting the same existing values and their indexes.
Set doesn’t allow duplicates. Set and all of the classes which implements Set interface should have unique elements.
Map stored the elements as key & value pair. Map doesn’t allow duplicate keys while it allows duplicate values.
2) Null values: List allows any number of null values.
Set allows single null value at most.
Map can have single null key at most and any number of null values.
3) Order: List and all of its implementation classes maintains the insertion order.
Set doesn’t maintain any order; still few of its classes sort the elements in an order such as LinkedHashSet maintains the elements in insertion order.
Similar to Set Map also doesn’t stores the elements in an order, however few of its classes does the same. For e.g. TreeMap sorts the map in the ascending order of keys and LinkedHashMap sorts the elements in the insertion order, the order in which the elements got added to the LinkedHashMap.
Difference between Set, List and Map in Java -
Set, List and Map are three important interface of Java collection framework and Difference between Set, List and Map in Java is one of the most frequently asked Java Collection interview question. Some time this question is asked as When to use List, Set and Map in Java. Clearly, interviewer is looking to know that whether you are familiar with fundamentals of Java collection framework or not. In order to decide when to use List, Set or Map , you need to know what are these interfaces and what functionality they provide. List in Java provides ordered and indexed collection which may contain duplicates. Set provides an un-ordered collection of unique objects, i.e. Set doesn't allow duplicates, while Map provides a data structure based on key value pair and hashing. All three List, Set and Map are interfaces in Java and there are many concrete implementation of them are available in Collection API. ArrayList and LinkedList are two most popular used List implementation while LinkedHashSet, TreeSet and HashSet are frequently used Set implementation. In this Java article we will see difference between Map, Set and List in Java and learn when to use List, Set or Map.
Set vs List vs Map in Java
As I said Set, List and Map are interfaces, which defines core contract e.g. a Set contract says that it can not contain duplicates. Based upon our knowledge of List, Set and Map let's compare them on different metrics.
Duplicate Objects
Main difference between List and Set interface in Java is that List allows duplicates while Set doesn't allow duplicates. All implementation of Set honor this contract. Map holds two object per Entry e.g. key and value and It may contain duplicate values but keys are always unique. See here for more difference between List and Set data structure in Java.
Order
Another key difference between List and Set is that List is an ordered collection, List's contract maintains insertion order or element. Set is an unordered collection, you get no guarantee on which order element will be stored. Though some of the Set implementation e.g. LinkedHashSet maintains order. Also SortedSet and SortedMap e.g. TreeSet and TreeMap maintains a sorting order, imposed by using Comparator or Comparable.
Null elements
List allows null elements and you can have many null objects in a List, because it also allowed duplicates. Set just allow one null element as there is no duplicate permitted while in Map you can have null values and at most one null key. worth noting is that Hashtable doesn't allow null key or values but HashMap allows null values and one null keys. This is also the main difference between these two popular implementation of Map interface, aka HashMap vs Hashtable.
Popular implementation
Most popular implementations of List interface in Java are ArrayList, LinkedList and Vector class. ArrayList is more general purpose and provides random access with index, while LinkedList is more suitable for frequently adding and removing elements from List. Vector is synchronized counterpart of ArrayList. On the other hand, most popular implementations of Set interface are HashSet, LinkedHashSet and TreeSet. First one is general purpose Set which is backed by HashMap , see how HashSet works internally in Java for more details. It also doesn't provide any ordering guarantee but LinkedHashSet does provides ordering along with uniqueness offered by Set interface. Third implementation TreeSet is also an implementation of SortedSet interface, hence it keep elements in a sorted order specified by compare() or compareTo() method. Now the last one, most popular implementation of Map interface are HashMap, LinkedHashMap, Hashtable and TreeMap. First one is the non synchronized general purpose Map implementation while Hashtable is its synchronized counterpart, both doesn' provide any ordering guarantee which comes from LinkedHashMap. Just like TreeSet, TreeMap is also a sorted data structure and keeps keys in sorted order.
Given a List of MyClass objects (and a custom Comparitor myComparitor if needed), what good options are there for checking if the List contains two "equal" objects?
Edit: if there are duplicates, return a reference to one or more of the duplicates.
Overriding MyClass.equals(MyClass) in this case is not an option.
My initial thought is to create a hash table of sorts, but I suspect that there's a non-hack way to accomplish the same thing:
SortedSet mySet = new TreeSet(myComparitor);
mySet.addAll(myList);
// Find duplicates in a sorted set in O(N) time
P.S. Is there a good reference on Markdown?
If the element's equals(Object) method does not give you the semantic that you require, then HashMap or HashSet are not options. Your choices are:
Use a TreeMap for de-duping. This is O(NlogN).
Sort the ArrayList or a copy, then iterate over looking for element i equals element i + 1. This is O(NlogN).
Find an alternative implementation of hash sets that allows you to provide a separate object to implement equality and hashing. (Neither Apache or Google collections support this, so you'll need to look further afield.)
Create a wrapper class for your element type that overrides equals(Object) and hashCode(), and de-dup using a HashSet of wrapped objects. This is O(N), but the constant of proportionality will be larger than a simple HashSet due to creation of wrapper objects.
When de-duping with a Set it is probably better to use a loop rather than addAll. This is necessary if you need to know what all of the duplicates are. If you don't need to know that, then using a loop allows you to stop when you find the first duplicate. The only case where addAll is likely to perform better is when there are likely to be no duplicates.
if you already have a sorted list, you could just look at any element and the next element, and if they're the same you have dups.
in your question you are using a TreeSet, which would have culled out duplicates already, so if you just need to know if you have duplicates, just check the size of mySet vs the size of myList. if they aren't the same you have dups.