For example, I want to zip a file stored in /Users/me/Desktop/image.jpg
I made this method:
public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// VER SI HAY QUE CREAR EL ROOT PATH
boolean result = (new File(destinationDir)).mkdirs();
String zipFullFilename = destinationDir + "/" + zipFilename ;
System.out.println(result);
// Create the ZIP file
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename));
// Compress the files
for (String filename: sourcesFilenames) {
FileInputStream in = new FileInputStream(filename);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(filename));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
// Complete the entry
out.closeEntry();
in.close();
} // Complete the ZIP file
out.close();
return true;
} catch (IOException e) {
return false;
}
}
But when I extract the file, the unzipped files have the full path.
I don't want the full path of each file in the zip i only want the filename.
How can I made this?
Here:
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(filename));
You're creating the entry for that file using the whole path. If you just use the name ( without the path ) you'll have what you need:
// Add ZIP entry to output stream.
File file = new File(filename); //"Users/you/image.jpg"
out.putNextEntry(new ZipEntry(file.getName())); //"image.jpg"
You're finding your source data using the relative path to the file, then setting the Entry to the same thing. Instead you should turn the source into a File object, and then use
putNextEntry(new ZipEntry(sourceFile.getName()))
that'll give you just the final part of the path (ie, the actual file name)
Do as Jason said, or if you want to keep your method signature, do it like this:
out.putNextEntry(new ZipEntry(new File(filename).getName()));
or, using FileNameUtils.getName from apache commons/io:
out.putNextEntry(new ZipEntry(FileNameUtils.getName(filename)));
You could probably get away with accessing source files via new FileInputStream(new File(sourceFilePath, sourceFileName)).
// easy way of zip a file
import java.io.*;
import java.util.zip.*;
public class ZipCreateExample{
public static void main(String[] args) throws Exception {
// input file
FileInputStream in = new FileInputStream("F:/ZipCreateExample.txt");;
// out put file
ZipOutputStream out =new ZipOutputStream(new FileOutputStrea("F:/tmp.zip"));
// name of file in zip folder
out.putNextEntry(new ZipEntry("zippedfile.txt"));
byte[] b = new byte[1024];
int count;
// writing files to new zippedtxt file
while ((count = in.read(b)) > 0) {
System.out.println();
out.write(b, 0, count);
}
out.close();
in.close();
}
}
try {
String zipFile = "/locations/data.zip";
String srcFolder = "/locations";
File folder = new File(srcFolder);
String[] sourceFiles = folder.list();
//create byte buffer
byte[] buffer = new byte[1024];
/*
* To create a zip file, use
*
* ZipOutputStream(OutputStream out) constructor of ZipOutputStream
* class.
*/
//create object of FileOutputStream
FileOutputStream fout = new FileOutputStream(zipFile);
//create object of ZipOutputStream from FileOutputStream
ZipOutputStream zout = new ZipOutputStream(fout);
for (int i = 0; i < sourceFiles.length; i++) {
if (sourceFiles[i].equalsIgnoreCase("file.jpg") || sourceFiles[i].equalsIgnoreCase("file1.jpg")) {
sourceFiles[i] = srcFolder + fs + sourceFiles[i];
System.out.println("Adding " + sourceFiles[i]);
//create object of FileInputStream for source file
FileInputStream fin = new FileInputStream(sourceFiles[i]);
/*
* To begin writing ZipEntry in the zip file, use
*
* void putNextEntry(ZipEntry entry) method of
* ZipOutputStream class.
*
* This method begins writing a new Zip entry to the zip
* file and positions the stream to the start of the entry
* data.
*/
zout.putNextEntry(new ZipEntry(sourceFiles[i].substring(sourceFiles[i].lastIndexOf("/") + 1)));
/*
* After creating entry in the zip file, actually write the
* file.
*/
int length;
while ((length = fin.read(buffer)) > 0) {
zout.write(buffer, 0, length);
}
/*
* After writing the file to ZipOutputStream, use
*
* void closeEntry() method of ZipOutputStream class to
* close the current entry and position the stream to write
* the next entry.
*/
zout.closeEntry();
//close the InputStream
fin.close();
}
}
//close the ZipOutputStream
zout.close();
System.out.println("Zip file has been created!");
} catch (IOException ioe) {
System.out.println("IOException :" + ioe);
}
If you zip two files of the same name but with different paths you will run into duplicate file entry errors, though.
Related
My app is a tender document system where each tender number has one or more pdf files attached.
application is done in java ee using struts and mysql.
in a database table the paths of each related pdf file for a tender number is stores.
I want to get all the pdf files and create a single ZIP file for each tender number so that user can download that zip file and have all the related documents in a single click.
I tried Google and found something called ZipOutputStream but i cannot understand how to use this in my application.
You're almost there... This is a small example of how to use ZipOutputStream... let's asume that you have a JAVA helper H that returns database records with pdf file paths (and related info):
FileOutputStream zipFile = new FileOutputStream(new File("xxx.zip"));
ZipOutputStream output = new ZipOutputStream(zipFile);
for (Record r : h.getPdfRecords()) {
ZipEntry zipEntry = new ZipEntry(r.getPdfName());
output.putNextEntry(zipEntry);
FileInputStream pdfFile = new FileInputStream(new File(r.getPath()));
IOUtils.copy(pdfFile, output); // this method belongs to apache IO Commons lib!
pdfFile.close();
output.closeEntry();
}
output.finish();
output.close();
Checkout this code, here you can easily create a zip file directory:
public class CreateZipFileDirectory {
public static void main(String args[])
{
try
{
String zipFile = "C:/FileIO/zipdemo.zip";
String sourceDirectory = "C:/examples";
//create byte buffer
byte[] buffer = new byte[1024];
FileOutputStream fout = new FileOutputStream(zipFile);
ZipOutputStream zout = new ZipOutputStream(fout);
File dir = new File(sourceDirectory);
if(!dir.isDirectory())
{
System.out.println(sourceDirectory + " is not a directory");
}
else
{
File[] files = dir.listFiles();
for(int i=0; i < files.length ; i++)
{
System.out.println("Adding " + files[i].getName());
FileInputStream fin = new FileInputStream(files[i]);
zout.putNextEntry(new ZipEntry(files[i].getName()));
int length;
while((length = fin.read(buffer)) > 0)
{
zout.write(buffer, 0, length);
}
zout.closeEntry();
fin.close();
}
}
zout.close();
System.out.println("Zip file has been created!");
}
catch(IOException ioe)
{
System.out.println("IOException :" + ioe);
}
}
}
My UnZip class does not unzip whole the file. This class is called from another activity. My zip file is saved in the main directory of the phone's internal storage. The zip file has folders and some video.
What's wrong with this unzip?
What and how should I read file from zip' decompress and unzip is the same meaning?
Thanks for your help!
public class Unzip {
private static final String INPUT_ZIP_FILE = "sdcard/downloaded_issue.zip";
private static final String OUTPUT_FOLDER = "sdcard/Atlantis/";
public static void main()
{
Unzip unZip = new Unzip();
unZip.unZipIt(INPUT_ZIP_FILE, OUTPUT_FOLDER);
}
/**
* Unzip it
* #param zipFile input zip file
* #param outputFolder zip file output folder
*/
public void unZipIt(String zipFile, String outputFolder){
byte[] buffer = new byte[1024];
try{
//create output directory is not exists
File folder = new File(OUTPUT_FOLDER);
if(!folder.exists()){
folder.mkdir();
}
//get the zip file content
ZipInputStream zis =
new ZipInputStream(new FileInputStream(zipFile));
//get the zipped file list entry
ZipEntry ze = zis.getNextEntry();
while(ze!=null){
String fileName = ze.getName();
File newFile = new File(outputFolder + File.separator + fileName);
System.out.println("file unzip : "+ newFile.getAbsoluteFile());
//create all non exists folders
//else you will hit FileNotFoundException for compressed folder
new File(newFile.getParent()).mkdirs();
FileOutputStream fos = new FileOutputStream(newFile);
int len;
while ((len = zis.read(buffer)) > 0) {
fos.write(buffer, 0, len);
}
fos.close();
if (ze.isDirectory()) {
ze = zis.getNextEntry();
}
}
zis.closeEntry();
zis.close();
System.out.println("Done");
}catch(IOException ex){
ex.printStackTrace();
}
}
}
I think your 'while' loop is broken; you're only fetching the next entry if that next entry is a directory, while I assume you're probably trying to skip the directories.
Anyway, since you create the folders for all files you encounter, you can just skip the folder entries and write the file entries. The only exception would be the creation of empty folders.
Replacing the while-loop by this code should work:
while(ze!=null){
String fileName = ze.getName();
File newFile = new File(outputFolder + File.separator + fileName);
System.out.println("file unzip : "+ newFile.getAbsoluteFile());
//create all non exists folders
//else you will hit FileNotFoundException for compressed folder
if (ze.isDirectory()) {
// create the folder
newFile.mkdirs();
}
else {
// create the parent folder and write to disk
new File(newFile.getParent()).mkdirs();
FileOutputStream fos = new FileOutputStream(newFile);
int len;
while ((len = zis.read(buffer)) > 0) {
fos.write(buffer, 0, len);
}
fos.close();
}
// get the next item
ze = zis.getNextEntry();
}
if(!ErmUtil.isNull(listOfActualFilePaths) && listOfActualFilePaths.size()>0){
FileOutputStream fos = new FileOutputStream("/smiles/wrk/attachments/ermWeb/taxation/testing.zip");
ZipOutputStream zos = new ZipOutputStream(fos);
Iterator itrOnFNames = listOfActualFilePaths.iterator();
while (itrOnFNames.hasNext()) {
StringBuffer ActualPath = (StringBuffer) itrOnFNames.next();
addToZipFile(ActualPath.toString(), zos);
}
zos.close();//Closing Both Streams
fos.close();
}
public void addToZipFile(String fileName, ZipOutputStream zos) throws FileNotFoundException, IOException {
System.out.println("Writing '" + fileName + "' to zip file");
File file = new File(fileName);
int index = fileName.lastIndexOf("/");
String fileNameForZip = fileName.substring(index+1);
FileInputStream fis = new FileInputStream(file);
ZipEntry zipEntry = new ZipEntry(fileNameForZip);
zos.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zos.write(bytes, 0, length);
}
zos.closeEntry();
fis.close();
}
I am using above code, to save zip-ed file on a specific location. But what i want to do is that, instead of saving that file, it get downloaded directly.
Edit 1
See If I want to download a zip file,then according to above code, on path /smiles/wrk/attachments/ermWeb/taxation/testing.zip it will be saved first,then from that folder, I(server) can send it to client(Computer).
But I don't want to save it on the specified path,Instead of "saving first to folder and then sending to client", I directly want to send it to client.
I am trying to create a zip file of multiple image files. I have succeeded in creating the zip file of all the images but somehow all the images have been hanged to 950 bytes. I don't know whats going wrong here and now I can't open the images were compressed into that zip file.
Here is my code. Can anyone let me know what's going here?
String path="c:\\windows\\twain32";
File f=new File(path);
f.mkdir();
File x=new File("e:\\test");
x.mkdir();
byte []b;
String zipFile="e:\\test\\test.zip";
FileOutputStream fout=new FileOutputStream(zipFile);
ZipOutputStream zout=new ZipOutputStream(new BufferedOutputStream(fout));
File []s=f.listFiles();
for(int i=0;i<s.length;i++)
{
b=new byte[(int)s[i].length()];
FileInputStream fin=new FileInputStream(s[i]);
zout.putNextEntry(new ZipEntry(s[i].getName()));
int length;
while((length=fin.read())>0)
{
zout.write(b,0,length);
}
zout.closeEntry();
fin.close();
}
zout.close();
This is my zip function I always use for any file structures:
public static File zip(List<File> files, String filename) {
File zipfile = new File(filename);
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// create the ZIP file
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipfile));
// compress the files
for(int i=0; i<files.size(); i++) {
FileInputStream in = new FileInputStream(files.get(i).getCanonicalName());
// add ZIP entry to output stream
out.putNextEntry(new ZipEntry(files.get(i).getName()));
// transfer bytes from the file to the ZIP file
int len;
while((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
// complete the entry
out.closeEntry();
in.close();
}
// complete the ZIP file
out.close();
return zipfile;
} catch (IOException ex) {
System.err.println(ex.getMessage());
}
return null;
}
Change this:
while((length=fin.read())>0)
to this:
while((length=fin.read(b, 0, 1024))>0)
And set buffer size to 1024 bytes:
b=new byte[1024];
I am trying to implement program to zip and unzip a file. All I want to do is to zip a file (fileName.fileExtension) with name as fileName.zip and on unzipping change it again to fileName.fileExtension.
This is how I used to rename files or change its extension.
public static void modify(File file)
{
int index = file.getName().lastIndexOf(".");
//print filename
//System.out.println(file.getName().substring(0, index));
//print extension
//System.out.println(file.getName().substring(index));
String ext = file.getName().substring(index);
//use file.renameTo() to rename the file
file.renameTo(new File("Newname"+ext));
}
edit: John's method renames the file (keeping the extension). To change the extension do:
public static File changeExtension(File f, String newExtension) {
int i = f.getName().lastIndexOf('.');
String name = f.getName().substring(0,i);
return new File(f.getParent(), name + newExtension);
}
This changes only the last extension to a filename, i.e. the .gz part of archive.tar.gz. Therefore it works fine with Linux hidden files, for which the name starts with a .
This is quite safe because if getParent() returns null (i.e. in the event of the parent being the system root) it is "cast" to an empty String as the whole argument to the File constructor is evaluated first.
The only case where you will get a funny output is if you pass in a File representing the system root itself, in which case the null is prepended to the rest of the path string.
Try with:
File file = new File("fileName.zip"); // handler to your ZIP file
File file2 = new File("fileName.fileExtension"); // destination dir of your file
boolean success = file.renameTo(file2);
if (success) {
// File has been renamed
}
I would check, if the file has an extension before changing. The solution below works also with files without extension or multiple extensions
public File changeExtension(File file, String extension) {
String filename = file.getName();
if (filename.contains(".")) {
filename = filename.substring(0, filename.lastIndexOf('.'));
}
filename += "." + extension;
file.renameTo(new File(file.getParentFile(), filename));
return file;
}
#Test
public void test() {
assertThat(changeExtension(new File("C:/a/aaa.bbb.ccc"), "txt"),
is(new File("C:/a/aaa.bbb.txt")));
assertThat(changeExtension(new File("C:/a/test"), "txt"),
is(new File("C:/a/test.txt")));
}
By the same logic as mentioned #hsz, but instead simply use replacement:
File file = new File("fileName.fileExtension"); // creating object of File
String str = file.getPath().replace(".fileExtension", ".zip"); // replacing extension to another
file.renameTo(new File(str));
I want to avoid the new extension just happening to be in the path or filename itself. I like a combination of java.nio and apache StringFilenameUtils.
public void changeExtension(Path file, String extension) throws IOException {
String newFilename = FilenameUtils.removeExtension(file.toString()) + EXTENSION_SEPARATOR_STR + extension;
Files.move(file, Paths.get(newFilename, StandardCopyOption.REPLACE_EXISTING));
}
If you are using Kotlin you can use from this property of your file object:
file.nameWithoutExtension + "extension"
FilenameUtils.getFullPathNoEndSeparator(doc.getDocLoc()) + "/" +
FilenameUtils.getBaseName(doc.getDocLoc()) + ".xml"
My firend was working on a zipper in Java some 4 months back, I got this code from him.
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipFiles {
List<String> filesListInDir = new ArrayList<String>();
public static void main(String[] args) {
File file = new File("/Users/pankaj/sitemap.xml");
String zipFileName = "/Users/pankaj/sitemap.zip";
File dir = new File("/Users/pankaj/tmp");
String zipDirName = "/Users/pankaj/tmp.zip";
zipSingleFile(file, zipFileName);
ZipFiles zipFiles = new ZipFiles();
zipFiles.zipDirectory(dir, zipDirName);
}
/**
* This method zips the directory
* #param dir
* #param zipDirName
*/
private void zipDirectory(File dir, String zipDirName) {
try {
populateFilesList(dir);
//now zip files one by one
//create ZipOutputStream to write to the zip file
FileOutputStream fos = new FileOutputStream(zipDirName);
ZipOutputStream zos = new ZipOutputStream(fos);
for(String filePath : filesListInDir){
System.out.println("Zipping "+filePath);
//for ZipEntry we need to keep only relative file path, so we used substring on absolute path
ZipEntry ze = new ZipEntry(filePath.substring(dir.getAbsolutePath().length()+1, filePath.length()));
zos.putNextEntry(ze);
//read the file and write to ZipOutputStream
FileInputStream fis = new FileInputStream(filePath);
byte[] buffer = new byte[1024];
int len;
while ((len = fis.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
zos.closeEntry();
fis.close();
}
zos.close();
fos.close();
} catch (IOException e) {
e.printStackTrace();
}
}
/**
* This method populates all the files in a directory to a List
* #param dir
* #throws IOException
*/
private void populateFilesList(File dir) throws IOException {
File[] files = dir.listFiles();
for(File file : files){
if(file.isFile())
filesListInDir.add(file.getAbsolutePath());
else
populateFilesList(file);
}
}
/**
* This method compresses the single file to zip format
* #param file
* #param zipFileName
*/
private static void zipSingleFile(File file, String zipFileName) {
try {
//create ZipOutputStream to write to the zip file
FileOutputStream fos = new FileOutputStream(zipFileName);
ZipOutputStream zos = new ZipOutputStream(fos);
//add a new Zip Entry to the ZipOutputStream
ZipEntry ze = new ZipEntry(file.getName());
zos.putNextEntry(ze);
//read the file and write to ZipOutputStream
FileInputStream fis = new FileInputStream(file);
byte[] buffer = new byte[1024];
int len;
while ((len = fis.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
//Close the zip entry to write to zip file
zos.closeEntry();
//Close resources
zos.close();
fis.close();
fos.close();
System.out.println(file.getCanonicalPath()+" is zipped to "+zipFileName);
} catch (IOException e) {
e.printStackTrace();
}
}
}
I haven't tried it personally, but he and also some of my other friends told me that it works.