I put a browser in my jsp page, and when I select the file via the browser
and I'm doing a System.outn select the file path, I only have the name,
and I need to recover all the file path selected
<form:form onsubmit="document.getElementById('idButton').value='Traîtement en cours ...'" action="ajouter.html"
method="POST">
<input type="file" name="cible">
<input type="submit" id="idButton" name="ajouter" value="Ajouter" tabindex="50"/>
</form:form>
(ActionForm)
String leChemin = (String) request.getParameter("cible");
System.out.println("leChemin = " + leChemin);
You cannot do this, for security reasons, file path from clients are not shown.
But if really need to get the path, do not rely on the browser use applet.
The path would be useless for you, none the less. Moreover, as a privacy concern, its not really a good idea to know the path at client's machine.
Related
I'm creating a fantastic HTML editor. I haven't thought about the title, so it's gonna be "HTML Editor." The input (in the code below) is to name the file. how could I name a file using the HTML's JavaScript components? Is there anything wrong with the code, or what?
<input id="title" required placeholder="File Name" title="Please fill this space up, and don't include symbols.">
<a download href="data:text/html;utf-8,(contents)"> <button>Download File</button> </a>
The downloading part is great and all, and I'm glad to say it's working, but... the name "download" is pretty irritating. Can you help me out here?
You need to set the download attribute to your filename.
<a download="filename.jpg" ... />
I'm working on the problem for almost one day,and I can't figure out a solution.
I want to add a download service into my jsp page,and the code like this:
response.setHeader("Content-Disposition","attachment;filename=authData"+new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(new Date())+".csv");
PrintWriter out = response.getWriter();
and I use a trigger button to link to background.and the codes like this:
<input type="submit" class="btn_sure fw" value="query" onclick="queryAuthDataList();"/>
<input type="reset" class="btn_cancel fw" value="reset">
<input type="submit" class="btn_sure fw" value="download CSV" onclick="exportAuthDataList();" >
and the following onclick funtion like this:
function exportAuthDataList(){
$("#queryAuthDataForm").attr("action","export").submit();
}
function queryAuthDataList(){
$("#queryAuthDataForm").attr("action","query").submit();
}
for some reasons , I must use GET to collect the tag names and values in jsp file.
Here comes the problem,when I select data from DB2,and there're many results,I must paging them,But when I click next page,it's starting download csv file automaticly.I define different redirect keywords in Jquery,but I can't simplely add jquery function in the "next page" link.Because I may get some other links.
How can I stop the file downloading when I click a different link ?
I am stucked to something. In spring 2.5 framework, I want to upload file by using MultipartFile. I have a class called Dosya including property which is MultipartFile multiDosya. My command object is dosya. Additonally, The file which will be uploaded is stored BLOB type in database, sql developer,.
In jsp, I try to bind this propert like below:
<spring:bind path="dosya.multiDosya">
<input class="file" type="file" name="yuklenecekDosya" id="yuklenecekDosya" />
</spring:bind>
In onSubmit,
Dosya dosyaObjesi = (Dosya)command;
MultipartFile yuklenecekDosya = dosyaObjesi.getMultiDosya();
The commandObject dosyaObjesi is taken without problem, however,
dosyaObjesi.getMultiDosya()
value is coming null although file that will be uploaded is selected in jsp.
After searching on the net, I found that this line below should be added to the initBinder.
binder.registerCustomEditor(byte[].class, new ByteArrayMultipartFileEditor());
However, my class says that there is no such class ByteArrayMultipartFileEditor, but it is available in spring-2.5.jar. I import
import org.springframework.web.multipart.*;
can trace out the problem . could someone please help me out
Thanks in advance.
Have you specified form encryption type(enctype="multipart/form-data")?. That could be the reason sometimes.
Ex:
<form method="post" name="formName" action="action.htm" commandName="object" enctype="multipart/form-data">
I have solved the problem. Everything is ok, however, in the code below
<input class="file" type="file" name="yuklenecekDosya" id="yuklenecekDosya" />
the attribute name must be ${status.expression} . That is, exactly, name="${status.expression}" like that. If only the name property value is given like that, bind operation works correctly.
Thanks,
Regards,
I have been trying to load a file trough a form in HTML and send it to Java in order to process it. I made a JavaScript function so i can pass the file path but it won't work because it will send only the file's name and extension so Java will just get just a String to process and throw a NullPointerEception.
Does anyone have any idea how i can solve this problem?
PS: I'm sorry for the noobie question but i don't know JS.
i think the file which you forward for java is must read by input output operation in bytes beacuse java is understand only text file or byte array by byte array you can store any image ,pdf etc.
i have a regular html form like this:
<form action="MultipartServlet" name="form" id="form" method="post" enctype="multipart/form-data">
<td><input type="file" name="upload" id="upload" />
<td><input type="button" value="Check" onclick="FileValidator.check()"/>
i cannot use type="submit" because for an odd reason the application is crushing
the JS code:
check: function() {
var file = $F("upload");
new Ajax.Request( 'url', {
parameters: '...&action=fileValidator&upload=' + file,
onSuccess: function(response) {
var result = eval('(' + response.responseText + ')');
if (result.success) {
displayErrorsFromFile();
} else {
alert("Errors! " + response.responseText);
}
},
onFailure: reportError
})
}
in the Java code i just try to get the file trough the "upload" parameter and validate the file's imput.
so i guess that the "upload" parameter has to get a bites array of the entire file so it can process it... or somehow the path of the file
"The content type "multipart/form-data" should be used for submitting forms that contain files, non-ASCII data, and binary data."
http://www.w3.org/TR/html4/interact/forms.html#h-17.13.4.2
What does enctype='multipart/form-data' mean?
So basically it doesn't really matter how your submit your form on the client, <input type="submit" />, some java script like document.forms["myform"].submit(); or however your js library does it, as long as you have <input type="file" /> in your form on the client and some server side component (like servlet), which could get to the binary file submitted, from the request.
For e really comprehensive example and explanation see this post:
How to upload files to server using JSP/Servlet?
I am pretty new to servlets and web development in general.
So basically I have a servlet that queries a database and returns some values, like a name. What I want is to turn the name into a link that opens a details page for that name (which another servlet would handle). How can I send the name to the other servlet so it can query a database for the relevant details?
Maybe I'm taking the wrong approach?
Edit: I am using Tomcat 5.5
Pass it as request parameter.
Either add it to the query string of the URL of the link to the other servlet which is then available by request.getParameter("name") in the doGet() method.
link
Or add it as a hidden input field in a POST form which submits to the other servlet which is then available by request.getParameter("name") in the doPost() method.
<form action="otherservlet" method="post">
<input type="hidden" name="name" value="${name}" />
<input type="submit" />
</form>
See also:
Servlets info page - contains a Hello World
Not sure if I understand correctly, but you may look at javax.servlet.RequestDispatcher and forward the url to the second servlet.
The url could be created using the name:
http://myhost.mydomain/my.context/servlet2.do?name=John
I would create the URL either in the first servlet or in a client using a configurable template for the URL. This way both servlets are clearly separated - you can even have each one on different machine.