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Hibernate duplicates record along with null value(new row as duplicate) while saving

I am getting following issue while saving entity in hibernate -
It duplicates the record with null values -
(2661956,2601555,'Chloe','Chloe','Thooks',null,null,null,null,null,null,'Y','N','XYZ',to_date('15-NOV-16','DD-MON-RR'),null,null)
with a duplicate -
(2661946,2601555,null,null,null,null,null,null,null,null,null,'Y','N','XYZ',to_date('15-NOV-16','DD-MON-RR'),null,null) -
We have the following mapping -
Parent -
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping default-lazy="false">
<class name="com.sm.persistence.LOADetailBO" table="LOADETAILS">
<id name="loaDetailsId" type="long">
<column name="LOA_ID" precision="38" scale="0"/>
<generator class="com.sm.persistence.dao.seqgen.LOADetailSeqGen">
</generator>
</id>
<many-to-one name="reregistration" class="com.sm.persistence.RerBO" fetch="join">
<column name="RER_ID" precision="38" scale="0"/>
</many-to-one>
<property name="relatedPlanManager" type="string">
<column name="RELATED_PLAN_MANAGER"/>
</property>
<property name="relatedPlanManagerCode" type="string">
<column name="RELATED_PLAN_MANAGER_CODE"/>
</property>
<set name="relatedPlanManagerAddress" inverse="true" cascade="all-delete-orphan">
<key>
<column name="LOA_ID" precision="38" scale="0" not-null="false"/>
</key>
<one-to-many class="com.sm.persistence.AddressBO" />
</set>
<set name="corporateCustomers" inverse="true" cascade="all-delete-orphan">
<key>
<column name="LOA_ID" precision="38" scale="0" not-null="false"/>
</key>
<one-to-many class="com.sm.persistence.CorporateCustomerBO" />
</set>
<set name="privateCustomers" inverse="true" cascade="all-delete-orphan">
<key>
<column name="LOA_ID" precision="38" scale="0" not-null="false" />
</key>
<one-to-many class="com.sm.persistence.PrivateCustomerBO"/>
</set>
<set name="unwrappedAccount" inverse="true" cascade="all-delete-orphan">
<key>
<column name="LOA_ID" precision="38" scale="0" not-null="false"/>
</key>
<one-to-many class="com.sm.persistence.UnwrappedAccountBO" />
</set>
<set name="wrappedAccount" inverse="true" cascade="all-delete-orphan">
<key>
<column name="LOA_ID" precision="38" scale="0" not-null="false" />
</key>
<one-to-many class="com.sm.persistence.WrappedAccountBO"/>
</set>
</class>
</hibernate-mapping>
Child -
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping default-lazy="false">
<class name="com.sm.persistence.PrivateCustomerBO" table="RER_CUSTOMER_DETAIL">
<id name="privateCustomerId" type="long">
<column name="RERE_CUSTOMER_ID" precision="38" scale="0"/>
<generator class="com.sm.persistence.dao.seqgen.PrivateCustomerSeqGen">
</generator>
</id>
<many-to-one name="loaDetail" class="com.sm.persistence.LOADetailBO" fetch="join">
<column name="LOA_DETAILS_ID" precision="38" scale="0"/>
</many-to-one>
<property name="title" type="string">
<column name="TITLE"/>
</property>
<property name="firstName" type="string">
<column name="FIRST_NAME"/>
</property>
<property name="surname" type="string">
<column name="SURNAME"/>
</property>
<set name="address" inverse="false" cascade="all-delete-orphan">
<key>
<column name="PRIVATE_CUSTOMER_ID" precision="38" scale="0" not-null="false"/>
</key>
<one-to-many class="com.sm.persistence.AddressBO" />
</set>
<property name="primary" type="string">
<column name="IS_PRIMARY"/>
</property>
<property name="corporate" type="string">
<column name="IS_CORPORATE"/>
</property>
<!--<property name="dateofBirth" type="string">
<column name="DATE_OF_BIRTH"/>
</property>-->
<property name="nationalInsurance" type="string">
<column name="NINO"/>
</property>
</class>
</hibernate-mapping>
I checked parent object both pre and post save and can't find any object with null value populated. However, when I fetch the object hierarchy with criteria api it returns duplicate record with null.
Please guide.

Quick answer:
PrivateCustomerBO is a child of LOADetailBO. So when your java code
saves a PrivateCustomerBO object it will write to all tables
specified against these 2 objects: RER_CUSTOMER_DETAIL = primary
table for PrivateCustomerBO, LOADETAILS = primary table for
LOADetailBO, plus all tables referenced by these two objects via
many-to-one or one-to-many mappings. CORRECT BEHAVIOUR
Expanding the bolded bit above, LOADetailBO is referenced by
PrivateCustomerBO via:
<many-to-one name="loaDetail" class="com.sm.persistence.LOADetailBO" fetch="join">
<column name="LOA_DETAILS_ID" precision="38" scale="0"/>
</many-to-one>
This means that LOADETAILS is additionally referenced as a related
table, not just a parent and a second row is written (in this case
there is some data missing (NULL) because your program hasn't
populated it for the referenced entity). INCORRECT BEHAVIOUR.
Fix: remove the many-to-one mapping shown above (it's redundant and covered by parent).

How to do many-to-one mapping in a Hibernate hbm file

I need to use many to one relationship between two tables while using the spring hibernate integrated program. I have employee.hbm.xml and admin.hbm.xml which has corresponding bean classes.
empid in employee.hbm.xml acts as a foreign key in admin.hbm.xml .
employee.hbm.xml
<hibernate-mapping>
<class name="entity.Employee" table="employee">
<id name="empid" column="empid" type="java.lang.Integer">
<generator class="native"></generator>
</id>
<property name="empname" column="empname" type="java.lang.String"></property>
<property name="password" column="password" type="java.lang.String"></property>
<property name="designation" column="designation" type="java.lang.String"></property>
<property name="domain" column="domain" type="java.lang.String"></property>
<property name="role" column="role" type="java.lang.String"></property>
<property name="head" column="head" type="java.lang.String"></property>
<property name="specialist" column="specialist" type="java.lang.String"></property>
</class>
</hibernate-mapping>
admin.hbm.xml
<hibernate-mapping>
<class name="entity.Admin" table="admin">
<id name="courseid" column="courseid" type="java.lang.Integer">
<generator class="increment"></generator>
</id>
<property name="coursename" column="coursename" type="java.lang.String"></property>
<property name="participants" column="participants" type="java.lang.Integer"></property>
<!-- <property name="empid" column="empid" type="java.lang.Integer"/> -->
<many-to-one name="employee" class="entity.Employee" fetch="select"
column="empid" cascade="all"/>
</class>
</hibernate-mapping>
while i try to insert to admin table, i get a NullPointerException on field empid. what should i modify to make foreign key constraint between these two hbm files???

How to map an auto increment field in hibernate?

Please have a look at the below XML code
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<!-- Generated Feb 17, 2015 10:01:43 PM by Hibernate Tools 4.3.1 -->
<hibernate-mapping>
<class name="model.main.Family" table="family" catalog="****" optimistic-lock="version">
<id name="idFamily" type="int">
<column name="idFamily" />
<generator class="assigned" />
</id>
<many-to-one name="employee" class="model.main.Employee" fetch="select">
<column name="idEmployee" not-null="true" />
</many-to-one>
<property name="firstName" type="string">
<column name="FirstName" length="45" />
</property>
<property name="middleName" type="string">
<column name="MiddleName" length="45" />
</property>
<property name="lastName" type="string">
<column name="LastName" length="45" />
</property>
<property name="dob" type="date">
<column name="DOB" length="10" />
</property>
<property name="passportNumber" type="string">
<column name="PassportNumber" length="45" not-null="true" />
</property>
<property name="dateLeft" type="date">
<column name="DateLeft" length="10" />
</property>
<property name="lastUpdated" type="timestamp">
<column name="LastUpdated" length="19" not-null="true" />
</property>
<set name="visas" table="visa" inverse="true" lazy="true" fetch="select">
<key>
<column name="idFamily" />
</key>
<one-to-many class="model.main.Visa" />
</set>
</class>
</hibernate-mapping>
It is the Hibernate mapping class of my database table Family. We create the database separately using MySQL Work bench and then generate the mapping classes. We auto generated the mapping files using netbeans as mentioned in "Generating Hibernate Mapping Files and Java Classes" section of netbeans tutorial.
Now we have a problem. That is, we changed the primary key (idFamily) of our table Family to an auto generated field inside MySQL. Now, how can we change the above hibernate code so it identifies the idFamily as an auto generated one?
The other question is, manually editing one mapping class without regenerating all the mappings via a tool can "break" the system? For an example, like messing up with relationships?

In Annotation It work for me as
#GeneratedValue(strategy= GenerationType.IDENTITY)
for you hope it works
<generated-value strategy="IDENTITY" />

You're looking for an identity column. That indicates that the column value is auto-generated as an identity for the row by the RDBMS.
<generator class="identity" />
See the these Hibernate docs for more information. According to it:
Identity
supports identity columns in DB2, MySQL, MS SQL Server, Sybase and HypersonicSQL. The returned identifier is of type long, short or int.

Just replace your generator class to increment it will treat it as autoincrement
<generator class="increment"/>

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="com.tech.spring4.model.User" table="Customer">
<id name="id" type="long">
<column name="USERID" unique="true"/>
<generator class="increment"/>
</id>
<property name="username"><column name="username" length="30" not-null="true"></column></property>
<property name="email"><column name="email" length="100" not-null="true"></column></property>
<property name="address"><column name="address" length="100" not-null="true"></column></property>
</class>
</hibernate-mapping>

Error When writing Hibernate HQL

I'm testing the following hql but getting an error
String SQL="From Bid bid where bid.Auction.AuctionId=3655"
Class Bid Mapping File:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Jan 19, 2011 5:25:35 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="com.BiddingSystem.Models.Bid" table="BID">
<id name="BidId" type="long">
<column name="BIDID" />
<generator class="native" />
</id>
<property name="BidAmount" type="long">
<column name="BIDAMOUNT" />
</property>
<many-to-one name="User" class="com.BiddingSystem.Models.Users" fetch="join">
<column name="UserId" />
</many-to-one>
<many-to-one name="auction" class="com.BiddingSystem.Models.Auction" fetch="join" lazy="false">
<column name="AuctionId" />
</many-to-one>
<property name="TimePosted" type="java.util.Date" access="field">
<column name="TIMEPOSTED" />
</property>
</class>
</hibernate-mapping>
Auction Mapping File:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 28, 2010 9:14:12 PM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="com.BiddingSystem.Models.Auction" table="AUCTION">
<id name="AuctionId" type="long">
<column name="AUCTIONID" />
<generator class="native" />
</id>
<property name="StartTime" type="java.util.Date">
<column name="STARTTIME" />
</property>
<property name="EndTime" type="java.util.Date">
<column name="ENDTIME" />
</property>
<property name="DatePlaced" type="java.util.Date">
<column name="DatePlaced" />
</property>
<property name="StartingBid" type="long">
<column name="STARTINGBID" />
</property>
<property name="MinIncrement" type="long">
<column name="MININCREMENT" />
</property>
<many-to-one name="CurrentItem" class="com.BiddingSystem.Models.Item" fetch="join" not-null="true" cascade="all" unique="true" lazy="false">
<column name="CURRENTITEM" />
</many-to-one>
<property name="AuctionStatus" type="java.lang.String">
<column name="AUCTIONSTATUS" />
</property>
<property name="BestBid" type="long">
<column name="BESTBID" />
</property>
<many-to-one name="User" class="com.BiddingSystem.Models.Users" fetch="join">
<column name="UserId" />
</many-to-one>
</class>
</hibernate-mapping>
Error:
Caused by: org.hibernate.QueryException: could not resolve property: Auction of: com.BiddingSystem.Models.Bid [From com.BiddingSystem.Models.Bid bid where bid.Auction.AuctionId=3655 and bid.User.UserId=3657]
at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:81)
at org.hibernate.persister.entity.AbstractPropertyMapping.toType(AbstractPropertyMapping.java:75)
at org.hibernate.persister.entity.AbstractEntityPersister.toType(AbstractEntityPersister.java:1449)
at org.hibernate.hql.ast.tree.FromElementType.getPropertyType(FromElementType.java:315)
at org.hibernate.hql.ast.tree.FromElement.getPropertyType(FromElement.java:487)
at org.hibernate.hql.ast.tree.DotNode.getDataType(DotNode.java:611)
at org.hibernate.hql.ast.tree.DotNode.prepareLhs(DotNode.java:263)
at org.hibernate.hql.ast.tree.DotNode.resolve(DotNode.java:210)
at org.hibernate.hql.ast.tree.DotNode.resolveFirstChild(DotNode.java:175)
at org.hibernate.hql.ast.HqlSqlWalker.lookupProperty(HqlSqlWalker.java:571)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.addrExpr(HqlSqlBaseWalker.java:4774)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.expr(HqlSqlBaseWalker.java:1326)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.exprOrSubquery(HqlSqlBaseWalker.java:4471)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.comparisonExpr(HqlSqlBaseWalker.java:3944)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2047)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:1972)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.whereClause(HqlSqlBaseWalker.java:831)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:617)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:301)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:244)
at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254)
at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185)
at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80)
at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:124)
at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:156)
at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:135)
at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1770)
at com.BiddingSystem.server.ServiceImpl.getBid(ServiceImpl.java:1463)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at net.sf.gilead.gwt.PersistentRemoteService.processCall(PersistentRemoteService.java:174)

Based on your Bid mapping file, your SQL should be like this:-
String SQL="From Bid bid where bid.auction.AuctionId=3655"
But seriously, your camel-casing in your beans are really messed up. Property names in your bean SHOULD begin with small letter first (ex: auctionId, auction, timePosted, etc).

I bet this will work
String SQL="From Bid bid where bid.auction.auctionId=3655"
Properties are supposed to always start with lowercase characters in java.

Placing List Index when using List in Hibernate

I was using a Set but now due to a widget restriction, I need to use a list.a
a sample of my mapping file using A SET and a List are as follows. Can someone help me to place the list index. I am getting some confusion.
**Attribute Mapping File using Set**
?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 16, 2010 5:25:09 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Attribute" table="ATTRIBUTE">
<id name="AttributeId" type="long">
<column name="ATTRIBUTEID" />
<generator class="native" />
</id>
<property name="AttributeName" type="java.lang.String">
<column name="ATTRIBUTENAME" />
</property>
<set name="Options" table="ATTRIBUTEOPTION" inverse="false" cascade="all" lazy="true">
<key>
<column name="ATTRIBUTEID" />
</key>
<one-to-many class="h.AttributeOption" />
</set>
</class>
</hibernate-mapping>
**Category Mapping File using Set**
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 16, 2010 8:37:02 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Category" table="CATEGORY">
<id name="CategoryId" type="long">
<column name="CATEGORYID" />
<generator class="native" />
</id>
<property name="CategoryName" type="java.lang.String">
<column name="CATEGORYNAME" />
</property>
<many-to-one name="ParentCategory" class="h.Category">
<column name="PARENT_CATEGORY_ID" />
</many-to-one>
<set name="SubCategory" lazy="true" cascade="all-delete-orphan" inverse="true">
<key>
<column name="PARENT_CATEGORY_ID" />
</key>
<one-to-many class="h.Category" />
</set>
<set name="AllAttributes" table="ATTRIBUTE" inverse="false" lazy="true" cascade="all">
<key>
<column name="CATEGORYID" />
</key>
<one-to-many class="h.Attribute" />
</set>
</class>
</hibernate-mapping>
Category Mapping File using list without the list index
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 17, 2010 2:10:50 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Category" table="CATEGORY">
<id name="CategoryId" type="long">
<column name="CATEGORYID" />
<generator class="assigned" />
</id>
<property name="CategoryName" type="java.lang.String">
<column name="CATEGORYNAME" />
</property>
<many-to-one name="ParentCategory" class="h.Category" fetch="join">
<column name="PARENTCATEGORY" />
</many-to-one>
<list name="SubCategory" inverse="false" table="CATEGORY" lazy="true">
<key>
<column name="CATEGORYID" />
</key>
<list-index></list-index>
<one-to-many class="h.Category" />
</list>
<list name="AllAttributes" inverse="false" table="ATTRIBUTE" lazy="true" cascade="all">
<key>
<column name="CATEGORYID" />
</key>
<list-index></list-index>
<one-to-many class="h.Attribute" />
</list>
</class>
</hibernate-mapping>
Attribute Mapping File using list with not list index
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 17, 2010 2:10:50 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
<class name="h.Attribute" table="ATTRIBUTE">
<id name="AttributeId" type="long">
<column name="ATTRIBUTEID" />
<generator class="assigned" />
</id>
<property name="AttributeName" type="java.lang.String">
<column name="ATTRIBUTENAME" />
</property>
<list name="Options" inverse="false" table="ATTRIBUTEOPTION" lazy="true" cascade="all">
<key>
<column name="ATTRIBUTEID" />
</key>
<list-index></list-index>
<one-to-many class="h.AttributeOption" />
</list>
</class>
</hibernate-mapping>

Read Hibernate Reference: 6.2.3. Indexed collections
For Example:
<list name="whatEver">
<key column="whatEver_fk"/>
<index column="idx"/>
<one-to-many class="WhatEver"/>
</list>

The Hibernate 3.3 reference says "The index of an array or list is always of type integer...", and also "If your table does not have an index column, and you still wish to use list as the property type, you can map the property as a Hibernate <bag>."
A example of bag:
<bag name="options" table="ATTRIBUTEOPTION" order-by="column_name asc|desc" inverse="true" lazy="true" fetch="select">
<key column="ATTRIBUTEID" />
<one-to-many class="h.AttributeOption" />
</bag>

I think you should give "index" property in POJO for which you are creating one-to-many relation
<list name="whatEver">
<key column="whatEver_fk"/>
<index column="idx"/>
<one-to-many class="WhatEver_Class"/>
</list>
In above example , "WhatEver_Class" POJO should have a index property , and it's hbm file should have below property tag.
<property name="index" type="long" insert="false" update="false">
<column name="idx" />
</property>