Unable to exchange data encrypted with AES-256 between Java and PHP - java

My problem is: what I encrypt in Java I can decrypt perfectly in Java, but PHP mcrypt can't decrypt. What I encrypt with mcrypt I can decrypt with mcrypt, but can't in Java.
I want to send and receive encrypted data from a Java application to a PHP page, so I need it to be compatible.
Here's what I have...
JAVA...
public static String crypt(String input, String key){
byte[] crypted = null;
try{
SecretKeySpec skey = new SecretKeySpec(Base64.decodeBase64(key), "AES");
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
cipher.init(Cipher.ENCRYPT_MODE, skey);
crypted = cipher.doFinal(input.getBytes());
}catch(Exception e){
}
return Base64.encodeBase64String(crypted);
}
public static String decrypt(String input, String key){
byte[] output = null;
try{
SecretKeySpec skey = new SecretKeySpec(Base64.decodeBase64(key), "AES");
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, skey);
output = cipher.doFinal(Base64.decodeBase64(input));
}catch(Exception e){
}
return new String(output);
}
Running:
public static void main(String[] args) {
String key = "Zvzpv8/PXbezPCZpxzQKzL/FeoPw68jIb+NONX/LIi8=";
String data = "example";
System.out.println(Cpt.decrypt(Cpt.crypt(data, key), key));
}
Output:
example
PHP...
function getEncrypt($sStr, $sKey) {
return base64_encode(
mcrypt_encrypt(
MCRYPT_RIJNDAEL_256,
$sKey,
$sStr,
MCRYPT_MODE_ECB
)
);
}
function getDecrypt($sStr, $sKey) {
return mcrypt_decrypt(
MCRYPT_RIJNDAEL_256,
$sKey,
base64_decode($sStr),
MCRYPT_MODE_ECB
);
}
Running:
$crypt = getDecrypt(getEncrypt($str, $key), $key);
echo "<p>Crypt: $crypt</p>";
Output:
Crypt: example�������������������������
Using PHP to crypt "example" with key "Zvzpv8/PXbezPCZpxzQKzL/FeoPw68jIb+NONX/LIi8=" I get "YTYhgp4zC+w5IsViTR5PUkHMX4i7JzvA6NJT1FqhoGY=".
Using Java to crypt the same thing with the same key I get "+tdAZqTE7WAVPXhB3Tp5+g==".
I'm encoding and decoding to base64 in the right order and I tested base64 encode and decode compatibility between Java and PHP and it's working.

BUG#1
MCRYPT_RIJNDAEL_256 is not AES. The 256 in that constant refers to the blocksize, not the keysize. Use MCRYPT_RIJNDAEL_128 to get the same algorithm as AES. The keysize is set just by the number of bytes in the key argument you supply. So supply 32 bytes and you get AES with a 256-bit key.
BUG#2
These two lines are never correct in Java and indicate a fundamental misunderstanding of the nature of the arbitrary binary data produced by cryptographic transforms:
output = cipher.doFinal(Base64.decodeBase64(input));
return new String(output);
There is nothing wrong with transmitting and storing byte[] directly, but if you must use only printable strings then you should base64 encode/decode to do so. As you are already using base64 extensively that would seem like the way to go. I would guess that the correct two lines would be:
output = cipher.doFinal(Base64.decodeBase64(input));
return new String(Base64.encodeBase64(output), "UTF-8");
EDIT:
Just kidding about bug #2. Really, I was wrong, I didn't notice it was the decrypt direction. Of course, if you know the decrypted byte[] is a valid string then it is perfectly correct to do what your code does.

I know this is an old topic, but I will add my working solution.
You have to rewrite PHP side of the script:
function getEncrypt($sStr, $sKey) {
return base64_encode(
mcrypt_encrypt(
MCRYPT_RIJNDAEL_128,
base64_decode($sKey),
$sStr,
MCRYPT_MODE_ECB
)
);
}
function getDecrypt($sStr, $sKey) {
return mcrypt_decrypt(
MCRYPT_RIJNDAEL_128,
base64_decode($sKey),
base64_decode($sStr),
MCRYPT_MODE_ECB
);
}
You should base64_decode($sKey) because your key is base64 encoded.
$key = "Zvzpv8/PXbezPCZpxzQKzL/FeoPw68jIb+NONX/LIi8=";
Then, you need to create this function (credit goes to beltrachi from http://www.php.net/manual/en/function.mcrypt-decrypt.php):
function pkcs5_pad ($text, $blocksize) {
$pad = $blocksize - (strlen($text) % $blocksize);
return $text . str_repeat(chr($pad), $pad);
}
Use this code do encode/decode:
$decrypt = getDecrypt("6XremNEs1jv/Nnf/fRlQob6oG1jkge+5Ut3PL489oIo=", $key);
echo $decrypt;
echo "\n\n";
echo getEncrypt(pkcs5_pad("My very secret text:)", 16), $key);
I hope this will be useful for someone! :)

Please see here:
Difference in PHP encryption from iOS and .NET
AES Encrypt in C#, decrypt in PHP
DES Encryption in PHP and C#
The problem you're encountering is a padding-issue. I don't know Java, but AES/ECB/PKCS5Padding looks like you're using a PKCS#5 (that's essentially the same as PKCS#7) padding while PHP natively only support NULL-padding. That's what PKCS#5/7 does:
Pad the input with a padding string of
between 1 and 8 bytes to make the
total length an exact multiple of 8
bytes. The value of each byte of the
padding string is set to the number of
bytes added - i.e. 8 bytes of value
0x08, 7 bytes of value 0x07, ..., 2
bytes of 0x02, or one byte of value
0x01.
So the PHP code to do the padding right is trivial:
$blockSize = mcrypt_get_block_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB);
$padding = $blockSize - (strlen($data) % $blockSize);
$data .= str_repeat(chr($padding), $padding);

Keep in mind to have the same encoding for the strings. Try to convert the strings in both languages to UTF-8, e.g., and than convert to binary data that is encoded:
PHP (s. utf8_encode() function):
$strAndBlob = utf8_encode("My string");
Java:
String str = "My string";
byte[] blob = str.getBytes("utf-8");
PHP, e.g., must not use UTF-8 by default.

Related

PHP analogue for JAVA TripleDES function

I have a sample Java function and would like to make an analogue for PHP:
public static string Encrypt(string plainText, string key)
{
byte[] byteKey = new ASCIIEncoding().GetBytes(key);
MemoryStream mStream = new MemoryStream();
// Create a CryptoStream using the MemoryStream
// and the passed key and initialization vector (IV).
CryptoStream cStream = new CryptoStream(mStream,
new TripleDESCryptoServiceProvider().CreateEncryptor(byteKey, byteKey),
CryptoStreamMode.Write);
// Convert the passed string to a byte array.
byte[] toEncrypt = new ASCIIEncoding().GetBytes(plainText);
// Write the byte array to the crypto stream and flush it.
cStream.Write(toEncrypt, 0, toEncrypt.Length);
cStream.FlushFinalBlock();
// Get an array of bytes from the
// MemoryStream that holds the
// encrypted data.
byte[] ret = mStream.ToArray();
// Close the streams.
cStream.Close();
mStream.Close();
return Convert.ToBase64String(ret);
}
Here is my PHP function, but it doesn't give me the exact result:
function Encrypt($data, $secret)
{
//Generate a key from a hash
$key = md5(utf8_encode($secret), true);
//Take first 8 bytes of $key and append them to the end of $key.
$key .= substr($key, 0, 8);
//Pad for PKCS7
$blockSize = mcrypt_get_block_size('tripledes', 'ecb');
$len = strlen($data);
$pad = $blockSize - ($len % $blockSize);
$data .= str_repeat(chr($pad), $pad);
//Encrypt data
$encData = mcrypt_encrypt('tripledes', $key, $data, 'ecb');
return base64_encode($encData);
}
The string I'm trying to encrypt is:
Java generated string: i00KAKI7U0L7fyvrEnDdB7DtaJNO1HuwRh0/J5aWnCQ=
PHP generated string: 6065L3jC5Oji8NAVzipA4OZZ102j1zFd/KfLgAdnRX0=
Any help is greatly appreciated
It seems that are not using the cipher in the same way.
In your Java code, you are using an IV for your encryption, while you are not doing the same in your PHP code.
That is because ECB, the mode you have specified in your PHP code, doesn't need any initialization, while whatever mode you are using in Java does.
What library are you using?
As stated here here in the reference of Microsoft libraries that look very similar to the one you used with Java, the default encryption mode is
CBC (which is generally considered more secure than ECB). It is very likely that CBC is being used in your library too.
You need to use the same mode of encryption if you want the same result. So, either set CBC (and the same IV you used in Java) in your PHP code, or use TripleDESCryptoServiceProvider to set the ECB mode in Java.

RSA transfer iOS to Java

I want to encrypt a String in Objective-C (iOS) and decrypt it after HTTP Transfer in Java.
The Public Key was successfully transmitted from Java to iOS (at least it is recognied in the Keychain)
In ObjC I try to send the text "Hallo" using this:
NSData* myData = [#"Hallo" dataUsingEncoding:NSUTF8StringEncoding];
OSStatus status = noErr;
size_t cipherBufferSize;
uint8_t *cipherBuffer;
cipherBufferSize = SecKeyGetBlockSize(publicKey);
cipherBuffer = malloc(cipherBufferSize);
size_t dataLength = [self length];
uint8_t* intDataToEncrypt = (uint8_t*)[self bytes];
if (cipherBufferSize < dataLength) {
printf("Could not encrypt. Packet too large.\n");
return NULL;
}
status = SecKeyEncrypt( publicKey,
kSecPaddingNone,
intDataToEncrypt,
dataLength,
cipherBuffer,
&cipherBufferSize
);
NSData *encryptedData = [NSData dataWithBytes:cipherBuffer length:cipherBufferSize];
"encryptedData" is then send base64 encoded via HTTP Post to a Java Servlet which uses this (BouncyCastle is used and the data converted back from Base64 first, the key is read from a file):
PKCS8EncodedKeySpec keySpec = new PKCS8EncodedKeySpec(b64.decodeBuffer(key));
PrivateKey privateKey = kf.generatePrivate(keySpec);
Cipher cipher = Cipher.getInstance("RSA/NONE/NoPadding");
cipher.init(Cipher.DECRYPT_MODE, privateKey);
byte[] myData = cipher.doFinal(byteData, 0, 256);
The output is completely messed up when trying to use as new String(myData, "UTF-8");
I tried sending only the "Hallo" without encryption this works, so it seems base64 is ok.
When I encrypt the same phrase in Java directly the output differs in 2 Bytes from the ObjC encryption.
In the End I want to use OAEP Padding instead of none...
I hope someone can help with this, the iOS Security Framework seems really to be very bad
The Problem was not in the RSA part but the Base64 encoding and transfer. All "+" in the String were received as " " due to HTTP(S) transfer (of course, I should have thought of that).
Replacing them with "-" as proposed by the unofficial Base64URL version solves the problem. (also all "/" with "_")
This also explain why only 2 bytes were different - those were the "+" symbol bytes.

iOS symmetric key encryption / decryption equivalent to Java

I am trying to encrypt/decrypt data ios to java & java to ios but I data encrypted in java is not properly decrypted in ios & data encrypted in ios is not properly decrypted in java
- (NSData *) encrypt:(NSData *) dataToEncrypt symmetricKey:(NSData *)symmetricKey context:(CCOperation)encryptOrDecrypt{
NSUInteger data_length= [dataToEncrypt length];
uint8_t input_raw_data[data_length];
//The [dataToEncrypt length] gives the number of chars present in the string.So say there are 10 chars.
//Now,the getBytes needs to get the raw bytes from this i.e. binary NSData.But suppose the encoding was
//full 16 bit encoding then the number of bytes needed wd have been double- 20.But as we are using the
//NSUTF8StringEncoding,the number of byes needed is 1 per char as the chars(even if originally unicode are
//compressed into an 8 bit UTF8 encoding.)
[dataToEncrypt getBytes:&input_raw_data length:data_length];
// [dataToEncrypt getBytes:&input_raw_data maxLength:data_length usedLength:NULL encoding:NSUTF8StringEncoding options:0 range:NSMakeRange(0,data_length) remainingRange:NULL];
//According to the doc: For block ciphers, the output size will always be less than or
//equal to the input size plus the size of one block.
//That's why we need to add the size of one block here
size_t buffer_size = data_length + kCCBlockSizeAES128;
void* buffer = malloc(buffer_size);
size_t num_bytes_encrypted = 0;
CCCryptorStatus crypt_status = CCCrypt(encryptOrDecrypt, kCCAlgorithmAES128, 0x0000,
[symmetricKey bytes], kCCKeySizeAES128,
NULL,
input_raw_data, data_length,
buffer, buffer_size,
&num_bytes_encrypted);
// NSLog(#"~~num bytes encrypted: %d",num_bytes_encrypted);
if (crypt_status == kCCSuccess){
NSLog(#"~~Data encoded successfully...");
return [NSData dataWithBytesNoCopy:buffer length:num_bytes_encrypted];
}
free(buffer); //free the buffer;
return nil;
}
I have used this
Java Code -
Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding");
String keyString = "keykeykeykeykeykeykeykey";
byte[] keyBytes = keyString.getBytes("UTF-8");
cipher.init(Cipher.ENCRYPT_MODE, new SecretKeySpec(keyBytes, "AES"), new IvParameterSpec(new byte[16]));
byte[] resultBytes = cipher.doFinal("Hallo Welt!".getBytes("UTF8"));
FileOutputStream out = new FileOutputStream(new File("encryptedFileJava"));
out.write(resultBytes); out.close();
and this is encrypted text - “Se áJbë|8”R ,
key - BW3dKDf2bkDC4Bq9xTdr1g==
Please help me or suggest me any solution.
Thank you.
You have at least two problems:
The Objective C code is using ECB mode, while the Java code is using CBC mode. Use a bytearray of zeroes instead of NULL in the CCrypt-invocation to use CBC mode with a zero IV like the Java code.
Since keyBytes is 24 bytes long, Java will use AES-192. CCrypt will just ignore the extra bytes. Either specify AES-192 to CCrypt or use a 128 bit key ("keykeykeykeykeyk" should work).
For secured communication between IOS and Java devices, symmetric key encryption can be used.
In such cases where the platforms are different it is advisable that the key generated is a plain text key and not a API generated key.
AES 128 bit encryption can be used in such cases. IOS devices are capable of generating a symmetric key and encrypting the text using AES encryption.
Below link provides the java code to encrypt and decrypt using plain text symmetric key
http://www.java-redefined.com/2015/06/symmetric-key-encryption-ios-java.html

AES-128 Encryption with Base64 Encoding doesn't act the same in Java and PHP with longer strings

I have been trying to get Encryption/Decryption to work the same in Java (Android) and PHP and produce the same results for client/server communications.
I'm using the code below for encryption, but I don't know what's wrong with it. Running both with the same key and small strings produce the same encrypted value, with longer strings however, I get two different results.
PHP:
$str = 'test1234test1234';
$key = 'TESTKEYTESTKEY12';
$block = mcrypt_get_block_size('des', 'ecb');
$pad = $block - (strlen($str) % $block);
$str .= str_repeat(chr($pad), $pad);
echo base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_128, $key, $str, MCRYPT_MODE_ECB));
and in Java ( on Android ):
public static String encryptTest() {
String cleartext = "test1234test1234";
String key = "TESTKEYTESTKEY12";
byte[] raw = key.getBytes();
SecretKeySpec skeySpec = new SecretKeySpec(raw, "AES");
try {
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.ENCRYPT_MODE, skeySpec);
byte[] encrypted;
encrypted = cipher.doFinal(cleartext.getBytes());
return new String(Base64.encode(encrypted,Base64.DEFAULT));
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
Running this with String test1234 gives: 8i4KEe82TQl0Zdlc14fwAg== in both implementations.
With string test1234test1234 however I get 4s5a0edsvwWt/3/enRe0wgJQD/0zL45NRb/r3p6L/Is= with PHP, and 4s5a0edsvwWt/3/enRe0wgA0jk78zwWJr1xsosZbYUA= with Java. I'm not sure what's wrong and I'm not knowledgeable enough about Cryptography.
The main problem of your Java code is that you don't specify the cipher mode and the used padding algorithm. Therefore which cipher mode and padding algorithm is used depends on the used crypto provider and in this specific detail Android works different to J2SE.
If I execute your Java code on J2SE I get the same result as you got with PHP. This does not change if I change the code to use Cipher.getInstance("AES/ECB/PKCS5Padding");.
As only the last block of your cipher text changes I assume that Android uses a different padding algorithm by default.
The fact you have different results for short versus long strings suggest you are using different padding on each implementation.
Make sure you use the same type of padding on both your java and your php implementations.

Encryption using AES-128 in Java

I have a problem with ecrypting data using AES-128/ecb/PKCS5Padding+base64. I am using the following code to encrypt my data:
String input = "{\"action\":\"getQuestion\"}";
String key = "4288f0b8060ca1b682bf795f2617cfdc";
byte[] data = input.getBytes();
byte[] encrypted = null;
byte[] keyBytes = new BigInteger(key, 16).toByteArray();
SecretKeySpec keySpec = new SecretKeySpec(keyBytes, "AES");
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
cipher.init(Cipher.ENCRYPT_MODE, keySpec);
encrypted = cipher.doFinal(data);
System.out.println(Base64.encodeBytes(encrypted));
I receive 6GuKXA6FFR+yMmO8ksAEOLL5e574a5tLob7tt5IG+jk= after encryption but I can't decrypt on the server using a PHP function.
When I encrypt this data using the PHP function:
function encrypt($encrypt, $key=null)
{
$iv = mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_ECB), MCRYPT_RAND);
$encrypted = base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_128, $key, $encrypt, MCRYPT_MODE_ECB, $iv));
return $encrypted;
}
I receive 6Wc3LPWvfJ7T86iG0igmdQaeZ8xs9qY419mAVWfNH+M= and I can successfully do the decryption using the following PHP function:
function decrypt($decrypt, $key=null)
{
$iv = mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_ECB), MCRYPT_RAND);
$decrypted = mcrypt_decrypt(MCRYPT_RIJNDAEL_128, $key, base64_decode($decrypt), MCRYPT_MODE_ECB, $iv);
return $decrypted;
}
With base64 encryption and decryption there are no problems; I only encounter the issue when encrypting using AES-128.
The problem isn't with the IV or the padding as I initially thought. It is with how you are handling the key in the PHP code. If you are using the actual string 4288f0b8060ca1b682bf795f2617cfdc as the key passed into mcrypt_encrypt and mcrypt_decrypt then you aren't using the same key as in the Java code. You will need to convert that hex string into bytes. You can do this in the following way:
$decrypted = mcrypt_decrypt(MCRYPT_RIJNDAEL_128, pack("H*", $key), base64_decode($decrypt), MCRYPT_MODE_ECB, $iv);
Notice the addition of pack("H*", $key) to convert the value. I found that here in the comments for the PHP bin2hex function. This will fix the current problem. You may run into padding troubles when working with data of different lengths since PHP doesn't do PKCS5 padding. See this comment about implementing that missing function. Also, I'd recommend looking into CBC instead of ECB due to ECB's unsuitability and weaknesses for data encryption.
You can validate the output from your Java method at the command line using openssl. Java will default your IV to 0 if unspecified.
The file "enc.txt" contains "6GuKXA6FFR+yMmO8ksAEOLL5e574a5tLob7tt5IG+jk=" [corrected]
Run
openssl aes-128-ecb -in enc.txt -a -K 4288f0b8060ca1b682bf795f2617cfdc -iv 0 -d
The result is:
{"action":"getQuestion"}
Try your mcrypt_decrypt with an $iv value of 0.

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