Im receiving a file trough this code and the "bos.write" are saving it o to my HDD.
Everything working good.
Since im sending the file in a few second i thought i could store the file in memory
instead of HDD.
Now how do i do this?
File path = new File("C://anabella//test1.txt");
BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(path));
int size = 1024;
int val = 0;
byte[] buffer = new byte[1024];
while (fileSize >0) {
val = in.read(buffer, 0, size);
bos.write(buffer, 0, val);
fileSize -= val;
if (fileSize < size)
size = (int) fileSize;
}
Presumably bos is a FileOutputStream? To use an in-memory buffer use a ByteArrayOutputStream instead.
If you know the size in advance you don't even need a ByteArrayOutputStream
InputStream is = socket.getInputStream(); // or where ever the inputstream comes from.
DataInputStream in = new DataInputStream(is);
byte[] bytes = new byte[fileSize];
in.readFully(bytes);
to send the bytes to any OutputStream like
OutputStream os = ...
os.write(bytes);
The bytes will contain the contents of the file.
Related
Suppose I have the following code that will download something from my website.
URL website = new URL(url);
ReadableByteChannel rbc = Channels.newChannel(website.openStream());
FileOutputStream fos = new FileOutputStream("something.zip");
fos.getChannel().transferFrom(rbc, 0, Long.MAX_VALUE);
fos.close();
I want to make a JProgressBar that would display the progress of the file that is being downloaded. To achieve this, I know that one way is to get the total size of the file and the currently downloaded bytes of the file, then get the percent. Here is the following code for getting the size of the file:
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("HEAD");
long fileSize = conn.getContentLengthLong();
However, getting the downloaded bytes of FileOutputStream is difficult, because you have to make loop that keeps track of the current bytes that are being downloaded. How would you be able to achieve this then?
Note: The algorithm should be suitable for very large files, as the files I am downloading from the internet are one gigabyte in size.
I provide below the code snippet you can look into it. Basically, you have to calculate the number of bytes and then make a calculation by diving into 100 to make some percentage.
InputStream inputStream = util.getInputStream();
// opens an output stream to save into file
FileOutputStream outputStream = new FileOutputStream(saveFilePath);
byte[] buffer = new byte[BUFFER_SIZE];
int bytesRead = -1;
long totalBytesRead = 0;
int percentCompleted = 0;
long fileSize = util.getContentLength();
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
totalBytesRead += bytesRead;
percentCompleted = (int) (totalBytesRead * 100 / fileSize);
setProgress(percentCompleted);
For more details, refer this link
I am creating a ZipOutputStream and adding files to it this is being done in memory , later I want to be able to get/read files from this. I have tried multiple permutations and combinations but am not able to get it done.
I know if I use FileOutpuStream and attach a physical file to it I will be able to use it but I am not allowed to create physical file.
Current Code:-
ByteArrayOutputStream bos = new ByteArrayOutputStream();
ZipOutputStream zos = new ZipOutputStream(bos);
ZipEntry ze = new ZipEntry(“Temp.txt”);
zos.putNextEntry(ze);
FileInputStream fis = new FileInputStream("Test/File1.txt");
byte[] buffer = new byte[1024];
int len;
while ((len = fis.read(buffer)) > 0) {
//System.out.println(new String(buffer));
zos.write(buffer, 0, len);
}
You're on the right track! To read the file back, simply use:
byte[] zipBytes = bos.toByteArray();
ByteArrayInputStream bis = new ByteArrayInputStream(zipBytes);
ZipInputStream zis = new ZipInputStream(bis);
When I try upload the file from server, I use this code. I get the file size of 500kb, when the original file size about 300kb.
What am I doing wrong?
attachmentContent = applicationApi.getApplicationAttachmentContent(applicationame);
InputStream in = new BufferedInputStream(attachmentContent.getAttachmentContent().getInputStream());
ByteArrayOutputStream out = new ByteArrayOutputStream();
byte[] buf = new byte[1024];
int n=0;
while (-1 !=(n=in.read(buf)))
{
out.write(buf,0,n);
}
out.close();
in.close();
byte[] response = out.toByteArray();
File transferredFile = new File(attachmentName);
FileOutputStream outStream = new FileOutputStream(transferredFile);
attachmentContent.getAttachmentContent().writeTo(outStream);
outStream.write(response);
outStream.close();
Simplify. The same result:
File transferredFile = new File(attachmentName);
FileOutputStream outStream = new FileOutputStream(transferredFile);
attachmentContent.getAttachmentContent().writeTo(outStream);
outStream.close();
The ByteArrayOutputStream is a complete waste of time and space. You're reading the attachment twice, and writing it twice too. Just read from the attachment and write directly to the file. Simplify, simplify. You don't need 90% of this.
I am using the code provided by this accepted answer to send a list of files over a socket in Java. My goal is to be receiving a list of images. What I would like to do is read these images directly into memory as BufferedImages before writing them to disk. However, my first attempts, which was to use ImageIO.read(bis) (again, see the attached question) failed, as it attempted to continue reading beyond the end of the first image file.
My current idea is to write the data from the socket to a new output stream, then read that stream from an intput stream that is passed to ImageIO.read(). This way, I can write it byte by byte as the program is currently doing, but send it to the BufferedImage rather than the file. however I'm not sure how to link the output stream to an input stream.
Can anyone recommend simple edits to the code above, or provide another method of doing this?
In order to read the image before writing it to disk, you'll need to use a ByteArrayInputStream. http://docs.oracle.com/javase/6/docs/api/java/io/ByteArrayInputStream.html
Basically, it creates a inputstream that reads from a specified byte array. So, you'd read the image length, then it's name, then the length-amount of bytes, create the ByteArrayInputStream, and pass it to ImageIO.read
Example snippet:
long fileLength = dis.readLong();
String fileName = dis.readUTF();
byte[] bytes = new byte[fileLength];
dis.readFully(bytes);
BufferedImage bimage = ImageIO.read(new ByteArrayInputStream(bytes));
Or using the code from the other answer you cited:
String dirPath = ...;
ServerSocket serverSocket = ...;
Socket socket = serverSocket.accept();
BufferedInputStream bis = new BufferedInputStream(socket.getInputStream());
DataInputStream dis = new DataInputStream(bis);
int filesCount = dis.readInt();
File[] files = new File[filesCount];
for(int i = 0; i < filesCount; i++)
{
long fileLength = dis.readLong();
String fileName = dis.readUTF();
byte[] bytes = new byte[fileLength];
dis.readFully(bytes);
BufferedImage bimage = ImageIO.read(new ByteArrayInputStream(bytes));
//do some shit with your bufferedimage or whatever
files[i] = new File(dirPath + "/" + fileName);
FileOutputStream fos = new FileOutputStream(files[i]);
BufferedOutputStream bos = new BufferedOutputStream(fos);
bos.write(bytes, 0, fileLength);
bos.close();
}
dis.close();
I have a FileInputStream created using Context.openFileInput(). I now want to convert the file into a byte array.
Unfortunately, I can't determine the size of the byte array required for FileInputStream.read(byte[]). The available() method doesn't work, and I can't create a File to check it's length using the specific pathname, probably because the path is inaccessible to non-root users.
I read about ByteArrayOutputStream, and it seems to dynamically adjust the byte array size to fit, but I can't get how to read from the FileInputStream to write to the ByteArrayOutputStream.
This should work.
InputStream is = Context.openFileInput(someFileName);
ByteArrayOutputStream bos = new ByteArrayOutputStream();
byte[] b = new byte[1024];
while ((int bytesRead = is.read(b)) != -1) {
bos.write(b, 0, bytesRead);
}
byte[] bytes = bos.toByteArray();
This is the easiest way
FileInputStream fis = openFileInput(fileName);
byte[] buffer = new byte[(int) fis.getChannel().size()];
fis.read(buffer);
You can pre-allocate the byte array using
int size = context.getFileStreamPath(filename).length();
This way, you will avoid allocating memory chunks every time your ByteArrayOutputStream fills up.
For the method to work on any device and aplication you just need to replace:
InputStream is = Context.getContentResolver().openInputStream(yourFileURi);
This way you can encode external files as well.