Use HashMap in XMLRPC result - java

I am new in Android development, and I am trying to receive a HashMap in RESULT by using XMLRPC but every time it's crash the application, this is my code please advice me :
Object RESULT = XMLRPCClient.callEx(methodname,new Object[] {params});
Map FRESULT= (Map) RESULT;


I have been dealing with this also and managed to get the values this way:
try {
Object[] answer = (Object[]) client.call("call", sessionId, method, params);
HashMap map = (HashMap) answer[0]; // get first item of the response because in my case the response was an array of Objects with one item in it holding the HashMap
Object[] records = (Object[]) map.get("records"); // I only needed values from "records" key
for (int i = 0; i < records.length; i++) {
HashMap record = (HashMap) records[i]; // create another map from the records values, in my case uid's of categories
Category cat = new Category(); // creating new instance of my Category class
cat.setCatUid((String) record.get("uid")); // calling a method of the Category class to set Uid to the value from record HashMap
m_categories.add(cat); // this adds it to my ArrayList<Category>
}
} catch (XMLRPCException e) {
Log.e(method, "Exception", e);
}
I'm sure it's a mess, I'm noob in Java myself, but it worked for me. Hope it helps :)


Now the Application pass this peacefully after implementing :
Object RESULT = XmlRpcConnect.ServerCall_a(method,new Object[] {params});
Map<String, Object> FRESULT= (HashMap<String, Object>) RESULT;
with some changes in my XmlRpcConnect Class:
#SuppressWarnings("unchecked");
public static Object ServerCall_a(String method, Object[] params){
XMLRPCClient client = new XMLRPCClient(server);
HashMap<String, Object> result=null;
try{
result = (HashMap<String, Object>) client.callEx(method, params);
}
catch(XMLRPCFault f){
// result = ("Fault message: " + f.getMessage());
}
catch(XMLRPCException e){
// result = ("Exception message: " + e.getMessage());
}
return result;
}
but when trying to extract the values it's crash again , any advice :
if (FRESULT.get("status") == null) {
result = (String) FRESULT.get("status");
toastDialog(result);
}

Related

java - how to parse String back to List of Map

I have a String with this format (it's a List of Map assigned to a string var)
[{code=1, data=Male} , {code=2, data=Female}]
.. how can I parse the above string back to list of map.. without using any String.split function (cause it is prone to error)
here is the code I've tried.. but with split function..
if(!string.equals("")){
String[] listArray = string.split(DELIMITER);
for (int i=0;i<listArray.length;i++) {
String val=listArray[i];
val = val.replaceAll("[\\{\\}]", "");
//Gets the value from DATA key
if(val.split(EQDELIMITER)[0].trim().equalsIgnoreCase("DATA")){
try{
map.put("DATA", val.split(EQDELIMITER)[1]);
}catch(IndexOutOfBoundsException e){
map.put("DATA", "");
}
}
//Gets the value from CODE key
if(val.split(EQDELIMITER)[0].trim().equalsIgnoreCase("CODE")){
try{
map.put("CODE", val.split(EQDELIMITER)[1]);
}catch(IndexOutOfBoundsException e){
map.put("CODE", "");
}
}
if (map != null && map.size() >= 2) {
//add map to codeList
codeList.add(map);
map = new HashMap<String,Object>();
}
}
}

If you are flexible enough to use a library, then Use google's GSON
Map map = gson.fromJson(jsonString, Map.class);
As you want a list of Map, wo you can also use TypeToken
List<Map<E,V>> list= new Gson().fromJson(jsonString,
new TypeToken<List<Map<E, V>>() {}.getType());
replace E, V with actual types.

Why can't you go for object Mapper..?(org.codehaus.jackson.map.ObjectMapper)
it would be something like this...
ObjectMapper mapper= new ObjectMapper();
Map<Integer,String> map = mapper.readValue(yourString,org.codehaus.jackson.type.TypeReference.TypeReference<Map<Integer,String>>() {
});

Java - Getting a list of contacts using Infusionsofts API

I'm using Java and Infusionsofts API to get a list of contacts based on the customer id. I can't figure out a way to do this. I'm using Googles Guava to use multimap but it's producing an error:
org.apache.xmlrpc.common.XmlRpcExtensionException: Serializable objects aren't supported, if isEnabledForExtensions() == false
So now i'm trying hashmap and i'm inserting "Id" as the key and the customer id as the value but there's always one entry in the hashmap.
How can I add to the parameters variable a map that contains:
["Id",11111]
["Id",22322]
["Id",44444]
List parameters = new ArrayList();
parameters.add(APP_ID);
parameters.add(TABLE_NAME);
parameters.add(LIMIT);
parameters.add(pageNumber);
HashMap<String, Integer> map = new HashMap<String, Integer>();
for(int customerId : customerIds){
map.put("Id", customerId);
}
//PROBLEM IS HERE
parameters.add(map);
//THIS IS THE PROBLEM, I NEED TO ADD ["Id", customerId] multiple
//times with the customerId being different but since there's a hashmap
//There's always 1 entry in the map
String[] fields = {"Email","FirstName"};
parameters.add(fields);
Object[] contacts = null;
try{
contacts = ( Object [] ) client.execute("DataService.query",parameters);
}catch(XmlRpcException e){
e.printStackTrace();
}
for (int i = 0; i < contacts.length; i++) {
Map contact = (Map) contacts[i];
System.out.println(contact+"\n\n");
}

Convert JSON object with duplicate keys to JSON array

I have a JSON string that I get from a database which contains repeated keys. I want to remove the repeated keys by combining their values into an array.
For example
Input
{
"a":"b",
"c":"d",
"c":"e",
"f":"g"
}
Output
{
"a":"b",
"c":["d","e"],
"f":"g"
}
The actual data is a large file that may be nested. I will not know ahead of time what or how many pairs there are.
I need to use Java for this. org.json throws an exception because of the repeated keys, gson can parse the string but each repeated key overwrites the last one. I need to keep all the data.
If possible, I'd like to do this without editing any library code

As of today the org.json library version 20170516 provides accumulate() method that stores the duplicate key entries into JSONArray
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("a", "b");
jsonObject.accumulate("c", "d");
jsonObject.accumulate("c", "e");
jsonObject.accumulate("f", "g");
System.out.println(jsonObject);
Output:
{
"a":"b",
"c":["d","e"],
"f":"g"
}

I want to remove the repeated keys by combining their values into an array.
Think other than JSON parsing library. It's very simple Java Program using String.split() method that convert Json String into Map<String, List<String>> without using any library.
Sample code:
String jsonString = ...
// remove enclosing braces and double quotes
jsonString = jsonString.substring(2, jsonString.length() - 2);
Map<String, List<String>> map = new HashMap<String, List<String>>();
for (String values : jsonString.split("\",\"")) {
String[] keyValue = values.split("\":\"");
String key = keyValue[0];
String value = keyValue[1];
if (!map.containsKey(key)) {
map.put(key, new ArrayList<String>());
}
map.get(key).add(value);
}
output:
{
"f": ["g"],
"c": ["d","e"],
"a": ["b"]
}

In order to accomplish what you want, you need to create some sort of custom class since JSON cannot technically have 2 values at one key. Below is an example:
public class SomeClass {
Map<String, List<Object>> values = new HashMap<String, List<Object>>();
public void add(String key, Object o) {
List<Object> value = new ArrayList<Object>();
if (values.containsKey(key)) {
value = values.get(key);
}
value.add(o);
values.put(key, value);
}
public JSONObject toJson() throws JSONException {
JSONObject json = new JSONObject();
JSONArray tempArray = null;
for (Entry<String, List<Object>> en : values.entrySet()) {
tempArray = new JSONArray();
for (Object o : en.getValue()) {
tempArray.add(o);
}
json.put(en.getKey(), tempArray);
}
return json;
}
}
You can then retrieve the values from the database, call the .add(String key, Object o) function with the column name from the database, and the value (as the Object param). Then call .toJson() when you are finished.

Thanks to Mike Elofson and Braj for helping me in the right direction. I only wanted to have the keys with multiple values become arrays so I had to modify the code a bit. Eventually I want it to work for nested JSON as well, as it currently assumes it is flat. However, the following code works for what I need it for at the moment.
public static String repeatedKeysToArrays(String jsonIn) throws JSONException
{
//This assumes that the json is flat
String jsonString = jsonIn.substring(2, jsonIn.length() - 2);
JSONObject obj = new JSONObject();
for (String values : jsonString.split("\",\"")) {
String[] keyValue = values.split("\":\"");
String key = keyValue[0];
String value = "";
if (keyValue.length>1) value = keyValue[1];
if (!obj.has(key)) {
obj.put(key, value);
} else {
Object Oold = obj.get(key);
ArrayList<String> newlist = new ArrayList<String>();
//Try to cast as JSONArray. Otherwise, assume it is a String
if (Oold.getClass().equals(JSONArray.class)) {
JSONArray old = (JSONArray)Oold;
//Build replacement value
for (int i=0; i<old.length(); i++) {
newlist.add( old.getString(i) );
}
}
else if (Oold.getClass().equals(String.class)) newlist = new ArrayList<String>(Arrays.asList(new String[] {(String)Oold}));
newlist.add(value);
JSONArray newarr = new JSONArray( newlist );
obj.put(key,newarr);
}
}
return obj.toString();
}

Android get specific data from JSON

I'm newbie on android and I'm trying to create an application that catch data from JSON.
For now I already get all data, but the problem is how can I get specific data that I only need.
Here's my JSON example
[{"id":"152","category_id":"1","item_name":"Restaurant1","description":"Restaurant1","address":"Restaurant1","area":"42","area_name":"Kuta","longitude":"2131","latitude":"1231","open_detail":"24hours","kids":"","free_text_for_kids":"","cuisine_id":"3","cuisine_name":"Chinese","cuisine_uniqe_code":"CNS","price_category":"5","hotel_official_star_rating":"0","phone":"123","mobile_phone":"123","review":"Restaurant1","promotion":"0","promotion_free_text":"","promotion_start_date":"0000-00-00","promotion_end_date":"0000-00-00","active":"1","image_count":"3","created_date":"1401644001","created_by":"1","updated_date":"1402029631","updated_by":"1","facebook":"Restaurant1","twitter":"Restaurant1","instagram":"Restaurant1"},
{"id":"153","category_id":"1","item_name":"Restaurant2","description":"Restaurant2","address":"Restaurant2","area":"42","area_name":"Kuta","longitude":"1231","latitude":"1231231","open_detail":"24hours","kids":"","free_text_for_kids":"","cuisine_id":"17","cuisine_name":"Middle Eastern","cuisine_uniqe_code":"MID","price_category":"3","hotel_official_star_rating":"0","phone":"1231","mobile_phone":"231","review":"Restaurant2","promotion":"0","promotion_free_text":"","promotion_start_date":"0000-00-00","promotion_end_date":"0000-00-00","active":"1","image_count":"0","created_date":"1401644082","created_by":"1","updated_date":"1402029930","updated_by":"1","facebook":"Restaurant2","twitter":"Restaurant2","instagram":"Restaurant2"},
{"id":"162","category_id":"2","item_name":"Bars1","description":"Bars1","address":"Bars1","area":"34","area_name":"Seminyak","longitude":"213312","latitude":"21312","open_detail":"Bars1","kids":"","free_text_for_kids":"","cuisine_id":"","cuisine_name":null,"cuisine_uniqe_code":null,"price_category":"2","hotel_official_star_rating":"0","phone":"1231","mobile_phone":"1231","review":"Bars1","promotion":"0","promotion_free_text":"","promotion_start_date":"0000-00-00","promotion_end_date":"0000-00-00","active":"1","image_count":"0","created_date":"1401644461","created_by":"1","updated_date":"1402939937","updated_by":"1","facebook":"Bars1","twitter":"Bars1","instagram":"Bars1"},
{"id":"163","category_id":"2","item_name":"Bars2","description":"Bars2","address":"Bars2","area":"42","area_name":"Kuta","longitude":"1232131","latitude":"231","open_detail":"Bars2","kids":"","free_text_for_kids":"","cuisine_id":"","cuisine_name":null,"cuisine_uniqe_code":null,"price_category":"5","hotel_official_star_rating":"0","phone":"11231","mobile_phone":"213","review":"Bars2","promotion":"0","promotion_free_text":"","promotion_start_date":"0000-00-00","promotion_end_date":"0000-00-00","active":"1","image_count":"0","created_date":"1401644494","created_by":"1","updated_date":"1402030999","updated_by":"1","facebook":"Bars2","twitter":"Bars2","instagram":"Bars2"},
As you can see, there's two type category_id, how can I get only category_id "1" for restaurant.
I know that I have to use if statement, but where should I put it?
Here's My java code
#Override
protected Void doInBackground(Void... arg0) {
// Creating service handler class instance
ServiceHandler sh = new ServiceHandler();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);
Log.d("Response: ", "> " + jsonStr);
if (jsonStr != null) {
try {
restaurant = new JSONArray(jsonStr);
// looping through All Contacts
for (int i = 0; i < restaurant.length(); i++) {
JSONObject c = restaurant.getJSONObject(i);
String item_name = c.getString(TAG_ITEM_NAME);
String cuisine_name = c.getString(TAG_CUISINE_NAME);
// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();
// adding each child node to HashMap key => value
contact.put(TAG_ITEM_NAME, item_name);
contact.put(TAG_CUISINE_NAME, cuisine_name);
// adding contact to contact list
restaurantList.add(contact);
}
} catch (JSONException e) {
e.printStackTrace();
}
} else {
Log.e("ServiceHandler", "Couldn't get any data from the url");
}
return null;
}
Thanks Before :D

Create an if statement that checks if the category is 1 and if it is then add the to the HashMap if it is not then do not do anything continue to the next json object.
sample:
for (int i = 0; i < restaurant.length(); i++) {
JSONObject c = restaurant.getJSONObject(i);
String category = c.getString("category_id");
if(category.equals("1"))
{
String item_name = c.getString(TAG_ITEM_NAME);
String cuisine_name = c.getString(TAG_CUISINE_NAME);
// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();
// adding each child node to HashMap key => value
contact.put(TAG_ITEM_NAME, item_name);
contact.put(TAG_CUISINE_NAME, cuisine_name);
// adding contact to contact list
restaurantList.add(contact);
}
}

Actually I found the answer by myself.
Here's the code that I use
for (int i = 0; i < restaurant.length(); i++) {
JSONObject c = restaurant.getJSONObject(i);
if(c.getString("category_id").equals("1")) {
String item_name = c.getString(TAG_ITEM_NAME);
String cuisine_name = c.getString(TAG_CUISINE_NAME);
// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();
// adding each child node to HashMap key => value
contact.put(TAG_ITEM_NAME, item_name);
contact.put(TAG_CUISINE_NAME, cuisine_name);
// adding contact to contact list
restaurantList.add(contact);
}
}
Thanks a lot for everyone that already answer it. I really appriciate it :D

Problems with creating a map of <String, List>

I've a row in db returned by query below. Columns to select include rec, head, amount. I want to sort the rows by head column. I tried Map where string for head and list for other two columns.
I've hit the wall with my non-working code posted below. How would I append another list to list of repeated key. Documentation says it replaces the value for same key whereas I need it appended to the list value. I would be really greatful for any help.
Query q= session.createQuery("select tally_receipt_prefix, tally_receipt_no, tally_head, tally_amount from Tally_table where tally_system_date='"+fmtd_date+"' and tally_dbcr_indicator='DB' and tally_mode='Ca' order by tally_head,tally_receipt_prefix,tally_receipt_no"); System.out.println("query "+q);
List heads=new ArrayList();
for(Iterator it=q.iterate(); it.hasNext(); )
{
Object[] row= (Object[]) it.next();
payincash1=new LinkedHashMap<String, List>();
heads.add((String)row[2]);
List tails = null;
tails=new ArrayList();
tails.add((String)row[0]);
tails.add((String)row[1]);
tails.add((String)row[3]);
System.out.println("heads in dao from iter 1: "+heads);
System.out.println("tails in dao from iter1 on: "+tails);
if(heads.contains((String)row[2])) // for head in temp list
{
System.out.println("in first if");
if(payincash1.containsKey((String)row[2]))
{
System.out.println("map if repeat: "+payincash1);
payincash1.put((String)row[2],tails);
}
}
else
{
System.out.println("map if not repeat: "+payincash1);
payincash1.put((String)row[2], tails);
}
}

Sounds more like you want a list of lists
Something like Map<String, List<List>>
Then you'd end up with something like...
Map<String, List<List>> payincash1 = new LinkedHashMap<String, List<List>>();
heads.add((String) row[2]);
List tails = null;
tails = new ArrayList();
tails.add((String) row[0]);
tails.add((String) row[1]);
tails.add((String) row[3]);
System.out.println("heads in dao from iter 1: " + heads);
System.out.println("tails in dao from iter1 on: " + tails);
List master = payincash1.get((String)row[2]);
if (master == null) {
master = new List();
payincash1.put((String)row[2], master);
}
master.add(tails);
Now, personally, I'd be creating a "data" object that would contain all this information.
public class MyData {
private String rec, head, amount, ??; // Apparently you have another variable I don't know about
public MyData(String rec, String head, String amount, String ??) {
// Initalise...
}
// Setters and getters not inclueded
}
Then you could do something like this...
Map<String, List<MyData>> payincash1 = new LinkedHashMap<String, List<MyData>>();
MyData data = new MyData(row[0], row[1], row[2], row[3]);
List master = payincash1.get((String)row[2]);
if (master == null) {
master = new List<MyData>();
payincash1.put((String)row[2], master);
}
master.add(data);
Which is a little cleaner (IMHO)

From what I understand you need Multimap of guava library.

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