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Java - get number of days between dates [duplicate]

This question already has answers here:
Calculating days between two dates with Java
(16 answers)
Closed 5 years ago.
I've got a list of dates in format "yyyy-MM-dd", I'd like to have a number of days between my today date "2017-04-15" and first date from list which is higher than mine today date.

I am assuming that your events are not sorted by date. I am assuming that you can use Java 8. This is one of the tasks that have become so much easier with the java.time classes introduced in Java 8 (and backported to Java 6 and 7).
Use LocalDate.now() to get today’s date.
Iterate through your events, all the time keeping track of the closest future event date. For each event use LocalDate.parse() to convert the event’s date to a LocalDate. The 1-arg parse method fits your format. Compare with today’s date and with the earliest future event date encountered so far; if between, store as the new closest date. Use isAfter() and/or isBefore for the comparisons.
After your loop, you will either know the date or you will know that there are no future events at all. In the former case, use ChronoUnit.DAYS.between() to get the number of days from the current date to the event date.

Solution 1
If you are using joda library, then it will be easy, you can use Days.daysBetween :
Date startDate = ...;
Date endDate = ...;
int nbrDays = Days.daysBetween(new LocalDate(startDate), new LocalDate(endDate)).getDays();
Solution 2
Date startDate = ...;
Date endDate = ...;
Calendar cal = Calendar.getInstance();
cal.setTime(startDate);
int day1 = cal.get(Calendar.DAY_OF_MONTH);
cal.setTime(endDate);
int day2 = cal.get(Calendar.DAY_OF_MONTH);
int nbrDays = day1 - day2;
System.out.println(nbrDays);
You have to import :
import java.util.Calendar;
import java.util.Date;
Solution 3
If your dates are in this format "yyyy-MM-dd" so you can have two dates like this :
String date1 = "1991-07-03";
String date2 = "2017-04-15";
What you should to do, split your dates with - :
String spl1[] = date1.split("-");
String spl2[] = date2.split("-");
Calculate the difference between the two dates :
int year1 = Integer.parseInt(spl1[0]);
int month1 = Integer.parseInt(spl1[1]);
int days1 = Integer.parseInt(spl1[2]);
int year2 = Integer.parseInt(spl2[0]);
int month2 = Integer.parseInt(spl2[1]);
int days2 = Integer.parseInt(spl2[2]);
//make some calculation and in the end you can get the diffidence, this work i will let it for you.

This should solve your problem.
SimpleDateFormat myDateFormat = new SimpleDateFormat("yyyy-MM-dd");
List<Date> dateList = new ArrayList<Date>();
try {
beforeDate = myDateFormat.parse("2016-01-13");
dateList.add(myDateFormat.parse("2016-01-10"));
dateList.add(myDateFormat.parse("2016-01-11"));
dateList.add(myDateFormat.parse("2016-01-12"));
dateList.add(myDateFormat.parse("2016-01-19"));
dateList.add(myDateFormat.parse("2016-01-20"));
dateList.add(myDateFormat.parse("2016-01-21"));
} catch (ParseException e) {
System.out.println(e.getMessage());
}
//add here
boolean check = true;
for(int i = 0; check && i < dateList.size();i++){
if(dateList.get(i).after(beforeDate)){
afterDate = dateList.get(i);
check = false;
}
}
System.out.println(beforeDate+" "+afterDate);
long days = ChronoUnit.DAYS.between(LocalDate.parse(myDateFormat.format(beforeDate)), LocalDate.parse(myDateFormat.format(afterDate)));
if(days>0){
System.out.println(days);
}else{
System.out.println(0-days);
}
if you want to sort dateList then want to get afterDate then use this code after addition of date elements in dateList
Collections.sort(dateList,new Comparator<Date>() {
#Override
public int compare(Date o1, Date o2) {
return o1.compareTo(o2);
}
});
This will allow you to sort dates in ascending order..

Java - Generate Random DOB [duplicate]

This question already has answers here:
How can I pad an integer with zeros on the left?
(18 answers)
Adding zero to a single digit number, Is it possible?
(2 answers)
Generate random date of birth
(15 answers)
Closed 5 years ago.
I want to generate random DOB for the given range of year. So I tried the below code
private static String randomDataOfBirth(int yearStart, int yearEnd)
{
GregorianCalendar gc = new GregorianCalendar();
int year = randBetween(yearStart, yearEnd);
gc.set(Calendar.YEAR, year);
int dayOfYear = randBetween(1, gc.getActualMaximum(Calendar.DAY_OF_YEAR));
gc.set(Calendar.DAY_OF_YEAR, dayOfYear);
String date = null;
if(gc.get(Calendar.MONTH) == 0)
{
date = gc.get(Calendar.YEAR) + "-" + 1 + "-" + gc.get(Calendar.DAY_OF_MONTH);
}else
{
date = gc.get(Calendar.YEAR) + "-" + gc.get(Calendar.MONTH) + "-" + gc.get(Calendar.DAY_OF_MONTH);
}
return date;
}
private static int randBetween(int start, int end) {
// TODO Auto-generated method stub
return start + (int)Math.round(Math.random() * (end - start));
}
Main:-
public static void main(String[] args) {
String dob = randomDataOfBirth(1899, 1937);
System.out.println(dob);
}
I can be able to generate the random DOB. But only for the Month and Day, I want to add a prefix '0' for the range from 1 to 9
Month - 01, 02, 03 and ... up to 09
Day - 01, 02, 03 and ... up to 09

Apart from the desired formatting of you date I see some other problems with your code that I think you would want to address:
Assuming you want a usual month number, 01 for January through 12 for December, your handling of the month number is not correct. get(Calendar.MONTH) gives you a 0-based month: 0 for January through 11 for December. Therefore, your code not only will never give you 12 as month and 1 all too often. It will also give you non-existing dates. I have seen 1905-2-31 and 1929-4-31 (because you get 2 for March, which we interpret as February, etc.).
Possibly unimportant, your distribution gives each day in a leap year slightly smaller probablity than other days.
If you can, I suggest you use LocalDate. The class was introduced in Java 8:
private static String randomDataOfBirth(int yearStartInclusive, int yearEndExclusive) {
LocalDate start = LocalDate.ofYearDay(yearStartInclusive, 1);
LocalDate end = LocalDate.ofYearDay(yearEndExclusive, 1);
long longDays = ChronoUnit.DAYS.between(start, end);
int days = (int) longDays;
if (days != longDays) {
throw new IllegalStateException("int overflow; too many years");
}
int day = randBetween(0, days);
LocalDate dateOfBirth = start.plusDays(day);
return dateOfBirth.toString();
}
This gives you evenly distributed, correct dates formatted with 2 digits for month and day-of-month, e.g., 1926-07-05.
If you want to avoid the overflow check, you may of course rewrite your randBetween() to handle longs.
If you cannot use Java 8, you can do something similar with GregorianCalendar and SimpleDateFormat. Counting the exact number of days from lower to upper bound is complicated, though, so you will probably want to stick to your way of picking the date. SimpleDateFormat can still give you correct dates formatted with two digits for month and day. Edit: In your class, declare:
static DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
Now just substitute your if-else statement with this:
String date = formatter.format(gc.getTime());
If your randomDataOfBirth() may be accessed from more than one thread, this won’t work since SimpleDateFormat is not thread-safe. If so, each thread should have its own SimpleDateFormat instance.

With Java7 you can try with something like this:
public class DobMaker
{
public String getDOB(int min, int max)
{
Calendar calendar = Calendar.getInstance(TimeZone.getTimeZone("UTC"));
int year = min + new Random().nextInt(max - min + 1);
calendar.set(Calendar.YEAR, year);
int day = 1+new Random().nextInt(calendar.getActualMaximum(Calendar.DAY_OF_YEAR));
calendar.set(Calendar.DAY_OF_YEAR, day);
return new SimpleDateFormat("yyyy-MM-dd").format(calendar.getTime());
}
public static void main(String[] args)
{
DobMaker d = new DobMaker();
System.out.println(d.getDOB(1970, 1980));
System.out.println(d.getDOB(1970, 1971));
System.out.println(d.getDOB(2007, 2016));
}
}

Get difference between two dates in years - without months - without days

I am using the following function in Joda-Time to get difference between two dates:
public static int getDiffYear(Date first) {
int yearsBetween = Years.yearsBetween(new DateTime(first), new DateTime()).getYears();
return yearsBetween;
}
The date supplied to function is: 0001-10-02 (YYYY-MM_DD)
I get the difference as 2013 as checked against today, however I find the correct result should be 2012. Because the day still is 01.
I have a separate function in pure Java, with the desired result:
public static int getDiffYear(Date first) {
Calendar a = Calendar.getInstance();
a.setTime(first);
Calendar b = Calendar.getInstance();
int diff = b.get(Calendar.YEAR) - a.get(Calendar.YEAR);
if (a.get(Calendar.MONTH) > b.get(Calendar.MONTH) ||
(a.get(Calendar.MONTH) == b.get(Calendar.MONTH) && a.get(Calendar.DATE) > b.get(Calendar.DATE))) {
diff--;
}
return diff;
}

Joda will take days into account with yearsBetween. Try this:
public static int getDiffYear() {
LocalDate firstDate = new LocalDate(1, 10, 2);
LocalDate today = new LocalDate();
int yearsBetween = Years.yearsBetween(firstDate, today).getYears();
return yearsBetween;
}
It will return 2012 as of today (2014/10/01). This indicates something is happening in the conversion from java.util.Date.
EDIT: This is due to what Marko Topolnik mentioned. When you do new DateTime(first) you are getting a DateTime of 0001-09-30.

The Years utility class is going to only check the difference in years. If you need to keep the days into account, you should use the Days class and recalculate the result to years.

Comparing Just the Date (not time)

I need to compare 2 dates to a third date and ignore the time portion of all of them.
The code below generates a parse exception because the toString() method returns something like "Wed Feb 26 00:00:00 EST 2014".
Any suggestions on how I might fix this?
private boolean needToSendEmail(EmSelfCertEntity escd) throws ParseException {
boolean sendEmail = false;
DateFormat df = new SimpleDateFormat("MM/dd/yyyy");
Date justTheDate = df.parse(escd.getCurrentFCESDate().toString());
Calendar firstSent = Calendar.getInstance();
firstSent.setTime(justTheDate);
justTheDate = df.parse(new Date().toString());
Calendar firstFollowUp = Calendar.getInstance();
firstFollowUp.setTime(justTheDate);
firstFollowUp.add(Calendar.DATE, -daysToFirstFollowUpEmail);
Calendar secondFollowUp = Calendar.getInstance();
secondFollowUp.setTime(justTheDate);
secondFollowUp.add(Calendar.DATE, -daysToSecondFollowUpEmail);
if ((firstSent.before(firstFollowUp) && escd.countEmailsSent <= 1)
|| (firstSent.before(secondFollowUp) && escd.countEmailsSent <= 2)) {
sendEmail = true;
}
return sendEmail;
}
Thanks!

Why are you parsing the String when you already have the Date?
If you want to format your existing Date into the format you specified, use the format() method instead:
String justTheDate = df.format(new Date());
Then you can compare the Strings using the equals() method to check for matches.
Edit- By the way, if Java 8 is an option (it came out on Tuesday!), its new DateTime features will do exactly what you're looking for: http://docs.oracle.com/javase/tutorial/datetime/

The cause for your exception is that toString in escd.getCurrentFCESDate().toString()
delivers another format than "MM/dd/yyyy".
So make sure that either your format String in line SimpleDateFormat("MM/dd/yyyy") is correct.
Or check if you can get the year, month, and day directly from getCurrentFCESDate().
Just Use the calendar to create a date, where you take the year, months, day from the existing date but set the hours, minutes, seconds and millis to zero.
The result will be a Date object:
Something like
firstSent.set(Calendar.HOUR, 0);
firstSent.set(Calendar.MINUTE, 0);
firstSent.set(Calendar.SECOND, 0);
firstSent.set(Calendar.MILLISECOND, 0);
Then use before() and after()

The easiest approach would be to convert the dates to numbers in this format: yyyyMMdd.
And after that you can just compare the numbers.
But yes, please work with timezone adjustments before converting to numbers.

you can calculate the time in millis and substract the time with a simple / division.
This way you can compare 2 longs and check if one is bigger than another.
Take this example where we get to different dates for today (500 milliseconds from one to another) but... if you divide by 86400000 then... you get the same number.
Try this:
public static void main(String[] args) throws Exception {
Date d1= new Date();
Thread.sleep(500);
Date d2= new Date();
final int MILLISECONDS = 1000;
final int SECONDS = 60;
final int MINUTES = 60;
final int HOURS = 24;
final long MILLI_PER_DAY= MILLISECONDS*SECONDS*MINUTES*HOURS;
System.out.println(MILLI_PER_DAY);
System.out.println(d1.getTime());
System.out.println(d2.getTime());
System.out.println(d1.getTime()/MILLI_PER_DAY);
System.out.println(d2.getTime()/MILLI_PER_DAY);
}
You will see that the last 2 entries are the same:
1395338535623 --> time 1 in millis
1395338536123 --> time 2 in millis
16149 --> time 1 / 86400000
16149 --> time 2 / 86400000 --> THE SAME

How to write a method that returns number (int) of days from provided day to the todays date?

Please help me to write a method that returns number (int) of days from a provided day to the todays date.
So let's say, I am providing into a method an int 110515 (for May 15, 2011). It should return 9 (inclusive or exclusive is not important to me).

If you can use Joda, this is super simple:
Days d = Days.daysBetween(startDate, endDate);
int days = d.getDays();
Of course you could combine these.
int days = Days.daysBetween(startDate, endDate).getDays();
Joda objects can go back and forth between the JDK's date class pretty easily.
For the first part, make a DateFormatter then parse the string based on it, like this:
DateTimeFormatter fmt = DateTimeFormat.forPattern("yyyyMMdd");
DateTime dt = fmt.parseDateTime(strInputDateTime);
(After turning the int into a string of course.)

Should dates in the future include the current day? Meaning if today is May 24th 2011, should 110529 result in 4 or 5?
public static long numberOfDays(final long date) throws ParseException {
final Calendar compare = Calendar.getInstance();
compare.setTime(new SimpleDateFormat("yyMMdd").parse(String.valueOf(date)));
final int dstOffset = compare.get(Calendar.DST_OFFSET);
final long currentTimeMillis = System.currentTimeMillis();
final long compareTimeInMillis = compare.getTimeInMillis();
long difference = 0;
if (currentTimeMillis >= compareTimeInMillis) {
difference = currentTimeMillis - compareTimeInMillis - dstOffset;
} else {
difference = compareTimeInMillis - currentTimeMillis + dstOffset;
}
return difference / (24 * 60 * 60 * 1000);
}

Since this seems like a homework question I will help you out. You will want to use Calendar.getTimeInMillis. Then you will want to create a constant that is NUMBER_OF_MILLIS_IN_DAY . From there you subtract the initialDate from the currentDate (both time in millis) and divide by the constant.