I need to create a XML Document object using the NodeList. Can someone pls help me to do this. This is my Java code:
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.*;
import org.w3c.dom.*;
public class ReadFile {
public static void main(String[] args) {
String exp = "/configs/markets";
String path = "testConfig.xml";
try {
Document xmlDocument = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(path);
XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression xPathExpression = xPath.compile(exp);
NodeList nodes = (NodeList)
xPathExpression.evaluate(xmlDocument,
XPathConstants.NODESET);
} catch (Exception ex) {
ex.printStackTrace();
}
}
}
I want to have an XML file like this:
<configs>
<markets>
<market>
<name>Real</name>
</market>
<market>
<name>play</name>
</market>
</markets>
</configs>
Thanks in advance.
You should do it like this:
you create a new org.w3c.dom.Document newXmlDoc where you store the nodes in your NodeList,
you create a new root element, and append it to newXmlDoc
then, for each node n in your NodeList, you import n in newXmlDoc, and then you append n as a child of root
Here is the code:
public static void main(String[] args) {
String exp = "/configs/markets/market";
String path = "src/a/testConfig.xml";
try {
Document xmlDocument = DocumentBuilderFactory.newInstance()
.newDocumentBuilder().parse(path);
XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression xPathExpression = xPath.compile(exp);
NodeList nodes = (NodeList) xPathExpression.
evaluate(xmlDocument, XPathConstants.NODESET);
Document newXmlDocument = DocumentBuilderFactory.newInstance()
.newDocumentBuilder().newDocument();
Element root = newXmlDocument.createElement("root");
newXmlDocument.appendChild(root);
for (int i = 0; i < nodes.getLength(); i++) {
Node node = nodes.item(i);
Node copyNode = newXmlDocument.importNode(node, true);
root.appendChild(copyNode);
}
printTree(newXmlDocument);
} catch (Exception ex) {
ex.printStackTrace();
}
}
public static void printXmlDocument(Document document) {
DOMImplementationLS domImplementationLS =
(DOMImplementationLS) document.getImplementation();
LSSerializer lsSerializer =
domImplementationLS.createLSSerializer();
String string = lsSerializer.writeToString(document);
System.out.println(string);
}
The output is:
<?xml version="1.0" encoding="UTF-16"?>
<root><market>
<name>Real</name>
</market><market>
<name>play</name>
</market></root>
Some notes:
I've changed exp to /configs/markets/market, because I suspect you want to copy the market elements, rather than the single markets element
for the printXmlDocument, I've used the interesting code in this answer
I hope this helps.
If you don't want to create a new root element, then you may use your original XPath expression, which returns a NodeList consisting of a single node (keep in mind that your XML must have a single root element) that you can directly add to your new XML document.
See following code, where I commented lines from the code above:
public static void main(String[] args) {
//String exp = "/configs/markets/market/";
String exp = "/configs/markets";
String path = "src/a/testConfig.xml";
try {
Document xmlDocument = DocumentBuilderFactory.newInstance()
.newDocumentBuilder().parse(path);
XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression xPathExpression = xPath.compile(exp);
NodeList nodes = (NodeList) xPathExpression.
evaluate(xmlDocument,XPathConstants.NODESET);
Document newXmlDocument = DocumentBuilderFactory.newInstance()
.newDocumentBuilder().newDocument();
//Element root = newXmlDocument.createElement("root");
//newXmlDocument.appendChild(root);
for (int i = 0; i < nodes.getLength(); i++) {
Node node = nodes.item(i);
Node copyNode = newXmlDocument.importNode(node, true);
newXmlDocument.appendChild(copyNode);
//root.appendChild(copyNode);
}
printXmlDocument(newXmlDocument);
} catch (Exception ex) {
ex.printStackTrace();
}
}
This will give you the following output:
<?xml version="1.0" encoding="UTF-16"?>
<markets>
<market>
<name>Real</name>
</market>
<market>
<name>play</name>
</market>
</markets>
you can try the adoptNode() method of Document. Maybe you will need to iterate over your NodeList. You can access the individual Nodes with nodeList.item(i).If you want to wrap your search results in an Element, you can use createElement() from the Document and appendChild() on the newly created Element
Related
Given the xml snippet:
<AddedExtras>
<AddedExtra Code="1234|ABCD" Quantity="1" Supplier="BDA"/>
<AddedExtra Code="5678|EFGH" Quantity="1" Supplier="BDA"/>
<AddedExtra Code="9111|ZXYW" Quantity="1" Supplier="BDA"/>
</AddedExtras>
The following XPath expression:
//*["AddedExtra"]/#Code
when run through a checker evaluates to:
Attribute='Code=1234|ABCD'
Attribute='Code=5678|EFGH'
Attribute='Code=9111|ZXYW'
Why then, does the following code only return the first line?
private String allCodes = "//*["AddedExtra"]/#Code";
get my XML from system and parse it into a Doc:
public Document parseResponse(String response){
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(true);
DocumentBuilder builder;
Document doc = null;
//Create a document reader and an XPath object
try {
builder = factory.newDocumentBuilder();
doc = builder.parse(new InputSource((new StringReader(response))));
} catch (ParserConfigurationException | org.xml.sax.SAXException | IOException e) {
e.printStackTrace();
}
return doc;
}
Get the new doc:
public Document getParsedResponse(String response) {
return parseResponse(response);
}
Return the Xpath value from the doc:
public String getAllCodeOptions(String response){
Document doc = getParsedResponse(response);
return getNodeValueFromNodeList(doc, allCodes);
}
new method to read the XML nodes:
public String getNodeValueFromNodeList(Document doc, String expression){
NodeList nodeList = null;
String nodes = null;
try {
nodeList = (NodeList) xpath.compile(expression).evaluate(doc, XPathConstants.NODESET);
} catch (XPathExpressionException e) {
e.printStackTrace();
}
for(int i=0; i < nodeList.getLength(); i++){
Node node = nodeList.item(i);
nodes = node.getNodeValue();
}
return nodes;
}
returns:
Attribute='Code=1234|ABCD'
You would require to use right evaluate method which takes return type as an argument. Something like below,
NodeSet result = (NodeSet)e.evaluate(e, doc, XPathConstants.NODESET);
for(int index = 0; index < result.getLength(); index ++)
{
Node node = result.item(index);
String name = node.getNodeValue();
}
The problem is that you are asking for only one value.
Try this:
NodeList nodeList = (NodeList)e.evaluate(doc, XPathConstants.NODESET);
for multiple values.
See http://viralpatel.net/blogs/java-xml-xpath-tutorial-parse-xml/ for a tutorial.
Given the following XML (example):
<?xml version="1.0" encoding="UTF-8"?>
<rsb:VersionInfo xmlns:atom="http://www.w3.org/2005/Atom" xmlns:rsb="http://ws.rsb.de/v2">
<rsb:Variant>Windows</rsb:Variant>
<rsb:Version>10</rsb:Version>
</rsb:VersionInfo>
I need to get the values of Variant and Version. My current approach is using XPath as I cannnot rely on the given structure. All I know is that there is an element rsb:Version somewhere in the document.
XPath xpath = XPathFactory.newInstance().newXPath();
String expression = "//Variant";
InputSource inputSource = new InputSource("test.xml");
String result = (String) xpath.evaluate(expression, inputSource, XPathConstants.STRING);
System.out.println(result);
This however does not output anything. I have tried the following XPath expressions:
//Variant
//Variant/text()
//rsb:Variant
//rsb:Variant/text()
What is the correct XPath expression? Or is there an even simpler way getting to this element?
I would suggest just looping through the document to find the given tag
public static void main(String[] args) throws SAXException, IOException,ParserConfigurationException, TransformerException {
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document document = docBuilder.parse(new File("test.xml"));
NodeList nodeList = document.getElementsByTagName("rsb:VersionInfo");
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
if (node.getNodeType() == Node.ELEMENT_NODE) {
// do something with the current element
System.out.println(node.getNodeName());
}
}
}
Edit: Yassin pointed out that it won't get child nodes. This should point you in the right direction for getting the children.
private static List<Node> getChildren(Node n)
{
List<Node> children = asList(n.getChildNodes());
Iterator<Node> it = children.iterator();
while (it.hasNext())
if (it.next().getNodeType() != Node.ELEMENT_NODE)
it.remove();
return children;
}
I need to check a bunch of .xml files for a specific permission, which is an attribute. If there is such a permission attribute i have to find out which value the attribute has.
this is my code which produces NullPointerExceptions:
public static void checkXmlPermissions(String path)
{
FileInputStream file;
try
{
file = new FileInputStream(new File(path));
DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
//XPath initialisieren;
DocumentBuilder builder = builderFactory.newDocumentBuilder();
Document xmlDocument = builder.parse(file);
XPath xPath = XPathFactory.newInstance().newXPath();
String expression ="//*[#permission]"; //Expression;
NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(xmlDocument, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++)
{
String match = nodeList.item(i).getFirstChild().getNodeValue();
System.out.println(match);
}
}
catch(Exception ex)
{
System.out.println(ex);
}
}
I guess my mistake is the NodeList but I can´t find a solution by my own.
change:
String match = nodeList.item(i).getFirstChild().getNodeValue();
to:
String match = nodeList.item(i).getTextContent();
Hi!
I've spent some time to parse an XML document with XPath. It seeams to be a simple task but I got in troubles since the begining.
My code is :
public class QueryXML3 {
public static void main(String[] args) {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(true);
DocumentBuilder builder;
Document doc = null;
try {
builder = factory.newDocumentBuilder();
//doc = builder.parse("SampleExample.xml");
InputStream is = QueryXML3.class.getClassLoader().getResourceAsStream("SampleXml.xml");
doc = builder.parse(is);
XPathFactory xpathFactory = XPathFactory.newInstance();
// Create XPath object
XPath xpath = xpathFactory.newXPath();
Node parNode = getParameterNode(doc, xpath);
System.out.println("parameter node:" + parNode);
NodeList res = getParameterNodeList(doc, xpath );
System.out.println("List of nodes" + res);
} catch (ParserConfigurationException | SAXException | IOException e) {
e.printStackTrace();
}
}
public static Node getParameterNode(Document doc, XPath xpath) {
Node res = null;
try {
res = (Node) xpath.evaluate("/definitions/process", doc, XPathConstants.NODE);
} catch (XPathExpressionException e) {
e.printStackTrace();
}
return res;
}
public static NodeList getParameterNodeList(Document doc, XPath xpath) {
NodeList nodeList = null;
try {
nodeList = (NodeList) xpath.evaluate("/definitions/process", doc, XPathConstants.NODESET);
for (int i = 0; i > nodeList.getLength(); i++) {
System.out.print(nodeList.item(i).getNodeName() + " ");
}
} catch (XPathExpressionException e) {
e.printStackTrace();
}
return nodeList;
}
}
As a result i get this:
parameter node:[process: null]
List of nodes com.sun.org.apache.xml.internal.dtm.ref.DTMNodeList#2f17aadf
I just want to output all the nodes of my xml file and theire attributes...
You are really asking how to serialize an Element to a string - use either a Transformer or DOMImplementationLS.
The NodeList type has no toString() contract and the implementation does not override the default Object.toString(). You need to iterate over the nodes and serialize each Element as above.
You could easily parse an XML file in java using a 3rd party package such as JSoup or JDom.
As an example, here is some simple output of an XML files elements using JSoup:
<note>
<to>Tove</to>
<from>Jani</from>
<heading>Reminder</heading>
<body>Don't forget me this weekend!</body>
</note>
Java code printing all elements and the selected <from>-element:
String xml = "<note>\n"
+ "<to>Tove</to>\n"
+ "<from>Jani</from>\n"
+ "<heading>Reminder</heading>\n"
+ "<body>Don't forget me this weekend!</body>\n"
+ "</note>";
Document doc = Jsoup.parse(xml, "", Parser.xmlParser());
for (Element e : doc.children()) {
System.out.println(e);
}
Element fromElement = doc.select("from").first();
System.out.println("\nThis is the <from>-element content:\n" + fromElement);
I've created a simple xml file here:
http://roberthan.host56.com/productsNew.xml
which is quite simple, the root node is [products] while all other element nodes are [product]. Under each [product] node, there are two child nodes, [code] and [name], so it basically looks like:
[product]
[code]ddd[/code]
[name]ssss[/name]
[/product]
I've also written up the following Java code to parse this XML file and take out the text content of the [product] node, and add it to a JComboBox.
docBuilder = docFactory.newDocumentBuilder();
doc = docBuilder.parse("http://roberthan.host56.com/productsNew.xml");
NodeList productNodes = doc.getElementsByTagName("product");
productlist.clear();
for (i = 0; i < productNodes.getLength(); i++)
{
Node childNode = productNodes.item(i);
if (childNode.hasChildNodes()) {
NodeList nl = childNode.getChildNodes();
Node nameNode = nl.item(2);
productlist.add(nameNode.getTextContent());
}
}
final JComboBox productComboB = new JComboBox();
Iterator iterator = productlist.iterator();
while(iterator.hasNext())
{
productComboB.addItem(iterator.next().toString());
}
The code is quite straightforward, I firstly parse the xml and get all the product nodes and put them into a nodelist, and the productList is an arrayList. I loop through the all the [product] nodes, for each of them, if it has child nodes, then I take the second child node (which is the [name] node) and put the text content of it in the array list, and finally, I loop through the arrayList and add each item to the combo box.
The problem I got is, if I select the [code] child node, which means "Node nameNode = nl.item(1)", it will work perfectly; however, if I change that item(1) to item(2) to extract all the [name] nodes, the combo box will have a drop down list, but all the items are blank, like I have inserted 10 empty strings.
Also, if I try to add a "Hello World" string into the combo box after the above code, the "Hello World" item will appear after the 10 empty items.
I have spent the whole afternoon debugging this but still no breakthrough, the XML is actually quite simple and the Java is straightforward too. Could anyone share some thoughts with me on this please. Thanks a lot!
It is because the node list contains text nodes also.
If you add the following snippet to your code you will find that
for(int j = 0;j<nl.getLength();j++){
System.out.println(nl.item(j).getNodeName());
}
It will give the following output for each iteration of the product
#text
code
#text
name
#text
This means you have to get the 3rd element to get the name node.
Node nameNode = nl.item(3);
But I'll suggest you to use XPath to solve this problem.
NodeList nodelist = XPathAPI.selectNodeList(doc, "//products/product/name");
for (int i = 0; i < nodelist.getLength(); i++) {
productlist.add(nodelist.item(i).getTextContent());
}
XPath using this expression will easily solve your problem:
String XPATH_EXPRESSION1 = "//name/text()";
e.g.,
public static final String PRODUCTS_NEW = "http://roberthan.host56.com/productsNew.xml";
public static final String XPATH_EXPRESSION1 = "//name/text()";
public XmlFun() {
URL productsUrl;
try {
productsUrl = new URL(PRODUCTS_NEW);
List<String> nameList = xPathExtract(productsUrl.openStream());
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
} catch (XPathExpressionException e) {
e.printStackTrace();
}
}
private List<String> xPathExtract(InputStream inStream) throws ParserConfigurationException, SAXException, IOException, XPathExpressionException {
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document domDoc = builder.parse(inStream);
XPathFactory xFactory = XPathFactory.newInstance();
XPath xpath = xFactory.newXPath();
XPathExpression xExpr = xpath.compile(XPATH_EXPRESSION1);
NodeList nodes = (NodeList)xExpr.evaluate(domDoc, XPathConstants.NODESET);
List<String> resultList = new ArrayList<String>();
for (int i = 0; i < nodes.getLength(); i++) {
String node = nodes.item(i).getNodeValue();
resultList.add(node);
}
return resultList;
}