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How to get child node value in Java

I am tying to get child node value:
My XML file:
<url-mappings>
<url-mapping url="/screen1">
<request-handler-class>com.mappingtool.rh.Screen1RH</request-handler-class>
</url-mapping>
<url-mapping url="/screen2">
<request-handler-class>com.mappingtool.rh.Screen2RH</request-handler-class>
</url-mapping>
</url-mappings>
My Code is this:
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathFactory;
import java.io.File;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
public class MappingTool {
public static void main(String[] args) throws Exception {
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document document = db.parse(new File("src/com/mappingtool/requestmapping.xml"));
NodeList nodeList = document.getElementsByTagName("url-mapping");
XPath xpath = XPathFactory.newInstance().newXPath();
for(int x=0,size= nodeList.getLength(); x<size; x++) {
System.out.println(nodeList.item(x).getAttributes().getNamedItem("url").getNodeValue());
//System.out.println(nodeList.item(x).getChildNodes().item(0));
//XPathExpression expr = xpath.compile("/request-handler-class/text()");
XPathExpression expr = xpath.compile("/url-mappings/url-mapping/request-handler-class/text()");
//XPathExpression expr = xpath.compile("/url-mappings/url-mapping["+ x +"]/request-handler-class/text()");
String rhClass = (String)expr.evaluate(nodeList.item(x), XPathConstants.STRING);
System.out.println(rhClass);
}
}
}
I am getting output
/screen1
com.mappingtool.rh.Screen1RH
/screen2
com.mappingtool.rh.Screen1RH
But I need
/screen1
com.mappingtool.rh.Screen1RH
/screen2
com.mappingtool.rh.Screen2RH

You can use expression like
XPathExpression expr = xpath.compile("/url-mappings/url-mapping[contains(#url,'"+nodeValue+"')]/request-handler-class/text()"); where nodeValue is value printed by first System.out.println.

XPathExpression.evaluate using Node [duplicate]

I want to manipulate xml doc having default namespace but no prefix. Is there a way to use xpath without namespace uri just as if there is no namespace?
I believe it should be possible if we set namespaceAware property of documentBuilderFactory to false. But in my case it is not working.
Is my understanding is incorrect or I am doing some mistake in code?
Here is my code:
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(false);
try {
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document dDoc = builder.parse("E:/test.xml");
XPath xPath = XPathFactory.newInstance().newXPath();
NodeList nl = (NodeList) xPath.evaluate("//author", dDoc, XPathConstants.NODESET);
System.out.println(nl.getLength());
} catch (Exception e) {
e.printStackTrace();
}
Here is my xml:
<?xml version="1.0" encoding="UTF-8"?>
<root xmlns="http://www.mydomain.com/schema">
<author>
<book title="t1"/>
<book title="t2"/>
</author>
</root>

The XPath processing for a document that uses the default namespace (no prefix) is the same as the XPath processing for a document that uses prefixes:
For namespace qualified documents you can use a NamespaceContext when you execute the XPath. You will need to prefix the fragments in the XPath to match the NamespaceContext. The prefixes you use do not need to match the prefixes used in the document.
http://download.oracle.com/javase/6/docs/api/javax/xml/namespace/NamespaceContext.html
Here is how it looks with your code:
import java.util.Iterator;
import javax.xml.namespace.NamespaceContext;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
public class Demo {
public static void main(String[] args) {
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(true);
try {
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document dDoc = builder.parse("E:/test.xml");
XPath xPath = XPathFactory.newInstance().newXPath();
xPath.setNamespaceContext(new MyNamespaceContext());
NodeList nl = (NodeList) xPath.evaluate("/ns:root/ns:author", dDoc, XPathConstants.NODESET);
System.out.println(nl.getLength());
} catch (Exception e) {
e.printStackTrace();
}
}
private static class MyNamespaceContext implements NamespaceContext {
public String getNamespaceURI(String prefix) {
if("ns".equals(prefix)) {
return "http://www.mydomain.com/schema";
}
return null;
}
public String getPrefix(String namespaceURI) {
return null;
}
public Iterator getPrefixes(String namespaceURI) {
return null;
}
}
}
Note:
I also used the corrected XPath suggested by Dennis.
The following also appears to work, and is closer to your original question:
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
public class Demo {
public static void main(String[] args) {
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document dDoc = builder.parse("E:/test.xml");
XPath xPath = XPathFactory.newInstance().newXPath();
NodeList nl = (NodeList) xPath.evaluate("/root/author", dDoc, XPathConstants.NODESET);
System.out.println(nl.getLength());
} catch (Exception e) {
e.printStackTrace();
}
}
}

Blaise Doughan is right, attached code is correct.
Problem was somewhere elese. I was running all my tests through Application launcher in Eclipse IDE and nothing was working. Then I discovered Eclipse project was cause of all grief. I ran my class from command prompt, it worked. Created a new eclipse project and pasted same code there, it worked there too.
Thank you all guys for your time and efforts.

I've written a simple NamespaceContext implementation (here), that might be of help. It takes a Map<String, String> as input, where the key is a prefix, and the value is a namespace.
It follows the NamespaceContext spesification, and you can see how it works in the unit tests.
Map<String, String> mappings = new HashMap<>();
mappings.put("foo", "http://foo");
mappings.put("foo2", "http://foo");
mappings.put("bar", "http://bar");
context = new SimpleNamespaceContext(mappings);
context.getNamespaceURI("foo"); // "http://foo"
context.getPrefix("http://foo"); // "foo" or "foo2"
context.getPrefixes("http://foo"); // ["foo", "foo2"]
Note that it has a dependency on Google Guava

How to get the value of text node inside <div> element using XPATH and Jtidy

I have been banging my head over for two days now.
I have a XHTML web-page from which i want to scrap some data
I am using JTidy to DOMParse and then XPathFactory to find nodes using XPath
The Xhtml snippet is something like this
<div style="line-height: 22px;" id="dvTitle" class="titlebtmbrdr01">BAJAJ AUTO LTD.</div>
Now i want that BAJAJ AUTO LTD.
The code that i am using is :
import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.Vector;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class BSEQuotesExtractor implements valueExtractor {
#Override
public Vector<String> getName(Document d) throws XPathExpressionException {
// TODO Auto-generated method stub
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile("//div[#id='dvTitle']/text()");
Object result = expr.evaluate(d, XPathConstants.NODESET);
NodeList nodes = (NodeList)result;
for(int i=0;i<nodes.getLength();i++)
{
System.out.println(nodes.item(i).getNodeValue());
}
return null;
}
public static void main(String[] args) throws MalformedURLException, IOException, XPathExpressionException{
BSEQuotesExtractor q = new BSEQuotesExtractor();
DOMParser parser = new DOMParser(new URL("http://www.bseindia.com/bseplus/StockReach/StockQuote/Equity/BAJAJ%20AUTO%20LTD/BAJAJAUT/532977/Scrips").openStream());
Document d = parser.getDocument();
q.getName(d);
}
}
But i gett a null output and not BAJAJ AUTO LTD.
Please rescue me

try this.
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile("//div[#id='dvTitle']");
Object result = expr.evaluate(d, XPathConstants.NODE);
Node node = (Node)result;
System.out.println(node.getTextContent());

you must use XPathConstants.STRING instead of XPathConstants.NODESET.
You want to get a value of a single element (div), not a list of nodes.
Write:
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
String divContent = (String) path.evaluate("//div[#id='dvTitle']", document, XPathConstants.STRING);
Into divContent you get "BAJAJ AUTO LTD.".

Parse Last.Fm XML from API in Java

URL: http://ws.audioscrobbler.com/2.0/?method=chart.gethypedtracks&api_key=1732077d6772048ccc671c754061cb18&limit=10
From the above url I need to somehow remove the Artist name and the track name from the XML file produced from each Song given but I have no Idea how to work with an XML file structured in this way ??
Any help or pointers would be very much appreciated !
Thanks,
Ross

Here's a fully working class that loads the URL you have indicated and parses the Track and artist names.
Basically it reads the xml into a Document, and runs 2 xpath queries in loops to get the data you want.
The document itself is simple xml, if you reformat it, it looks like:
<?xml version="1.0" encoding="utf-8"?>
<lfm status="ok">
<tracks page="1" perPage="10" totalPages="50" total="500">
<track>
<name>Hysterical</name>
<duration>231</duration>
<percentagechange>3626</percentagechange>
<mbid/>
<url>http://www.last.fm/music/Clap+Your+Hands+Say+Yeah/_/Hysterical</url>
<streamable fulltrack="0">0</streamable>
<artist>
<name>Clap Your Hands Say Yeah</name>
...
All I did to clean it up was run it through a re-formatter like xmlstarlet as I mentioned in my comment. Note: you don't have to reformat it for java to read it if it's well formed. Human readable is all a re-format does for you.
The first xpath query gets the track name using a path lfm/tracks/track/name. You can use something like this xpath tester to try out your xpath queries (you can paste your xml in and it will reformat it too). If you don't understand xpath, there are many sources on the net.
The second xpath works relative to the current track name node, and looks for a following-sibling node of type artist with a name sub-node, and then displays the text of the node.
Here's the code
package net.fish;
import java.net.URL;
import java.net.URLConnection;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class ParseXML {
private static final DocumentBuilderFactory DOCUMENT_BUILDER_FACTORY = DocumentBuilderFactory.newInstance();
private static final XPathFactory XPATH_FACTORY = XPathFactory.newInstance();
public static void main(String[] args) throws Exception {
new ParseXML().parseXml("http://ws.audioscrobbler.com/2.0/?method=chart.gethypedtracks&api_key=1732077d6772048ccc671c754061cb18&limit=10");
}
private void parseXml(String urlPath) throws Exception {
URL url = new URL(urlPath);
URLConnection connection = url.openConnection();
DocumentBuilder db = DOCUMENT_BUILDER_FACTORY.newDocumentBuilder();
final Document document = db.parse(connection.getInputStream());
XPath xPathEvaluator = XPATH_FACTORY.newXPath();
XPathExpression nameExpr = xPathEvaluator.compile("lfm/tracks/track/name");
NodeList trackNameNodes = (NodeList) nameExpr.evaluate(document, XPathConstants.NODESET);
for (int i = 0; i < trackNameNodes.getLength(); i++) {
Node trackNameNode = trackNameNodes.item(i);
System.out.println(String.format("Track Name: %s" , trackNameNode.getTextContent()));
XPathExpression artistNameExpr = xPathEvaluator.compile("following-sibling::artist/name");
NodeList artistNameNodes = (NodeList) artistNameExpr.evaluate(trackNameNode, XPathConstants.NODESET);
for (int j=0; j < artistNameNodes.getLength(); j++) {
System.out.println(String.format(" - Artist Name: %s", artistNameNodes.item(j).getTextContent()));
}
}
}
}

Why doesn't XPath namespace-uri() work out of the box with Java?

I am trying to use the namespace-uri() function in XPath to retrieve nodes based on their fully qualified name. The query //*[local-name() = 'customerName' and namespace-uri() = 'http://example.com/officeN'] in this online XPath tester, among others, correctly returns the relevant nodes. Yet the following self-contained Java class does not retrieve anything. What am I doing wrong with namespace-uri()?
import java.io.StringReader;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
public class Test{
public static void main(String[] args)throws Exception {
XPathExpression expr = XPathFactory.newInstance().newXPath().compile(
"//*[local-name() = 'customerName' and namespace-uri() = 'http://example.com/officeN']");
String xml=
"<Agents xmlns:n=\"http://example.com/officeN\">\n"+
"\t<n:Agent>\n\t\t<n:customerName>Joe Shmo</n:customerName>\n\t</n:Agent>\n"+
"\t<n:Agent>\n\t\t<n:customerName>Mary Brown</n:customerName>\n\t</n:Agent>\n</Agents>";
System.out.println(xml);
Document doc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(new InputSource(new StringReader(xml)));
NodeList nodes = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
System.err.println("\n\nNodes:");
for (int i = 0; i < nodes.getLength(); i++) {
System.err.println(nodes.item(i));
}
}
}

The query looks fine. You also need to declare your DocumentBuilderFactory to be "namespace-aware".
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setNamespaceAware(true);
dbf.newDocumentBuilder().parse(new InputSource(new StringReader(xml)));