I am having a string which contains xyaahhfhajfahj{adhadh}fsfhgs{sfsf}.
Now I want to replace {string} with a space.
I want to replace the curly brackets and the string in it with null.
I want to use replaceFirst for it but I don't know the regex for doing it.
Try this:
public class TestCls {
public static void main(String[] args) {
String str = "xyaahhfhajfahj{adhadh}fsfhgs{sfsf}";
String str1 = str.replaceAll("\\{[a-zA-z0-9]*\\}", " ");// to replace string within "{" & "}" with " ".
String str2 = str.replaceFirst("\\{[a-zA-z0-9]*\\}", " ");// to replace first string within "{" & "}" with " ".
System.out.println(str1);
System.out.println(str2);
}
}
If you're saying that you want to find the first occurrence of anything inside of { and }, then replace it including the brackets with nothing, here's an example that will do that:
String input = "xyaahhfhajfahj{adhadh}fsfhgs{sfsf}";
String output = input.replaceFirst("\\{.*?\\}", "");
System.out.println(output ); // output will be "xyaahhfhajfahjfsfhgs{sfsf}"
Related
I have a string from which I need to remove all mentioned punctuations and spaces. My code looks as follows:
String s = "s[film] fever(normal) curse;";
String[] spart = s.split("[,/?:;\\[\\]\"{}()\\-_+*=|<>!`~##$%^&\\s+]");
System.out.println("spart[0]: " + spart[0]);
System.out.println("spart[1]: " + spart[1]);
System.out.println("spart[2]: " + spart[2]);
System.out.println("spart[3]: " + spart[3]);
System.out.println("spart[4]: " + spart[4]);
But, I am getting some elements which are blank. The output is:
spart[0]: s
spart[1]: film
spart[2]:
spart[3]: fever
spart[4]: normal
My desired output is:
spart[0]: s
spart[1]: film
spart[2]: fever
spart[3]: normal
spart[4]: curse
Try with this:
public static void main(String[] args) {
String s = "s[film] fever(normal) curse;";
String[] spart = s.split("[,/?:;\\[\\]\"{}()\\-_+*=|<>!`~##$%^&\\s]+");
for (String string : spart) {
System.out.println("'"+string+"'");
}
}
output:
's'
'film'
'fever'
'normal'
'curse'
I believe it is because you have a Greedy quantifier for space at the end there. I think you would have to use an escape sequence for the plus sign too.
String spart = s.replaceAll( "\\W", " " ).split(" +");
I have a string:
100-200-300-400
i want replace the dash to "," and add single quote so it become:
'100','200','300','400'
My current code only able to replace "-" to "," ,How can i plus the single quote?
String str1 = "100-200-300-400";
split = str1 .replaceAll("-", ",");
if (split.endsWith(","))
{
split = split.substring(0, split.length()-1);
}
You can use
split = str1 .replaceAll("-", "','");
split = "'" + split + "'";
As an alternative if you are using java 1.8 then you could create a StringJoiner and split the String by -. This would be a bit less time efficient, but it would be more safe if you take, for example, a traling - into account.
A small sample could look like this.
String string = "100-200-300-400-";
String[] splittet = string.split("-");
StringJoiner joiner = new StringJoiner("','", "'", "'");
for(String s : splittet) {
joiner.add(s);
}
System.out.println(joiner);
This will work for you :
public static void main(String[] args) throws Exception {
String s = "100-200-300-400";
System.out.println(s.replaceAll("(\\d+)(-|$)", "'$1',").replaceAll(",$", ""));
}
O/P :
'100','200','300','400'
Or (if you don't want to use replaceAll() twice.
public static void main(String[] args) throws Exception {
String s = "100-200-300-400";
s = s.replaceAll("(\\d+)(-|$)", "'$1',");
System.out.println(s.substring(0, s.length()-1));
}
I have Strings "a,b,c,d,,,,, ", ",,,,a,,,,"
I want these strings to be converted into "a,b,c,d" and ",,,,a" respectively.
I am writing a regular expression for this. My java code looks like this
public class TestRegx{
public static void main(String[] arg){
String text = ",,,a,,,";
System.out.println("Before " +text);
text = text.replaceAll("[^a-zA-Z0-9]","");
System.out.println("After " +text);
}}
But this is removing all the commas here.
How can write this to achieve as given above?
Use :
text.replaceAll(",*$", "")
As mentioned by #Jonny in comments, can also use:-
text.replaceAll(",+$", "")
Your first example had a space at the end, so it needs to match [, ]. When using the same regular expression multiple times, it's better to compile it up front, and it only needs to replace once, and only if at least one character will be removed (+).
Simple version:
text = text.replaceFirst("[, ]+$", "");
Full code to test both inputs:
String[] texts = { "a,b,c,d,,,,, ", ",,,,a,,,," };
Pattern p = Pattern.compile("[, ]+$");
for (String text : texts) {
String text2 = p.matcher(text).replaceFirst("");
System.out.println("Before \"" + text + "\"");
System.out.println("After \"" + text2 + "\"");
}
Output
Before "a,b,c,d,,,,, "
After "a,b,c,d"
Before ",,,,a,,,,"
After ",,,,a"
Example:
Input
Str = P.O.Box
Output
Str= PO BOX
I can able to convert the string to uppercase and replace all dot(.) with a space.
public static void main(String args[]){
String s = "P.O.Box 1836";
String uppercase = s.toUpperCase();
System.out.println("uppercase "+uppercase);
String replace = uppercase.replace("."," ");
System.out.println("replace "+replace);
}
System.out.print(s.toUpperCase().replaceFirst("[.]", "").replaceAll("[.]"," "));
If you look the String API carefully, you would notice that there's a methods that goes by:-
replaceFirst(String regex, String replacement)
Hope it helps.
You have to use the replaceFirst method twice. First for replacing the . with <nothing>. Second for replacing the second . with a <space>.
String str = "P.O.Box";
str = str.replaceFirst("[.]", "");
System.out.println(str.replaceFirst("[.]", " "));
This one liner should do the job:
String s = "P.O.Box";
String replace = s.toUpperCase().replaceAll("\\.(?=[^.]*\\.)", "").replace('.', ' ');
//=> PO BOX
String resultValue = "";
String[] result = uppercase.split("[.]");
for (String value : result)
{
if (value.toCharArray().length > 1)
{
resultValue = resultValue + " " + value;
}
else
{
resultValue = resultValue + value;
}
}
Try this
System.out.println("P.O.Box".toUpperCase().replaceFirst("\\.","").replaceAll("\\."," "));
Out put
PO BOX
NOTE: \\ is needed here if you just use . only your out put will blank.
Live demo.
You should use replaceFirst method twice.
String replace = uppercase.replace("\\.", "").replaceFirst("\\.", "");
As you want to remove the first dot and replace the second one with a space, you need replace the whole P.O. section
Use
replace("P\\.O\\.", "PO ");
i have a space before a new line in a string and cant remove it (in java).
I have tried the following but nothing works:
strToFix = strToFix.trim();
strToFix = strToFix.replace(" \n", "");
strToFix = strToFix.replaceAll("\\s\\n", "");
myString.replaceAll("[ \t]+(\r\n?|\n)", "$1");
replaceAll takes a regular expression as an argument. The [ \t] matches one or more spaces or tabs. The (\r\n?|\n) matches a newline and puts the result in $1.
try this:
strToFix = strToFix.replaceAll(" \\n", "\n");
'\' is a special character in regex, you need to escape it use '\'.
I believe with this one you should try this instead:
strToFix = strToFix.replace(" \\n", "\n");
Edit:
I forgot the escape in my original answer. James.Xu in his answer reminded me.
Are you sure?
String s1 = "hi ";
System.out.println("|" + s1.trim() + "|");
String s2 = "hi \n";
System.out.println("|" + s2.trim() + "|");
prints
|hi|
|hi|
are you sure it is a space what you're trying to remove? You should print string bytes and see if the first byte's value is actually a 32 (decimal) or 20 (hexadecimal).
trim() seems to do what your asking on my system. Here's the code I used, maybe you want to try it on your system:
public class so5488527 {
public static void main(String [] args)
{
String testString1 = "abc \n";
String testString2 = "def \n";
String testString3 = "ghi \n";
String testString4 = "jkl \n";
testString3 = testString3.trim();
System.out.println(testString1);
System.out.println(testString2.trim());
System.out.println(testString3);
System.out.println(testString4.trim());
}
}