How can I load html page and insert its content into div element? I don't want to use ContentPanel.setUrl (for example), because it will create IFrame
Is it possible?
Simply use Gxt's HtmlContainer class and it's setUrl() method:
http://dev.sencha.com/deploy/gxt-2.2.1/docs/api/com/extjs/gxt/ui/client/widget/HtmlContainer.html#setUrl(java.lang.String)
Yes, use RequestBuilder go get content of given url:
http://code.google.com/p/google-web-toolkit-doc-1-5/wiki/DevGuideHttpRequests
Remember about same origin policy - if you want to get content of a page from other domain then you will need to write GWT service which will make the server download the content and return to your application through RPC.
Related
In my application, the http://localhost:8080/TestApplication/subCategories/2 will display subcategories of my table with id 2.
Click Here
When I click on the link rendered by the HTML above, my server is redirecting to http://localhost:8080/SecondOpinion/subCategories/hello
I want it to redirect to
http://localhost:8080/SecondOpinion/hello
How do I achieve that?
First of all, this is nothing to do with "anchor tags". An anchor tag is an HTML element of the form <a name="here">, and it defines a location within the HTML that another URL can link to.
What you have is an ordinary HTML link, and what you are seeing is standard HTML behavior for a relative link.
A relative link is resolved related to the "parent" URL for the page containing the link.
If you want a link to go somewhere else, you can:
Use an absolute URL
Use path in the relative link; e.g. `Click Here
Put a <base href="..."> element into your document's <head> section.
In your case, you seem to be1 combining relative URLs with some unspecified server-side redirection. In this case, you could either:
change as above, so that the URL that is sent to the server (before redirection) goes to a better place, or
change the redirection logic in your server.
I can't tell which would be more appropriate.
1 - I am inferring this because you said "my server is redirecting to". It is possible that you actually mean that the browser is sending that URL to the server, and there is no redirection happening at all.
I'm using struts2 framework(java/js/html/css combo) for my webapp. I am reading a text file from server and I want to write the response to an iFrame present in the same jsp.
Flow:
(1) On click of a link, I pass the relative URL of the text file to jsp.
(2) When the jsp page loads, the java code in the jsp reads the file from server.
(3) Now this response has to be written to an iFrame present in the same jsp file
Can anyone plz help me in writing such response to an iFrame?
Thanks in advance :)
[code not tested, only a demostration of the concept]
here's some very rough idea as to how to fix your code, they definitly not the best but they should be enough to help you understand the concept.
However I'd still recommend going over the whole concept and maybe come up with a more efficent way to do what you need.
if you insist on using iframe, you need to make use of 2 seperate jsp as W3C says in "Implementing HTML Frames":
Any frame that attempts to assign as its SRC a URL used by any of its ancestors is treated as if it has no SRC URL at all (basically a blank frame).
so you'll need 2 jsp, the first one is basically what you have but the the src of the iframe changed to:
<iframe scrolling="yes" width="80%" height="200" src="second.jsp?content=<%=all%>" name="imgbox" id="imgbox">
and the second one will be something like :
<html><body><%= request.getAttribute("content") %></body></html>
From the code you've shown you forced a "content update" on the iframe by using javascript. The proper/usual way to update an iframe is to provide different input parameter to the second jsp and let it update it for you.
Finally, I'd recommend using JSTL as much as possible instead of scriptlets. It is much cleaner.
What you need to do is set the src attribute of the IFRAME to the jsp url when your link is clicked. Another way to do it is doing something like this:
<iframe src="" name="iframe_a"></iframe>
<p>W3Schools.com</p>
with the correct parameters of course
I'm developing with Liferay portal.
And now I'm facing a little problem:
I'm making site for some Company that has subsidiaries.
Then, I must cut out some parts(precisely header and footer)
of other site(sub. site) and put the body of page without'em in iframe of main site.
I was "googling", looking for something about Grabbers.
but I've found just about how to grab with PHP or Perl.
and here
It doesn't seem to be exact what I need.
You can try the WebProxy portlet for this.
As you'll have to modify the external content's body, you can't simply show it in an iframe, so this portlet might be what you need. It doesn't work with an iframe internally and you can replace some content on-the-fly.
how to get html source code which was rendered by a javascript in webpage. How can i proceed this? Using xsl or javascript or java.
Get entire HTML in current page:
function getHTML(){
var D=document,h=D.getElementsByTagName('html')[0],e;
if(h.outerHTML)return h.outerHTML;
e=D.createElement('div');
e.appendChild(h.cloneNode(true));
return e.innerHTML;
}
outerHTML is non-standard property thus might not supported in some browser (i.e., Firefox), in this case this function mimic the outerHTML feature by cloning the html node into unattached element and read it's innerHTML property.
Javascript provides
document.getElementByTagName('')
You can get any tag from this line. Moreover if you want to do any operation to this tag then assign any id to that tag. then you can use document.getElementById('') to do any operation on it.
These will give you source code.
I decided to store uploaded to servlet pictures in DB. But how to show them in browser (in particular div with css image-background style) without page reload?
In details: I have an full-AJAX web client that works with java servlet.
Thanks.
Create a servlet that accepts a name / id uniquely identifying the picture as a GET parameter
Let the servlet load the picture from DB (as byte array or better - as stream)
Stream the picture using response.getOutputStream()
Don't forget to set the content-type to image/png or image/jpeg
Refer to the image in the css with url: imageServlet?id=13214