Using an Interface in another interface - java

I am not sure how to proceed with adding element to the Priority Queue. I don't want code to be spoon feed to me, can someone just explain to me how to use interface passed to another interface as parameter and a class implementing one of its method. Please give me pointers, I will look it up and learn how to implement this code.
QueueItem class
public interface QueueItem
{
/**
* Returns the priority of this item. The priority is guaranteed to be
* between 0 - 100, where 0 is lowest and 100 is highest priority.
*/
public int priority();
}
PriorityQueue class
public interface PriorityQueue
{
/**
* Inserts a queue item into the priority queue.
*/
public void insert(QueueItem q);
/**
* Returns the item with the highest priority.
*/
public QueueItem next();
}
QuickInsertQueue class
public class QuickInsertQueue implements PriorityQueue {
#Override
public void insert(QueueItem q) {
// TODO Auto-generated method stub
}
#Override
public QueueItem next() {
// TODO Auto-generated method stub
return null;
}
}
I have to Write a QuickInsertQueue class that implements the PriorityQueue
interface having insert() method O(1).

You are already on the right track. Your interfaces are defined and your class definition has the correct implementation attached. Since you say you dont want code spoon fed to you which I applaud - the next step you want to implement is actually adding the HashMap instance variable to your class, since that is your underlying storage. And in your method implementation for insert, you will be adding your variable to the map.
Eventually you are going to need to read about Generics.

Ted and Perception have you told you what you need. One more suggestion I have is you need to find the right data structure to use so that insertion would be O(1). I suggest you look at heaps. Specifically looking at min-heaps allows you to insert in contant time. Look here. I hope this helps.

You use an interface to guarantee that any object you receive will behave according to the interface. That's why your QuickInsertQueue needs to implement the methods of PriorityQueue. The only information it can use about the inserted objects, though, is that they behave according to the QueueItem interface—that is, they have a priority() method that returns an int. Your implementation can rely on that, but nothing else, about the objects it will be managing.

You are on the right track.
So, without getting into code level details that you are right you should figure out on your own, how it (is supposed to) work in an ideal world is -
All interaction in your system between different kind of objects is defined by using interfaces. i.e. if you need to find out "how do things interact in my application" you should need to look no further than all the interfaces. (Everything else is implementation detail.) In other words, all the real work is done by classes (that implement interfaces) but the interaction is defined by the interfaces.
One implementation class e.g. QuickInsertQueue, should not need to know anything about other implementations. (e.g. implementation of QueueItem) i.e. QueueItem does not need to know about what class is implementing PriorityQueue nor does PriorityQueue need to know about the class that implements QueueItem. (For this to work, make sure an in interface has all the methods necessary to allow others to interact with it. Also note that classes can implement multiple interfaces)
Practically,
Unless you are make use of things like factory method pattern and/or IoC containers like Spring or Guice, you will have at the least, an implementation instance (i.e. an object of a class) instantiating other implementations (objects of other classes) in your system.
(In this case, data structure to use so that insertion should be O(1) is an implementation detail quuestion/discussion)

Related

What is use of assaigning subclass object to superclass reference variable [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
What does it mean to “program to an interface”?
I keep coming across this term:
Program to an interface.
What exactly does it mean? A real life design scenario would be highly appreciated.
To put it simply, instead of writing your classes in a way that says
I depend on this specific class to do my work
you write it in a way that says
I depend on any class that does this stuff to do my work.
The first example represents a class that depends on a specific concrete implementation to do its work. Inherently, that's not very flexible.
The second example represents a class written to an interface. It doesn't care what concrete object you use, it just cares that it implements certain behavior. This makes the class much more flexible, as it can be provided with any number of concrete implementations to do its work.
As an example, a particular class may need to perform some logging. If you write the class to depend on a TextFileLogger, the class is forever forced to write out its log records to a text file. If you want to change the behavior of the logging, you must change the class itself. The class is tightly coupled with its logger.
If, however, you write the class to depend on an ILogger interface, and then provide the class with a TextFileLogger, you will have accomplished the same thing, but with the added benefit of being much more flexible. You are able to provide any other type of ILogger at will, without changing the class itself. The class and its logger are now loosely coupled, and your class is much more flexible.
An interface is a collection of related methods, that only contains the signatures of those methods - not the actual implementation.
If a class implements an interface (class Car implements IDrivable) it has to provide code for all signatures defined in the interface.
Basic example:
You have to classes Car and Bike. Both implement the interface IDrivable:
interface IDrivable
{
void accelerate();
void brake();
}
class Car implements IDrivable
{
void accelerate()
{ System.out.println("Vroom"); }
void brake()
{ System.out.println("Queeeeek");}
}
class Bike implements IDrivable
{
void accelerate()
{ System.out.println("Rattle, Rattle, ..."); }
void brake()
{ System.out.println("..."); }
}
Now let's assume you have a collection of objects, that are all "drivable" (their classes all implement IDrivable):
List<IDrivable> vehicleList = new ArrayList<IDrivable>();
list.add(new Car());
list.add(new Car());
list.add(new Bike());
list.add(new Car());
list.add(new Bike());
list.add(new Bike());
If you now want to loop over that collection, you can rely on the fact, that every object in that collection implements accelerate():
for(IDrivable vehicle: vehicleList)
{
vehicle.accelerate(); //this could be a bike or a car, or anything that implements IDrivable
}
By calling that interface method you are not programming to an implementation but to an interface - a contract that ensures that the call target implements a certain functionality.
The same behavior could be achieved using inheritance, but deriving from a common base class results in tight coupling which can be avoided using interfaces.
Polymorphism depends on programming to an interface, not an implementation.
There are two benefits to manipulating objects solely in terms of the interface defined by abstract classes:
Clients remain unaware of the specific types of objects they use, as long as the objects adhere to the interface that clients expect.
Clients remain unaware of the classes that implement these objects. Clients only know about the abstract class(es) defining the interface.
This so greatly reduces implementation dependencies between subsystems that it leads to this principle of programming to an interface.
See the Factory Method pattern for further reasoning of this design.
Source: "Design Patterns: Elements of Reusable Object-Oriented Software" by G.O.F.
Also See: Factory Pattern. When to use factory methods?
Real-world examples are applenty. One of them:
For JDBC, you are using the interface java.sql.Connection. However, each JDBC driver provides its own implementation of Connection. You don't have to know anything about the particular implementation, because it conforms to the Connection interface.
Another one is from the java collections framework. There is a java.util.Collection interface, which defines size, add and remove methods (among many others). So you can use all types of collections interchangeably. Let's say you have the following:
public float calculateCoefficient(Collection collection) {
return collection.size() * something / somethingElse;
}
And two other methods that invoke this one. One of the other methods uses a LinkedList because it's more efficient for it's purposes, and the other uses a TreeSet.
Because both LinkedList and TreeSet implement the Collection interface, you can use only one method to perform the coefficient calculation. No need to duplicate your code.
And here comes the "program to an interface" - you don't care how exactly is the size() method implemented, you know that it should return the size of the collection - i.e. you have programmed to the Collection interface, rather than to LinkedList and TreeSet in particular.
But my advice is to find a reading - perhaps a book ("Thinking in Java" for example) - where the concept is explained in details.
Every object has an exposed interface. A collection has Add, Remove, At, etc. A socket may have Send, Receive, Close and so on.
Every object you can actually get a reference to has a concrete implementation of these interfaces.
Both of these things are obvious, however what is somewhat less obvious...
Your code shouldn't rely on the implementation details of an object, just its published interface.
If you take it to an extreme, you'd only code against Collection<T> and so on (rather than ArrayList<T>). More practically, just make sure you could swap in something conceptually identical without breaking your code.
To hammer out the Collection<T> example: you have a collection of something, you're actually using ArrayList<T> because why not. You should make sure you're code isn't going to break if, say, you end up using LinkedList<T> in the future.
"Programming to an interface" happens when you use libraries, other code you depend upon in your own code. Then, the way that other code represents itself to you, the method names, its parameters, return values etc make up the interface you have to program to. So it's about how you use third-party code.
It also means, you don't have to care about the internals of the code you depend on, as long as the interface stays the same, your code is safe (well, more or less...)
Technically there are finer details, like language concepts called "interfaces" in Java for example.
If you want to find out more, you could ask what "Implementing an Interface" means...
I think this is one of Erich Gamma's mantras. I can't find the first time he described it (before the GOF book), but you can see it discussed in an interview at: http://www.artima.com/lejava/articles/designprinciples.html
It basically means that the only part of the library which you're going to use you should rely upon is it's API (Application programming interface) and that you shouldn't base your application on the concrete implementation of the library.
eg. Supposed you have a library that gives you a stack. The class gives you a couple of methods. Let's say push, pop, isempty and top. You should write your application relying only on these. One way to violate this would be to peek inside and find out that the stack is implemented using an array of some kind so that if you pop from an empty stack, you'd get some kind of Index exception and to then catch this rather than to rely on the isempty method which the class provides. The former approach would fail if the library provider switched from using an array to using some kind of list while the latter would still work assuming that the provider kept his API still working.

Using interfaces as class members [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
What does it mean to “program to an interface”?
I keep coming across this term:
Program to an interface.
What exactly does it mean? A real life design scenario would be highly appreciated.
To put it simply, instead of writing your classes in a way that says
I depend on this specific class to do my work
you write it in a way that says
I depend on any class that does this stuff to do my work.
The first example represents a class that depends on a specific concrete implementation to do its work. Inherently, that's not very flexible.
The second example represents a class written to an interface. It doesn't care what concrete object you use, it just cares that it implements certain behavior. This makes the class much more flexible, as it can be provided with any number of concrete implementations to do its work.
As an example, a particular class may need to perform some logging. If you write the class to depend on a TextFileLogger, the class is forever forced to write out its log records to a text file. If you want to change the behavior of the logging, you must change the class itself. The class is tightly coupled with its logger.
If, however, you write the class to depend on an ILogger interface, and then provide the class with a TextFileLogger, you will have accomplished the same thing, but with the added benefit of being much more flexible. You are able to provide any other type of ILogger at will, without changing the class itself. The class and its logger are now loosely coupled, and your class is much more flexible.
An interface is a collection of related methods, that only contains the signatures of those methods - not the actual implementation.
If a class implements an interface (class Car implements IDrivable) it has to provide code for all signatures defined in the interface.
Basic example:
You have to classes Car and Bike. Both implement the interface IDrivable:
interface IDrivable
{
void accelerate();
void brake();
}
class Car implements IDrivable
{
void accelerate()
{ System.out.println("Vroom"); }
void brake()
{ System.out.println("Queeeeek");}
}
class Bike implements IDrivable
{
void accelerate()
{ System.out.println("Rattle, Rattle, ..."); }
void brake()
{ System.out.println("..."); }
}
Now let's assume you have a collection of objects, that are all "drivable" (their classes all implement IDrivable):
List<IDrivable> vehicleList = new ArrayList<IDrivable>();
list.add(new Car());
list.add(new Car());
list.add(new Bike());
list.add(new Car());
list.add(new Bike());
list.add(new Bike());
If you now want to loop over that collection, you can rely on the fact, that every object in that collection implements accelerate():
for(IDrivable vehicle: vehicleList)
{
vehicle.accelerate(); //this could be a bike or a car, or anything that implements IDrivable
}
By calling that interface method you are not programming to an implementation but to an interface - a contract that ensures that the call target implements a certain functionality.
The same behavior could be achieved using inheritance, but deriving from a common base class results in tight coupling which can be avoided using interfaces.
Polymorphism depends on programming to an interface, not an implementation.
There are two benefits to manipulating objects solely in terms of the interface defined by abstract classes:
Clients remain unaware of the specific types of objects they use, as long as the objects adhere to the interface that clients expect.
Clients remain unaware of the classes that implement these objects. Clients only know about the abstract class(es) defining the interface.
This so greatly reduces implementation dependencies between subsystems that it leads to this principle of programming to an interface.
See the Factory Method pattern for further reasoning of this design.
Source: "Design Patterns: Elements of Reusable Object-Oriented Software" by G.O.F.
Also See: Factory Pattern. When to use factory methods?
Real-world examples are applenty. One of them:
For JDBC, you are using the interface java.sql.Connection. However, each JDBC driver provides its own implementation of Connection. You don't have to know anything about the particular implementation, because it conforms to the Connection interface.
Another one is from the java collections framework. There is a java.util.Collection interface, which defines size, add and remove methods (among many others). So you can use all types of collections interchangeably. Let's say you have the following:
public float calculateCoefficient(Collection collection) {
return collection.size() * something / somethingElse;
}
And two other methods that invoke this one. One of the other methods uses a LinkedList because it's more efficient for it's purposes, and the other uses a TreeSet.
Because both LinkedList and TreeSet implement the Collection interface, you can use only one method to perform the coefficient calculation. No need to duplicate your code.
And here comes the "program to an interface" - you don't care how exactly is the size() method implemented, you know that it should return the size of the collection - i.e. you have programmed to the Collection interface, rather than to LinkedList and TreeSet in particular.
But my advice is to find a reading - perhaps a book ("Thinking in Java" for example) - where the concept is explained in details.
Every object has an exposed interface. A collection has Add, Remove, At, etc. A socket may have Send, Receive, Close and so on.
Every object you can actually get a reference to has a concrete implementation of these interfaces.
Both of these things are obvious, however what is somewhat less obvious...
Your code shouldn't rely on the implementation details of an object, just its published interface.
If you take it to an extreme, you'd only code against Collection<T> and so on (rather than ArrayList<T>). More practically, just make sure you could swap in something conceptually identical without breaking your code.
To hammer out the Collection<T> example: you have a collection of something, you're actually using ArrayList<T> because why not. You should make sure you're code isn't going to break if, say, you end up using LinkedList<T> in the future.
"Programming to an interface" happens when you use libraries, other code you depend upon in your own code. Then, the way that other code represents itself to you, the method names, its parameters, return values etc make up the interface you have to program to. So it's about how you use third-party code.
It also means, you don't have to care about the internals of the code you depend on, as long as the interface stays the same, your code is safe (well, more or less...)
Technically there are finer details, like language concepts called "interfaces" in Java for example.
If you want to find out more, you could ask what "Implementing an Interface" means...
I think this is one of Erich Gamma's mantras. I can't find the first time he described it (before the GOF book), but you can see it discussed in an interview at: http://www.artima.com/lejava/articles/designprinciples.html
It basically means that the only part of the library which you're going to use you should rely upon is it's API (Application programming interface) and that you shouldn't base your application on the concrete implementation of the library.
eg. Supposed you have a library that gives you a stack. The class gives you a couple of methods. Let's say push, pop, isempty and top. You should write your application relying only on these. One way to violate this would be to peek inside and find out that the stack is implemented using an array of some kind so that if you pop from an empty stack, you'd get some kind of Index exception and to then catch this rather than to rely on the isempty method which the class provides. The former approach would fail if the library provider switched from using an array to using some kind of list while the latter would still work assuming that the provider kept his API still working.

Why are iterators private?

Iterators are nested classes exported to clients. Then why are the declared private instead of public ?
eg:
private abstract class HashIterator<E> implements Iterator<E> {
private final class EntryIterator extends HashIterator<Map.Entry<K,V>> {
public Map.Entry<K,V> next() {
return nextEntry();
}
}
It hides implementation details which class users dont need to know. Eg HashSet
public Iterator<E> iterator()
Returns an iterator over the elements in this set.
it does not say which concrete Iterator is returned, it is a private class invisible for users, users dont need to know implementation details and HashSet designers are free to change the implementation without notice
In the general case, they don't have to be private; i.e. if you are designing a data structure, there is nothing stopping you from declaring your iterator class as public.
However, private iterators are "good design" if the data structure is intended to be a string abstraction; i.e. one where the internal representation is hidden from client code.
One reason is that making the iterator class private prevents undesirable coupling; i.e. it stops some external class from depending on the actual iterator code in a way that would make future code changes harder.
Another reason is that in most cases an extensible public iterator class couldn't be instantiated anyway. Or at least, not without relaxing the abstraction boundary of the data structure.
Another way to look at this is that making the iterator class public would not achieve anything. The caller typically doesn't need to use anything apart from the methods in the Iterator API. And if it does, then the solution is to extend the iterator API (interface) to provide the additional methods.
There are many reasons and caveats to it:
Keeping class private would not allow client to depend on the actual implementation
Keeps the code loosely coupled
It strictly applies code to an interface as it will not allow you to cast to actual implementation because of it being private
It logically emphasizes that the class is only useful to the parent class and no other code should depend on that
Actual implementation can change anytime without notice from Java team as already stated in other answer.

OOP-Design: Interface-Methods with implementation-dependent parameters

The subject says it already:
I am thinking right now about following design-problem: I define an interface for a specific type of object that contains various methods.
Now i have the problem, that different implementations of this interface, need additional/different method-parameters (because the way they are implemented makes this necessary), which i cannot incorporate into the interface because they are not common to all interface-implementations.
Now i realize that interface implementations could come with their own property-files, loading their additional parameters from there, but what if these parameters need to be passed in at runtime?
Currently i can only think of passing in a Map<String, Object> parameters to overcome this problem - since JDK-Classes like DocumentBuilderFactory are doing something very similar by providing methods like setAttribute(String attName, Object attValue) this
seems like a feasible approach to solve this problem.
Nevertheless i would be interested in how others solve issues like this, alternative ideas?
I dont want to derive from the interface and add additional methods, since in my case i would then have to throw NotImplementException from the methods of the base interface.
UPDATE:
What could be eventual problems of the Map-approach? Implementing classes are free to ignore it completely if they cant make use of additional parameters.
Others might check if the Map contains the desired parameter-names, check the type of their values and use them if valid, throw an exception if not.
I have also seen this being used for the abstract class JAXBContext, so it seems to be a common approach..
UPDATE:
I decided to go for the map-approach, since i dont see any obvious disadvantages and it is being used in the JDK as well (yes, i know this does not necessarily mean much :)
Since i cannot accept an answer on this question, i will just upvote. Thanks for your input!
regards,
--qu
You should just initialize each inheritor with its own specific required parameters and let the interface method remain parameter-less, as in:
Interface Runnable:
public interface Runnable {
public abstract void run();
}
Implementation:
public class MyRunnable {
private final String myConcreteString;
public MyRunnable(String myConcreteString) {
this.myConcreteString = myConcreteString;
}
public void run() {
// do something with myConcreteString
}
}
The point of the interfaces is to have something that is common to all implementations. By trying to do this you destroy the whole reason why interfaces exists.
If you absolutely must do that there is a simple enough way that I have used before.
My answer is in C++ because I'm just not that fluent in other languages. I'm sure there are ways to implement this in java as well.
SomeMethod(void* parameterData);
void* parameterData is a pointer to a struct containing your data. In each implementation you know what you are receiving. You can even have a enum to tell you what kind of data you are receiving.
SSomeData* data = (SSomeData)parameterData
EDIT:
Another approach would be to create a new interface for the parameters: IParameterData.
Inside that interface you have 2 methods: GetParameter(name) and SetParameter(name).
For each implementation of your primary interface you create a implementation of IParameterData.
I hope it helps
couldn't you design subinterfaces that extend your (super)interface?
anyhow I see a design problem if you need a method with different parameters depending on the implementation!
edit: code to clarify
interface CommonBehaviour
{
void methodA(int aParam);
}
interface SpecificBehaviour extends CommonBehaviour
{
void methodB(int aParam, int anotherParam);
}
class SpecificBehaviourImpl implements SpecificBehaviour
{
void methodA(int aParam)
{
//do something common
}
void methodB(int aParam, int anotherParam)
{
//do something specific
}
}
CommonBehaviour myObj = new SpecificBehaviourImpl();
EDIT: You may benefit from the Command pattern:
"Using command objects makes it easier to construct general components that need to delegate, sequence or execute method calls at a time of their choosing without the need to know the owner of the method or the method parameters."
(source: wikipedia)
I don't think the Map approach to be any good, I may accept it as a fix of existing code that would allow you to have any parameter number and type, but without formal checks! You're trying to define a common behavior (interface methods) given a variable, runtime, state.
You should introduce parameter object representing a super-set of possible arguments.
In your place, I would consider finding appropriate design pattern to your problem, rather then try to bend the interface methods to suit your needs. Look into Strategy Pattern for starters.
Can you invert the problem, and implement an interface on the user of these objects which they can query for the additional parameters?
So, when you instantiate these objects implementing the common interface, you also pass in (e.g. to their constructor) an object which provides a way of accessing the additional parameters they might require.
Say your interface has a method 'doSomething' taking parameter 'a', but you have an implementation that needs to know what 'b' is inside this 'doSomething' method. It would call 'getB' on the object you provided to it's constructor to get this information.

How to write a method that accepts stacks and queues?

So I have this really large method I wrote. If it's given a stack, it will return a stack. If it's given a queue, it will return a queue. It uses a lot of recursion, and it accepts a queue/stack and returns that same queue/stack modified accordingly.
I don't want to copy/paste my method just so I can change the type used inside, so is there any way I can make this generic? As in, it will accept any old collection and play with it? I tried just using Collection, but the trouble with that is it doesn't have a .remove() I can use with the stack/queue.
Any help would be greatly appreciated.
Thanks.
Make your method private, and create two public methods: one which takes a stack and one which takes a queue. have each of these methods cast and return the result of calling the private method. That way you avoid repetition while still having specific method signatures.
You could use Collection but then have special case handling just around your remove operations. Of course you'll have to figure out what to do when you get a collection that's not one of the two.
if (myCollection instanceof Queue) {
((Queue)myCollection).remove();
} else if (myCollection instanceof Stack) {
((Stack)myCollection).remove(thingy);
} else {
// Oops! Now what?
}
Queue and Stack both have a remove() method, but the method is not the same. Because of this, Java will need to know which of those methods to call when compiling the code. You will need to have 2 separate methods. Sorry
You need to write an interface that has the operations you need from both Stack and Queue, since you want to use recursion/operations upon both.
This new interface would have two concrete classes that would rely on instances of Stack and Queue underneath, then polymorphism would to the magic.
You can always have a method for 'getUnderlyingCollection()' so you could have the actual Stack or Queue, after the proper cast, but attain to polymorphic operations would make your recursive algorithm more generic.
I presume you mean java.util.Stack and java.util.Queue. Queue defines its own remove() method. Stack inherits its remove(...) methods from java.util.Vector, so I assume you actually mean pop()?
Two ways spring to mind:
Provide two public method overloads which both call a private method with two parameters, one of which is always null.
Define an interface with the common methods you need, with an anonymous inner class definition in each of two private methods (or a full concrete class definitions if they're sufficiently large).
Which you should choose depends on how many ugly conditional method calls you will need to do internally. An OO-purist would prefer the interface implementation regardless. :-)

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