How do I load database credentials from a properties file in JPA? - java

So I have a Java/JPA2.0 (EclipseLink) app that connects to a MySQL database. My intention is just passing a JAR file around with a db.properties file. The db.properties should contain the server host address, username, password, etc so that the end user can just plug that in and start using the JAR in their projects.
Currently, I just used Netbeans to create a persistence.xml file with the credentials and that works. But how do I implement the properties file?
My EntityManager class:
public class Factories {
private static final EntityManagerFactory entityManagerFactory = buildEntityManagerFactory();
private static EntityManagerFactory buildEntityManagerFactory() {
try {
return Persistence.createEntityManagerFactory("MyPU");
} catch (Exception ex) {
throw new ExceptionInInitializerError(ex);
}
}
public static EntityManager getEntityManager() {
return entityManagerFactory.createEntityManager();
}
}
Thanks

You can use the two-parameter version of the createEntityManagerFactory() method. The second argument (the Map) can be used to pass properties including the credentials to the database. You can therefore pass in a map with keys javax.persistence.jdbc.user and javax.persistence.jdbc.password and appropriate values.
An example in the EclipseLink wiki demonstrates how to achieve this, although it uses classes provided by EclipseLink to achieve this:
import static org.eclipse.persistence.config.PersistenceUnitProperties.*;
...
Map properties = new HashMap();
// Ensure RESOURCE_LOCAL transactions is used.
properties.put(TRANSACTION_TYPE,
PersistenceUnitTransactionType.RESOURCE_LOCAL.name());
// Configure the internal EclipseLink connection pool
properties.put(JDBC_DRIVER, "oracle.jdbc.OracleDriver");
properties.put(JDBC_URL, "jdbc:oracle:thin:#localhost:1521:ORCL");
properties.put(JDBC_USER, "scott");
properties.put(JDBC_PASSWORD, "tiger");
// Configure logging. FINE ensures all SQL is shown
properties.put(LOGGING_LEVEL, "FINE");
properties.put(LOGGING_TIMESTAMP, "false");
properties.put(LOGGING_THREAD, "false");
properties.put(LOGGING_SESSION, "false");
// Ensure that no server-platform is configured
properties.put(TARGET_SERVER, TargetServer.None);
// Now the EntityManagerFactory can be instantiated for testing using:
Persistence.createEntityManagerFactory(unitName, properties);
Note that, it is also possible to do this via the EntityManagerFactory.createEntityManager() method, which accepts properties. However, if you read the EclipseLink auditing example carefully, you'll notice that a shared connection pool (whose properties are derived from persistence.xml) is also created, and that actual connection in use would depend on whether you are performing reads or writes.

Related

Dynamic dialect with Hibernate and Hikari

I am new at Hibernate.
Into my code, the connection to the DB is managed with the Hikari data source.
My code is right now multitenant, but it manages the same hibernate dialect for all tenants.
Is it possible to create a configuration where each tenant can use a different dialect?
The type of dialect can be provided as a tenant's property.
This is an example of the entityManagerFactory:
#Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
Map<String, Object> jpaProperties = new HashMap<>();
jpaProperties.put(..., ...);
jpaProperties.put(org.hibernate.cfg.Environment.DIALECT, "myDialect");
LocalContainerEntityManagerFactoryBean emfBean = new LocalContainerEntityManagerFactoryBean();
emfBean.setPackagesToScan(new String[] {MyEntity.class.getPackage().getName()});
emfBean.setJpaVendorAdapter(new HibernateJpaVendorAdapter());
emfBean.setJpaPropertyMap(jpaProperties);
return emfBean;
}
Edit
I was looking to this solution: it suggests to create a duplicated LocalContainerEntityManagerFactoryBean for each dialect.
What I do not understand is how can I tell when using one EntityManager (MySQL) and when the other one (Postgres or MsSQL): the solution discriminates the entities (each entity has its own DB) but in my case, all entities are on all DBs. Is the tenant that discriminates.
For example: if I create a second instance of LocalContainerEntityManagerFactoryBean (i.e. msSQLEntityManagerFactory()) with setted the dialect for SQL Server, the application fails to start with:
Application failed to start due to an exceptionorg.springframework.beans.factory.NoUniqueBeanDefinitionException:
No qualifying bean of type 'javax.persistence.EntityManagerFactory' available:
expected single matching bean but found 2:
msSQLEntityManagerFactory,entityManagerFactory
That's not really possible as the dialect affects certain quoting rules etc. which you can't just "swap out" at runtime based on a tenant identifier. Just create two persistence units, each pointing to a different data source for every database type. You will have to somehow lookup the appropriate EntityManager/EntityManagerFactory based on your tenant identifier which makes it a bit harder when you want to use Spring Data JPA as that requires a compilation static name reference for the entity manager factory. Maybe you can create a custom EntityManagerFactory that delegates all method calls to the appropriate instance based on the tenant identifier. Overall, this is not so easy and you will probably have to do a lot of trial and error.
IMO it would be better to have a separate application deployment with separate configuration if possible per database type.
I finally managed to find a solution for this problem.
I managed to get around the problem with the dialects by having an entity manager factory for each dialect (in this case MySQL, Postgres and MS SQL Server).
Create a bean for EntityManagerFactory and return a proxy of that interface and in the handler, based on your logic, you can switch which emf to use to suit the used data source.
I have created a video for this because it seems like there is no documentation online.
Session Scoped Connection
It is pretty similar to what you're trying to achieve but in my case the users are providing the credentials, so it's even more complicated.

Create SqlSession from existing Connection directly

I'm working with existing Java code wherein there is an existing JDBC connection pooling mechanism on deployed systems and an already existing setup to get JDBC connections. I'd like to leverage this to create a MyBatis SqlSession object without creating a Configuration, DataSource, and other things
I have code that already creates a java.sql.Connection object is given the desired resource. I'd like to leverage this and get that SqlSession object and use MyBatis from that point onwards.
I don't want MyBatis to manage connection pooling, determining which data source to use, etc. Is this possible?
I'm afraid you can't avoid creation of the Configuration object. It is used by the internal mybatis machinery like executors. But even if you could it will not help you much. In this case you will need to implement most of Configuration functionality yourself so it does not make sense to do that.
You main goal is to be able to use SqlSessionFactory.openSession(Connection connection) method. To do this you need to have SqlSessionFactory. The easiest way for you is to create Configuration like it is descried in mybatis documentation:
TransactionFactory transactionFactory = new JdbcTransactionFactory();
Environment environment = new Environment("development", transactionFactory, dataSource);
Configuration configuration = new Configuration(environment);
// set properties to configuration here
SqlSessionFactoryBuilder builder = new SqlSessionFactoryBuilder();
SqlSessionFactory factory = builder.build(configuration);
Now if your connection pool does implement DataSource you use it directly to create environment. If it does not you need to create an adapter around your pool which implements javax.sql.DataSource.
My solution is similar to Roman's above, but I needed to create an Oracle datasource. For various reasons, the connection needs to be created using the Class.forName type sequence
Class.forName("oracle.jdbc.driver.OracleDriver");
String connectionString = "jdbc:oracle:thin:#//yadayada";
String username = "myusername";
String password = "mypassword";
OracleDataSource oracleDataSource = new OracleDataSource();
oracleDataSource.setURL(connectionString);
oracleDataSource.setPassword(password);
oracleDataSource.setUser(username);
environment = new Environment("dev",transactionFactory,oracleDataSource);
configuration = new Configuration(environment);
configuration.addMappers("MyMybatisMapper");
sqlSessionFactory = new SqlSessionFactoryBuilder().build(configuration);
return sqlSessionFactory.openSession();
What I was missing was the OracleDataSource object.

How to configure two database in Hibernate

I have to configure two database on same project by configuring two CFG file,
I tried but it is always use the first configuration file,
May i know how can i use two database on same project
In your code, what you need to do is to open two different session factory for different databases.
For example:
Configuration configA=new Configuration();//use the default hibernate.cgf.xml file
Congiruration configB=new Configuration.configure('/hibernate_db2.cfg.xml') // use hibernate_db2.cfg.xml under root folder.
SessionFactory sfa=configA.buildSessionFactory();
SessionFactory sfb=configB.buildSessionFactory();
Now, you open different session using different db.
You need to have two configuration files.
hibernate-mysql.cfg.xml
hibernate-oracle.cfg.xml
And code should be like this.
mysql configuration
private static SessionFactory sessionAnnotationFactory;
sessionAnnotationFactory = new Configuration().configure("hibernate-mysql.cfg.xml").buildSessionFactory();
Session session = sessionAnnotationFactory.openSession();
oracle sql configuration
sessionAnnotationFactory = new Configuration().configure("hibernate-oracle.cfg.xml").buildSessionFactory();
Session session = sessionAnnotationFactory.openSession()

OSGi and Persistence Units

Good day guys, I'm programming an OSGi bundle in charge of authenticating users. For design reasons I'm obligated to perform queries over multiple database schemas (these schemas can be created or deleted dynamically). I'm running MySQL as storage engine.
Somehow I need to be able to create on demand entity managers for those schemas, but I haven't been successful in my attempts. Here is what I have tried that has got me closer to what I need:
Creating a persistence unit (Eclipselink) using a JTA data source that can, in fact, establish a database connection to the default schema. However, when I try to override any property, say, the javax.persistence.jdbc.url. However, it keeps pointing to the default schema always.
I believe I'm not overriding correctly the property, or that JTA datasource properties cannot be modified from EntityManager to EntityManager. Here is how I create the EntityManagers:
Map<String, String> dbProps = new HashMap<String, String>();
dbProps.put("javax.persistence.jdbc.url","jdbc:mysql://mydomain:3306/mydynamicdb);
EntityManagerFactory fact = Persistence.createEntityManagerFactory("myPersistenceUnit", dbProps);
EntityManager myEM = fact.createEntityManager();
At the end, they all keep poiting to the default schema, so my questions are:
Is this an efficient approach for dynamic EntityManager handling? if so, how can I override effectively the schema property?
Is there any other alternative besides the overriding?
I thank you in advance for any guidance you may provide.
If you want to use EclipseLink in OSGi you must use the Gemini JPA project that wraps EclipseLink and create and register an EntityManagerFactory and an EntityManagerFactoryBuilder services for your PU bundle.
If want to share the jdbc connections between PUs you can use JDBC services provided by Gemini DBAccess
You should be able to acquire the EntityManagerFactory as an OSGi service, you can (LDAP) filter the correct one using the service property osgi.unit.name as in:
ServiceReference[] refs = null;
String filter = "(osgi.unit.name=myPersistenceUnit)";
ServiceReference[] refs = ctx.getServiceReferences(EntityManagerFactory.class.getName(), filter);
//Should only be one reference, check (throw exception etc)
return (EntityManagerFactory)ctx.getService(refs[0]);
You can check that all Persistence Units are present, by listing the EntityManagerFactory services (with properties) in your OSGi shell.

Modify persistence.xml on runtime

I'm developping a program that uses JPA, and I deployed it in a single jar. I wish to modify (or ask to the user, in an menĂº item) the configuration of the connection data with the database server.
It's possible to modify the data (user, password, ip) of the server "on the fly"?
(I apologize my bad english)
how about making a HashMap<String,Object> containing your options and passing it to Persistence.createEntityManagerFactory("unitName",map)?
From the Docs:
public static EntityManagerFactory createEntityManagerFactory(String persistenceUnitName, Map properties)
Create and return an EntityManagerFactory for the named persistence unit using the given properties.
Source
The JPA spec doesn't allow for dynamic modification of persistence-units. Some implementations may provide an implementation-specific way of defining a persistence-unit dynamically. With DataNucleus JPA we do it as per the foot of this page

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