I found this great tutorial on how to use JSON to retrieve Twitter updates, and post it in a TextView:
http://www.ibm.com/developerworks/xml/library/x-andbene1/
I've followed this tutorial step by step, so my code is the same.
In the method examineJSONFile(), we have this line:
InputStream is = this.getResources().openRawResource(R.raw.jsontwitter);
This file is downloaded directly from the Twitter website, as mentioned in the second paragraph of http://www.ibm.com/developerworks/xml/library/x-andbene1/#aotf.
All this is great, except for one thing: it's absolutely no use that one has to download the Twitter updates (tweets) and then build the app using this as a raw file. It should be possible to download this JSON file at runtime, and then show the tweets in the TextView afterwards.
I have tried to create the InputStream in another way, like this:
String url = "http://twitter.com/statuses/user_timeline/bbcnews.json";
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = httpclient.execute(new HttpGet(url));
InputStream is = response.getEntity().getContent();
BufferedReader br = new BufferedReader(new InputStreamReader(is,"UTF-8"));
StringBuffer sb = new StringBuffer();
try
{
String line = null;
while ((line = br.readLine())!=null)
{
sb.append(line);
sb.append('\n');
}
}
catch (IOException e)
{
e.printStackTrace();
}
String jsontext = new String(sb.toString());
But it seems this line: HttpResponse response = httpclient.execute(new HttpGet(url)); throws an exception.
Any help please?
You seem to be missing the INTERNET permission. Look at the logs and it would be clear what exactly is the problem.
Related
I use java to get youtube video url from a youtube url,it seems like i should decode video url twice to get the original video url,but something is wrong when i access the video url which i get from my code. Im sure i can access any video url which i get when i first run the code after i finish the code, but after that ,i can not access any video url i get no matter the video url is from decode first or twice. I suppose maybe only youtube itself can access the video url i get or the server blocked my IP. So i need you guys to help me to tell me whats wrong and how i could do to get the video url that can play, thx. My code and answer is below:
try {
String ytUrl = "https://www.youtube.com/watch?v=Cj3AV92fJ90";
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(ytUrl);
HttpResponse response = client.execute(request);
String html = "";
InputStream in = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
str.append(line.replace("\\u0026", "&"));
}
in.close();
html = str.toString();
String val=RegexUtil.find(html,"stream_map\":.*?\"(.*?)\"",1);
if (!StringUtils.isEmpty(val)) {
String url = URLDecoder.decode(val, "UTF-8");
System.out.println("1 decode url: "+url);
url = URLDecoder.decode(url, "UTF-8");;
System.out.println("2 decode url: "+url );
}
} catch (Exception e) {
e.printStackTrace();
}
1 decode url: url=https://r4---sn-i3b7knlk.googlevideo.com/videoplayback?id=o-AE4MBDOnLdC4X0a7wjJ63diBNkBpJ2XiuejUOXrB8onv&dur=421.442&mime=video%2Fmp4&fvip=4&requiressl=yes&ms=au%2Conr&mt=1540798558&ratebypass=yes&itag=22&pl=25&sparams=dur%2Cei%2Cid%2Cinitcwndbps%2Cip%2Cipbits%2Citag%2Clmt%2Cmime%2Cmm%2Cmn%2Cms%2Cmv%2Cpl%2Cratebypass%2Crequiressl%2Csource%2Cexpire&source=youtube&mv=m&mn=sn-i3b7knlk%2Csn-npoeene7&lmt=1537570091802082&key=yt6&ei=8LjWW9P1Ns2R8gOGhKO4AQ&c=WEB&expire=1540820305&ip=114.113.240.105&ipbits=0&initcwndbps=362500&mm=31%2C26&itag=22&type=video/mp4; codecs="avc1.64001F, mp4a.40.2"&s=C8C80C74C92B4306498EE1183D683A0E60962F69BD.4F1AE9CE009B83425F389362CFC2FE23A45948D5&quality=hd720&sp=signature
2 decode url: url=https://r4---sn-i3b7knlk.googlevideo.com/videoplayback?id=o-AE4MBDOnLdC4X0a7wjJ63diBNkBpJ2XiuejUOXrB8onv&dur=421.442&mime=video/mp4&fvip=4&requiressl=yes&ms=au,onr&mt=1540798558&ratebypass=yes&itag=22&pl=25&sparams=dur,ei,id,initcwndbps,ip,ipbits,itag,lmt,mime,mm,mn,ms,mv,pl,ratebypass,requiressl,source,expire&source=youtube&mv=m&mn=sn-i3b7knlk,sn-npoeene7&lmt=1537570091802082&key=yt6&ei=8LjWW9P1Ns2R8gOGhKO4AQ&c=WEB&expire=1540820305&ip=114.113.240.105&ipbits=0&initcwndbps=362500&mm=31,26&itag=22&type=video/mp4; codecs="avc1.64001F, mp4a.40.2"&s=C8C80C74C92B4306498EE1183D683A0E60962F69BD.4F1AE9CE009B83425F389362CFC2FE23A45948D5&quality=hd720&sp=signature
I've seen other StackOverflow threads, use HTTP Get to access source code of web pages. But obviously this can take a while, as this requires plentiful download time and string manipulation techniques.
I've not made use of Tripadvisor Content API before.
So an example which could possibly accomplish something similar to described below, would be incredibly helpful. Thanks
The data I would like to attain from TripAdvisor within Android is:
for a particular location (e.g. by lon and lat) e.g. Prague Bohemia etc.
A List of:
Attraction Types within that location
Ranked locations, for attraction types within that location
As shown on this page:
tripadvisor.co.uk/Attractions-g274707-Activities-Prague_Bohemia.html
Example of HTTP GET described above:
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);
String html = "";
InputStream in = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
str.append(line);
}
in.close();
html = str.toString();
I am testing the uploading of files to a dataset on CKAN / datahub.io through a Java client of the API.
public String uploadFile()
throws CKANException {
String returned_json = this._connection.MultiPartPost("", "");
System.out.println("r: " + returned_json);
return returned_json;
}
and
protected String MultiPartPost(String path, String data)
throws CKANException {
URL url = null;
try {
url = new URL(this.m_host + ":" + this.m_port + path);
} catch (MalformedURLException mue) {
System.err.println(mue);
return null;
}
String body = "";
HttpClient httpclient = new DefaultHttpClient();
try {
String fileName = "D:\\test.jpg";
FileBody bin = new FileBody(new File(fileName),"image/jpeg");
StringBody comment = new StringBody("Filename: " + fileName);
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("bin", bin);
reqEntity.addPart("comment", comment);
HttpPost postRequest = new HttpPost("http://datahub.io/api/storage/auth/form/2013-01-24T130158/test.jpg");
postRequest.setEntity(reqEntity);
postRequest.setHeader("X-CKAN-API-Key", this._apikey);
HttpResponse response = httpclient.execute(postRequest);
int statusCode = response.getStatusLine().getStatusCode();
System.out.println("status code: " + statusCode);
BufferedReader br = new BufferedReader(
new InputStreamReader((response.getEntity().getContent())));
String line;
while ((line = br.readLine()) != null) {
body += line;
}
System.out.println("body: " + body);
} catch (IOException ioe) {
System.out.println(ioe);
} finally {
httpclient.getConnectionManager().shutdown();
}
return body;
}
2 responses I get to my POST request:
a 413 error ("request entity too large") when the jpeg I try to upload is 2.83 Mb. This disappears when I shrink the file to a smaller size. Is there a limit to file size uploads?
a 500 error ("internal server error"). This is where I am stuck. It might have to do with the fact that my dataset on datahub.io is not "datastore enabled"? (I see a disabled "Data API" button next to my resource files in the dataset, with a tooltip saying:
"Data API is unavailable for this resource as DataStore is disabled"
=> is it a possible reason for this 500 error? If so, how could I enable it from the client side? (pointers to Python code would be useful!)
Thx!
PS: the dataset I am using for testing purposes: http://datahub.io/dataset/testapi
Only someone with access to the exception log could tell you why the 500 is occurring.
However, I'd check your request is the same as what you'd get from the python client that was written alongside the datastore: https://github.com/okfn/ckanclient/blob/master/ckanclient/init.py#L546
You're sending the "bin" image buffer and "comment" file_key in your multipart request. Note the file_key must be changed for every upload, so add in a timestamp or something. And maybe you need to add in a Content-Type: for the binary.
I have been going through the same kind of troubles as the poster of this question. After quite a bit of trial and error, I came up with a solution to the problem. In my case, I had some control over the CKAN repository that I wanted to upload to. If you don't, your problem might be impossible to solve...
I assume you are using the 1.8 version of CKAN?
First of all, check whether the CKAN repository has been set up to allow file upload and if not, configure it to allow that. This can be done on the server using the steps posted here: http://docs.ckan.org/en/ckan-1.8/filestore.html#local-file-storage
The 413 error that you mentioned should be adressed next. This has to do with the general configuration of the server. In my case, the CKAN was hosted through nginx. I added a "client_max_body_size 100M" line to the nginx.conf file. See this post for instance: http://recursive-design.com/blog/2009/11/18/nginx-error-413-request-entity-too-large/
Then there is only the 500 error left. At the time of this writing, the api documentation of CKAN is still a little immature... It does indeed say that you have to build a request like you have made for file upload. However, this request is just to ask for permission for the file upload. If your credentials check out for file upload (not every user may be allowed to upload files), the response holds an object telling you where to send your file to... Because of the unclear api, you ended up merging these two requests.
The following scenario shows a follow up of two requests to handle the file upload. It might be that some steps in the scenario work out differently in your case, because of a repository that has been set up a little differently. If you get error messages, please be sure to check the response's body for clues!
Here is the authentication request that I used:
String body = "";
String generatedFilename=null;
HttpClient httpclient = new DefaultHttpClient();
try {
// create new identifier for every file, use time
SimpleDateFormat dateFormatGmt = new SimpleDateFormat("yyyyMMMddHHmmss");
dateFormatGmt.setTimeZone(TimeZone.getTimeZone("GMT"));
String date=dateFormatGmt.format(new Date());
generatedFilename=date +"/"+filename;
HttpGet getRequest = new HttpGet(this.CKANrepos+ "/api/storage/auth/form/"+generatedFilename);
getRequest.setHeader(CKANapiHeader, this.CKANapi);
HttpResponse response = httpclient.execute(getRequest);
int statusCode = response.getStatusLine().getStatusCode();
BufferedReader br = new BufferedReader(
new InputStreamReader((response.getEntity().getContent())));
String line;
while ((line = br.readLine()) != null) {
body += line;
}
if(statusCode!=200){
throw new IllegalStateException("File reservation failed, server responded with code: "+statusCode+
"\n\nThe message was: "+body);
}
}finally {
httpclient.getConnectionManager().shutdown();
}
Now, if all goes well, the server responds with a json object holding the parameters to use when doing the actual file upload. In my case, the object looked like:
{file_key:"some-filename-to-use-when-uploading"}
Be sure to check the json object though, as I'm given to understand that there may be custom ckan repositories that require more or different parameters.
These responses can then be used in the actual file upload:
File file = new File("/tmp/file.rdf");
String body = "";
HttpClient httpclient = new DefaultHttpClient();
try {
FileBody bin = new FileBody(file,"application/rdf+xml");
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("file", bin);
reqEntity.addPart("key", new StringBody(filename));
HttpPost postRequest = new HttpPost(this.CKANrepos+"/storage/upload_handle");
postRequest.setEntity(reqEntity);
postRequest.setHeader(CKANapiHeader, this.CKANapi);
HttpResponse response = httpclient.execute(postRequest);
int statusCode = response.getStatusLine().getStatusCode();
BufferedReader br = new BufferedReader(
new InputStreamReader((response.getEntity().getContent())));
String line;
while ((line = br.readLine()) != null) {
body += line;
}
if(statusCode!=200){
getWindow().showNotification("Upload Statuscode: "+statusCode,
body,
Window.Notification.TYPE_ERROR_MESSAGE);
}
}finally {
httpclient.getConnectionManager().shutdown();
}
as you can see, the file_key property has now been transformed into the simple 'key' property. I don't know why.
This will get your file uploaded. The response to this upload request will hold a json object telling you where the file got uploaded to. edit: actually it seems that my ckan responded with a simple html page to tell me that the file got uploaded... I had to parse the page to confirm that the file was uploaded correctly :(
In my case, the file was at
this.CKANrepos +"/storage/f/"+location
where location is the filename returned in the authentication phase.
In the previous code fragments:
//the location of your ckan repository, including /api and possibly version, e.g.
this.CKANrepos = "http://datahub.io/api/3/";
this.CKANapiHeader="X-CKAN-API-Key";
this.CKANapi = "your ckan api key here";
This question already has answers here:
How to get HttpClient returning status code and response body?
(5 answers)
Closed 2 years ago.
I've just begun using Apache's HTTP Client library and noticed that there wasn't a built-in method of getting the HTTP response as a String. I'm just looking to get it as as String so that i can pass it to whatever parsing library I'm using.
What's the recommended way of getting the HTTP response as a String? Here's my code to make the request:
public String doGet(String strUrl, List<NameValuePair> lstParams) {
String strResponse = null;
try {
HttpGet htpGet = new HttpGet(strUrl);
htpGet.setEntity(new UrlEncodedFormEntity(lstParams));
DefaultHttpClient dhcClient = new DefaultHttpClient();
PersistentCookieStore pscStore = new PersistentCookieStore(this);
dhcClient.setCookieStore(pscStore);
HttpResponse resResponse = dhcClient.execute(htpGet);
//strResponse = getResponse(resResponse);
} catch (ClientProtocolException e) {
throw e;
} catch (IOException e) {
throw e;
}
return strResponse;
}
You can use EntityUtils#toString() for this.
// ...
HttpResponse response = client.execute(get);
String responseAsString = EntityUtils.toString(response.getEntity());
// ...
You need to consume the response body and get the response:
BufferedReader br = new BufferedReader(new InputStreamReader(httpresponse.getEntity().getContent()));
And then read it:
String readLine;
String responseBody = "";
while (((readLine = br.readLine()) != null)) {
responseBody += "\n" + readLine;
}
The responseBody now contains your response as string.
(Don't forget to close the BufferedReader in the end: br.close())
You can do something like:
Reader in = new BufferedReader(
new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
Using the reader you will be able to build your string. But if you are using SAX you can give the stream to the parser directly. This way you will not have to create the string and your memory footprint will be lower too.
In terms of conciseness of code it might be using the Fluent API like this:
import org.apache.http.client.fluent.Request;
[...]
String result = Request.Get(uri).execute().returnContent().asString();
The documentation warns though that this approach is not ideal in terms of memory consumption.
So, i am using this code to get the whole HTML of a website. But i dont seem to get non-ascii characters with me. all i get is diamonds with question mark.
characters like this: å, appears like this: �
I doubt its because of the charset, what could it then be?
Log.e("HTML", "henter htmlen..");
String url = "http://beep.tv2.dk";
HttpClient client = new DefaultHttpClient();
client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION,
HttpVersion.HTTP_1_1);
client.getParams().setParameter(CoreProtocolPNames.HTTP_ELEMENT_CHARSET, "UTF-8");
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);
Header h = HeaderValueFormatter
response.addHeader(header)
String html = "";
InputStream in = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
str.append(line);
}
in.close();
//b = false;
html = str.toString();
Thank you. This worked (in case others have the issue):
HttpClient client = new DefaultHttpClient();
client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION,
HttpVersion.HTTP_1_1);
client.getParams().setParameter(CoreProtocolPNames.HTTP_ELEMENT_CHARSET, "iso-8859-1");
HttpGet request = new HttpGet(url);
request.setHeader("Accept-Charset", "iso-8859-1, unicode-1-1;q=0.8");
HttpResponse response = client.execute(request);
String html = "";
InputStream in = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(in,"iso-8859-1"));
use the new InputStreamReader(in, "UTF-8") constructor
Set the Accept-Charset request header to, say, Accept-Charset: iso-8859-5, unicode-1-1;q=0.8
Make sure the page opens properly in a browser. If it does not, then it might be a server-side issue.
If none of the above works, check other headers using firebug (or similar tool)
This really helped me get started, but I was having the same problem while reading a text file. It was fixed using the following command:
BufferedReader br = new BufferedReader(new InputStreamReader(new
FileInputStream(fileName), "iso-8859-1"));
...and of course, the HTTP Response needs to have the encoding set as well:
response.setCharacterEncoding("UTF-8");
Thanks for the help!