I have a local .json file. I don't want it to be on a server, I just want it to be included in my app. I tried to paste it directly into Eclipse in my project, but I got a FileNotFoundException, I also tried to paste it in the workspace folder in Windows Explorer/Finder and got the same exception. Where should I put it?
Thanks!
You should put the file either in the /assets or /res/raw directory of your Android project. From there, you can retrieve it with either: Context.getResources().openRawResource(R.raw.filename) or Context.getResources().getAssets().open("filename").
Put the json file in assets folder, I have used this method like this
public static String jsonToStringFromAssetFolder(String fileName,Context context) throws IOException {
AssetManager manager = context.getAssets();
InputStream file = manager.open(fileName);
byte[] data = new byte[file.available()];
file.read(data);
file.close();
return new String(data);
}
While parsing we can use the method like:
String jsondata= jsonToStringFromAssetFolder(your_filename, your_context);
jsonFileToJavaObjectsParsing(jsondata); // json data to java objects implementation
More Info: Prativa's Blog
Put the file in the assets folder.
You can use the AssetManager open(String fileName) to read the file.
Under /assets in your project folder. If you don't have one, make it.
Copy Asset to Local Storage
I had a very similar need. I had a label template file that I needed to provide a Bluetooth printer configuration so I included it in my assets directory and copied it to the internal storage for later use:
private static final String LABEL_TEMPLATE_FILE_NAME = "RJ_4030_4x3_labels.bin";
InputStream inputStreamOfLabelTemplate = getAssets().open( LABEL_TEMPLATE_ASSET_PATH );
labelTemplateFile = new File( getFilesDir() + LABEL_TEMPLATE_FILE_NAME );
copyInputStreamToFile( inputStreamOfLabelTemplate, labelTemplateFile );
printer.setCustomPaper( labelTemplateFile.getAbsolutePath() );
copyInputStreamToFile Function
// Copy an InputStream to a File.
//
private void copyInputStreamToFile(InputStream in, File file) {
try {
OutputStream out = new FileOutputStream(file);
byte[] buf = new byte[1024];
int len;
while((len=in.read(buf))>0){
out.write(buf,0,len);
}
out.close();
in.close();
} catch (Exception e) {
e.printStackTrace();
}
}
Related
Is it possible to access Assets inside the Java code in Play Framework? How?
We access assets from the scala HTML templates this way:
<img src="#routes.Assets.versioned("images/myimage.png")" width="800" />
But I could not find any documentation nor code example to do it from inside the Java code. I just found a controllers.Assets class but it is unclear how to use it. If this is the class that has to be used, should it maybe be injected?
I finally found a way to access the public folder even from a production mode application.
In order to be accessible/copied in the distributed version, public folder need to be mapped that way in build.sbt:
import NativePackagerHelper._
mappings in Universal ++= directory("public")
The files are then accessible in the public folder in the distributed app in production form the Java code:
private static final String PUBLIC_IMAGE_DIRECTORY_RELATIVE_PATH = "public/images/";
static File getImageAsset(String relativePath) throws ResourceNotFoundException {
final String path = PUBLIC_IMAGE_DIRECTORY_RELATIVE_PATH + relativePath;
final File file = new File(path);
if (!file.exists()) {
throw new ResourceNotFoundException(String.format("Asset %s not found", path));
}
return file;
}
This post put me on the right way to find the solution: https://groups.google.com/forum/#!topic/play-framework/sVDoEtAzP-U
The assets normally are in the "public" folder, and I don't know how you want to use your image so I have used ImageIO .
File file = new File("./public/images/nice.png");
boolean exists = file.exists();
String absolutePath = file.getAbsolutePath();
try {
ImageInputStream input = ImageIO.read(file); //Use it
} catch (IOException e) {
e.printStackTrace();
}
System.out.println("EX = "+exists+" - "+absolutePath);
I am creating a java app that will extract the embedded thumbnail inside of a Powerpoint (PPTX) document. Since pptx files are zip archives, I am trying to use TrueZip to get the thumbnail found inside of the archive. Unfortunately whenever I try running my application it throws an IOException stating that the file is missing C:\Users\test-user\Desktop\DocumentsTest\Hello.pptx\docProps\thumbnail.jpeg (missing file)
Below is the code I use to get the thumbnail:
public Boolean GetThumbPPTX(String inFile, String outFile)
{
try
{
TFile srcFile = new TFile(inFile, "docProps\\thumbnail.jpeg");
TFile dstFile = new TFile(outFile);
if(dstFile.exists())
dstFile.delete();
srcFile.toNonArchiveFile().cp_rp(dstFile);
return dstFile.exists();
} catch (IOException ex) {
Logger.getLogger(DocumentThumbGenerator.class.getName()).log(Level.SEVERE, null, ex);
}
return false;
}
Where inFile is the absolute path of the pptx file and outFile is the path that the thumbnail will be copied to. I can verify that the archive does have a thumbnail inside of it at the same exact path.
Can someone help please?
I just found the answer. It seems I did not have the Zip driver configured correctly. I added this to my class constructor and it all works now:
TConfig.get().setArchiveDetector(new TArchiveDetector(
TArchiveDetector.NULL,
new Object[][] {
{ "zip|pptx", new ZipDriver(IOPoolLocator.SINGLETON)},
}));
I did this small Java project that in it's turn opens different MP3 files. For that I downloaded the JLayer 1.0.1 library and added it to my project. I also added the MP3 files to a package on my project -as well as some JPG images- so as to obtain them from there, and I'm using a hashmap (mapa) and this method to get them:
public static String consiguePath (int i) {
return AppUtils.class.getClass().getResource("/Movimiento/" + mapa.get(i)).getPath();
}
so as to avoid absolute paths.
When I open an MP3 file I do this:
try {
File archivo = new File(AppUtils.consiguePath(12));
FileInputStream fis = new FileInputStream(archivo);
BufferedInputStream bis = new BufferedInputStream(fis);
try {
Player player = new Player(bis);
player.play();
} catch (JavaLayerException jle) {
}
} catch (IOException e) {
}
The whole thing runs perfectly in NetBeans, but when I build a .jar file and execute it it runs well but it won't open the MP3 files. What called my attention is that it doesn't have trouble in opening the JPG files that are on the same package.
After generating the .jar I checked the MyProject/build/classes/Movimiento folder and all of the MP3 files were actually there, so I don't know what may be happening.
I've seen others had this problem before but I haven't seen any satisfactory answer yet.
Thanks!
Change the consiguePath to return the resulting URL from getResource
public static URL consiguePath(int i) {
return AppUtils.class.getClass().getResource("/Movimiento/" + mapa.get(i));
}
And then use it's InputStream to pass to the Player
try {
URL url = AppUtils.consiguePath(12);
Player player = new Player(url.openStream());
player.play();
} catch (JavaLayerException | IOException e) {
e.printStackTrace();
}
Equally, you could just use Class#getResourceAsStream
Resources are packaged into your Jar file and can no longer be treated as Files
In my Android app I'm downloading Video file using Quickblox API, on successful download I'm getting file content in the form of InputStream object now, using that InputStream object I wants to create android supported Video file and stored it on to the SDCard but I don't know how to create Video file using InputStream object. Please see the following code where I'm getting InputStream object.
QBContent.downloadFileTask(fileId, new QBEntityCallbackImpl<InputStream>()
{
#Override
public void onSuccess(InputStream inputStreamObject, Bundle params)
{
// TODO Auto-generated method stub
super.onSuccess(inputStreamObject, params);
});
}
Please help. Thank you..!
If the inputStreamObject is the content of an mp4 file, you could simply save the input stream to a file. That's your mp4 .
public static final String PREFIX = "myMusicfile";
public static final String SUFFIX = ".mp4";
public static File stream2file (InputStream in) throws IOException {
final File tempFile = File.createTempFile(PREFIX, SUFFIX);
tempFile.deleteOnExit();
try (FileOutputStream out = new FileOutputStream(tempFile)) {
IOUtils.copy(in, out);
}
return tempFile;
}
Hope it help :)
Thanks
Sorry for my English, but I want to write in this file because in my opinion is the best.
Now my problem:
I want to create a folder in Internal storage to share with 2 application.
In my app, I downloaded an Apk from my server and I run it.
Before I used external storage and everything worked.
Now I want to use the internal storage for users that don't have an external storage.
I use this:
String folderPath = getFilesDir() + "Dir"
but when i try to run the Apk, it doesn't work, and I can't find this folder on my phone.
Thank you..
From this post :
Correct way:
Create a File for your desired directory (e.g., File path=new
File(getFilesDir(),"myfolder");)
Call mkdirs() on that File to create the directory if it does not exist
Create a File for the output file (e.g., File mypath=new File(path,"myfile.txt");)
Use standard Java I/O to write to that File (e.g., using new BufferedWriter(new FileWriter(mypath)))
Enjoy.
Also to create public file I use :
/**
* Context.MODE_PRIVATE will create the file (or replace a file of the same name) and make it private to your application.
* Other modes available are: MODE_APPEND, MODE_WORLD_READABLE, and MODE_WORLD_WRITEABLE.
*/
public static void createInternalFile(Context theContext, String theFileName, byte[] theData, int theMode)
{
FileOutputStream fos = null;
try {
fos = theContext.openFileOutput(theFileName, theMode);
fos.write(theData);
fos.close();
} catch (FileNotFoundException e) {
Log.e(TAG, "[createInternalFile]" + e.getMessage());
} catch (IOException e) {
Log.e(TAG, "[createInternalFile]" + e.getMessage());
}
}
Just set theMode to MODE_WORLD_WRITEABLE or MODE_WORLD_READABLE (note they are deprecated from api lvl 17).
You can also use theContext.getDir(); but note what doc says :
Retrieve, creating if needed, a new directory in which the application can place its own custom data files. You can use the returned File object to create and access files in this directory. Note that files created through a File object will only be accessible by your own application; you can only set the mode of the entire directory, not of individual files.
Best wishes.
You can create a public into a existing system public folder, there is some public folder accessible from internal storage :
public static String DIRECTORY_MUSIC = "Music";
public static String DIRECTORY_PODCASTS = "Podcasts";
public static String DIRECTORY_RINGTONES = "Ringtones";
public static String DIRECTORY_ALARMS = "Alarms";
public static String DIRECTORY_NOTIFICATIONS = "Notifications";
public static String DIRECTORY_PICTURES = "Pictures";
public static String DIRECTORY_MOVIES = "Movies";
public static String DIRECTORY_DOWNLOADS = "Download";
public static String DIRECTORY_DCIM = "DCIM";
public static String DIRECTORY_DOCUMENTS = "Documents";
To create your folder, use this code :
File myDirectory = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOCUMENTS), "MyPublicFolder");
myDirectory.mkdir();
With this example, a public will be created in Documents and can be visible in any file's explorer app for Android.
try the below
File mydir = context.getDir("Newfolder", Context.MODE_PRIVATE); //Creating an internal dir;
if(!mydir.exists)
{
mydir.mkdirs();
}
This is what i have used and is working fine for me:
String extStorageDirectory = Environment.getExternalStorageDirectory().toString();
File file = new File(extStorageDirectory, fileName);
File parent=file.getParentFile();
if(!parent.exists()){
parent.mkdirs();
}
This will create a new directory if not already present or use the existing if already present.