For the last two hours i've been trying to make a POST request to this page http://www.halebop.se/butik/byt_behall_nummer/ and tried to send numberToPort. However i get a bunch of cookies and a 302 moved temporarily back.
All i want to do is send the POST request with the number and get the final page back. On iOS, i do this using ASIHTTPRequest which handles the redirect and cookies.
iOS code:
NSString *halebopURLString = #"http://www.halebop.se/kontantkort/byt_behall_nummer/#";
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:[NSURL URLWithString:halebopURLString]];
[request setPostValue:halebopNumber forKey:#"numberToPort"];
[request setPostValue:#"continue" forKey:#"action"];
[request setPostValue:#"submit" forKey:#"submit"];
[request startSynchronous];
How do i do this on Android?
As an alternative, a PHP solution is acceptable.
Edit: Tried this, it gives no output and no exceptions. I have the internet permission. Expected result: Send POST, get 302 and cookies back, send cookies to URL from 302 and get HTML back (Checked with FireBug) however i get nothing.
try {
InputStream myInputStream =null;
URL url;
url = new URL("http://www.halebop.se/kontantkort/byt_behall_nummer/#");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setInstanceFollowRedirects(true);
conn.setRequestMethod("POST");
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write("numberToPort="+n+"&action=continue&submit=submit");
wr.flush();
myInputStream = conn.getInputStream();
wr.close();
BufferedReader rd = new BufferedReader(new InputStreamReader(myInputStream), 4096);
String line;
StringBuilder sbResult = new StringBuilder();
while ((line = rd.readLine()) != null) {
sbResult.append(line);
Log.d(TAG, "Line "+line);
}
rd.close();
String contentOfMyInputStream = sbResult.toString();
Log.d(TAG, "Output "+contentOfMyInputStream);
} catch (Exception e) {
Log.d(TAG,e.getMessage());
}
Here is how you can set the post parameters:
HttpPost httpost = new HttpPost(LOGIN_URL);
List <NameValuePair> nvps = new ArrayList <NameValuePair>();
nvps.add(new BasicNameValuePair("test1","test1" ));
nvps.add(new BasicNameValuePair("test2", "test2" ));
httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));
response = getResponse(httpost);
Here is the detailed explanation about the code.
I also explained How to retrieve HTTP cookies from your response and set them into request here
If you are using HttpUrlConnection, then HttpUrlConnection#setFollowRedirects might be what you are after. Set it to true to make it automatically resolve the redirect. Even better to use setInstanceFollowRedirects(true) since blindly following redirects (what the static setFollowRedirects would cause) is frowned upon from a security perspective.
Related
API route in Python (Flask)
#app.route('/secret')
def secret():
if request.get_json(force=True)['key'] == 'secret key':
return jsonify(msg='Hello!')
It is working linux terminal
curl -iX GET -d '{"key":"secret key"}' localhost
Linux terminal output this
{"msg":"Hello!"}
It doesn't need to work in browser.
try{
HttpURLConnection connection = (HttpURLConnection)
new URL("http://<my local ip>/secret").openConnection();
connection.setRequestMethod("GET");
connection.setDoOutput(true);
connection.connect();
JSONObject jsonInput = new JSONObject();
jsonInput.put("key", "secret key");
OutputStream os = connection.getOutputStream();
byte[] input = jsonInput.toString().getBytes(StandardCharsets.UTF_8);
os.write(input, 0, input.length);
os.flush();
os.close();
BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
StringBuilder response = new StringBuilder();
String responseLine = null;
while ((responseLine = br.readLine()) != null) {
response.append(responseLine.trim());
}
return response.toString();
} catch (IOException | JSONException e) {
Log.e("MainActivity", "Error: " + e.getMessage());
}
Although the GET method is set to the connection request in my codes, a POST request is being sent to the Python server.
Python Interpreter
Is it impossible to fix this?
Request Body is not recommended in HTTP GET requests. See HERE
A payload within a GET request message has no defined semantics;
sending a payload body on a GET request might cause some existing
implementations to reject the request.
When you try to write on a URL, you are implicitly POSTing on it despite you had set GET as the HTTP method. At below lines:
OutputStream os = connection.getOutputStream();
byte[] input = jsonInput.toString().getBytes(StandardCharsets.UTF_8);
os.write(input, 0, input.length);
For confirmation of my words see Writing to a URLConnection
writing to a URL is often called posting to a URL. The server
recognizes the POST request and reads the data sent from the client.
I've been working with the Slack API in java and have been trying to get an HTTP method that can be used like my below example block of code. That code block works, but the issue is I need to also include a 200 response code, and can't figure out how to get it to work.
Basically, how can I, In Java, send an HTTP post and also tag on the 200 status code using the URL and the content?
Current code:
public void httpRequest(URL url, String content) {
try {
byte[] contentBytes = content.getBytes("UTF-8");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestProperty("Accept-Charset", "UTF-8");
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("Content-Length", Integer.toString(contentBytes.length));
connection.setRequestProperty("Status", Integer.toString(200));
OutputStream requestStream = connection.getOutputStream();
requestStream.write(contentBytes, 0, contentBytes.length);
requestStream.close();
String response = "";
BufferedReader responseStream;
response = "" + ((HttpURLConnection) connection).getResponseCode();
try {
if (((HttpURLConnection) connection).getResponseCode() == 200) {
responseStream = new BufferedReader(new InputStreamReader(connection.getInputStream(), "UTF-8"));
} else {
responseStream = new BufferedReader(new InputStreamReader(((HttpURLConnection) connection).getErrorStream(), "UTF-8"));
}
response = responseStream.readLine();
responseStream.close();
} catch (NullPointerException ignored) {
}
} catch (IOException e) {
e.printStackTrace();
}
}
The call to setDoOutput(true) triggers a post, i.e. you do not need to add
connection.setRequestMethod("POST");
Adding a status header to the request is possible, as you have done, but typically one associates status codes with http responses, not requests. - And off course, adding such custom header would only make sense if the server was designed to use this information to anything.
See this big, and highly up-voted answer on java.net.HttpURLConnection.
Also, you have some problems relating to your response variable as well as the BufferedReader. You accidentally override the value you initially assigned to the response field, instead of concatening. Also, your readLine() should probably be in a loop:
String tmp;
while ((tmp = responseStream.readLine()) !=null){
response += tmp;
}
i am currently trying to use REST api provided by Paypal to create my own service using servlet. I manage to transfer the cURL code into HttpsURLConnection using java.
Here is my code:
JSONObject returnJson = new JSONObject();
PrintWriter out = response.getWriter();
JSONParser jparser = new JSONParser();
try{
String inputStr = request.getParameter("input");
System.out.println(inputStr);
JSONObject inputJson = (JSONObject) jparser.parse(inputStr);
String accessToken = (String) inputJson.get("access_token");
String invoiceId = (String) inputJson.get("invoiceId");
String url = "https://api.sandbox.paypal.com/v1/invoicing/invoices/"+invoiceId;
URL obj = new URL(url);
HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();
//add reuqest header
con.setRequestMethod("PUT");
con.setRequestProperty("Accept-Language", "text/html; charset=UTF-8");
con.setRequestProperty("Content-Type", "application/json");
con.setRequestProperty("Authorization", "Bearer "+accessToken);
//Tentatively, the input is hard coded, after integration, the input comes from http request.
//However, only merchant email in mandatory for invoice creation in sand box so far
//For details of invoice attributes please refer to this link--> https://developer.paypal.com/docs/api/#update-an-invoice
String urlJsonString = "{\"id\":\""+invoiceId+"\",\"status\":\"DRAFT\",\"merchant_info\":{\"email\":\"rui.song.2013-facilitator#sis.smu.edu.sg\",\"first_name\":\"Dennis\",\"last_name\":\"Doctor\",\"business_name\":\"MedicalProfessionals,LLC\",\"phone\":{\"country_code\":\"US\",\"national_number\":\"5032141716\"},\"address\":{\"line1\":\"1234MainSt.\",\"city\":\"Portland\",\"state\":\"LALA\",\"postal_code\":\"97217\",\"country_code\":\"US\"}},\"billing_info\":[{\"email\":\"sally-patient#example.com\"}],\"shipping_info\":{\"first_name\":\"Sally\",\"last_name\":\"Patient\",\"business_name\":\"Notapplicable\",\"address\":{\"line1\":\"1234BroadSt.\",\"city\":\"Portland\",\"state\":\"LALA\",\"postal_code\":\"97216\",\"country_code\":\"US\"}},\"items\":[{\"name\":\"Sutures\",\"quantity\":100,\"unit_price\":{\"currency\":\"USD\",\"value\":\"250\"}}],\"invoice_date\":\"2014-01-07PST\",\"payment_term\":{\"term_type\":\"NO_DUE_DATE\"},\"tax_calculated_after_discount\":false,\"tax_inclusive\":false,\"note\":\"MedicalInvoice16Jul,2013PST\",\"total_amount\":{\"currency\":\"USD\",\"value\":\"250\"}}";
System.out.println(urlJsonString);
con.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(con.getOutputStream());
wr.write(urlJsonString);
wr.close();
int responseCode = con.getResponseCode();
System.out.println("Response Code : " + responseCode);
out.print(responseCode);
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer res= new StringBuffer();
while ((inputLine = in.readLine()) != null) {
res.append(inputLine);
}
in.close();
returnJson = (JSONObject) jparser.parse(res.toString());
System.out.println(returnJson);
}catch(Exception e){
e.printStackTrace();
returnJson.put("message", e);
}
out.print(returnJson);
I am testing the service on localhost, and i will manually pass in TWO parameters: "access_token" and "invoiceId" like this:
http://localhost:8080/Authentication/PaypalUpdateInvoiceServlet?input={"access_token":"A015Rv3XNo4fmFh4JC2sJiGjl1oEQ5w-B9azU.H6nlzMm1s","invoiceId":"INV2-9TRP-2S2R-OPBD-XK9T"}
These two pieces of info are obtained by me using the similar code i mentioned above.
I only modified codes in the entier HttpsURLConnection part to correspond with the cURL request and response sample provided in Paypal site. Link -->(https://developer.paypal.com/docs/api/#update-an-invoice)
Thus far, i successfully implement Create, Retrieve for invoice. I use the same way to make the servlet call with the specific parameters required and are able to get the expected response show on Paypal site.
BUT Now i am stuck with update invoice. When i make the servlet call.
i will receive:
500{"message":java.io.IOException: Server returned HTTP response code: 500 for URL: https://api.sandbox.paypal.com/v1/invoicing/invoices/IINV2-9TRP-2S2R-OPBD-XK9T}
Can anyone help me explain why i get this error and how shall i fix this?
I need to send a post request to url which is formed as follows:
www.abc.com/service/postsomething?data={'name':'rikesh'}&id=45
Using HttpPost client in java, how can post request to such query strings
I could connect from javascript easily through ajax but from java client, it's failing.
(I know sending querystring in post request is stupid idea. Since I am connecting to someone else's server I cannot not change the way it is)
Here is one way to send JSON in a POST request using Java (without Apache libraries). You might find this helpful:
//init
String json = "{\"name\":\"rikesh\"}";
String requestString = "http://www.example.com/service/postsomething?id=45";
//send request
URL url = new URL(requestString);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json");
OutputStream os = conn.getOutputStream();
os.write(json.getBytes());
os.flush();
int responseCode = conn.getResponseCode();
//get result if there is one
if(responseCode == 200) //HTTP 200: Response OK
{
String result = "";
BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String output;
while((output = br.readLine()) != null)
{
result += output;
}
System.out.println("Response message: " + result);
}
i'm trying to run a soap request in a basic http request...naturally i tried with external tools the message and is correct, like the endpoint i'm using as targetUrl, the wsdl is in something like
http://00.00.00.00/a-ws/services/basic?wsdl
and my actual end point is
http://00.00.00.00/a-ws/services/basic.targetservice
and i'm using this last as target url
URL url = new URL(targetUrl);
connection = (HttpURLConnection)url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", "text/xml;charset=UTF-8");
connection.setRequestProperty("SOAPAction", action);
connection.setRequestProperty("User-Agent", "myagent");
connection.setRequestProperty("Host", "localhost");
//connection.setRequestProperty("Content-Length", "" + Integer.toString(message.getBytes().length));
connection.setUseCaches (false);
connection.setDoInput(true);
connection.setDoOutput(true);
//Send request
OutputStream wr = connection.getOutputStream ();
wr.write (message.getBytes());
wr.flush ();
wr.close ();
//Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line=null;
StringBuffer response = new StringBuffer();
while( (line = rd.readLine()) != null) {
if (line!=null)
response.append(line);
}
rd.close();
return response.toString();
the raw message is tested with chrome plugin, the only thing i can't test is headers but the result is always an exception on getInputStream
java.io.IOException: Server returned HTTP response code: 500 for URL:
why?
It was a very stupid issue of encoding (like I was supposing)...i didn't escape double quote inside the message.
The evidence of problem was visible using a fake http server that just echo contents.
UPDATE:
Another thing nobody already pointed out is that is useful in case of exception to retrieve
connection.getErrorStream()
that contains the response in case of error!