We Keep Coding

Include files in Maven JAR package

I have a maven project with the following structure:
project
-src
--main
---java
----(All my .java files are here in their packages)
---resource
----(All my resources are here)
-database (HSQLDB files)
--db.script
--db.properties
--db.data
-target
--Maven build directory
pom.xml
I want the maven jar plugin to package in the database folder when it builds a JAR file. I've tried including as outlined here: https://maven.apache.org/plugins/maven-jar-plugin/examples/include-exclude.html, but it doesn't find the directory "../database" (or ../../database OR ../../../database!), and also it now doesn't include any of the classes or resources (It was including them before).
So what should I have in the configuration of the maven jar plugin?
Which is the correct path to include and how do I keep the files it was including before?
Thanks

By default, only resources located in src/main/resources are added in the JAR.
What you tried to do by configuring the maven-jar-plugin defines only the filetset to exclude or include in the built JAR.
But these files still have to be located in a resources folder where Maven looks for resources.
So, you have two ways to solve your requirement:
move database in the standard directory : src/main/resources.
specifies two resource folders for resources :
To do the latter, in the pom.xml add in the build tag :
<resources>
<resource>
<directory>src/main/resources</directory>
</resource>
<resource>
<directory>database-resources</directory>
</resource>
</resources>
Then add the database folder that you want package inside the database-resources.

Managing resources that will be external to a Jar file using Maven (and Eclipse)

I feel like I'm going round in circles with this, so hopefully its something relatively easy to solve.
For the application I'm developing I want to have a set of XML files which contain configuration information. And I would like these to be editable without having to re-compile the jar file. So what I would like is to have them in a folder called resources in the same folder as the jar file.
So my intended structure is something like
root
|
- app.jar
|
- resources
|
- config
|
- config1.xml
- config2.xml
I have managed to adjust my pom.xml so that it will copy the resources into my target folder using copy-resources within the maven-resource-plugin.
I've also added my resources directory as a resource (so that it works within eclipse) using
<resources>
<resource>
<directory>resources</directory>
</resource>
</resources>
so that I can access them using
getClass().getResource("/config/xml/config1.xml");
And included my resources directory on the classpath of the manifest of the jar (I think) using manifestEntries in the maven-jar-plugin.
<manifestEntries>
<Class-Path>. resources</Class-Path&>
</manifestEntries>
And attempted to exclude my resource from being compiled into the jar file using
<configuration>
<exclude>resources/**/*.xml</exclude>
</configuration>
they are still getting compiled into the jar file. And if I remove them from the jar file manually then I get a null pointer exception when attempting to access the resource.
So what I'm trying to achieve, and need help figuring out is
a way to obtain the structure I've roughly outlined above for external resources which are not compiled into the jar file but which are are accessible (via the classpath) by code within a jar in the same root directory and which still functions in eclipse.
Any help or guidance would be appreciated.

You have missed tag excludes
<configuration>
<excludes>
<exclude>resources/**/*.xml</exclude>
</excludes>
</configuration>

You can complicatedly exclude all folder like this :
<excludes>
<exclude>config/</exclude>
</excludes>
or just all xml files from config
<excludes>
<exclude>**/config/*.xml</exclude>
</excludes>

Add generated build file to classpath

During my build I generate a build.properties files via the maven properties plugin (properties-maven-plugin) containing build information.
What's the best way to have this file included in the generated jar? I don't want to put it into the src/main/resources directory as this would pollute my default resource directory.
Is there not a "generated-resources" directory as there is with source?

I thought there was a default generated-resources directory, but I can't find any documentation on that at the moment. You can always configure additional resource directories in your pom:
<build>
<resources>
<resource>
<directory>${basedir}/src/main/resources</directory>
</resource>
<resource>
<directory>${project.build.directory}/generated-resources</directory>
</resource>
</resources>
...
</build>

Place generated sources in target/generated-sources
There is a plugin called build-helper that allows you to add that folder to the source-folders list.

You can use maven assembly plugin to organize files and filesets in packages. have a look at http://maven.apache.org/plugins/maven-assembly-plugin/advanced-descriptor-topics.html
I think it is what you need.

you can output your files to any directory and add that resource directory to your <resources> of your <build>

You should put it in the target/classes directory
(fixed now from just target) and I think that this is better than the accepted one. As there is no need to process this resource as resource anymore

ImplementedVersion is not accessible in exec:java target

I have used this how2 to add the Version number to our produkt: http://www.christophkiehl.com/easy-way-to-display-your-apps-version-using-maven-and-manifest
when i now build a jar with mvn assembly:single i see the correct version.
But when i just run everything with mvn exec:java i get null...
what do i have to do that App.class.getPackage().getImplementationVersion() does not return null when i just start the programm from the non-jar?

The technique that you have used to add version number works only when built as a jar.
A different way to achieve the same would be to have a properties file which gets updated with the project version during build, which in turn is read by your java code.
Say, you have a file version.properties in src/main/resources, which has an entry
product.version=${project.version}
In the place you call App.class.getPackage().getImplementationVersion(), you read this property and display the contents.
This will work in both jar and non-jar case.
Update: You would need to update the pom to enable filtering for resources - essentially add a snippet like the below (refer this for details).
<resources>
<resource>
<directory>${basedir}/src/main/resources</directory>
<filtering>true</filtering>
</resource>
</resources>

How to make Maven copy resource file into WEB-INF/lib directory?

I'm using NewRelic for monitoring. I want Maven to package both newrelic.jar and newrelic.yaml files into my WEB-INF/lib inside the war file. With the newrelic.jar there is no problem since it's a simple dependency, but newrelic.yaml is a resource file. It resides in resources directory. I want Maven (war plugin) to copy it to WEB-INF/lib when packaging the war.
Thanks.
Alex

While I agree with #matt b that this is odd, here's what you can do:
Try changing the configuration of the maven war plugin to include a webResource:
<configuration>
<webResources>
<resource>
<directory>pathtoyaml</directory>
<includes>
<include>**/*.yaml</include>
</includes>
<targetPath>WEB-INF/lib</targetPath>
</resource>
</webResources>
</configuration>
The directory is relative to the pom.xml. See the plugin's documentation for more info.

You can also specify most configuration for the New Relic agent including the location of the config file via flags passed to the java command. In this case, it's something like:
-Dnewrelic.config.file=/etc/newrelic.yml
(ok, it's exactly like that, but you need to specify whatever path you need if it's not that.)

You should try adding .yaml file to newrelic.jar's resources, later
you can access it via classpath.
Or try changing/overriding build.xml build target by adding something like < copy file=".yaml"
todir="WEB-INF/lib" />
Try googling for more info on changing build.xml.