We Keep Coding

Multithreading Thread restart

i'am writing a small app to remote control a (Behringer x32) Mixing console. And i got a problem with the communication.
I'am sending data from the pc (app) to the console (port 10023 UDP Protocol), then the console answers to the port from the pc has send data, (random port).
So i have 2 Threads one for sending data, and one for listening for data from the console..... so every time i send data to the console, i need to change the listening port... so i have to kill the listening thread and start it new.
But after some time a have and the app has about x1000 threads open.
How can i restart the Thread or update the listening port without create a new thread?
here's the code for this section, the whole files are # gihub
the listening thread class:
public class Receiver implements Runnable {
private List<IReceiverListener> listeners;
private final static int PACKETSIZE = 48;
private int port;
public Receiver() {
listeners = new ArrayList();
}
public void addReceiverListener(IReceiverListener listener) {
listeners.add(listener);
}
private void update(String data, String adress) {
for (IReceiverListener listener : listeners) {
listener.receiveConsoleData(data, adress);
if (data.indexOf("active") > -1) {
listener.incrementWatchDog();
}
}
}
#Override
public void run() {
try {
// Convert the argument to ensure that is it valid
// Construct the socket
while (true) {
//System.out.println("Listen on Port:" + this.port);
DatagramSocket socket = new DatagramSocket(this.port);
// Create a packet
DatagramPacket packet = new DatagramPacket(new byte[PACKETSIZE], PACKETSIZE);
// Receive a packet (blocking)
socket.receive(packet);
// Print the packet
update(new String(packet.getData()), packet.getAddress().toString());
//logger.addLogData(new String(packet.getData())+" "+packet.getAddress().toString());
// Return the packet to the sender
socket.close();
}
} catch (IOException e) {
}
}
public void setPort(int port) {
this.port = port;
}
public int getPort() {
return port;
}
}
and here my port updateFunction
#Override
public void updatePort(int port) {
receiverThread.interrupt();
receiverThread = null;
receiver.setPort(port);
receiverThread = new Thread(receiver);
receiverThread.start();
}
and the sending thread does this, when it sends data:
listener.updatePort(dsocket.getLocalPort());

This is actually not a threading problem. The problem is, that the receiver thread is stuck in the receive method, so it cannot react to the changed port. However, calling the method DatagramSocket#close from another thread releases the blocking receiver thread with a SocketException.
Thus, you can solve this by closing the currently receiving socket when the receiving port was changed. The receiving thread can now catch the SocketException and create a new DatagramSocket that listens on the new port.
There is no need to kill and recreate threads.
First you put the socket into a field. This allows you to access it from another thread, so you can call the socket.close() method. Second, you put another try-catch block into the while(true) loop, which only catches SocketException.
Something like this might work fine:
public class Receiver implements Runnable {
private static final int PACKETSIZE = 48;
private final ConcurrentLinkedQueue<IReceiverListener> listeners = new ConcurrentLinkedQueue<>();
private volatile DatagramSocket socket;
private volatile int port;
public Receiver(int port) {
this.port = port;
}
public void addReceiverListener(IReceiverListener listener) {
listeners.add(listener);
}
public void updatePort(int port) {
this.port = port;
DatagramSocket socket = this.socket;
if (socket != null) {
socket.close();
}
}
#Override
public void run() {
try {
while (true) {
receiveLoop(new DatagramSocket(port));
}
} catch (IOException e) {
// handle error
}
}
private void receiveLoop(DatagramSocket newSocket) throws IOException {
try (DatagramSocket socket = newSocket) {
this.socket = newSocket;
while (true) {
DatagramPacket packet = new DatagramPacket(new byte[PACKETSIZE], PACKETSIZE);
socket.receive(packet);
process(packet);
}
} catch (SocketException e) {
// port was changed -> return and restart with a new socket
} finally {
this.socket = null;
}
}
private void process(DatagramPacket packet) {
update(new String(packet.getData()), packet.getAddress().toString());
}
private void update(String data, String adress) {
for (IReceiverListener listener : listeners) {
listener.receiveConsoleData(data, adress);
if (data.indexOf("active") > -1) {
listener.incrementWatchDog();
}
}
}
}
Please note, that this might still contains some bugs. It is only supposed to give you a rough idea of how to solve this.

As you are using DatagramSocket, you can change the used port by Binding the socket to a new port rather than the used one:
socket.bind(new InetSocketAddress(new_port));
But remember that bind() method won't work unless the socket is already opened and a port assigned to it, so at the first time you have to create the socket regularly, then when you try to change the port, just bind it.
And the following is a complete visualization of the process:
public void video_udp_server(int port) throws Exception
{
byte[] receiveData = new byte[Integer.MAX_VALUE/100];
for(int i = 0; i < receiveData.length; i++){
receiveData[i] = ' ';
}
DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
DatagramSocket socket = null;
try{
socket = new DatagramSocket(port);
}catch(Exception ex){
socket.bind(new InetSocketAddress(port));
}
socket.setReuseAddress(true);
socket.receive(receivePacket);
System.out.println(new String(receivePacket.getData()));
}

Why must I include a Thread.sleep(10) to get data to be sent over a socket

I have the following code for sending data over a socket:
socketclient.java
import java.io.*;
import java.net.Socket;
import java.net.UnknownHostException;
public class SocketClient
implements Runnable
{
private Socket socket;
private String ServerIP = "192.168.0.11";
private static final int ServerPort = 7000;
#Override
public void run()
{
try
{
socket = new Socket(ServerIP, ServerPort);
}
catch(Exception e)
{
System.out.print("Whoops! It didn't work on ip" + ServerIP + "!:");
System.out.print(e.getLocalizedMessage());
System.out.print("\n");
}
}
public void Send(String s)
{
try
{
Thread.sleep(10);
OutputStream out = socket.getOutputStream(); //Starts the output stream
PrintWriter output = new PrintWriter(out);
output.println(s); //sends the data over the socket
output.flush(); //flushes the outputwriter
output.close(); //closes the outputwriter
out.close(); //closes the outputstream
}
catch (UnknownHostException e) {
System.out.print(e.toString());
} catch (IOException e) {
System.out.print(e.toString());
}catch (Exception e) {
System.out.print(e.toString());
}
}
}
When i dont have the sleep in the send function the server output looks like this (i have it set to print the 'conn' and 'addr' of every connection), the server is coded in python
Connected with 192.168.0.11:52578
in client thread
Connected with 192.168.0.11:52579
in client thread
Connected with 192.168.0.11:52609
in client thread
and the server connection data recieveing/main connection thread is this:
def clientthread(conn):
#Sending message to connected client
#Receiving from client
data = conn.recv(4096)
print data
#came out of loop
conn.close()
My goal for the server is to open/close sockets on the client-side everytime i want to send data because i want each reciever to create its own connections using a socket class i created.
What is the reason for having to add a thread.sleep() before sending a string over a TCP socket in java?
Also, this is how i use my Socketclient class:
SMSClient = new SocketClient();
Thread thread = new Thread(SMSClient);
thread.start();
SMSClient.Send(smsData);

When you instantiate a new SocketClient object you are not running the new thread. You should call your Send(String s) method just after socket = new Socket(ServerIP, ServerPort); from inside the run method.
To know the current thread in your running code put some log like the following: Log.d("label", "thread id: "+android.os.Process.myTid()). Try for example to evaluate the current thread inside run method, and inside the Send(String s) method when you call this latter as you are doing and after having moved the call to the method inside the run.
I suggest to use IntentService for your purpose since, when needed, you can managed easily the socket connection and transmission in a separate thread.

When the thread.start() call returns the thread may not have executed yet. And then you are sending already your first request. You may wait with sleep after thread.start() that is better (while sleeping in the main thread the connection thread has a chance to run) - but still not best practice. Here is my working code ( I added a main function to the SocketClient ):
import java.io.*;
import java.net.Socket;
import java.net.UnknownHostException;
public class SocketClient
implements Runnable
{
private Socket socket;
private String ServerIP = "127.0.0.1";
private static final int ServerPort = 7000;
#Override
public void run()
{
try
{
socket = new Socket(ServerIP, ServerPort);
}
catch(Exception e)
{
System.out.print("Whoops! It didn't work on ip" + ServerIP + "!:");
System.out.print(e.getLocalizedMessage());
System.out.print("\n");
}
}
public void Send(String s)
{
try
{
OutputStream out = socket.getOutputStream(); //Starts the output stream
PrintWriter output = new PrintWriter(out);
output.println(s); //sends the data over the socket
output.flush(); //flushes the outputwriter
output.close(); //closes the outputwriter
out.close(); //closes the outputstream
}
catch (UnknownHostException e) {
System.out.print(e.toString());
} catch (IOException e) {
System.out.print(e.toString());
}catch (Exception e) {
System.out.print(e.toString());
}
}
static public void main(String[] args)
{
SocketClient socketClient = new SocketClient();
Thread thread = new Thread(socketClient);
thread.start();
try
{
Thread.sleep(19);
}
catch(Exception e) {}
socketClient.Send("hallo");
}
}

How to create Java Socket object serving on localhost only?

I ask this question again here ( How to create Java socket that is localhost only? ) 'cause all before mentioned methods (simply to say to create one ServerSocket by 3 parameters method) can not solve my problem.
I am working in one big intranet in which, every time when I open one browser, I need enter my proxy account and password to access internet. This is why I hope to test my socket program on localhost.
Occasionally my Client side can connect the Server side, but usually I have to wait for a long time before she coming out. I suppose, it should be related with some of proxy/firewall.
Although I look over all following resources and believe all of them are well worth reading, but I still can not get my issues out.
http://zerioh.tripod.com/ressources/sockets.html
How to determine an incoming connection is from local machine
My Server Side Code
import java.net.Socket;
import java.net.ServerSocket;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.IOException;
import java.net.InetAddress;
public class Myserver {
private int serverPort = 8000;
private ServerSocket serverSock = null;
public Myserver(int serverPort) {
this.serverPort = serverPort;
try {
/*SocketAddress socketAddress = new InetSocketAddress(InetAddress.getByName("localhost"), serverPort);
ServerSocket serverSocket = new ServerSocket();
serverSocket.bind(socketAddress);
serverSocket.accept();*/
serverSock = new ServerSocket(serverPort, 0, InetAddress.getByName(null));
}
catch (IOException e){
e.printStackTrace(System.err);
}
}
public void handleConnection(InputStream sockInput, OutputStream sockOutput) {
while(true) {
byte[] buf=new byte[1024];
int bytes_read = 0;
try {
// This call to read() will wait forever, until the
// program on the other side either sends some data,
// or closes the socket.
bytes_read = sockInput.read(buf, 0, buf.length);
// If the socket is closed, sockInput.read() will return -1.
if(bytes_read < 0) {
System.err.println("Tried to read from socket, read() returned < 0, Closing socket.");
return;
}
System.err.println("Received "+bytes_read
+" bytes, sending them back to client, data="
+(new String(buf, 0, bytes_read)));
sockOutput.write(buf, 0, bytes_read);
// This call to flush() is optional - we're saying go
// ahead and send the data now instead of buffering
// it.
sockOutput.flush();
// sockOutput.close();
}
catch (Exception e){
System.err.println("Exception reading from/writing to socket, e="+e);
e.printStackTrace(System.err);
return;
}
}
}
public void waitForConnections() {
Socket sock = null;
InputStream sockInput = null;
OutputStream sockOutput = null;
while (true) {
try {
// This method call, accept(), blocks and waits
// (forever if necessary) until some other program
// opens a socket connection to our server. When some
// other program opens a connection to our server,
// accept() creates a new socket to represent that
// connection and returns.
sock = serverSock.accept();
System.err.println("Have accepted new socket.");
// From this point on, no new socket connections can
// be made to our server until we call accept() again.
sockInput = sock.getInputStream();
sockOutput = sock.getOutputStream();
}
catch (IOException e){
e.printStackTrace(System.err);
}
// Do something with the socket - read bytes from the
// socket and write them back to the socket until the
// other side closes the connection.
handleConnection(sockInput, sockOutput);
// Now we close the socket.
try {
System.err.println("Closing socket.");
sock.close();
}
catch (Exception e){
System.err.println("Exception while closing socket.");
e.printStackTrace(System.err);
}
System.err.println("Finished with socket, waiting for next connection.");
}
}
}
My Client Side Code
import java.net.Socket;
import java.net.ServerSocket;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.IOException;
public class MyClient {
private String serverHostname = null;
private int serverPort =0;
private byte[] data = null;
private Socket sock = null;
private InputStream sockInput = null;
private OutputStream sockOutput = null;
public MyClient(String serverHostname, int serverPort, byte[] data){
this.serverHostname = serverHostname;
this.serverPort = serverPort;
this.data = data;
}
public void sendSomeMessages(int iterations) {
System.err.println("Opening connection to "+serverHostname+" port "+serverPort);
try {
sock = new Socket(serverHostname, serverPort);
sockInput = sock.getInputStream();
sockOutput = sock.getOutputStream();
}
catch (IOException e){
e.printStackTrace(System.err);
return;
}
System.err.println("About to start reading/writing to/from socket.");
byte[] buf = new byte[data.length];
int bytes_read = 0;
for(int loopi = 1; loopi <= iterations; loopi++) {
try {
sockOutput.write(data, 0, data.length);
bytes_read = sockInput.read(buf, 0, buf.length);
}
catch (IOException e){
e.printStackTrace(System.err);
}
if(bytes_read < data.length) {
System.err.println("run: Sent "+data.length+" bytes, server should have sent them back, read "+bytes_read+" bytes, not the same number of bytes.");
}
else {
System.err.println("Sent "+bytes_read+" bytes to server and received them back again, msg = "+(new String(data)));
}
// Sleep for a bit so the action doesn't happen to fast - this is purely for reasons of demonstration, and not required technically.
try { Thread.sleep(50);} catch (Exception e) {};
}
System.err.println("Done reading/writing to/from socket, closing socket.");
try {
sock.close();
}
catch (IOException e){
System.err.println("Exception closing socket.");
e.printStackTrace(System.err);
}
System.err.println("Exiting.");
}
}
My Test Code
import java.net.*;
public class Mytest {
public static void main(String[] args) {
String hostname = "localhost";
int port = 8000;
try {
InetAddress add = InetAddress.getLocalHost();
System.out.println( add);
}
catch (UnknownHostException e)
{
e.printStackTrace();
}
byte[] data = "my program".getBytes();
MyClient client = new MyClient(hostname, port, data);
client.sendSomeMessages(10);
Myserver server = new Myserver(port);
server.waitForConnections();
}
}
I try telnet, but I can't connect it at all

The first problem is that the test code runs both the client and the server. In Mytest.main(), the main thread does the following:
Creates a client (I would have thought that this step would fail)
Tries to send some messsages (but no ServerSocket has been started)
The server is created
The server waits forever, blocking the main thread on accept()
As a starter to get your code working. Create two test classes TestServer and TestClient, both of these must have main() methods. Launch TestServer first in it's own Java process. Next launch TestClient in separate Java process. This should work!
After you've got everything working, you should introduce some concurrency into your server. The way that it's currently written it can only serve a single client at a time. Create new threads to manage new sockets returned from accept().
Good luck!

Is it possible to have multiple threads listening on the same DatagramSocket?

I'm writing a chat program in java and I have been stuck for hours with this problem. This is my class that waits for clients to connect to the server.
Every time a new client connects I create a new ChatClient(String name, DatagramSocket serverSocket,InetAddress IPAddress, int port) object.
My idea was that every ChatClient object listens on the socket and when a package is sent from the same IP as the ChatClient, it will handle it, otherwise do nothing.
As it is now, when I only have one client connected; the client gets every 2 packages, then run() in WaitForConnection() gets the rest.
So my question, is it possible to have multiple threads listening on the same DatagramSocket without loss (everyone gets everything send). If there is a solution, how?
private ArrayList<ChatClient> clients;
private DatagramSocket serverSocket;
private boolean running;
public WaitForConnection() {
running = true;
clients = new ArrayList<ChatClient>();
try {
serverSocket = new DatagramSocket(ChatServer.port);
} catch (SocketException e) {
System.out
.println("Couldn't open socket. Port might alreadybe in use");
e.printStackTrace();
}
try {
serverSocket.setReuseAddress(true);
} catch (SocketException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
#Override
public void run() {
while (running) {
for (ChatClient ch : clients) {
System.out.println(ch.toString());
}
byte[] handShake = new byte[1024];
DatagramPacket receivePacket = new DatagramPacket(handShake,
handShake.length);
try {
serverSocket.receive(receivePacket);
} catch (IOException e) {
System.out.println("Waiting for connections error");
e.printStackTrace();
}
String connect = new String(receivePacket.getData());
System.out.println(connect);
InetAddress IPAddress = receivePacket.getAddress();
// if connect == "OPEN_CONNECTION" -> new client want to connect.
if (connect.contains("openconnection")) {
int port = receivePacket.getPort();
try {
ChatClient chatClient = new ChatClient(
IPAddress.getHostName(), serverSocket, IPAddress,
port);
// Don't want double clients.
for (int i = 0; i < clients.size(); i++) {
if (clients.get(i).equals(chatClient)) {
clients.remove(i);
}
}
clients.add(chatClient);
} catch (IOException e) {
System.out.println("Couldn't connect to client");
e.printStackTrace();
}
}
}
}
}
Code for ChatClient if you need to look at it.
public class ChatClient extends Thread {
private InetAddress IPAddress;
private DatagramSocket serverSocket;
private int port;
private String name;
public ChatClient(String name, DatagramSocket serverSocket,
InetAddress IPAddress, int port) throws IOException {
super(name);
this.name = name;
this.IPAddress = IPAddress;
this.serverSocket = serverSocket;
this.port = port;
byte[] confirmConnection = new byte[1024];
String connected = "Connection to server established";
confirmConnection = connected.getBytes();
serverSocket.send(new DatagramPacket(confirmConnection,
confirmConnection.length, IPAddress, port));
start();
}
public void run() {
while (true) {
byte[] message = new byte[1024];
DatagramPacket receivedPacket = new DatagramPacket(message,
message.length);
try {
serverSocket.receive(receivedPacket);
} catch (IOException e) {
System.out
.println("Something went wrong receiving data in ChatClient");
}
if (receivedPacket.getAddress().equals(IPAddress)) {
String connect = new String(receivedPacket.getData());
connect = connect.toUpperCase();
System.out.println(connect + "client side");
message = connect.getBytes();
try {
serverSocket.send(new DatagramPacket(message,
message.length, IPAddress, port));
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
}

It is possible for multiple threads to receive from the same DatagramSocket, but only one of them will get each datagram.
I don't see why you think you need this.

It is technically not possible, because the network hardware receives the packet only once. But then you can always duplicate it in memory once it is read. In your code basically just do Arrays.copyOf(receivePacket)
For a more sophisticated version, you could use the NIO package and work with a Selector. This would allow you to have all network connections run through a single thread, that reads and distributes the data to processing threads. That saves you the extra threading-overhead if you have multiple connections from many clients.

how to communicate between client and server in java

I have a chat program. Now the code works for communicate between client and server via command line. But it gives an exception (java.net.SocketException: Socket is closed) while running. Please help me to fix that problem.
In a java chat program,how will the communication be implemented between client and server?
ie.
client<-->server (between server and client)
or
client A<-->server<-->client B (server act as a bridge between two clients)
Is the 2 way communication can be implemented through a single socket?
Are there any other methods ?
How to communicate more than one client simultaneously?
server code
class Server
{
ServerSocket server;
Socket client;
public Server()
{
try
{
server = new ServerSocket(2000);
System.out.println("\tServer Started..........");
while (true)
{
client = server.accept();
Send objsend = new Send(client);
Recive objrecive = new Recive(client);
//client.close();
}
}
catch (Exception e)
{
System.out.println("Exception4 " + e);
}
}
public static void main(String arg[])
{
new Server();
}
}
class Recive implements Runnable
{
Socket client;
public Recive(Socket client1)
{
client=client1;
Thread trsend=new Thread(this);
trsend.start();
}
public void run()
{
ObjectInputStream ois;
Message M=new Message();
try
{
ois = new ObjectInputStream(client.getInputStream());
M = (Message)ois.readObject();
M.display();
ois.close();
}
catch (Exception e)
{
System.out.println("Exception1 " + e);
}
}
}
class Send implements Runnable
{
Socket client;
public Send(Socket client1)
{
client=client1;
Thread trrecive=new Thread(this);
trrecive.start();
}
public void run()
{
Message M=new Message();
InputStreamReader isr=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(isr);
try
{
System.out.println("Me(server)");
M.strmessage=br.readLine();
ObjectOutputStream oos=new ObjectOutputStream(cli ent.getOutputStream());
oos.writeObject((Message)M);
oos.flush();
oos.close();
}
catch (Exception e)
{
System.out.println("Exception " + e);
}
}
}
client code
class Client
{
public static void main(String arg[])
{
try
{
Send objsend=new Send();
Recive objrecive=new Recive();
}
catch(Exception e)
{
System.out.println("Exception "+e);
}
}
}
class Send implements Runnable
{
public Send()
{
Thread trsend=new Thread(this);
trsend.start();
}
public void run()
{
try
{
Message M=new Message();
InputStreamReader isr=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(isr);
while(true)
{
System.out.println("Me(client)");
M.strmessage=br.readLine();
Socket client=new Socket("localhost",2000);
ObjectOutputStream oos=new ObjectOutputStream(client.getOutputStream());
oos.writeObject((Message)M);
oos.flush();
oos.close();
}
}
catch(Exception e)
{
System.out.println("Exception "+e);
}
}
}
class Recive implements Runnable
{
public Recive()
{
Thread trrecive=new Thread(this);
trrecive.start();
}
public void run()
{
try
{
while(true)
{
Socket client=new Socket("localhost",2000);
ObjectInputStream ois=new ObjectInputStream(client.getInputStream());
Message CNE=(Message)ois.readObject();
CNE.display();
ois.close();
}
}
catch(Exception e)
{
System.out.println("Exception "+e);
}
}
}

First of all, don't close the streams in every run().
Secondly, check whether port for server which you are using is free.

This program makes your pc both host and server.
import java.io.IOException;
import java.net.*;
public class ClientServer {
static byte[] buffer = new byte[100];
private static void runClient() throws IOException {
byte buffer[] = new byte[100];
InetAddress address = InetAddress.getLocalHost();
DatagramSocket ds=new DatagramSocket();
int pos = 0;
while (pos<buffer.length) {
int c = System.in.read();
buffer[pos++]=(byte)c;
if ((char)c =='\n')
break;
}
System.out.println("Sending " + pos + " bytes");
ds.send(new DatagramPacket(buffer, pos, address, 3000));
}
private static void runServer() throws IOException {
InetAddress address = InetAddress.getLocalHost();
DatagramSocket ds = new DatagramSocket(3000, address);
DatagramPacket dp = new DatagramPacket(buffer, buffer.length);
ds.receive(dp);
String s=new String(dp.getData(),0,dp.getLength());
System.out.print(s);
}
public static void main(String args[]) throws IOException {
if (args.length == 1) {
runClient();
} else {
runServer();
}
}
}
also follow this link

There could be multiple places where the exception could be thrown. Without a stack trace it is difficult to state so accurately, as to the cause of failure.
But the root cause, is essentially due to the fact that you are closing the InputStream of the socket in your Receiver threads after reading a message, and closing the OutputStream of the socket in your Sender threads after sending a message. Closing either of these streams will automatically close the socket, so you if attempt to perform any further operation on it, a SocketException will be thrown.
If you need to ensure that your server and client do not shutdown in such an abrupt manner, you'll have to keep reading the InputStream (until you get a special message to shutdown, for instance). At the same time, you'll also have to keep writing to the OutputStream. Two-way communication is definitely possible, and the posted code is capable of the same (if the socket remains open).
If you have to handle multiple clients, you'll need multiple reader and writer threads on the server, each listening on an instance of a Socket returned from ServerSocket.accept(); in simpler words, you need a reader-writer pair listening on a distinct socket on the server for each client. At the moment, multiple clients can connect to the Server, as each incoming connection is provided its own client Socket object on the Server, that is provided to individual reader and writer threads. The main Server thread can continue to receive incoming connections and delegate the actual work to the reader-writer pairs.

chat programms normaly have a server through which all communication goes. The reason is that other wise every client needs to know how to reach every other client. And that doesn't work in the general case.
So you'll have a server, every client registers and talks with the server, which will forward messages to other clients.
Mostly communication is done via HTTP cause this is likely to go through firewalls and proxies. You probably want to read up on long polling if you are planning for anything serious.