Hibernate annotation object mapping - java

I'm pretty new with hibernate, and I'm trying to transform a JDBC project I have into Hibernate.
I'm using annotations, and I managed to annotate the basic stuff, however, I'm stuck now with the more heavy objects, I don't know how to annotate them.
Here's the Class:
#Entity
#Table(name = "person")
public class Person {
public Person{
}
// THIS WILL BE SOON INJECTED BY SPRING
private static transient PhoneNumberUtil phoneUtil = PhoneNumberUtil.getInstance();
private static transient EmailValidator validator = EmailValidator.getInstance();
#Id
#Column(name = "person_id")
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
#Column(name = "private_name", nullable = false, length = 20)
private String privateName;
#Column(name = "middle_name", length = 20)
private String middleName;
#Column(name = "family_name", nullable = false, length = 20)
private String familyName;
#Column(name = "age", nullable = false)
private int age;
#Column(name = "address1", nullable = false)
private String address1;
#Column(name = "address2")
private String address2;
//How do I annotate this ? --> Google LIBPHONENUMBER
private PhoneNumber phone;
// How do I annotate this ? --> This is a normal PNG image file.
private File image;
Edit:
The File was previously mapped as a BLOB.
The PhoneNumber was previously persisted as String, and was transformed using the PhoneNumber constructor to Phonenumber.

The other comments about using #Lob are correct for the File type. It is also correct that if you can change the schema to not save the file data in the DB, then you probably should.
To map your PhoneNumber class to a database field, you're going to need to use a Hibernate custom UserType. It basically tells Hibernate HOW to do the object<-->db mapping for classes that it doesn't already know about. Telling the PhoneNumber field in Person to use a custom user type is easy:
#Type(type = PhoneNumberType.CLASS_NAME)
#Column
private PhoneNumber phone;
This assumes a very simple one-column storage of the phone number.
To write PhoneNumberType, you'll need to implement UserType. It looks overwhelming, with the assemble/disassemble/deepCopy, but the main part you care about is nullSetGet/Set, returnedClass and sqlTypes. You'll end up with some code like this inside your custom type:
#Override
public Class<?> returnedClass() {
return PhoneNumber.class;
}
#Override
public int[] sqlTypes() {
return new int[] { Types.VARCHAR };
}
#Override
public Object nullSafeGet(ResultSet rs, String[] names, Object owner) throws HibernateException, SQLException {
final String value = rs.getString(names[0]);
return /* PhoneNumber instance created from string. */
}
#Override
public void nullSafeSet(PreparedStatement st, Object value, int index) throws HibernateException, SQLException {
if (value == null) {
st.setNull(index, Types.VARBINARY);
return;
}
st.setString(index, ((PhoneNumber) value).toString());
}
You can find plenty of information about how to implement the other methods via google, stackoverflow and the hibernate javadocs. It isn't that hard to do.
UPDATE: Multi-column user type
Implement CompositeUserType instead of just UserType. There are a few method changes that you care about. First you'll want to define the multiple property names and types:
public String[] getPropertyNames() {
return new String[] { "number", "code" };
}
public Type[] getPropertyTypes() {
return new Type[] { StandardBasicTypes.STRING,
StandardBasicTypes.STRING };
}
There's also getPropertyValue/setPropertyValue to implement. Your nullSafeXxxx implementations would change to read and write two properties instead of one:
#Override
public Object nullSafeGet(ResultSet rs, String[] names, Object owner) throws HibernateException, SQLException {
// Access column in order defined in getPropertyNames()
final String number = rs.getString(names[0]);
final String code = rs.getString(names[1]);
return /* PhoneNumber instance created from number and country code. */
}

Personally, I'd store only the filename in the object, and keep the file on the filesystem, where files belong.
Otherwise, map it as a Hibernate blob (#Lob) and you'd want it to be a byte array (would translate to a blob).
IMO this usually creates more trouble than it's worth, but that depends partially on the DB, driver revision, etc.

Just create a Hibernate UserType for PhoneNumber
import java.io.Serializable;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Types;
import org.apache.commons.lang.ObjectUtils;
import org.hibernate.HibernateException;
import org.hibernate.engine.spi.SessionImplementor;
import org.hibernate.type.StringRepresentableType;
import org.hibernate.usertype.UserType;
import com.google.i18n.phonenumbers.NumberParseException;
import com.google.i18n.phonenumbers.PhoneNumberUtil;
import com.google.i18n.phonenumbers.Phonenumber.PhoneNumber;
import com.tg.util.TGPhoneUtils;
public class PhoneNumberUserType implements UserType, StringRepresentableType<PhoneNumber>, Serializable {
private static final long serialVersionUID = -364436436346432L;
#Override
public boolean equals(Object x, Object y) throws HibernateException {
return ObjectUtils.equals(x, y);
}
#Override
public int hashCode(Object object) throws HibernateException {
return object.hashCode();
}
#Override
public Object deepCopy(Object value) throws HibernateException {
return value;
}
#Override
public boolean isMutable() {
return false;
}
#Override
public Serializable disassemble(Object value) throws HibernateException {
return (Serializable) value;
}
#Override
public Object assemble(Serializable cached, Object value) throws HibernateException {
return cached;
}
#Override
public Object replace(Object original, Object target, Object owner) throws HibernateException {
return original;
}
#Override
public String toString(PhoneNumber value) throws HibernateException {
return value.toString();
}
#Override
public Class<?> returnedClass() {
return PhoneNumber.class;
}
#Override
public int[] sqlTypes() {
return new int[] { Types.VARCHAR };
}
#Override
public PhoneNumber fromStringValue(String number) throws HibernateException {
try {
return PhoneNumberUtil.getInstance().parse(number, "US");
} catch (NumberParseException e) {
throw new HibernateException(e);
}
}
#Override
public Object nullSafeGet(ResultSet rs, String[] names, SessionImplementor arg2, Object owner) throws HibernateException, SQLException {
final String number = rs.getString(names[0]);
if (number == null) {
return null;
}
return TGPhoneUtils.parsePhoneNumber(number);
}
#Override
public void nullSafeSet(PreparedStatement st, Object value, int index, SessionImplementor si) throws HibernateException, SQLException {
if (value == null) {
st.setNull(index, Types.VARCHAR);
return;
}
st.setString(index, TGPhoneUtils.formatPhoneNumber((PhoneNumber)value));
}
}
and then here is the helper class
import com.google.i18n.phonenumbers.PhoneNumberUtil;
import com.google.i18n.phonenumbers.PhoneNumberUtil.PhoneNumberFormat;
import com.google.i18n.phonenumbers.Phonenumber.PhoneNumber;
public class TGPhoneUtils {
public static PhoneNumber parsePhoneNumber(String phoneNum) {
if (phoneNum == null) {
return null;
}
try {
return PhoneNumberUtil.getInstance().parse(phoneNum, "US");
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
public static String formatPhoneNumber(PhoneNumber phoneNum) {
if (phoneNum == null) {
return null;
}
return PhoneNumberUtil.getInstance().format(phoneNum, PhoneNumberFormat.E164);
}
}

You can annotate PhoneNumber like this:
#ManyToOne
#JoinColumn(name = "PHONE_NUMBER")
private PhoneNumber phone;
Assuming that the column PHONE_NUMBER exists and maps to the id of a phone number. The class PhoneNumber will also need to be annotated. This assumes that you want to maybe share a phone number among different entities (Many to one).
Regarding file, you probably need to decide if you want to actually store the file data in the db (normally not a good idea). Otherwise you could just store a String with a path to file.

Related

Deserializing an enum with Jackson (#JsonValue) [duplicate]

I'm using JAVA 1.6 and Jackson 1.9.9 I've got an enum
public enum Event {
FORGOT_PASSWORD("forgot password");
private final String value;
private Event(final String description) {
this.value = description;
}
#JsonValue
final String value() {
return this.value;
}
}
I've added a #JsonValue, this seems to do the job it serializes the object into:
{"event":"forgot password"}
but when I try to deserialize I get a
Caused by: org.codehaus.jackson.map.JsonMappingException: Can not construct instance of com.globalrelay.gas.appsjson.authportal.Event from String value 'forgot password': value not one of declared Enum instance names
What am I missing here?
The serializer / deserializer solution pointed out by #xbakesx is an excellent one if you wish to completely decouple your enum class from its JSON representation.
Alternatively, if you prefer a self-contained solution, an implementation based on #JsonCreator and #JsonValue annotations would be more convenient.
So leveraging on the example by #Stanley the following is a complete self-contained solution (Java 6, Jackson 1.9):
public enum DeviceScheduleFormat {
Weekday,
EvenOdd,
Interval;
private static Map<String, DeviceScheduleFormat> namesMap = new HashMap<String, DeviceScheduleFormat>(3);
static {
namesMap.put("weekday", Weekday);
namesMap.put("even-odd", EvenOdd);
namesMap.put("interval", Interval);
}
#JsonCreator
public static DeviceScheduleFormat forValue(String value) {
return namesMap.get(StringUtils.lowerCase(value));
}
#JsonValue
public String toValue() {
for (Entry<String, DeviceScheduleFormat> entry : namesMap.entrySet()) {
if (entry.getValue() == this)
return entry.getKey();
}
return null; // or fail
}
}
Note that as of this commit in June 2015 (Jackson 2.6.2 and above) you can now simply write:
public enum Event {
#JsonProperty("forgot password")
FORGOT_PASSWORD;
}
The behavior is documented here: https://fasterxml.github.io/jackson-annotations/javadoc/2.11/com/fasterxml/jackson/annotation/JsonProperty.html
Starting with Jackson 2.6 this annotation may also be used to change serialization of Enum like so:
public enum MyEnum {
#JsonProperty("theFirstValue") THE_FIRST_VALUE,
#JsonProperty("another_value") ANOTHER_VALUE;
}
as an alternative to using JsonValue annotation.
You should create a static factory method which takes single argument and annotate it with #JsonCreator (available since Jackson 1.2)
#JsonCreator
public static Event forValue(String value) { ... }
Read more about JsonCreator annotation here.
Actual Answer:
The default deserializer for enums uses .name() to deserialize, so it's not using the #JsonValue. So as #OldCurmudgeon pointed out, you'd need to pass in {"event": "FORGOT_PASSWORD"} to match the .name() value.
An other option (assuming you want the write and read json values to be the same)...
More Info:
There is (yet) another way to manage the serialization and deserialization process with Jackson. You can specify these annotations to use your own custom serializer and deserializer:
#JsonSerialize(using = MySerializer.class)
#JsonDeserialize(using = MyDeserializer.class)
public final class MyClass {
...
}
Then you have to write MySerializer and MyDeserializer which look like this:
MySerializer
public final class MySerializer extends JsonSerializer<MyClass>
{
#Override
public void serialize(final MyClass yourClassHere, final JsonGenerator gen, final SerializerProvider serializer) throws IOException, JsonProcessingException
{
// here you'd write data to the stream with gen.write...() methods
}
}
MyDeserializer
public final class MyDeserializer extends org.codehaus.jackson.map.JsonDeserializer<MyClass>
{
#Override
public MyClass deserialize(final JsonParser parser, final DeserializationContext context) throws IOException, JsonProcessingException
{
// then you'd do something like parser.getInt() or whatever to pull data off the parser
return null;
}
}
Last little bit, particularly for doing this to an enum JsonEnum that serializes with the method getYourValue(), your serializer and deserializer might look like this:
public void serialize(final JsonEnum enumValue, final JsonGenerator gen, final SerializerProvider serializer) throws IOException, JsonProcessingException
{
gen.writeString(enumValue.getYourValue());
}
public JsonEnum deserialize(final JsonParser parser, final DeserializationContext context) throws IOException, JsonProcessingException
{
final String jsonValue = parser.getText();
for (final JsonEnum enumValue : JsonEnum.values())
{
if (enumValue.getYourValue().equals(jsonValue))
{
return enumValue;
}
}
return null;
}
I've found a very nice and concise solution, especially useful when you cannot modify enum classes as it was in my case. Then you should provide a custom ObjectMapper with a certain feature enabled. Those features are available since Jackson 1.6. So you only need to write toString() method in your enum.
public class CustomObjectMapper extends ObjectMapper {
#PostConstruct
public void customConfiguration() {
// Uses Enum.toString() for serialization of an Enum
this.enable(WRITE_ENUMS_USING_TO_STRING);
// Uses Enum.toString() for deserialization of an Enum
this.enable(READ_ENUMS_USING_TO_STRING);
}
}
There are more enum-related features available, see here:
https://github.com/FasterXML/jackson-databind/wiki/Serialization-Features
https://github.com/FasterXML/jackson-databind/wiki/Deserialization-Features
Try this.
public enum Event {
FORGOT_PASSWORD("forgot password");
private final String value;
private Event(final String description) {
this.value = description;
}
private Event() {
this.value = this.name();
}
#JsonValue
final String value() {
return this.value;
}
}
I like the accepted answer. However, I would improve it a little (considering that there is now Java higher than version 6 available).
Example:
public enum Operation {
EQUAL("eq"),
NOT_EQUAL("ne"),
LESS_THAN("lt"),
GREATER_THAN("gt");
private final String value;
Operation(String value) {
this.value = value;
}
#JsonValue
public String getValue() {
return value;
}
#JsonCreator
public static Operation forValue(String value) {
return Arrays.stream(Operation.values())
.filter(op -> op.getValue().equals(value))
.findFirst()
.orElseThrow(); // depending on requirements: can be .orElse(null);
}
}
You can customize the deserialization for any attribute.
Declare your deserialize class using the annotationJsonDeserialize (import com.fasterxml.jackson.databind.annotation.JsonDeserialize) for the attribute that will be processed. If this is an Enum:
#JsonDeserialize(using = MyEnumDeserialize.class)
private MyEnum myEnum;
This way your class will be used to deserialize the attribute. This is a full example:
public class MyEnumDeserialize extends JsonDeserializer<MyEnum> {
#Override
public MyEnum deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
JsonNode node = jsonParser.getCodec().readTree(jsonParser);
MyEnum type = null;
try{
if(node.get("attr") != null){
type = MyEnum.get(Long.parseLong(node.get("attr").asText()));
if (type != null) {
return type;
}
}
}catch(Exception e){
type = null;
}
return type;
}
}
Here is another example that uses string values instead of a map.
public enum Operator {
EQUAL(new String[]{"=","==","==="}),
NOT_EQUAL(new String[]{"!=","<>"}),
LESS_THAN(new String[]{"<"}),
LESS_THAN_EQUAL(new String[]{"<="}),
GREATER_THAN(new String[]{">"}),
GREATER_THAN_EQUAL(new String[]{">="}),
EXISTS(new String[]{"not null", "exists"}),
NOT_EXISTS(new String[]{"is null", "not exists"}),
MATCH(new String[]{"match"});
private String[] value;
Operator(String[] value) {
this.value = value;
}
#JsonValue
public String toStringOperator(){
return value[0];
}
#JsonCreator
public static Operator fromStringOperator(String stringOperator) {
if(stringOperator != null) {
for(Operator operator : Operator.values()) {
for(String operatorString : operator.value) {
if (stringOperator.equalsIgnoreCase(operatorString)) {
return operator;
}
}
}
}
return null;
}
}
There are various approaches that you can take to accomplish deserialization of a JSON object to an enum. My favorite style is to make an inner class:
import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonProperty;
import org.hibernate.validator.constraints.NotEmpty;
import java.util.Arrays;
import java.util.Map;
import java.util.function.Function;
import java.util.stream.Collectors;
import static com.fasterxml.jackson.annotation.JsonFormat.Shape.OBJECT;
#JsonFormat(shape = OBJECT)
public enum FinancialAccountSubAccountType {
MAIN("Main"),
MAIN_DISCOUNT("Main Discount");
private final static Map<String, FinancialAccountSubAccountType> ENUM_NAME_MAP;
static {
ENUM_NAME_MAP = Arrays.stream(FinancialAccountSubAccountType.values())
.collect(Collectors.toMap(
Enum::name,
Function.identity()));
}
private final String displayName;
FinancialAccountSubAccountType(String displayName) {
this.displayName = displayName;
}
#JsonCreator
public static FinancialAccountSubAccountType fromJson(Request request) {
return ENUM_NAME_MAP.get(request.getCode());
}
#JsonProperty("name")
public String getDisplayName() {
return displayName;
}
private static class Request {
#NotEmpty(message = "Financial account sub-account type code is required")
private final String code;
private final String displayName;
#JsonCreator
private Request(#JsonProperty("code") String code,
#JsonProperty("name") String displayName) {
this.code = code;
this.displayName = displayName;
}
public String getCode() {
return code;
}
#JsonProperty("name")
public String getDisplayName() {
return displayName;
}
}
}
In the context of an enum, using #JsonValue now (since 2.0) works for serialization and deserialization.
According to the jackson-annotations javadoc for #JsonValue:
NOTE: when use for Java enums, one additional feature is that value returned by annotated method is also considered to be the value to deserialize from, not just JSON String to serialize as. This is possible since set of Enum values is constant and it is possible to define mapping, but can not be done in general for POJO types; as such, this is not used for POJO deserialization.
So having the Event enum annotated just as above works (for both serialization and deserialization) with jackson 2.0+.
Besides using #JsonSerialize #JsonDeserialize, you can also use SerializationFeature and DeserializationFeature (jackson binding) in the object mapper.
Such as DeserializationFeature.READ_UNKNOWN_ENUM_VALUES_USING_DEFAULT_VALUE, which give default enum type if the one provided is not defined in the enum class.
In my case, this is what resolved:
import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonProperty;
#JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum PeriodEnum {
DAILY(1),
WEEKLY(2),
;
private final int id;
PeriodEnum(int id) {
this.id = id;
}
public int getId() {
return id;
}
public String getName() {
return this.name();
}
#JsonCreator
public static PeriodEnum fromJson(#JsonProperty("name") String name) {
return valueOf(name);
}
}
Serializes and deserializes the following json:
{
"id": 2,
"name": "WEEKLY"
}
I hope it helps!
Here, 'value' acts as a deserialiser and 'namespace' acts as a serialiser. Hence, you can pass in value "Student Absent" to API while saving, and in DB it will be saved as "STUDENT_ABSENT". On the other hand, while retrieving data in your class, your API will return "Student Absent"
import com.fasterxml.jackson.annotation.JsonProperty;
public enum AttendanceEnums {
STUDENT_PRESENT,
#JsonProperty(value = "Student Absent", namespace = "Student Absent")
STUDENT_ABSENT;
}
I had been looking for a solution to enum serialization and I finally made a solution.
https://github.com/sirgilligan/EnumerationSerialization
https://digerati-illuminatus.blogspot.com/2022/10/java-enum-generic-serializer-and.html
It uses a new annotation and two new classes, EnumerationSerializer and EnumerationDeserializer. You can subclass the EnumerationDeserializer and make a class that sets the enum Class (typical approach) or you can annotate the enum and you don't have to have a subclass of EnumerationDeserializer.
#JsonSerialize(using = EnumerationSerializer.class)
#JsonDeserialize(using = EnumerationDeserializer.class)
#EnumJson(serializeProjection = Projection.NAME, deserializationClass = RGB.class)
enum RGB {
RED,
GREEN,
BLUE
}
Notice how the implementation of ContextualDeserializer pulls the class from the annotation.
https://github.com/sirgilligan/EnumerationSerialization/blob/main/src/main/java/org/example/EnumerationDeserializer.java
There is a lot of good code in this that might give insights.
For your specific question you could do this:
#JsonSerialize(using = EnumerationSerializer.class)
#JsonDeserialize(using = EnumerationDeserializer.class)
#EnumJson(serializeProjection = Projection.NAME, deserializationClass = Event.class)
public enum Event {
FORGOT_PASSWORD("forgot password");
//This annotation is optional because the code looks for value or alias.
#EnumJson(serializeProjection = Projection.VALUE)
private final String value;
private Event(final String description) {
this.value = description;
}
}
Or you could do this:
#JsonSerialize(using = EnumerationSerializer.class)
#JsonDeserialize(using = EnumerationDeserializer.class)
#EnumJson(serializeProjection = Projection.NAME, deserializationClass = Event.class)
public enum Event {
FORGOT_PASSWORD("forgot password");
private final String value;
private Event(final String description) {
this.value = description;
}
}
That's all you have to do.
Then if you have a class that "has a" event you can annotate each occurance to serialize the way you want.
class EventHolder {
#EnumJson(serializeProjection = Projection.NAME)
Event someEvent;
#EnumJson(serializeProjection = Projection.ORDINAL)
Event someOtherEvent;
#EnumJson(serializeProjection = Projection.VALUE)
Event yetAnotherEvent;
}
The simplest way I found is using #JsonFormat.Shape.OBJECT annotation for the enum.
#JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum MyEnum{
....
}
I did it like this :
// Your JSON
{"event":"forgot password"}
// Your class to map
public class LoggingDto {
#JsonProperty(value = "event")
private FooEnum logType;
}
//Your enum
public enum FooEnum {
DATA_LOG ("Dummy 1"),
DATA2_LOG ("Dummy 2"),
DATA3_LOG ("forgot password"),
DATA4_LOG ("Dummy 4"),
DATA5_LOG ("Dummy 5"),
UNKNOWN ("");
private String fullName;
FooEnum(String fullName) {
this.fullName = fullName;
}
public String getFullName() {
return fullName;
}
#JsonCreator
public static FooEnum getLogTypeFromFullName(String fullName) {
for (FooEnum logType : FooEnum.values()) {
if (logType.fullName.equals(fullName)) {
return logType;
}
}
return UNKNOWN;
}
}
So the value of the property "logType" for class LoggingDto will be DATA3_LOG
This post is old, but if it can help someone, use JsonFormat.Shape.STRING
#JsonFormat(shape = JsonFormat.Shape.STRING)
public enum SomeEnum{
#JsonProperty("SOME_PROPERTY")
someProperty,
...
}
Code results is like this
{"someenum":"SOME_PROPERTY"}
#JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum LoginOptionType {
PHONE(1, "Phone"), MAIL(2, "mail"), PERSONAL_EMAIL(3, "Personal email");
private static List<LoginOptionType> all;
static {
all = new ArrayList<LoginOptionType>() {
{
add(LoginOptionType.PHONE);
add(LoginOptionType.MAIL);
add(LoginOptionType.PERSONAL_EMAIL);
}
};
}
private final Integer viewValue;
private final String name;
LoginOptionType(Integer viewValue, String name) {
this.viewValue = viewValue;
this.name = name;
}
public Integer getViewValue() {
return viewValue;
}
public String getName() {
return name;
}
public static List<LoginOptionType> getAll() {
return all;
}
}
Response
[
{
"viewValue": 1,
"name": "Phone"
},
{
"viewValue": 2,
"name": "mail"
},
{
"viewValue": 3,
"name": "Personal email"
}
]

Java binary serializing fails because of jackson

I use jackson 2 to convert json into a java object. So far so good. But I also use hazelcast to distribute the objects in a cluster. Therefore all beans have to be java.io.Serializable. When I read the Object from json like so:
ObjectMapper mapper = new ObjectMapper();
mapper.addMixInAnnotations(AbstractBean.class, MongoIdMixIn.class);
// this is to prevent from failing on missing type class property: #JsonProperty("#class")
Object tgtObject = targetClass.newInstance();
mapper.readerForUpdating(tgtObject).readValue(dbo.toString());
// put into hazelcast map
target.put(dbo.get(keyColumn), tgtObject);
I will get an exception from hazelcast:
java.io.NotSerializableException: com.fasterxml.jackson.databind.deser.impl.TypeWrappedDeserializer
I am wondering where the com.fasterxml.jackson.databind.deser.impl.TypeWrappedDeserializer is coming from since the Object is a plain java bean (but using inheritance).
My Abstract class is:
#JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
#JsonIgnoreProperties(ignoreUnknown = true)
#JsonTypeInfo(use=JsonTypeInfo.Id.CLASS, include=JsonTypeInfo.As.PROPERTY, property="#javaClass")
public abstract class AbstractBean implements Serializable {
#JsonIgnore public static final transient IMarkupParser MARKUP_PARSER = new WikiMarkupParser();
#JsonProperty("id")
private String id;
#JsonProperty("#class")
private String clazz;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getClazz() {
return this.getClass().getSimpleName();
}
}
And my child is:
public class Posting extends AbstractBean {
private String postingSource;
private String languageCode;
public String getPostingSource() {
return postingSource;
}
public void setPostingSource(String postingSource) {
this.postingSource = postingSource;
}
public String getLanguageCode() {
return languageCode;
}
public void setLanguageCode(String languageCode) {
this.languageCode = languageCode;
}
}
I have no Idea why the serailizer would even try to serialize the mixins since the are not part of the bean but here they are (yes I have tried to make them serializable too, just as a test, no luck):
public interface IdMixins extends Serializable {
}
public interface MongoIdMixIn extends IdMixins {
#JsonProperty("_id")
#JsonSerialize(using = MongoIdSerializer.class)
public String getId();
#JsonProperty("_id")
#JsonDeserialize(using = MongoIdDeserializer.class)
public void setId(String id);
}
public class MongoIdDeserializer extends JsonDeserializer<String> implements Serializable {
private static final long serialVersionUID = -5404276857799190647L;
#Override
public String deserialize(JsonParser jp, DeserializationContext deserializationContext) throws IOException, JsonProcessingException {
String value = null;
String tmp = jp.getText(); // {
validate(jp, tmp,"{");
int curly = 1;
while (jp.nextToken() != null) {
String v = jp.getText();
if (v.equals("{")) curly++;
if (v.equals("$oid")) {
jp.nextToken();
value = jp.getText();
}
if (v.equals("}")) curly--;
if (curly<=0) return value;
}
return null;
}
private void validate(JsonParser jsonParser, String input, String expected) throws JsonProcessingException {
if (!input.equals(expected)) {
throw new JsonParseException("Unexpected token: " + input, jsonParser.getTokenLocation());
}
}
}
public class MongoIdSerializer extends JsonSerializer<String> implements Serializable {
private static final long serialVersionUID = 3435689991839324194L;
#Override
public void serialize(String s, JsonGenerator jsonGenerator, SerializerProvider serializerProvider) throws IOException, JsonProcessingException {
jsonGenerator.writeStartObject();
jsonGenerator.writeFieldName("$oid");
jsonGenerator.writeString(s);
jsonGenerator.writeEndObject();
}
}
Stupid me! Somewhere in the serialization chain was a completely unnecessary ObjectMapper object. But it was hard to find because not the Posting object was the real reason, instead it was another object. But the Stacktrace and the com.fasterxml.jackson.databind.deser.impl.TypeWrappedDeserializer Exception were completely miss leading! ... clustered software is sometimes really painful to debug :-)
I'm 1 Rep. Point away from being able to comment. So I have to make a suggestion as an answer ;-).
Perhaps one of the Annotations do inject an instance of TypeWrappedDeserializer as a private property into the AbstractBean. Maybe as hint for the deserialization mechanism.
Could you inspect the created object with reflection to verify?
for (Field field : tgtObject.getClass().getDeclaredFields() )
{
// you can replace this by your logging method
System.out.println("Field: " + field.getName() + ":" + field.getType());
}
for (Field field : tgtObject.getClass().getSuperclass().getDeclaredFields() )
{
// you can replace this by your logging method
System.out.println("Field: " + field.getName() + ":" + field.getType());
}
If you find the apropriate type in the listing the Class was added by Byte Code Enhancement.

Hibernate entities mapping: Retrieve VARCHAR as boolean

I have a table INCIDENCIA in my database that has a VARCHAR column VISIBLE with two possible values: Y or N matching true or false.
I have it mapped in this entity:
#Entity
public class Incidencia {
private String visible;
//other fields
#Basic
#Column(name = "VISIBLE")
public String getVisible() {
return visible;
}
public void setVisible(String visible) {
this.visible = visible;
}
}
This field is a String since column in database is a VARCHAR, however I would like to retrieve it as java.lang.Boolean with a Y/N deserialization.
Is there any way to do this by Hibernate annotations?
Thanks.
You can create your own mapping type. Something like this:
package es.buena.jamon.type;
public class SpanishBoolean extends AbstractSingleColumnStandardBasicType<Boolean>
implements PrimitiveType<Boolean>, DiscriminatorType<Boolean>
{
private static final long serialVersionUID = 1L;
public static final SpanishBoolean INSTANCE = new SpanishBoolean();
public SpanishBoolean() {
super( CharTypeDescriptor.INSTANCE, new BooleanTypeDescriptor('S', 'N') );
}
#Override
public String getName() {
return "si_no";
}
#Override
public Class getPrimitiveClass() {
return boolean.class;
}
#Override
public Boolean stringToObject(String xml) throws Exception {
return fromString( xml );
}
#Override
public Serializable getDefaultValue() {
return Boolean.FALSE;
}
#Override
public String objectToSQLString(Boolean value, Dialect dialect) throws Exception {
return StringType.INSTANCE.objectToSQLString( value ? "S" : "N", dialect );
}
}
and then register it with the configuration:
Configuration configuration = new Configuration().configure();
configuration.registerTypeOverride(new SpanishBoolean());
and then use it in your entity:
#Type(type="es.buena.jamon.type.SpanishBoolean")
private Boolean visible;
Hope that helps.

Using UUID with EclipseLink and PostgreSQL

I want to use the PostgreSQL uuid type for objects' primary keys.
For that I've created a converter (implementing the Converter interface).
Bellow is the relevant code:
#Override
public void initialize(DatabaseMapping mapping, Session session) {
final DatabaseField field;
if (mapping instanceof DirectCollectionMapping) {
field = ((DirectCollectionMapping) mapping).getDirectField();
} else {
field = mapping.getField();
}
field.setSqlType(Types.OTHER);
field.setTypeName("uuid");
field.setColumnDefinition("UUID");
}
Then I've annotated the relevant entity X with the bellow annotations:
#Converter(name="uuidConverter",converterCalss=UUIDConverter.class)
#Convert("uuidConverter")
#Id
public UUID getId()
{
return id;
}
The problem is that I have another class (Y) which has the following definition:
#ManyToOne(targetEntity = X.class)
#JoinColumn(name = "x_id")
public X getX();
Although EclipseLink created the tables as expected it sends a string to the database when trying to insert objects of type Y.
Postgres returns the following error message:
column "id" is of type uuid but expression is of type character varying at character
Any solutions / work around will be appreciated.
I had the same issue with EclipseLink JPA + Postgresql + UUID as primary key.
To solve it, I've merged codes from Github and below link:
https://forums.oracle.com/forums/thread.jspa?messageID=4584157
The below code for UUIDConverter worked for me, though the code surely isn't the best.
public void initialize(DatabaseMapping ARGMapping, Session ARGSession)
{
final DatabaseField Field;
if (ARGMapping instanceof DirectCollectionMapping)
{
Field = ((DirectCollectionMapping) ARGMapping).getDirectField();
}
else
{
Field = ARGMapping.getField();
}
Field.setSqlType(Types.OTHER);
Field.setTypeName("uuid");
Field.setColumnDefinition("UUID");
for (DatabaseMapping m : ARGMapping.getDescriptor().getMappings())
{
assert OneToOneMapping.class.isAssignableFrom(ManyToOneMapping.class);
if (m instanceof OneToOneMapping)
{
for (DatabaseField field : ((OneToOneMapping) m).getForeignKeyFields())
{
field.setSqlType(Types.OTHER);
field.setColumnDefinition("UUID");
field.setTypeName("uuid");
}
}
}
}
I had some issues with EclipseLink JPA 2.1 + Postgresql + UUID as primary key but I find out different solution. I adopted AttributeConverter but I faced a problem with EclipseLink implementation that I resolved with this code:
#javax.persistence.Converter(autoApply = true)
public class PostgresUuidConverter implements AttributeConverter<UUID, Object> {
#Override
public Object convertToDatabaseColumn(UUID uuid) {
PostgresUuid object = new PostgresUuid();
object.setType("uuid");
try {
if (uuid == null) {
object.setValue(null);
} else {
object.setValue(uuid.toString());
}
} catch (SQLException e) {
throw new IllegalArgumentException("Error when creating Postgres uuid", e);
}
return object;
}
#Override
public UUID convertToEntityAttribute(Object dbData) {
if (dbData instanceof String) {
return UUID.fromString(dbData.toString());
} else {
return (UUID) dbData;
}
}
}
public class PostgresUuid extends PGobject implements Comparable<Object> {
private static final long serialVersionUID = 1L;
#Override
public int compareTo(Object arg0) {
return 0;
}
}
As I exaplined in detail in this post http://blog-ungarida.rhcloud.com/persisting-uuid-in-postgresql-using-jpa-eclipselink/
Try checking what the fieldClassification of the mapping is in the initialize method. It might be getting String.class somehow, try setting it to Object.class.
or, field.setType(Object.class)
It seems there is a bug/incompatibility between EclipseLink and PostgresQL. If you just use UUID for primary keys you should be okay. But if you have a nullable UUID column, and you try to store null in it, you will get the reported error:
column "whatever" is of type uuid but expression is of type character varying
See: https://bugs.eclipse.org/bugs/show_bug.cgi?id=538138 (log in and vote for it if you have the time!)
That bug report proved very useful to me. Specifically the link to the forum thread at:
https://www.eclipse.org/forums/index.php?t=msg&th=1073632&goto=1719530&#msg_1719530
I tried all sorts of solutions from here on SO, and elsewhere on the web. The only one that seemed to work for me was the one posted by David Wheeler there. Specifically, creating a cast from character varying to uuid in the database.
Note that you have to be user postgres to create the cast:
$ sudo su - postgres
$ psql <your database name>
# drop cast if exists (character varying as uuid);
# create or replace function uuid(_text character varying) returns uuid language sql as 'select uuid_in(_text::cstring)';
# create cast (character varying as uuid) with function uuid(character varying) as assignment;
For completeness here is the rest of what I use (in case it helps)
All my entities (that have a UUID primary key) extend a base class called EntityBase:
package com.example.entity;
import java.io.Serializable;
import java.util.UUID;
import javax.persistence.Id;
import javax.persistence.MappedSuperclass;
import org.eclipse.persistence.annotations.Convert;
import org.eclipse.persistence.annotations.Converter;
import com.example.converter.UUIDTypeConverter;
#MappedSuperclass
#Converter(name="uuidConverter", converterClass=UUIDTypeConverter.class)
public class EntityBase implements Serializable, Cloneable
{
private static final long serialVersionUID = 1L;
#Id
#Convert("uuidConverter")
private UUID id;
public EntityBase() {
this.id = UUID.randomUUID();
}
#Override
public int hashCode() {
return id.hashCode();
}
#Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (!(obj instanceof EntityBase)) {
return false;
}
EntityBase other = (EntityBase) obj;
return getId().equals(other.getId());
}
public UUID getId()
{
return this.id;
}
public void setId(UUID id)
{
this.id = id;
}
}
The UUID converter class looks like this:
package com.example.converter;
import java.sql.Types;
import java.util.UUID;
import org.eclipse.persistence.internal.helper.DatabaseField;
import org.eclipse.persistence.mappings.DatabaseMapping;
import org.eclipse.persistence.mappings.converters.Converter;
import org.eclipse.persistence.sessions.Session;
public class UUIDTypeConverter implements Converter
{
#Override
public UUID convertObjectValueToDataValue(Object objectValue, Session session)
{
return (UUID) objectValue;
}
#Override
public UUID convertDataValueToObjectValue(Object dataValue, Session session)
{
return (UUID) dataValue;
}
#Override
public boolean isMutable()
{
return true;
}
#Override
public void initialize(DatabaseMapping mapping, Session session)
{
DatabaseField field = mapping.getField();
field.setSqlType(Types.OTHER);
field.setTypeName("java.util.UUID");
field.setColumnDefinition("UUID");
}
}
If you have entities that have UUID columns that are not primary keys, you can annotate them as follows:
import org.eclipse.persistence.annotations.Convert
import org.eclipse.persistence.annotations.Converter;
#Entity
#Converter(name="uuidConverter", converterClass=UUIDTypeConverter.class)
public class BillingEvent extends EntityBase
{
#Convert("uuidConverter")
private UUID entityId;
}
Note that if that entity has other columns that use the standard javax.persistence.convert annotation, you'll need to differentiate the two Convert annotations to avoid a compile error.
For example:
import javax.persistence.Convert;
import org.eclipse.persistence.annotations.Converter;
#Entity
#Converter(name="uuidConverter", converterClass=UUIDTypeConverter.class)
public class BillingEvent extends EntityBase
{
#org.eclipse.persistence.annotations.Convert("uuidConverter")
private UUID entityId;
#Convert(converter = JSR310InstantTypeConverter.class)
private Instant createdOn;
}
I hope this saves others some time. Good luck!
Universal UUIDConverter for EclipseLink (not only PostgreSQL)
Code:
import java.nio.ByteBuffer;
import java.util.UUID;
import org.eclipse.persistence.internal.helper.DatabaseField;
import org.eclipse.persistence.mappings.DatabaseMapping;
import org.eclipse.persistence.mappings.DirectCollectionMapping;
import org.eclipse.persistence.mappings.converters.Converter;
import org.eclipse.persistence.sessions.Session;
public class UUIDConverter implements Converter {
private Boolean isUUIDasByteArray = true;
#Override
public Object convertObjectValueToDataValue(Object objectValue,
Session session) {
if (isUUIDasByteArray) {
UUID uuid = (UUID)objectValue;
if (uuid == null) return null;
byte[] buffer = new byte[16];
ByteBuffer bb = ByteBuffer.wrap(buffer);
bb.putLong(uuid.getMostSignificantBits());
bb.putLong(uuid.getLeastSignificantBits());
return buffer;
}
return objectValue;
}
#Override
public UUID convertDataValueToObjectValue(Object dataValue,
Session session) {
if (isUUIDasByteArray) {
byte[] bytes = (byte[])dataValue;
if (bytes == null) return null;
ByteBuffer bb = ByteBuffer.wrap(bytes);
long high = bb.getLong();
long low = bb.getLong();
return new UUID(high, low);
}
return (UUID) dataValue;
}
#Override
public boolean isMutable() {
return true;
}
#Override
public void initialize(DatabaseMapping mapping, Session session) {
final DatabaseField field;
if (mapping instanceof DirectCollectionMapping) {
// handle #ElementCollection...
field = ((DirectCollectionMapping) mapping).getDirectField();
} else {
field = mapping.getField();
}
if (session != null && session.getLogin()!= null && session.getLogin().getPlatform() != null) {
String platform = session.getLogin().getPlatform().getClass().getSimpleName();
if (platform.equals("PostgreSQLPlatform")) {
field.setSqlType(java.sql.Types.OTHER);
field.setTypeName("java.util.UUID");
field.setColumnDefinition("UUID");
isUUIDasByteArray = false;
} else if (platform.equals("H2Platform")) {
field.setColumnDefinition("UUID");
} else if (platform.equals("OraclePlatform")) {
field.setColumnDefinition("RAW(16)");
} else if (platform.equals("MySQLPlatform")) {
field.setColumnDefinition("BINARY(16)");
} else if (platform.equals("SQLServerPlatform")) {
field.setColumnDefinition("UNIQUEIDENTIFIER");
}
}
}
}
You don't need a converted. Use this column definition in the entity. You need to register the uuid extension first. This works with Postgres 10 and Wildfly 10.1
#Column(name = "UUID", nullable=false, insertable = false, columnDefinition="uuid DEFAULT uuid_generate_v4()")
private String uuid;

Mapping array with Hibernate

Can you please help me to map this class using Hibernate?
public class MyClass{
private Long id;
private String name;
private int[] values;
...
}
I'm using PostgreSQL and the column type in the table is integer[]
How my array should be mapped?
Hibernate (and JPA) can't directly map the PostgreSQL array type. See this question for how to proceed if you really need to retain your database structure as it is. This thread has an example of the required custom type.
If you can change your schema, you can let hibernate create an additional table to handle the collection - List<Integer>. Then, depending on the version of hibernate you are using:
JPA 2.0 compliant - use #ElementCollection
JPA 1.0 compliant - use #CollectionOfElements
Hibernate can map only the primitive types. Check under the org.hibernate.type folder of hibernate jar package. int array is not one of them. So you would have to write a custom type that can implement the UserType interface.
public class MyClass{
private Long id;
private String name;
private Integer[] values;
#Type(type = "com.usertype.IntArrayUserType")
public Integer[] getValues(){
return values;
}
public void setValues(Integer[] values){
this.values = values;
}
}
IntArrayUserType.class
package com.usertype.IntArrayUserType;
public class IntArrayUserType implements UserType {
protected static final int[] SQL_TYPES = { Types.ARRAY };
#Override
public Object assemble(Serializable cached, Object owner) throws HibernateException {
return this.deepCopy(cached);
}
#Override
public Object deepCopy(Object value) throws HibernateException {
return value;
}
#Override
public Serializable disassemble(Object value) throws HibernateException {
return (Integer[]) this.deepCopy(value);
}
#Override
public boolean equals(Object x, Object y) throws HibernateException {
if (x == null) {
return y == null;
}
return x.equals(y);
}
#Override
public int hashCode(Object x) throws HibernateException {
return x.hashCode();
}
#Override
public boolean isMutable() {
return true;
}
#Override
public Object nullSafeGet(ResultSet resultSet, String[] names, SessionImplementor session, Object owner)
throws HibernateException, SQLException {
if (resultSet.wasNull()) {
return null;
}
if(resultSet.getArray(names[0]) == null){
return new Integer[0];
}
Array array = resultSet.getArray(names[0]);
Integer[] javaArray = (Integer[]) array.getArray();
return javaArray;
}
#Override
public void nullSafeSet(PreparedStatement statement, Object value, int index, SessionImplementor session)
throws HibernateException, SQLException {
Connection connection = statement.getConnection();
if (value == null) {
statement.setNull(index, SQL_TYPES[0]);
} else {
Integer[] castObject = (Integer[]) value;
Array array = connection.createArrayOf("integer", castObject);
statement.setArray(index, array);
}
}
#Override
public Object replace(Object original, Object target, Object owner) throws HibernateException {
return original;
}
#Override
public Class<Integer[]> returnedClass() {
return Integer[].class;
}
#Override
public int[] sqlTypes() {
return new int[] { Types.ARRAY };
}
When you query for the MyClass entity you can add something like this:
Type intArrayType = new TypeLocatorImpl(new TypeResolver()).custom(IntArrayUserType.class);
Query query = getSession().createSQLQuery("select values from MyClass")
.addScalar("values", intArrayType);
List<Integer[]> results = (List<Integer[]>) query.list();
Maven dependency
The first thing you need to do is to set up the following Hibernate Types Maven dependency in your project pom.xml configuration file:
<dependency>
<groupId>com.vladmihalcea</groupId>
<artifactId>hibernate-types-52</artifactId>
<version>${hibernate-types.version}</version>
</dependency>
Maven ARRAY columns
Assuming you have this table in your database:
create table event (
id int8 not null,
version int4,
sensor_names text[],
sensor_values integer[],
primary key (id)
)
And you want to map it like this:
#Entity(name = "Event")
#Table(name = "event")
#TypeDefs({
#TypeDef(
name = "string-array",
typeClass = StringArrayType.class
),
#TypeDef(
name = "int-array",
typeClass = IntArrayType.class
)
})
public static class Event extends BaseEntity {
#Type( type = "string-array" )
#Column(
name = "sensor_names",
columnDefinition = "text[]"
)
private String[] sensorNames;
#Type( type = "int-array" )
#Column(
name = "sensor_values",
columnDefinition = "integer[]"
)
private int[] sensorValues;
//Getters and setters omitted for brevity
}
The string-array and int-array are custom types which can be defined in the BaseEntity superclass:
#TypeDefs({
#TypeDef(
name = "string-array",
typeClass = StringArrayType.class
),
#TypeDef(
name = "int-array",
typeClass = IntArrayType.class
)
})
#MappedSuperclass
public class BaseEntity {
#Id
private Long id;
#Version
private Integer version;
//Getters and setters omitted for brevity
}
The StringArrayType and IntArrayType are classes offered by the Hibernate Types project.
Testing time
Now, when you insert a couple of entities;
Event nullEvent = new Event();
nullEvent.setId(0L);
entityManager.persist(nullEvent);
Event event = new Event();
event.setId(1L);
event.setSensorNames(
new String[] {
"Temperature",
"Pressure"
}
);
event.setSensorValues(
new int[] {
12,
756
}
);
entityManager.persist(event);
Hibernate is going to generate the following SQL statements:
INSERT INTO event (
version,
sensor_names,
sensor_values,
id
)
VALUES (
0,
NULL(ARRAY),
NULL(ARRAY),
0
)
INSERT INTO event (
version,
sensor_names,
sensor_values,
id
)
VALUES (
0,
{"Temperature","Pressure"},
{"12","756"},
1
)
I have never mapped arrays to hibernate. I always use collections. So, I have slightly changed you class:
public class MyClass{
private Long id;
private String name;
private List<Integer> values;
#Id
// this is only if your id is really auto generated
#GeneratedValue(strategy=GenerationType.AUTO)
public Long getId() {
return id;
}
#OneToMany(cascade=CascadeType.ALL, fetch=FetchType.LAZY)
public List<Integer> getValues() {
return values;
}
...
From Hibernate 6.1 Final, basic arrays and collections may now be mapped to database ARRAY types if possible, or alternatively JSON/XML types.
https://in.relation.to/2022/06/14/orm-61-final/

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