I'm using a regex string that contains a carat (^) symbol somewhere inside of it. Is there a way in Java to remove these symbols? Here are a few methods I've tried:
string = "some^string";
string = string.replaceAll("\\^", "");
string = string.replaceAll(Pattern.quote("\\^"), "");
string = string.replaceAll(Pattern.quote("\u2038"), "");
None of which have worked. What am I missing?
There's no need to use regular expressions at all:
string = string.replace("^", "");
However, the first of your examples works too:
public class Test {
public static void main(String[] args) throws Exception {
String string = "some^string";
string = string.replaceAll("\\^", "");
System.out.println(string); // Prints somestring
}
}
... so it's entirely possible that your problem is elsewhere.
string.replaceAll("\\^", ""); should work.
Pls. delete last 2 lines from above your code and do write below things only then check.
string = "some^string";
string = string.replaceAll("\^", "");
I think you can try using another variable name, like for example:
String str1 = string.replace("^", "1");
and use the new str1, instead of the old string.
Related
I have question about String class in Java.
I want remove every punctuation marks. To be exact I use replace() method and replace all marks for: "";
But my question is can I do it more smoothly? Becouse now I replace every sign separately
String line1 = line.replace(".", "");
String line2 = line1.replace("?", "");
String line3 = line2.replace("!", "");
String line4 = line3.replace("\n", "");
Ok I find helpful and nice solution.
String line11 = line.replaceAll("[\\p{Punct}]", "");
use replaceAll, and reg []
String str = "hellol,lol/,=o/l.o?ll\no,llol";
str = str.replaceAll("[,=/\\n\\?\\.]", "");
System.out.println(str);
If we want to replace every punctuation mark then we can use the replaceAll() method in java to achieve that. replaceAll("[^a-zA-Z ]", "")), This line makes a java compiler to understand every character other than alphabets(both lowercase and uppercase) to be replaced by "" i.e,empty. with this we can replace every punctuation marks in a particular string.
public class HelloWorld {
public static void main(String[] args) {
String line="Th##is i*s a Ex()ample St!#ing!#";
System.out.println(line.replaceAll("[^a-zA-Z ]", ""));
}
}
Im trying to figure out how i can remove certain characters in an email address before the domain name using nothing but a simple regex and replaceAll in Java.
In email addresses,
Need to remove any number of . before #<domain name>
Also remove anything between + up to # but not including #. For instance in joebloggs+123#domain.com should be joebloggs#domain.com.
So far I have,
class Main {
public static void main(String[] args) {
String matchingRegex = "(\\.|(\\+.*(?=#)))";
System.out.println("joe.bloggs+123#gmail.com".replaceAll(matchingRegex, ""));
}
}
which replaces everything including the domain name.
joebloggs#gmailcom
What i really need is joebloggs#gmail.com.
Can this be achieved with regex alone ?
Another look ahead did the trick in the end.
class Main {
public static void main(String[] args) {
String matchingRegex = "((\\.+)(?=.*#)|(\\+.*(?=#)))";
System.out.println("joe.bloggs+123#gmail.com".replaceAll(matchingRegex, ""));
System.out.println("joebloggs+123#gmail.com".replaceAll(matchingRegex, ""));
System.out.println("joe.bloggs#gmail.com".replaceAll(matchingRegex, ""));
System.out.println("joe.bloggs.123#gmail.com".replaceAll(matchingRegex, ""));
System.out.println("joe.bloggs.123+456#gmail.com".replaceAll(matchingRegex, ""));
System.out.println("joebloggs#gmail.com".replaceAll(matchingRegex, ""));
System.out.println("joe.bloggs.123+456.789#gmail.com".replaceAll(matchingRegex, ""));
}
}
Results in,
joebloggs#gmail.com
joebloggs#gmail.com
joebloggs#gmail.com
joebloggs123#gmail.com
joebloggs123#gmail.com
joebloggs#gmail.com
joebloggs123#gmail.com
You could try spliting the string (the email) on the # and running replaceAll on the the first half and then put the strings back together.
Check out: How to split a string in Java
For splitting strings.
Try this regex [.](?=.*#)|(?=\\+)(.*)(?=#). It looks up dots up to # (even if there's text in between), or everything from + up to #. Hope it helps https://regex101.com/r/gyUpta/1
class Main {
public static void main(String[] args) {
String matchingRegex = "[.](?=.*#)|(?=\\+)(.*)(?=#)";
System.out.println("joe.bloggs+123#gmail.com".replaceAll(matchingRegex, ""));
}
}
This will do the trick...
public static void main(String args[]) {
String matchingRegex = "(\\.|(\\+.*(?=#)))";
String email = "joe.bloggs+123#gmail.com";
String user = email.substring(0, email.indexOf("#")+1);
String domain = email.substring(email.indexOf("#")+1);
System.out.println(user.replaceAll(matchingRegex, "") + domain);
}
This is the easiest way I have found to do it.
String address = "joe.bloggs+123#gmail.com";
int at = address.indexOf("#");
address = address.substring(0, at).replaceAll("\\.|\\+.*", "")
+ address.substring(at);
System.out.println(address);
if you try to split for regex sorry i don't remember java this example is in javascript
let string = "joe.bloggs+123#gmail.com"
//firts the function
function splitString(params) {
return params.split(/\+(.)+\#/)
}
//second the concat
let list = splitString(string)
// the first element+the las element
console.log(`${list[0]}${list[list.length -1]}`)
Input string is "ABC\1067546161"
I want to remove "\" backslash and get digits only from the string but we are getting string with ascii value.Result String is ABCF7546161 after print.
Please suggest some solution.
Input String is ABC\1067546161
Expected result is 1067546161
May be something like this
"ABC\1067546161".replaceAll("[a-zA-Z\\]", "")
I think this could work, but the code is ugly as hell..
String word = "ABC\1067546161";
char badChar = word.charAt(3);
String[] arr = word.split(Character.toString(badChar));
System.out.println(Integer.toOctalString(badChar) + arr[1]);
You only mentioned one string in the question, but on several cases, this would most likely not work.
As #TheLostMind pointed out in a comment, you can't replace the backslash directly because the String is created with that value.
The only way to do that is manipulate the input itself and convert it into a byte array instead of a String. Then you can call the String constructor that takes a byte[] as argument and it won't be converted.
Once you have that, you can use a regex to remove the part you don't want as others suggested. Here's the code I've used to test this:
public static void main(String[] args) {
// Input manipulation.
byte[] input = {'A','B','C','\\','1','0','6','7','5','4','6','1','6','1'};
String string = new String(input);
System.out.println(string);
// Splitting.
String[] result = string.split("\\\\");
System.out.println(result[1]);
}
I have string, and I want to replace one of its character with backslash \
I tried the following, but no luck.
engData.replace("'t", "\\'t")
and
engData = engData.replace("'t", String.copyValueOf(new char[]{'\\', 't'}));
INPUT : "can't"
EXPECTED OUTPUT : "can\'t"
Any idea how to do this?
Try this..
String s = "can't";
s = s.replaceAll("'","\\\\'");
System.out.println(s);
out put :
can\'t
This will replace every ' occurences with \' in your string.
Try like this
engData.replace("'", "\\\'");
INPUT : can't
EXPECTED OUTPUT : can\'t
String is immutable in Java. You need to assign back the modified string to itself.
engData = engData.replace("'t", "\\'t"); // assign the modified string back.
This is possible with regex:
engData = engData.replaceAll("('t)","\\\\$1");
The ( and ) specify a group. The 't will match any string containing 't. Finally, the second part replaced such a string with a backslash character: \\\\ (four because this), and the first group: $1. Thus you are replacing any substring 't with \'t
The same thing is possible without regex, what you tried (see this for output):
engData = engData.replace("'t","\\'t"); //note the assignment; Strings are immutable
See String.replace(CharSequence, CharSequence)
For String instances you can use, str.replaceAll() will return a new String with the changes requested:
String str = "./";
String s_modified = s.replaceAll("\\./", "");
The following works for me:
class Foobar {
public static void main(String[] args) {
System.err.println("asd\\'t".replaceAll("\\'t", "\\\'t"));
}
}
I'm having a hard time figuring this one out, so I ask for your help. Here's the deal:
String str = "02-EST-WHATEVER-099-00.dwg";
String newStr = str.replaceAll("([^-_\\.]+-[^-_\\.]+-[^-_\\.]+-[^-_\\.]+-)[^-_\\.]+(\\.[^-_\\.]+)", "$1$2");
The block of code above results in 02-EST-WHATEVER-099-.dwg (removed the last "00", just before the extension). Great, that's what I need!
But the RegEx I use above has to be created on the fly (the field I'm removing can be in a different position). So I used some code to create the RegEx string (here's what the result would look like if I just declared it):
String regexRemoveRev = "([^-_\\.]+-[^-_\\.]+-[^-_\\.]+-[^-_\\.]+-)[^-_\\.]+(\\.[^-_\\.]+)";
Now, if I out.print(regexRemoveRev), I get ([^-_\.]+-[^-_\.]+-[^-_\.]+-[^-_\.]+-)[^-_\.]+(\.[^-_\.]+) (notice the single backslashes).
And when i try the replaceAll again, it doesn't work:
String str = "02-EST-WHATEVER-099-00.dwg";
String newStr = str.replaceAll(regexRemoveRev, "$1$2");
So I thought it could be because of the single backslashes, and I tried declaring regexRemoveRev with 4 of them, instead of just 2:
String regexRemoveRev = "([^-_\\\\.]+-[^-_\\\\.]+-[^-_\\\\.]+-[^-_\\\\.]+-)[^-_\\\\.]+(\\\\.[^-_\\\\.]+)";
The output of out.print(regexRemoveRev) is the double backslash version of the RegEx, as expected:
([^-_\\.]+-[^-_\\.]+-[^-_\\.]+-[^-_\\.]+-)[^-_\\.]+(\\.[^-_\\.]+)
But the replace still doesn't work!
How do I get this to do what I want?
I have just wrote a short program and in both cases it works here it is:
public class StringTest
{
public static void main(String[] args)
{
String str = "02-EST-WHATEVER-099-00.dwg";
String newStr = str.replaceAll("([^-_\\.]+-[^-_\\.]+-[^-_\\.]+-[^-_\\.]+-)[^-_\\.]+(\\.[^-_\\.]+)", "$1$2");
String regexRemoveRev = "([^-_\\.]+-[^-_\\.]+-[^-_\\.]+-[^-_\\.]+-)[^-_\\.]+(\\.[^-_\\.]+)";
String newStr1 = str.replaceAll(regexRemoveRev, "$1$2");
System.out.println("newStr: "+newStr);
System.out.println("regexRemoveRev: "+regexRemoveRev);
System.out.println("newStr: "+newStr1);
}
}
The out put from the above:
newStr: 02-EST-WHATEVER-099-.dwg
regexRemoveRev: ([^-.]+-[^-.]+-[^-.]+-[^-.]+-)[^-.]+(.[^-.]+)
newStr: 02-EST-WHATEVER-099-.dwg
I am not sure why is not working for you!! or is it something else you are asking and I got wrong