Java serialization - java.io.InvalidClassException local class incompatible [duplicate] - java

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java.io.InvalidClassException: local class incompatible:
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Closed 3 years ago.
I've got a public class, which implements Serializable, that is extended by multiple other classes. Only those subclasses were ever serialized before - never the super class.
The super class had defined a serialVersionUID.
I'm not sure if it matters, but it was not marked private, but rather it just had the default protection - you might say it was package protected
static final long serialVersionUID = -7588980448693010399L;
The super class, nor any of the subclasses, however implemented readObject or writeObject, and none of the subclasses had an explicitly defined serialVersionUID. I figured one defined in the superclass would be sufficient.
Despite all this, things were fine as far as reading back previously serialized objects until a new instance variable, a List/ArrayList, along with a new method was added to the super class, and some private instance variables were added to one of its subclasses.
Now when trying to read back previously serialized objects, an exception is being thrown. One similar to this:
com.SomeCompany.SomeSubClass; local class incompatible: stream classdesc serialVersionUID = 1597316331807173261, local class serialVersionUID = -3344057582987646196
I'm assuming this is caused because the default serialVersionUID, which was used because I didn't declare one in any of the subclasses, has now changed due to the changes in the superclass and one subclass.
Suggestions on how to get out of this dilemma would be appreciated. I'm assuming I need to implement readObject and writeObject, but other than invoking defaultReadObject() and defaultWriteObject(), I'm not exactly sure what I need to do. Nor do I know if I need to add serialVerisonUIDs to all of the subclasses or if readObject and writeObject need to be implemented by each subclass, or if I can just implement them once, assuming I need to at all, in the superclass.

#DanielChapman gives a good explanation of serialVersionUID, but no solution. the solution is this: run the serialver program on all your old classes. put these serialVersionUID values in your current versions of the classes. as long as the current classes are serial compatible with the old versions, you should be fine. (note for future code: you should always have a serialVersionUID on all Serializable classes)
if the new versions are not serial compatible, then you need to do some magic with a custom readObject implementation (you would only need a custom writeObject if you were trying to write new class data which would be compatible with old code). generally speaking adding or removing class fields does not make a class serial incompatible. changing the type of existing fields usually will.
Of course, even if the new class is serial compatible, you may still want a custom readObject implementation. you may want this if you want to fill in any new fields which are missing from data saved from old versions of the class (e.g. you have a new List field which you want to initialize to an empty list when loading old class data).

The short answer here is the serial ID is computed via a hash if you don't specify it. (Static members are not inherited--they are static, there's only (1) and it belongs to the class).
http://docs.oracle.com/javase/6/docs/platform/serialization/spec/class.html
The getSerialVersionUID method returns the serialVersionUID of this
class. Refer to Section 4.6, "Stream Unique Identifiers." If not
specified by the class, the value returned is a hash computed from the
class's name, interfaces, methods, and fields using the Secure Hash
Algorithm (SHA) as defined by the National Institute of Standards.
If you alter a class or its hierarchy your hash will be different. This is a good thing. Your objects are different now that they have different members. As such, if you read it back in from its serialized form it is in fact a different object--thus the exception.
The long answer is the serialization is extremely useful, but probably shouldn't be used for persistence unless there's no other way to do it. Its a dangerous path specifically because of what you're experiencing. You should consider a database, XML, a file format and probably a JPA or other persistence structure for a pure Java project.

For me, I forgot to add the default serial id.
private static final long serialVersionUID = 1L;

This worked for me:
If you wrote your Serialized class object into a file, then made some changes to file and compiled it, and then you try to read an object, then this will happen.
So, write the necessary objects to file again if a class is modified and recompiled.
PS: This is NOT a solution; was meant to be a workaround.

Related

How are incompatible classes with same serialVersionUID handled? [duplicate]

I have a class that is serialised. Now I need to add a new variable into the class, with setter and getter methods. This class is sent over wire in RMI.
Without changing the UID, can I add new parameters and getter and setter methods for it? I tried to write an example class that is sent over wire, and did not change the UID, and added new parameters and getter and setter methods for it. On the other end, I tested it and I still got the values properly. I had assumed, if I add new parameters, getter and setter methods, I need to change the UID. Am I wrong?
If you hard-code the SerialVersionUID of a class, (to 1L, usually), store some instances, and then re-define the class, you basically get this behavior (which is more or less common sense):
New fields (present in class definition, not present in the serialized instance) are assigned a default value, which is null for objects, or the same value as an uninitialized field for primitives.
Removed fields (not present in class definition but present in the serialized instance) are simply ignored.
So the general rule of thumb is, if you simply add fields and methods, and don't change any of the existing stuff, AND if you're OK with default values for these new fields, you're generally OK.
Wow, a lot of bad information.
Java serialization is +very+ robust. There are a very well defined set of rules governing backwards compatibility of objects with the same uid and different data. the basic idea is that as long as you don't change the the type of an existing member, you can maintain the same uid without data issues.
that said, your code still needs to be smart about handling classes with potentially missing data. the object may deserialize correctly, but there may not be data in certain fields (e.g. if you added a field to the class and are deserializing an old version of the class). if your code can handle this, than you can probably keep the current uid. if not, then you should probably change it.
in addition to the pre-defined rules, there are advanced usage scenarios where you could even change the type of existing fields and still manage to deserialize the data, but that generally only necessary in extreme situations.
java serialization is very well documented online, you should be able to find all this information in the relevant sun/oracle tutorials/docs.
This only matters if you let Java generate a default UID for your class. It uses the actual members and methods of the class to generate it, thus making it invalid once you change the class structure. If you provide an UID for your class then this only matters if you need to deserialize older versions of your class from a file and such.
Want to define few point to highlight the changes which impacts serialization.
Below you will find the link to Oracle Java Docs for more details.
Incompatible Changes
Incompatible changes to classes are those changes for which the guarantee of interoperability cannot be maintained. The incompatible changes that may occur while evolving a class are:
Deleting fields
Moving classes up or down the hierarchy
Changing a nonstatic field to static or a nontransient field to transient
Changing the declared type of a primitive field
Changing the writeObject or readObject method so that it no longer writes or reads the default field data or changing it so that it attempts to write it or read it when the previous version did not.
Changing a class from Serializable to Externalizable or vice versa.
Changing a class from a non-enum type to an enum type or vice versa.
Removing either Serializable or Externalizable.
Adding the writeReplace or readResolve method to a class, if the behavior would produce an object that is incompatible with any older version of the class.
Link from where the above information is taken
http://docs.oracle.com/javase/7/docs/platform/serialization/spec/version.html#6678

Local class incompatible error when only a method has changed

I just came across "WTF" sort of error: I updated one of my classe's methods and added one method too. After running my program, this is what popped our when program tried to open and unserialize recently saved data (before the methods changes):
java.io.InvalidClassException: cz.autoclient.settings.Settings; local class incompatible: stream classdesc serialVersionUID = 2404650814140543454, local class serialVersionUID = 4256355437298300223
According to what java documentation says about that, java methods are not being serialized. So why does the serialVersionUID take class methods in account too?
Since Java programmers seem to be so mad about using getters and setters literally everywhere, why is it not possible to create getter for serialVersionUID so that I can implement my own algorithm that only calculates the properties?
The serialVersionUID can be overriden, but only with static final long serialVersionUID value which would require me to remember to change it when I change class's properties.
Based on the documentation for java, they recommend to use custom serialVersionUID as much as possible, because the default algorithm will take class implementation details and the result is said to vary from JVM implementation to another.
The default algorithm used by Java to generate the serialVersionUID seems to be considering the non-private methods (step 7) as well. Which explains the exception if you were using the default serialVersionUID in your implementation.
EDIT:
As you suggested, it would be great if we can have our own implementation of a method to do this, rather than overriding the serialVersionUID as a static final long. But I guess they don't allow that because if it were allowed, wrong implementations of such a method could invalidate the whole purpose of the serialVersionUID.
The Oracle docs indicate that if you do not provide a serialVersionUID, the compiler will generate one for you.
If a serializable class does not explicitly declare a serialVersionUID, then the serialization runtime will calculate a default serialVersionUID value for that class based on various aspects of the class, as described in the Java(TM) Object Serialization Specification. However, it is strongly recommended that all serializable classes explicitly declare serialVersionUID values, since the default serialVersionUID computation is highly sensitive to class details that may vary depending on compiler implementations, and can thus result in unexpected InvalidClassExceptions during deserialization. Therefore, to guarantee a consistent serialVersionUID value across different java compiler implementations, a serializable class must declare an explicit serialVersionUID value. It is also strongly advised that explicit serialVersionUID declarations use the private modifier where possible, since such declarations apply only to the immediately declaring class--serialVersionUID fields are not useful as inherited members. Array classes cannot declare an explicit serialVersionUID, so they always have the default computed value, but the requirement for matching serialVersionUID values is waived for array classes.
And according to the Java Object Serialization Specification section 5.1
Versioning raises some fundamental questions about the identity of a class, including what constitutes a compatible change. A compatible change is a change that does not affect the contract between the class and its callers.
What's happening here is that the compiler has decided the difference between the two versions of your code warrant a new serialVersionUID. If you feel that the state contained in an instance of Object(1) and Object(2) are interchangeable, you should manage this by setting the serialVersionUID manually and keeping it the same between those changes.
Yes, you will have to manually manage this, and change it when you make changes to the mechanisms which manage the internal state of the class.
As a note though, if the public methods have changed, you should consider if the original version of the class meets the same expectations as the new version. If you would like the data contained in the previously-serialized state to be loaded into a new version of the class, perhaps use a static constructor method to initialize the new version (new behavior) with the compatible, old state.

Serialization - Manually defining a SerialVersionUID required? [duplicate]

This question already has answers here:
What is a serialVersionUID and why should I use it?
(25 answers)
Closed 8 years ago.
I'm currently trying to justify the removal of the rule in findbugs/sonar that classifies making a class serializable, or in most of our cases, extending our base class that makes the classes serializable without the dev realising, then not defining a SerialVersionUID a critical error!
This of course makes our muggle management (read management that are not developers) panic, thinking we have critical bugs that must be fixed!
My argument is that in the current versions of Java, you do not need to provide a SerialVersionUID as the JVM will do that for you in cases where you serialize a class, but can anybody point any reasons why in todays day and age we should still provide a UID ourselves rather than leave it to the JVM? Looking on the web, the only reasoning I can really find for providing a UID nowadays is that not doing it is 'bad practice'.
Any ideas?
SerialVersionUID is used to check whether the version of class used for serializing and de-serializing is same or not across different JVM's.The default value generated by Serializable Runtime is sensitive to class details.So,although the classes loaded across different JVM may be compatible,but still you can get a false InvalidClassException .
Check the Javadoc:-
The serialization runtime associates with each serializable class a version number, called a serialVersionUID, which is used during deserialization to verify that the sender and receiver of a serialized object have loaded classes for that object that are compatible with respect to serialization. If the receiver has loaded a class for the object that has a different serialVersionUID than that of the corresponding sender's class, then deserialization will result in an InvalidClassException. A serializable class can declare its own serialVersionUID explicitly by declaring a field named "serialVersionUID" that must be static, final, and of type long:
*ANY-ACCESS-MODIFIER static final long serialVersionUID = 42L;
If a serializable class does not explicitly declare a serialVersionUID, then the serialization runtime will calculate a default serialVersionUID value for that class based on various aspects of the class, as described in the Java(TM) Object Serialization Specification. However, it is strongly recommended that all serializable classes explicitly declare serialVersionUID values, since the default serialVersionUID computation is highly sensitive to class details that may vary depending on compiler implementations, and can thus result in unexpected InvalidClassExceptions during deserialization. Therefore, to guarantee a consistent serialVersionUID value across different java compiler implementations, a serializable class must declare an explicit serialVersionUID value. It is also strongly advised that explicit serialVersionUID declarations use the private modifier where possible, since such declarations apply only to the immediately declaring class--serialVersionUID fields are not useful as inherited members. Array classes cannot declare an explicit serialVersionUID, so they always have the default computed value, but the requirement for matching serialVersionUID values is waived for array classes.*
I wanted to extend my comment but ran out of room.
nb These aren't my original thoughts, but rather from Joshua Bloch's Effective Java
Reason 1: Serialized objects can persist
Even small, otherwise trivial changes to the class will cause the JVM to generate a different ID. So when you try to deserialize an object serialized with an older but otherwise compatible class structure, the result is an InvalidClassException.
Changing something as innocuous as adding a convenience accessor to a class will force a different UID to be computed. Similarly, one of the things that influence the generated UID are private members. So not only are you restricted from changing the public facing API (which may be preferable), but you're also restricted from changing too drastically any private implementation details, for risk of causing a UID mismatch.
The other way to look at this is that by manually defining an UID, while you can ensure that the JVM will attempt to deserialize an object with its intended class, regardless of the changes to your class, you can also prevent the JVM from attempting to deserialize an object with its intended class (eg your new class is incompatible) by changing this UID.
Reason 2: Runtime computation is more expensive
Computed UIDs are computed at runtime. Manually specifying this field obviates this computation.
The central purpose of defining serialVersionUID is to control serialization compatibility. As other answers and the documentation has noted, unless a specific value is declared, the value is computed from a variety of class characteristics, even ones that don't actually affect the serialized form, such as the signatures of public methods. If you don't provide a serialVersionUID, and one or more of these characteristics of the class differs between serialization and deserialization, an InvalidClassException will be thrown.
Now to the question of when one should or should not declare a serialVersionUID.
If you care about serialization compatibility, you should almost always declare a serialVersionUID. Doing this is the only possible way to evolve the class and have the serialized form be compatible with other versions of the class. You will probably also have to provide custom readObject and writeObject methods and use various mechanisms like readFields, putFields, and serialPersistentFields to control the serialized format, and to cope with potential changes to the serialized format.
By "care about serialization compatibility", suppose you've serialized an object and have stored it in a file or database. Do you expect to have future versions of your system (with evolved versions of the classes) be able to read the stored serialized objects? Or, suppose you serialize objects and send them over a network to other applications that deserialize them. This happens in RMI, or it could happen if you develop your own network protocol that sends and receive serialized objects. If so, then on your network, can you have different versions of your application running in different places on the network, and do you expect them to be able to talk to each other successfully?
If any of the above are true, you care about serialization compatibility, and you need to declare serialVersionUID.
There are times when you might care about serialization compatibility but when it doesn't make sense to declare a serialVersionUID. One example is with anonymous inner classes. Such a class can be made serializable, but it's impractical to try to make it compatible, for several reasons. Anonymous inner classes have compiler-generated names that are implementation specific. They can also change across recompiles. AICs also contain references to their enclosing instance and references to any objects that might be captured from the local scope. All of these objects, and their transitive closure, become part of the serial form of an AIC. For these reasons it's a bad idea to serialize AICs, let alone try to achieve serial compatibility for them. In such cases, adding a serialVersionUID is just a distraction. If you are tempted to serialize AICs, you probably want to restructure the code to serialize something else instead.
There might be times when you don't care about serialization compatibility of different class versions at all.
One example is if you have a closely coupled set of JVMs that are all sharing classes from the same classpath, and they're exchanging serialized objects. Since they are using the same actual classes, there can't be any incompatibility. Declaring a serialVersionUID for classes in this case is useless busywork. In fact, doing so may conceal errors. In such a multi-JVM scheme, if there is a serialization compatibility error, that indicates some kind of configuration problem, since it means the JVMs are using different classes. You'd want that to be detected as soon as possible, and not declaring serialVersionUID would cause an error to be manifested more quickly.
Another reason is that Serializable is inherited, which may cause classes down the inheritance tree to become Serializable even if they are never intended to be serialized. Again, declaring serialVersionUID for such classes is useless busywork. There's no formal way for a class to reject its inheritance and "undeclare" serializability. Best practice, though, is for such classes to implement readObject and writeObject and for them to unconditionally throw an exception like InvalidObjectException or NotSerializableException.
Still another example is that your product requirements (or whatever) might simply decide not to care about serialization compatibility in certain cases or not at all. It's something that you might decide is just "not supported." The JDK itself has taken this approach. In general, most public, serializable classes in the JDK are constrained to be forward and backward serialization compatible. As such, all of these classes declare a serialVersionUID and take care to deal with missing or added fields. However, some portions of the JDK, most notably AWT and Swing, are explicitly not serialization compatible across releases. Such classes have a disclaimer that warns of serial incompatibility, and instead of declaring a serialVersionUID, these classes include an annotation #SuppressWarnings("serial") to eliminate the warnings.
Bottom line is that it's a mistake to slavishly declare serialVersionUID in every class that happens to inherit Serializable. There are good reasons to declare it, and there are also good reasons not to declare it. You should decide explicitly.

What is a serial version UID used for? [duplicate]

This question already has answers here:
What is a serialVersionUID and why should I use it?
(25 answers)
Closed 9 years ago.
I'm creating a Java application, and when creating an interface to use with an ADT, it finds the need to initialize a random number as an ID number.
public class StackFullException extends RuntimeException {
private static final long serialVersionUID = 1L;
public StackFullException(){}
public StackFullException(String message) {
super(message);
}
}
I'm curious as to whether leaving this out will impact anything consequential about my program and if so, how to avoid it.
The serialVersionUID is part of the black magic of the Java serialization API.
It is used to uniquely identify a version of the class so that when a class is de-serialized the version can be checked against the version of the class loaded by the ClassLoader.
The serialization API will generate a serialVersionUID itself if none is specified but this is then subject to random change by inconsequential changes (or at least ones that don't break serialization compatibility).
Adding the field yourself gives you control over this process - you decide when a change to the class should break de-serialization of older versions.
More information can be found in the JavaDocs for Serializable.
In short, if you plan to serialize this class and then de-serialize it later - but after making some changes to code and recompiling etc - this field is more-or-less essential to guarantee that this will work as intended.
The Serializable interface gives enough detail in this regard:
The serialization runtime associates with each serializable class a
version number, called a serialVersionUID, which is used during
deserialization to verify that the sender and receiver of a serialized
object have loaded classes for that object that are compatible with
respect to serialization. If the receiver has loaded a class for the
object that has a different serialVersionUID than that of the
corresponding sender's class, then deserialization will result in an
InvalidClassException. A serializable class can declare its own
serialVersionUID explicitly by declaring a field named
"serialVersionUID" that must be static, final, and of type long:
ANY-ACCESS-MODIFIER static final long serialVersionUID = 42L;
If a serializable class does not explicitly declare a serialVersionUID,
then the serialization runtime will calculate a default
serialVersionUID value for that class based on various aspects of the
class, as described in the Java(TM) Object Serialization
Specification. However, it is strongly recommended that all
serializable classes explicitly declare serialVersionUID values, since
the default serialVersionUID computation is highly sensitive to class
details that may vary depending on compiler implementations, and can
thus result in unexpected InvalidClassExceptions during
deserialization. Therefore, to guarantee a consistent serialVersionUID
value across different java compiler implementations, a serializable
class must declare an explicit serialVersionUID value.
Also you can read more about this in Java Object Serialization Specification
searialVersionUID is just a version number you place on the interface to know it's communicating with the same API. In other words, if the client's Java Object is "1L" and the server's is "2L" then it will throw a missmatch error.
UIDs in this context can also be used to distinguish between two objects being written to disk.
Source: http://www.mkyong.com/java-best-practices/understand-the-serialversionuid/
As others have said, the UID is optional and shouldn't impact your program.
It's used to reflect structural changes to the class when used with the JDK's serialization. It's completely optional to use. Personally, I never create such fields and often delete them when I find them.

How to fix Invalid Class Exception [duplicate]

Eclipse issues warnings when a serialVersionUID is missing.
The serializable class Foo does not declare a static final
serialVersionUID field of type long
What is serialVersionUID and why is it important? Please show an example where missing serialVersionUID will cause a problem.
The docs for java.io.Serializable are probably about as good an explanation as you'll get:
The serialization runtime associates with each serializable class a version number, called a serialVersionUID, which is used during deserialization to verify that the sender and receiver of a serialized object have loaded classes for that object that are compatible with respect to serialization. If the receiver has loaded a class for the object that has a different serialVersionUID than that of the corresponding sender's class, then deserialization will result in an
InvalidClassException. A serializable class can declare its own serialVersionUID explicitly by declaring a field named serialVersionUID that must be static, final, and of type long:
ANY-ACCESS-MODIFIER static final long serialVersionUID = 42L;
If a serializable class does not explicitly declare a serialVersionUID, then the serialization runtime will calculate a default serialVersionUID value for that class based on various aspects of the class, as described in the Java(TM) Object Serialization Specification. However, it is strongly recommended that all serializable classes explicitly declare serialVersionUID values, since the default serialVersionUID computation is highly sensitive to class details that may vary depending on compiler implementations, and can thus result in unexpected InvalidClassExceptions during deserialization. Therefore, to guarantee a consistent serialVersionUID value across different java compiler implementations, a serializable class must declare an explicit serialVersionUID value. It is also strongly advised that explicit serialVersionUID declarations use the private modifier where possible, since such declarations apply only to the immediately declaring class — serialVersionUID fields are not useful as inherited members.
If you're serializing just because you have to serialize for the implementation's sake (who cares if you serialize for an HTTPSession, for instance...if it's stored or not, you probably don't care about de-serializing a form object), then you can ignore this.
If you're actually using serialization, it only matters if you plan on storing and retrieving objects using serialization directly. The serialVersionUID represents your class version, and you should increment it if the current version of your class is not backwards compatible with its previous version.
Most of the time, you will probably not use serialization directly. If this is the case, generate a default SerialVersionUID by clicking the quick fix option and don't worry about it.
I can't pass up this opportunity to plug Josh Bloch's book Effective Java (2nd Edition). Chapter 10 is an indispensible resource on Java serialization.
Per Josh, the automatically-generated UID is generated based on a class name, implemented interfaces, and all public and protected members. Changing any of these in any way will change the serialVersionUID. So you don't need to mess with them only if you are certain that no more than one version of the class will ever be serialized (either across processes or retrieved from storage at a later time).
If you ignore them for now, and find later that you need to change the class in some way but maintain compatibility w/ old version of the class, you can use the JDK tool serialver to generate the serialVersionUID on the old class, and explicitly set that on the new class. (Depending on your changes you may need to also implement custom serialization by adding writeObject and readObject methods - see Serializable javadoc or aforementioned chapter 10.)
You can tell Eclipse to ignore these serialVersionUID warnings:
Window > Preferences > Java > Compiler > Errors / Warnings > Potential Programming Problems
In case you didn't know, there are a lot of other warnings you can enable in this section (or even have some reported as errors), many are very useful:
Potential Programming Problems: Possible accidental boolean assignment
Potential Programming Problems: Null pointer access
Unnecessary code: Local variable is never read
Unnecessary code: Redundant null check
Unnecessary code: Unnecessary cast or 'instanceof'
and many more.
serialVersionUID facilitates versioning of serialized data. Its value is stored with the data when serializing. When de-serializing, the same version is checked to see how the serialized data matches the current code.
If you want to version your data, you normally start with a serialVersionUID of 0, and bump it with every structural change to your class which alters the serialized data (adding or removing non-transient fields).
The built-in de-serialization mechanism (in.defaultReadObject()) will refuse to de-serialize from old versions of the data. But if you want to you can define your own readObject()-function which can read back old data. This custom code can then check the serialVersionUID in order to know which version the data is in and decide how to de-serialize it. This versioning technique is useful if you store serialized data which survives several versions of your code.
But storing serialized data for such a long time span is not very common. It is far more common to use the serialization mechanism to temporarily write data to for instance a cache or send it over the network to another program with the same version of the relevant parts of the codebase.
In this case you are not interested in maintaining backwards compatibility. You are only concerned with making sure that the code bases which are communicating indeed have the same versions of relevant classes. In order to facilitate such a check, you must maintain the serialVersionUID just like before and not forget to update it when making changes to your classes.
If you do forget to update the field, you might end up with two different versions of a class with different structure but with the same serialVersionUID. If this happens, the default mechanism (in.defaultReadObject()) will not detect any difference, and try to de-serialize incompatible data. Now you might end up with a cryptic runtime error or silent failure (null fields). These types of errors might be hard to find.
So to help this usecase, the Java platform offers you a choice of not setting the serialVersionUID manually. Instead, a hash of the class structure will be generated at compile-time and used as id. This mechanism will make sure that you never have different class structures with the same id, and so you will not get these hard-to-trace runtime serialization failures mentioned above.
But there is a backside to the auto-generated id strategy. Namely that the generated ids for the same class might differ between compilers (as mentioned by Jon Skeet above). So if you communicate serialized data between code compiled with different compilers, it is recommended to maintain the ids manually anyway.
And if you are backwards-compatible with your data like in the first use case mentioned, you also probably want to maintain the id yourself. This in order to get readable ids and have greater control over when and how they change.
What is a serialVersionUID and why should I use it?
SerialVersionUID is a unique identifier for each class, JVM uses it to compare the versions of the class ensuring that the same class was used during Serialization is loaded during Deserialization.
Specifying one gives more control, though JVM does generate one if you don't specify. The value generated can differ between different compilers. Furthermore, sometimes you just want for some reason to forbid deserialization of old serialized objects [backward incompatibility], and in this case you just have to change the serialVersionUID.
The javadocs for Serializable say:
the default serialVersionUID computation is highly sensitive to class
details that may vary depending on compiler implementations, and can
thus result in unexpected InvalidClassExceptions during
deserialization.
Therefore, you must declare serialVersionUID because it give us more control.
This article has some good points on the topic.
Original question has asked for 'why is it important' and 'example' where this Serial Version ID would be useful. Well I have found one.
Say you create a Car class, instantiate it, and write it out to an object stream. The flattened car object sits in the file system for some time. Meanwhile, if the Car class is modified by adding a new field. Later on, when you try to read (i.e. deserialize) the flattened Car object, you get the java.io.InvalidClassException – because all serializable classes are automatically given a unique identifier. This exception is thrown when the identifier of the class is not equal to the identifier of the flattened object. If you really think about it, the exception is thrown because of the addition of the new field. You can avoid this exception being thrown by controlling the versioning yourself by declaring an explicit serialVersionUID. There is also a small performance benefit in explicitly declaring your serialVersionUID (because does not have to be calculated). So, it is best practice to add your own serialVersionUID to your Serializable classes as soon as you create them as shown below:
public class Car {
static final long serialVersionUID = 1L; //assign a long value
}
First I need to explain what serialization is.
Serialization allows to convert an object to a stream, for sending that object over the network OR Save to file OR save into DB for letter usage.
There are some rules for serialization.
An object is serializable only if its class or its superclass implements the Serializable interface
An object is serializable (itself implements the Serializable interface) even if its superclass is not. However, the first superclass in the hierarchy of the serializable class, that does not implements Serializable interface, MUST have a no-arg constructor. If this is violated, readObject() will produce a java.io.InvalidClassException in runtime
All primitive types are serializable.
Transient fields (with transient modifier) are NOT serialized, (i.e., not saved or restored). A class that implements Serializable must mark transient fields of classes that do not support serialization (e.g., a file stream).
Static fields (with static modifier) are not serialized.
When Object is serialized, Java Runtime associates the serial version number aka, the serialVersionID.
Where we need serialVersionID:
During the deserialization to verify that sender and receiver are compatible with respect to serialization. If the receiver loaded the class with a different serialVersionID then deserialization will end with InvalidClassCastException.
A serializable class can declare its own serialVersionUID explicitly by declaring a field named serialVersionUID that must be static, final, and of type long.
Let's try this with an example.
import java.io.Serializable;
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
private String empname;
private byte empage;
public String getEmpName() {
return name;
}
public void setEmpName(String empname) {
this.empname = empname;
}
public byte getEmpAge() {
return empage;
}
public void setEmpAge(byte empage) {
this.empage = empage;
}
public String whoIsThis() {
return getEmpName() + " is " + getEmpAge() + "years old";
}
}
Create Serialize Object
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectOutputStream;
public class Writer {
public static void main(String[] args) throws IOException {
Employee employee = new Employee();
employee.setEmpName("Jagdish");
employee.setEmpAge((byte) 30);
FileOutputStream fout = new
FileOutputStream("/users/Jagdish.vala/employee.obj");
ObjectOutputStream oos = new ObjectOutputStream(fout);
oos.writeObject(employee);
oos.close();
System.out.println("Process complete");
}
}
Deserialize the object
import java.io.FileInputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
public class Reader {
public static void main(String[] args) throws ClassNotFoundException, IOException {
Employee employee = new Employee();
FileInputStream fin = new FileInputStream("/users/Jagdish.vala/employee.obj");
ObjectInputStream ois = new ObjectInputStream(fin);
employee = (Employee) ois.readObject();
ois.close();
System.out.println(employee.whoIsThis());
}
}
NOTE: Now change the serialVersionUID of the Employee class and save:
private static final long serialVersionUID = 4L;
And execute the Reader class. Not to execute the Writer class and you will get the exception.
Exception in thread "main" java.io.InvalidClassException:
com.jagdish.vala.java.serialVersion.Employee; local class incompatible:
stream classdesc serialVersionUID = 1, local class serialVersionUID = 4
at java.io.ObjectStreamClass.initNonProxy(ObjectStreamClass.java:616)
at java.io.ObjectInputStream.readNonProxyDesc(ObjectInputStream.java:1623)
at java.io.ObjectInputStream.readClassDesc(ObjectInputStream.java:1518)
at java.io.ObjectInputStream.readOrdinaryObject(ObjectInputStream.java:1774)
at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1351)
at java.io.ObjectInputStream.readObject(ObjectInputStream.java:371)
at com.krishantha.sample.java.serialVersion.Reader.main(Reader.java:14)
If you will never need to serialize your objects to byte array and send/store them, then you don't need to worry about it. If you do, then you must consider your serialVersionUID since the deserializer of the object will match it to the version of object its classloader has. Read more about it in the Java Language Specification.
If you get this warning on a class you don't ever think about serializing, and that you didn't declare yourself implements Serializable, it is often because you inherited from a superclass, which implements Serializable. Often then it would be better to delegate to such a object instead of using inheritance.
So, instead of
public class MyExample extends ArrayList<String> {
public MyExample() {
super();
}
...
}
do
public class MyExample {
private List<String> myList;
public MyExample() {
this.myList = new ArrayList<String>();
}
...
}
and in the relevant methods call myList.foo() instead of this.foo() (or super.foo()). (This does not fit in all cases, but still quite often.)
I often see people extending JFrame or such, when they really only need to delegate to this. (This also helps for auto-completing in a IDE, since JFrame has hundreds of methods, which you don't need when you want to call your custom ones on your class.)
One case where the warning (or the serialVersionUID) is unavoidable is when you extend from AbstractAction, normally in a anonymous class, only adding the actionPerformed-method. I think there shouldn't be a warning in this case (since you normally can't reliable serialize and deserialize such anonymous classes anyway accross different versions of your class), but I'm not sure how the compiler could recognize this.
To understand the significance of field serialVersionUID, one should understand how Serialization/Deserialization works.
When a Serializable class object is serialized Java Runtime associates a serial version no.(called as serialVersionUID) with this serialized object. At the time when you deserialize this serialized object Java Runtime matches the serialVersionUID of serialized object with the serialVersionUID of the class. If both are equal then only it proceeds with the further process of deserialization else throws InvalidClassException.
So we conclude that to make Serialization/Deserialization process successful the serialVersionUID of serialized object must be equivalent to the serialVersionUID of the class. In case if programmer specifies the serialVersionUID value explicitly in the program then the same value will be associated with the serialized object and the class, irrespective of the serialization and deserialzation platform(for ex. serialization might be done on platform like windows by using sun or MS JVM and Deserialization might be on different platform Linux using Zing JVM).
But in case if serialVersionUID is not specified by programmer then while doing Serialization\DeSerialization of any object, Java runtime uses its own algorithm to calculate it. This serialVersionUID calculation algorithm varies from one JRE to another. It is also possible that the environment where the object is serialized is using one JRE (ex: SUN JVM) and the environment where deserialzation happens is using Linux Jvm(zing). In such cases serialVersionUID associated with serialized object will be different than the serialVersionUID of class calculated at deserialzation environment. In turn deserialization will not be successful. So to avoid such situations/issues programmer must always specify serialVersionUID of Serializable class.
As for an example where the missing serialVersionUID might cause a problem:
I'm working on this Java EE application that is composed of a Web module that uses an EJB module. The web module calls the EJB module remotely and passes a POJO that implements Serializable as an argument.
This POJO's class was packaged inside the EJB jar and inside it's own jar in the WEB-INF/lib of the web module. They're actually the same class, but when I package the EJB module I unpack this POJO's jar to pack it together with the EJB module.
The call to the EJB was failing with the Exception below because I hadn't declared its serialVersionUID:
Caused by: java.io.IOException: Mismatched serialization UIDs : Source
(Rep.
IDRMI:com.hordine.pedra.softbudget.domain.Budget:5CF7CE11E6810A36:04A3FEBED5DA4588)
= 04A3FEBED5DA4588 whereas Target (Rep. ID RMI:com.hordine.pedra.softbudget.domain.Budget:7AF5ED7A7CFDFF31:6227F23FA74A9A52)
= 6227F23FA74A9A52
Don't bother, the default calculation is really good and suffice for 99,9999% of the cases. And if you run into problems, you can - as already stated - introduce UID's as the need arrise (which is highly unlikely)
I generally use serialVersionUID in one context: When I know it will be leaving the context of the Java VM.
I would know this when I to use ObjectInputStream and ObjectOutputStream for my application or if I know a library/framework I use will use it. The serialVersionID ensures different Java VMs of varying versions or vendors will inter-operate correctly or if it is stored and retrieved outside the VM for example HttpSession the session data can remain even during a restart and upgrade of the application server.
For all other cases, I use
#SuppressWarnings("serial")
since most of the time the default serialVersionUID is sufficient. This includes Exception, HttpServlet.
Field data represents some information stored in the class.
Class implements the Serializable interface,
so eclipse automatically offered to declare the serialVersionUID field. Lets start with value 1 set there.
If you don't want that warning to come, use this:
#SuppressWarnings("serial")
Why use SerialVersionUID inside Serializable class in Java?
During serialization, Java runtime creates a version number for a class, so that it can de-serialize it later. This version number is known as SerialVersionUID in Java.
SerialVersionUID is used to version serialized data. You can only de-serialize a class if it's SerialVersionUID matches with the serialized instance. When we don't declare SerialVersionUID in our class, Java runtime generates it for us but its not recommended. It's recommended to declare SerialVersionUID as private static final long variable to avoid default mechanism.
When you declare a class as Serializable by implementing marker interface java.io.Serializable, Java runtime persist instance of that class into disk by using default Serialization mechanism, provided you have not customized the process using Externalizable interface.
see also Why use SerialVersionUID inside Serializable class in Java
SerialVersionUID is used for version control of object. you can specify serialVersionUID in your class file also. Consequence of not specifying serialVersionUID is that when you add or modify any field in class then already serialized class will not be able to recover because serialVersionUID generated for new class and for old serialized object will be different. Java serialization process relies on correct serialVersionUID for recovering state of serialized object and throws java.io.InvalidClassException in case of serialVersionUID mismatch
Read more: http://javarevisited.blogspot.com/2011/04/top-10-java-serialization-interview.html#ixzz3VQxnpOPZ
It would be nice if CheckStyle could verify that the serialVersionUID on a class that implements Serializable has a good value, i.e. that it matches what the serial version id generator would produce. If you have a project with lots of serializable DTOs, for example, remembering to delete the existing serialVersionUID and regenerate it is a pain, and currently the only way (that I know of) to verify this is to regenerate for each class and compare to the old one. This is very very painful.
If you want to amend a huge number of classes which had no serialVersionUID set in the first place while maintain the compatibility with the old classes, tools like IntelliJ Idea, Eclipse fall short as they generate random numbers and does not work on a bunch of files in one go. I come up the following bash script(I'm sorry for Windows users, consider buy a Mac or convert to Linux) to make amending serialVersionUID issue with ease:
base_dir=$(pwd)
src_dir=$base_dir/src/main/java
ic_api_cp=$base_dir/target/classes
while read f
do
clazz=${f//\//.}
clazz=${clazz/%.java/}
seruidstr=$(serialver -classpath $ic_api_cp $clazz | cut -d ':' -f 2 | sed -e 's/^\s\+//')
perl -ni.bak -e "print $_; printf qq{%s\n}, q{ private $seruidstr} if /public class/" $src_dir/$f
done
you save the this script, say add_serialVersionUID.sh to you ~/bin. Then you run it in the root directory of your Maven or Gradle project like:
add_serialVersionUID.sh < myJavaToAmend.lst
This .lst includes the list of java files to add the serialVersionUID in the following format:
com/abc/ic/api/model/domain/item/BizOrderTransDO.java
com/abc/ic/api/model/domain/item/CardPassFeature.java
com/abc/ic/api/model/domain/item/CategoryFeature.java
com/abc/ic/api/model/domain/item/GoodsFeature.java
com/abc/ic/api/model/domain/item/ItemFeature.java
com/abc/ic/api/model/domain/item/ItemPicUrls.java
com/abc/ic/api/model/domain/item/ItemSkuDO.java
com/abc/ic/api/model/domain/serve/ServeCategoryFeature.java
com/abc/ic/api/model/domain/serve/ServeFeature.java
com/abc/ic/api/model/param/depot/DepotItemDTO.java
com/abc/ic/api/model/param/depot/DepotItemQueryDTO.java
com/abc/ic/api/model/param/depot/InDepotDTO.java
com/abc/ic/api/model/param/depot/OutDepotDTO.java
This script uses the JDK serialVer tool under hood. So make sure your $JAVA_HOME/bin is in the PATH.
This question is very well documented in Effective Java by Joshua Bloch. A very good book and a must read. I will outline some of the reasons below :
The serialization runtime comes up with a number called Serial version for each serializable class. This number is called serialVersionUID. Now there is some Math behind this number and it comes out based on the fields/methods that are defined in the class. For the same class the same version is generated every time. This number is used during deserialization to verify that the sender and receiver of a serialized object have loaded classes for that object that are compatible with respect to serialization. If the receiver has loaded a class for the object that has a different serialVersionUID than that of the corresponding sender's class, then deserialization will result in an InvalidClassException.
If the class is serializable you can also declare your own serialVersionUID explicitly by declaring a field named "serialVersionUID" that must be static, final, and of type long. Most IDE's like Eclipse help you generate that long string.
Each time an object is serialized the object is stamped with a version ID number for the object's class.This ID is called serialVersionUID and it is computed based on information about the class structure. Suppose you made an Employee class and it has version id #333 (assigned by JVM),Now when you will serialize the object of that class (Suppose Employee object), JVM will assign UID to it as #333.
Consider a situation - in the future you need to edit or change your class and in that case when you modify it, JVM will assign it a new UID (Suppose #444).
Now when you try to deserialize the employee object, JVM will compare serialized object's (Employee object) version ID(#333) with that of the class i.e #444(Since it was changed). On comparison JVM will find both version UID are different and hence Deserialization will fail.
Hence if serialVersionID for each class is defined by programmer itself. It will be same even if the class is evolved in future and hence JVM will always find that class is compatible with serialized object even though the class is changed. For more Info you can refer chapter 14 of HEAD FIRST JAVA.
A Simple Explanation:
Are you serializing data?
Serialization is basically writing class data to a file/stream/etc. De-serialization is reading that data back to a class.
Do you intend to go into production?
If you are just testing something with unimportant/fake data, then don't worry about it (unless you are testing serialization directly).
Is this the first version?
If so, set serialVersionUID=1L.
Is this the second, third, etc. prod version?
Now you need to worry about serialVersionUID, and should look into it in depth.
Basically, if you don't update the version correctly when you update a class you need to write/read, you will get an error when you try to read old data.
To tell the long story short this field is used to check if serialized data can be deserialized correctly. Serialization and deserialization are often made by different copies of program - for example server converts object to string and client converts received string to object. This field tells that both operates with same idea about what this object is. This field helps when:
you have many different copies of your program in different places (like 1 server and 100 clients). If you will change your object, alter your version number and forget to update one this clients, it will know that he is not capable of deserialization
you have stored your data in some file and later on you try to open it with updated version of your program with modified object - you will know that this file is not compatible if you keep your version right
When is it important?
Most obvious - if you add some fields to your object, older versions will not be able to use them because they do not have these fields in their object structure.
Less obvious - When you deserialize object, fields that where not present in string will be kept as NULL. If you have removed field from your object, older versions will keep this field as allways-NULL that can lead to misbehavior if older versions rely on data in this field (anyway you have created it for something, not just for fun :-) )
Least obvious - Sometimes you change the idea you put in some field's meaning. For example when you are 12 years old you mean "bicycle" under "bike", but when you are 18 you mean "motorcycle" - if your friends will invite you to "bike ride across city" and you will be the only one who came on bicycle, you will undestand how important it is to keep same meaning across fields :-)
'serialVersionUID' is a 64 bit number used to uniquely identify a class during deserialization process. When you serialize an object, serialVersionUID of the class also written to the file. Whenever you deserialize this object, java run time extract this serialVersionUID value from the serialized data and compare the same value associate with the class. If both do not match, then 'java.io.InvalidClassException' will be thrown.
If a serializable class do not explicitly declare a serialVersionUID, then serialization runtime will calculate serialVersionUID value for that class based on various aspects of the class like fields, methods etc.,, You can refer this link for demo application.
Firstly to answer your question, when we don't declare SerialVersionUID in our class, Java runtime generates it for us, but that process is sensitive to many class meta data including number of fields, type of fields, access modifier of fields, interface implemented by class etc. Therefore it is recommended to declare it ourselves and Eclipse is warning you about the same.
Serialization:
We often work with important objects whose state (data in the variables of the object) is so important that we can not risk to lose it due to power/system failures (or) network failures in case of sending the object state to other machine. The solution for this problem is named "Persistence" which simply means persisting (holding/saving) the data. Serialization is one of many other ways to achieve persistence (by saving data to disk/memory). When saving the state of the object, it is important to create an identity for the object, to be able to properly read it back (de-serialization). This unique identification is ID is SerialVersionUID.

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