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How to include resource folder in executable .jar file in eclipse?

I need to create an application for sorting various types of polygons using various parameters such as height, volume or base area. Arguments for Filename which has parameters for polygons, Sort type, Sort method will be pass through command line.That file is in my resource folder outside my src folder in a project. I have implemented all programs, It works fine when I run using pass arguments through eclipse run configuration. But when I try to run my .jar file using cmd same arguments it gives me FileNotFoundException.
I opened my jar file using 7zip and noticed it never extracted my resource folder in .jar file. I searched online and tried including my resource folder in to build path of eclipse. But still does't work.

Follow these steps:
1) click project -> properties -> Build Path -> Source -> Add Folder and select resources folder.
2) create your JAR!
EDIT: you can make sure your JAR contains folder by inspecting it using 7zip.
Reefer this link as well How do I add a resources folder to my Java project in Eclipse

First, you need to create a source folder for resources, for instance name it res, and then move your image folder to res. When you generate the jar file, you will see the image folder, not the res folder or files separately.

This comes down to how you are generating the JAR file.
When you're exporting the jar in eclipse make sure to checkbox the button that says "Export java sources and resources" https://www.cs.utexas.edu/~scottm/cs307/handouts/Eclipse%20Help/ensureJavaFiles.jpg
There are a lot of ways to do this one is to use Gradle is the recommended way, something like this will work Creating runnable JAR with Gradle

Exporting processing to a jar file

I've been working on a processing application using ControlP5 and Twitter4j. I want to have my project run from a single jar file from any operating system. Basically I want to package up my application. My application uses images. I've been browsing for more than an hour, but I cant find how to do this. Any suggestions?
using
processing 2
twitter4j3
Thanks in advance!

I dont know if you can directly do it from the Processing IDE however, if export your sketch to a Java applet then locate the .java the the sketch folder you can use this in conjunction with Eclipse to export to a jar file.

So, I know that this post is very old but if you are still looking for a solution, or to other people that see this thread, it's relatively simple.
Export the project
In the folder with the exported project (something like application.windows64), navigate to lib and find core.jar and project name.jar (you need to have file name extensions visible)
Rename the files to .zip files
Extract core.jar to whatever folder
Extract project name.jar into the same folder (make sure you don't do it into a subfolder)
Click yes if it asks if it wants you to replace a file (if it doesn't you extracted the files incorrectly)
Delete core.jar and project name.jar
If the project uses images, move them into the same folder as all the other files
Select all of the files in the folder, right click, hover over send to and select compressed (zipped) folder
Rename the .zip file to name of project.jar

This might be old, but i still find other posts about it on processing forums.
This is the best way to run processing project as a jar file.
When exporting application, you will always end up with a lib folder inside exported application(whether for Linux and Windows). For windows, open command prompt(or power shell), you can use right-click+shift and then click on open power shell here.
After that you can run the following command.
java -classpath lib\* DisplayDepthStream
Now DisplayDepthStream is the name of sketch file.
To explain the command, -classpath lib\* tells java to add everything under lib directory to the class path. And DisplayDepthStream is the name of my main class.
Hope this helps~!
Chears

Trouble making executable jar

When I try to make an executable jar in netbeans I get this error
C:\lwjgl\lwjgl-2.8.5\res is a directory or can't be read. Not copying the libraries. Not copying the libraries.The res folder holds files like jpgs and wavs that the program relies on to function. I'm using lwjgl, would that be part of the problem? What could be causing this?

try this
Right click on your project folder and click on >>>>clean and
build<<<<
right click on your project folder click on >>>Properties<<<< you
should see the location of your project folder normally this should
be in your documents folder under NetbeansProject folder. locate
your project name folder inside is a folder called >>>dist<<< in
there you should find your project name with a small java cafe
image which is your jar file.

Java: Cannot find package folder path

I have a project with the following package set up:
-src
-Interface
-Resources
-images
I want to find the path to the Resources package folder.
By using getClass().getClassLoader().getResource(), I am able to get to the images in the images folder but I also want to get the path for the folder Resources. As I do not know exactly what files will be there it is not possible to look for a determined resource. I am using the JFileChooser to enable the user to select the file, and the aim is to set the default directory to open in the Resources directory.
It works properly when running the project from NetBeans, but when I run the dist executable jar it does not find it as the path returned goes through the jar file. Any idea how to solve this situation?
So... I have been able to find the path returned whenever the project runs in Netbeans and when I run the dist jar. Follows the paths returned:
netbeans: "Scheduler/Resources/"
dist: "Scheduler/Scheduler.jar!/Resources/"

How can i create executable apple .app file from my java .jar file?

I have created an executable java Swing .jar application. It works fine on Windows. The application hierarchy is :
application.jar
images(Folder) .......... Contains all images the application uses.
libraries(Folder) ....... Contains all external jar libraries the application uses.
bundles(Folder) ......... Contains all bundle files the application uses.
database(Folder) ........ Contains the database files the application uses.
All the above folders exist outside the jar file. Now i am trying to create a Mac executable file (.app) from "application.jar" to run it on Mac so i used the "Jar Bundler" as specified here but when i run the output application.app file nothing happens, nothing runs and i can't even debug it.
I think the main reason is that it can't see the external folders. So is it impossible to create a .app file if the application has external folders ?
And is there a way to debug the .app file to see what's going on ?

Nothing runs, and i can't even debug it.
Diagnostic output from the launch process may be obtained as follows:
$ export JAVA_LAUNCHER_VERBOSE
$ ./YourApplication.app/Contents/MacOS/JavaApplicationStub
There's a related example here.

Most likely the problem is your working directory.
When you run an executable JAR file by double-clicking it, the working directory is the parent directory of the JAR file.
By default, the working directory of an application bundle is its parent directory. If you package the external folders into the application bundle they will be located under $APP_PACKAGE/Contents/Resources.
So the assumption about the working directory that you make for an executable JAR file does not hold for an application bundle.
In order to set the working directory to the resources directory, add
<key>WorkingDirectory</key>
<string>$APP_PACKAGE/Contents/Resources</string>
to the Info.plist file of your bundle.
In case you know nothing about application bundles, please read this document.

This might help: AppBundler by Josh Marinacci

I am not sure about your exact directory hierarchy. But on a Mac with Xcode installed is an application called "Jar Bundler". It exist for exact that purpose you are asking for.
BTW, Mac application use the suffix .app, that is right. But they are not files. Thery are directories.