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Extracting integer from a string

Hi I am just starting to learn java and i am stuck on a problem.
The problem states that if we have a string S
S = "123:456:789"
We have to extract the numbers 123 ,456,789 separately and store them in different variables such as
int a=123
Int b=456
Int c=789
How can we do that?

You can split them by the : character and then save parse the Strings and save them in an array as follows:
String S = "123:456:789";
String[] arr = S.split(":");
int[] integers = new int[arr.length];
for(int i = 0; i < arr.length; i++)
integers[i] = Integer.parseInt(arr[i]);

You can split the string based on a delimiter into a string array. Once you have the string array you can access each array's element to get the specific values.
String S = "123:456:789"
String[] example = S.split(":");
Source: https://javarevisited.blogspot.com/2017/01/how-to-split-string-based-on-delimiter-in-java.html

Look at the method split() in String, and into Integer.parseInt().
You also need to look into Regular Expressions

arrays splitting strings java

I'm sure this is a fairly easy question for someone but I cant work out the best way to do it as a relative beginner.
I am splitting a large file (the string temp) into about a 100 strings and setting it as an array, but I don't know the exact number of strings.
String[] idf = temp.split("===========");
String class1 = idf[0];
String class2 = idf[1];
String class3 = idf[1];
etc etc..
What is the best way to ensure that I can split all the strings and store them in an array?
Any suggestions or pointers would be most appreciated thanks!

You can do it like this:
String list = "hey there how are you";
String[] strarray = list.split("\\s+");
for (String str: strarray)
{
System.out.print(str);
}

Probably you want to iterate over your String array.
You can do it like that:
for(String s : idf) {
//operate on s here
}

Use for-each to get elements from array.
Please look at oracle official site for for-each loop.
Consider below code.
String tempString = "";
String regex = "";
String[] temparray = tempString.split(regex);
for (String temp : temparray)
{
System.out.println(temp);
}

Convert String elements to Array

I have a String :
str="[a],[b],[c]";
How can I convert str to array in Java (Android):
array[0] -> a
array[1] -> b
array[2] -> c
EDIT:
and what about multidimensinal array? str="[["a1","a2","a3"],["b1","b2","b3"]]";

try
String str="[a],[b],[c]";
str= str.replaceAll("\\]|\\[", "");
String[] arr= str.split(",");
===========================================
update
converting multi dimension array to single dimension is already answered in SO please check change multidimensional array to single array
just copied the solution
public static String[] flatten(String[][] data) {
List<String> toReturn = new ArrayList<String>();
for (String[] sublist : Arrays.asList(data)) {
for (String elem : sublist) {
toReturn.add(elem);
}
}
return toReturn.toArray(new String[0]);
}

You can use following way.
String Vstr = "[a],[b],[c]";
String[] array = Vstr.replaceAll("\\]|\\[", "").split(",");

You would need to process your string and build your array. You could either take a look at .split(String regex) (which might require you to do some more processing to clean the string) or else, use a regular expression and do as follows:
Use a regex like so: \[([^]]+?)\]. This will seek out characters in between square brackets and put them into a group.
Use the .find() method available from the Matcher class and iterate over the matches. Put everything into a list so that you can put in as many hits as you need.
If you really need the result to be in an array, use the .toArray() method.

Take a look at String.split() method

An alternative to the regex and what npinti, i think, is talking about:
String myStrg = "[a],[b],[c]";
int numCommas = 0;
for( int i = 0; i < myStrg.length(); i++ )
{
// Count commas
if( myStrg.charAt(i) == ',' )
{
numCommas++;
}
}
// Initialize array
myArry = new String[numCommas];
myArry = myStrg.split(",");
// Loop through and print contents of array
for( String arryStrg: myArry )
{
System.out.println( arryStrg );
}

Try this code.
String str="[a],[b],[c]";
str= str.replaceAll("\\]|\\[", "");
String[] arr= str.split(",");

Determining if a given string of words has words greater than 5 letters long

So, I'm in need of help on my homework assignment. Here's the question:
Write a static method, getBigWords, that gets a String parameter and returns an array whose elements are the words in the parameter that contain more than 5 letters. (A word is defined as a contiguous sequence of letters.) So, given a String like "There are 87,000,000 people in Canada", getBigWords would return an array of two elements, "people" and "Canada".
What I have so far:
public static getBigWords(String sentence)
{
String[] a = new String;
String[] split = sentence.split("\\s");
for(int i = 0; i < split.length; i++)
{
if(split[i].length => 5)
{
a.add(split[i]);
}
}
return a;
}
I don't want an answer, just a means to guide me in the right direction. I'm a novice at programming, so it's difficult for me to figure out what exactly I'm doing wrong.
EDIT:
I've now modified my method to:
public static String[] getBigWords(String sentence)
{
ArrayList<String> result = new ArrayList<String>();
String[] split = sentence.split("\\s+");
for(int i = 0; i < split.length; i++)
{
if(split[i].length() > 5)
{
if(split[i].matches("[a-zA-Z]+"))
{
result.add(split[i]);
}
}
}
return result.toArray(new String[0]);
}
It prints out the results I want, but the online software I use to turn in the assignment, still says I'm doing something wrong. More specifically, it states:
Edith de Stance states:
⇒     You might want to use: +=
⇒     You might want to use: ==
⇒     You might want to use: +
not really sure what that means....

The main problem is that you can't have an array that makes itself bigger as you add elements.
You have 2 options:
ArrayList (basically a variable-length array).
Make an array guaranteed to be bigger.
Also, some notes:
The definition of an array needs to look like:
int size = ...; // V- note the square brackets here
String[] a = new String[size];
Arrays don't have an add method, you need to keep track of the index yourself.
You're currently only splitting on spaces, so 87,000,000 will also match. You could validate the string manually to ensure it consists of only letters.
It's >=, not =>.
I believe the function needs to return an array:
public static String[] getBigWords(String sentence)
It actually needs to return something:
return result.toArray(new String[0]);
rather than
return null;
The "You might want to use" suggestions points to that you might have to process the array character by character.

First, try and print out all the elements in your split array. Remember, you do only want you look at words. So, examine if this is the case by printing out each element of the split array inside your for loop. (I'm suspecting you will get a false positive at the moment)
Also, you need to revisit your books on arrays in Java. You can not dynamically add elements to an array. So, you will need a different data structure to be able to use an add() method. An ArrayList of Strings would help you here.

split your string on bases of white space, it will return an array. You can check the length of each word by iterating on that array.
you can split string though this way myString.split("\\s+");

Try this...
public static String[] getBigWords(String sentence)
{
java.util.ArrayList<String> result = new java.util.ArrayList<String>();
String[] split = sentence.split("\\s+");
for(int i = 0; i < split.length; i++)
{
if(split[i].length() > 5)
{
if(split[i].matches("[a-zA-Z]+"))
{
result.add(split[i]);
}
if (split[i].matches("[a-zA-Z]+,"))
{
String temp = "";
for(int j = 0; j < split[i].length(); j++)
{
if((split[i].charAt(j))!=((char)','))
{
temp += split[i].charAt(j);
//System.out.print(split[i].charAt(j) + "|");
}
}
result.add(temp);
}
}
}
return result.toArray(new String[0]);
}

Whet you have done is correct but you can't you add method in array. You should set like a[position]= spilt[i]; if you want to ignore number then check by Float.isNumber() method.

Your logic is valid, but you have some syntax issues. If you are not using an IDE like Eclipse that shows you syntax errors, try commenting out lines to pinpoint which ones are syntactically incorrect. I want to also tell you that once an array is created its length cannot change. Hopefully that sets you off in the right directions.

Apart from syntax errors at String array declaration should be like new String[n]
and add method will not be there in Array hence you should use like
a[i] = split[i];
You need to add another condition along with length condition to check that the given word have all letters this can be done in 2 ways
first way is to use Character.isLetter() method and second way is create regular expression
to check string have only letter. google it for regular expression and use matcher to match like the below
Pattern pattern=Pattern.compile();
Matcher matcher=pattern.matcher();
Final point is use another counter (let say j=0) to store output values and increment this counter as and when you store string in the array.
a[j++] = split[i];

I would use a string tokenizer (string tokenizer class in java)
Iterate through each entry and if the string length is more than 4 (or whatever you need) add to the array you are returning.
You said no code, so... (This is like 5 lines of code)

Splitting string N into N/X strings

I would like some guidance on how to split a string into N number of separate strings based on a arithmetical operation; for example string.length()/300.
I am aware of ways to do it with delimiters such as
testString.split(",");
but how does one uses greedy/reluctant/possessive quantifiers with the split method?
Update: As per request a similar example of what am looking to achieve;
String X = "32028783836295C75546F7272656E745C756E742E657865000032002E002E005C0"
Resulting in X/3 (more or less... done by hand)
X[0] = 32028783836295C75546F
X[1] = 6E745C756E742E6578650
x[2] = 65000032002E002E005C0
Dont worry about explaining how to put it into the array, I have no problem with that, only on how to split without using a delimiter, but an arithmetic operation

You could do that by splitting on (?<=\G.{5}) whereby the string aaaaabbbbbccccceeeeefff would be split into the following parts:
aaaaa
bbbbb
ccccc
eeeee
fff
The \G matches the (zero-width) position where the previous match occurred. Initially, \G starts at the beginning of the string. Note that by default the . meta char does not match line breaks, so if you want it to match every character, enable DOT-ALL: (?s)(?<=\G.{5}).
A demo:
class Main {
public static void main(String[] args) {
int N = 5;
String text = "aaaaabbbbbccccceeeeefff";
String[] tokens = text.split("(?<=\\G.{" + N + "})");
for(String t : tokens) {
System.out.println(t);
}
}
}
which can be tested online here: http://ideone.com/q6dVB
EDIT
Since you asked for documentation on regex, here are the specific tutorials for the topics the suggested regex contains:
\G, see: http://www.regular-expressions.info/continue.html
(?<=...), see: http://www.regular-expressions.info/lookaround.html
{...}, see: http://www.regular-expressions.info/repeat.html

If there's a fixed length that you want each String to be, you can use Guava's Splitter:
int length = string.length() / 300;
Iterable<String> splitStrings = Splitter.fixedLength(length).split(string);
Each String in splitStrings with the possible exception of the last will have a length of length. The last may have a length between 1 and length.
Note that unlike String.split, which first builds an ArrayList<String> and then uses toArray() on that to produce the final String[] result, Guava's Splitter is lazy and doesn't do anything with the input string when split is called. The actual splitting and returning of strings is done as you iterate through the resulting Iterable. This allows you to just iterate over the results without allocating a data structure and storing them all or to copy them into any kind of Collection you want without going through the intermediate ArrayList and String[]. Depending on what you want to do with the results, this can be considerably more efficient. It's also much more clear what you're doing than with a regex.

How about plain old String.substring? It's memory friendly (as it reuses the original char array).

well, I think this is probably as efficient a way to do this as any other.
int N=300;
int sublen = testString.length()/N;
String[] subs = new String[N];
for(int i=0; i<testString.length(); i+=sublen){
subs[i] = testString.substring(i,i+sublen);
}
You can do it faster if you need the items as a char[] array rather as individual Strings - depending on how you need to use the results - e.g. using testString.toCharArray()

Dunno, you'll probably need a method that takes string and int times and returns a list of strings. Pseudo code (haven't checked if it works or not):
public String[] splintInto(String splitString, int parts)
{
int dlength = splitString.length/parts
ArrayList<String> retVal = new ArrayList<String>()
for(i=0; i<splitString.length;i+=dlength)
{
retVal.add(splitString.substring(i,i+dlength)
}
return retVal.toArray()
}