Thread.sleep method halts the thread permenantly - java

class SelfishRunner extends Thread{
private int tick = 1;
private int num ;
public SelfishRunner(int x){
this.num = x;
}
#Override
public void run(){
try{
while(tick < 400000){
Thread.sleep(250);
if((tick%50000) == 0){
System.out.println(" Thread# "+num+","+Thread.currentThread().getName()+", tick "+tick);
}
tick++;
}
}catch(Exception e){
System.out.println(e);
}
}
}
public class RaceDemo{
private final static int NUMRUNNERS = 2;
public static void main(String[] args){
SelfishRunner[] runners = new SelfishRunner[NUMRUNNERS];
for(int x=0,y=1; x < NUMRUNNERS; x++){
runners[x] = new SelfishRunner(x);
runners[x].setPriority(y++);
}
runners[0].setName("JEEPERS");
runners[1].setName("KREEPERS");
for(int x=0; x < NUMRUNNERS; x++){
runners[x].start();
}
}
}
The above code is trying to create a race condition, but in SelfRunner.run the call to Thread.sleep(250) halts program execution without printing output to the command line.
When I comment out that line, it works fine.
Can anybody tell me why?

You do realize that you are only printing something every 50000/4 seconds, right? You might want to wait a little bit longer. :)

Related

How can I assign a value to the threadArray variable in Task1 , Task2, Task3 class run() method?

I have to insert the elements using three threads by creating three classes, namely Task1,Task2 and Task3. The values to be inserted into the array are 0,1,2,....299.
Override the run method in the threads. Three integer i,j, and k representing the number of elements each thread should append inside the given array.
Thread one should append 0 to i-1 inside the array,thread two should append i to i+j-1 inside the array,and the third thread should append i+j to 299 inide the array.
Threads one and two must run simultaneously, and the values of the threads one and two must be inserted inside the indices of the array from 0 to i+j-1 randomly.The third thread should start only after the first two threads have been executed completely.
In these code three task are given.
first task and second task start executing the thread at the same time and after completion of first two task then only third task start. If these situation getting correct then test() method return true.
public static final int[] threadArray = new int[300]; how I add random number into these array using Task1 Task2 and Task3 class.
Input :
80
130
90
Output :
True
import java.util.Scanner;
class Task1 extends Thread
{
static int a = 0;
static int beg = 0;
public void run()
{
for(int i=a;i<=beg;i++)
{
Solution.threadArray[i] = i;
try {
Thread.sleep(500);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
class Task2 extends Thread
{
static int a = 0;
static int beg = 0;
#Override
public void run()
{
// TODO Auto-generated method stub
for(int i=a;i<=beg;i++)
{
Solution.threadArray[i] = i;
}
}
}
class Task3 extends Thread
{
static int a = 0;
static int beg = 0;
public void run()
{
// TODO Auto-generated method stub
for(int i=a;i<=beg;i++)
{
Solution.threadArray[i] = i;
}
}
}
public class Solution
{
public static final int[] threadArray = new int[300];
public static volatile String i = 0+"";
public boolean test() throws InterruptedException
{
Task1 task1 = new Task1();
Task2 task2 = new Task2();
Task3 task3 = new Task3();
Thread task2Thread = new Thread(task2);
Thread task3Thread = new Thread(task3);
task1.start();
task2Thread.start();
task1.join();
task2Thread.join();
task3Thread.start();
int first = Task1.a+Task2.a;
int containsSecondThread = Task1.a;
String oneAndTwo = "";
String sizeOfTask1 = "";
for(int i=0;i<first;i++)
{
oneAndTwo += threadArray[i]+" ";
}
for(int i=0;i<containsSecondThread;i++)
{
sizeOfTask1 += threadArray[i]+" ";
}
int begOfTask3 = Task3.beg;
String checkingString = "";
for(int i=begOfTask3;i<threadArray.length;i++)
{
checkingString += i + " ";
}
String task3String = "";
for(int j = begOfTask3;j<threadArray.length;j++)
{
task3String += threadArray[j]+" ";
}
if((!oneAndTwo.contains(begOfTask3+"") && sizeOfTask1.contains(Task2.beg+"")) || task3String.equals(checkingString))
{
return true;
}
return false;
}
public static void main(String[] args) throws InterruptedException
{
Scanner sc= new Scanner(System.in);
Solution solution = new Solution();
int one = sc.nextInt();
Task1.a = one;
Task1.beg = 0;
int two = sc.nextInt();
Task2.a = two;
Task2.beg = one;
int three = sc.nextInt();
Task3.a = three;
Task3.beg = one+two;
System.out.print(solution.test());
}
}
First, some observations regarding your code: Instead of using static variables in the classes (i.e., Task1, Task2, and Task3) that extend the class Thread (to understand why have a look at Why are static variables considered evil?):
static int a = 0;
static int beg = 0;
use non-static final fields, and initialize them via the constructor:
class Task1 extends Thread
{
private final int begin;
private final int end;
Task1(int begin, int end){
this.begin = begin;
this.end = end;
}
public void run(){
for(int i=begin; i<= end; i++)
....
}
}
adapt the main method accordingly:
public static void main(String[] args){
...
Task1 task1 = new Task1(begin, end);
}
and then pass the tasks-related objects as parameters of to the test method:
public boolean test(Task1 task1, Task2 task2, Task3 task3){
...
}
For the concatenation of the strings use StringBuilder:
StringBuilder oneAndTwo = new StringBuilder();
for(int i=0;i<first;i++)
{
oneAndTwo.append(threadArray[i]).append(" ");
}
This looks wrong:
Task1.a = one;
Task1.beg = 0;
by looking at the loop of the run method from Task1, this means that, if Task1.a is not a negative number, then Task1 will not do any work.
To use the threads to generate the random values of the array:
int[] threadArray = new int[300];
you can start by extracting a method to generate those random values, based on formula:
r.nextInt(high-low) + low;
this formula generates a random value between low and high.
Adapt the tasks, accordingly:
class Task1 extends Thread
{
private final Random random_values = new Random();
private final int low;
private final int high;
...
public int generate_random(){
return r.nextInt(high-low) + low;
}
public void run()
{
for(....)
{
Solution.threadArray[i] = generate_random();
...
}
}
}
Make sure to pass to the threads the information about the range of the random values to be generated (i.e., the low and high parameters), and the reference to the array that will be filled up with those random values (i.e., array int[] threadArray) . Also make sure that you split the iterations int[] threadArray among the threads. Therefore, each thread should generate a chunk of the random values. An example of such distribution would be:
Thread 1 : 0 to 100;
Thread 2 : 100 to 200;
Thread 3 : 200 to 300;
You can make this more robust and divide the array length by the number to threads and assign the work among threads, accordingly.
I could have provided you with the entire solution, but I feel that is better instead if I give you the pointers so that you can do it in your own.
EDIT: Based on the new edit of your question:
You just need to adapt the Task classes as follows:
class Task1 extends Thread {
static int a = 0;
static int beg = 0;
public void run(){
for(int i=beg;i < a;i++)
Solution.threadArray[i] = i;
}
}
class Task2 extends Thread {
static int a = 0;
static int beg = 0;
public void run(){
for(int i=beg; i< beg + a;i++)
Solution.threadArray[i] = i;
}
}
class Task3 extends Thread{
static int a = 0;
static int beg = 0;
public void run(){
for(int i=beg;i< a + beg;i++)
Solution.threadArray[i] = i;
}
}
Thread1 and Thread2 are supposed to access Common Resource in threadArray[0... Task1.a+Task2+a]. So we have to make use of static volatile variable i declared in Solution Class.
class Task1 extends Thread
{
static int a=0,beg=0;
public void run()
{
int k=Task1.beg;
int i1=0;
while(i1<Task1.a)
{
Solution.threadArray[Integer.parseInt(Solution.i)]=k++;
int a1=Integer.parseInt(Solution.i);
a1++;i1++;
Solution.i=a1+"";
try{
Thread.sleep(1);
}
catch(InterruptedException e){}
}
}
}
class Task2 extends Thread
{
static int a=0,beg=0;
public void run()
{
int y=0;
int k=Task2.beg;
while(y<Task2.a)
{
Solution.threadArray[Integer.parseInt(Solution.i)]=k++;
int a1=Integer.parseInt(Solution.i);
a1++;y++;
Solution.i=a1+"";
try{
Thread.sleep(1);
}
catch(InterruptedException e){}
}
}
}
Thread3 work independently after First 2 threads complete.
class Task3 extends Thread
{
static int beg=0,a=0;
public void run()
{
for(int i=Task3.beg;i<Task3.beg+Task3.a;i++)
{
Solution.threadArray[i]=i;
}
}
}

Java - Trying to understand Threading and new Thread(this).start();

I'm very new to Thread. I'm trying to understand how to apply the usage of threading by making a simple program. It doesn't seem to be working. The program just ask for two inputs and terminate right away after assigning value to those two variables. Moreover, it throws NullPointerException if the threadNum variable is more than 1 Could you please explain the proper way to do this?
Also, I'm confused about constructing and starting a thread with new Thread(this).start();
package helloworld;
import java.util.Scanner;
public class HelloWorld implements Runnable {
private int threadNum;
private int taskNum;
private int loopNum;
public HelloWorld(int threadNum, int taskNum){
this.taskNum = taskNum;
this.threadNum = threadNum;
int loop = taskNum / threadNum;
this.loopNum = loop;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Task Num = ");
int taskNum = sc.nextInt();
System.out.print("Thread Num = ");
int threadNum = sc.nextInt();
HelloWorld hello = new HelloWorld(threadNum, taskNum);
hello.activate();
}
public void activate(){
Thread[] a = new Thread[this.threadNum];
int count = 0;
for(Thread x : a){
x = new Thread(this);
}
for(int i = 0; i < a.length - 1 ; i++){
while(count < loopNum){
a[i].start();
count++;
}
count = 0;
while(count < taskNum - ((threadNum - 1) * loopNum)){
a[a.length - 1].start();
count ++;
}
}
}
#Override
public void run() {
System.out.println("Processing....");
try {
Thread.sleep(1000);
} catch (InterruptedException ex) {
ex.printStackTrace();
}
System.out.println("Done !!");
}
}
HelloWorld implements Runnable means new Thread(this) is passing a Runnable to the constructor of Thread. You aren't actually filling a in your current code. You can do that like
Thread[] a = new Thread[this.threadNum];
for(int i = 0; i < this.threadNum; i++){
a[i] = new Thread(this);
}
// Now `a` is filled with threads.
int count = 0;

Erastotenes Sieve in paraller programm Java

I would like to make a programm which count prime numbers using Erastotenes Sieve. In this issue I want to use semaphore to communicate between thread to make calculations on table with numbers.
So far I have written code like that.
public static void main( String[] args ) throws InterruptedException {
System.out.println("Podaj gorny zakres\n");
Scanner scanner = new Scanner(System.in);
Erastotenes erastotenes = new Erastotenes(Integer.parseInt(scanner.nextLine()));
erastotenes.initializeTable();
long start = System.nanoTime();
List<SingleProcess.MyThread> list = new ArrayList<>();
List<Integer> numbers = Dollar.$(2,erastotenes.getMaximumNumber()+1).toList();
for(int i=0;i<2;i++)
{
list.add(new SingleProcess.MyThread(erastotenes,numbers.subList((numbers.size()/2)*i,(numbers.size()/2)*i+numbers.size()/2)));
list.get(list.size()-1).start();
list.get(list.size()-1).join();
}
System.out.println(System.nanoTime() - start);
//System.out.println("Liczba elementów: "+erastotenes.countPrimeElements());
}
Erastotenes class.
public class Erastotenes {
private int upperRange;
private int maximumNumber;
private int table[];
public Erastotenes(int upperRange) {
this.upperRange = upperRange;
this.maximumNumber = (int)(Math.floor(Math.sqrt(upperRange)));
this.table = new int[upperRange+1];
}
public int getMaximumNumber() {
return maximumNumber;
}
public int getUpperRange() {
return upperRange;
}
public void initializeTable()
{
for(int i=1;i<=upperRange;i++) {
table[i] = i;
}
}
public void makeSelectionOfGivenNumber(int number)
{
if (table[number] != 0) {
int multiple;
multiple = number+number;
while (multiple<=upperRange) {
table[multiple] = 0;
multiple += number;
}
}
}
public List<Integer> getList()
{
List<Integer> list = Ints.asList(table);
return list.stream().filter(item->item.intValue()!=0 && item.intValue()!=1).collect(Collectors.toList());
}
}
The class describing single Thread to make calculations with static Semaphore looks like this.
public class SingleProcess {
static Semaphore semaphore = new Semaphore(1);
static class MyThread extends Thread {
Erastotenes erastotenes;
List<Integer> numbers;
MyThread(Erastotenes erastotenes,List<Integer> numbers) {
this.erastotenes = erastotenes;
this.numbers=numbers;
}
public void run() {
for(int number:numbers) {
try {
semaphore.acquire();
//1System.out.println(number + " : got the permit!");
erastotenes.makeSelectionOfGivenNumber(number);
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
semaphore.release();
}
}
}
}
}
I thought that splitting on half table with numbers from 2 to maximum numbers as square root like in erastotrenes algorithm for these two Threads will boost calculations, but with upperRange to 100000000 the difference between paraller and sequence is not so big. How can I in another realize this problem of paraller programming Erastotenes Sieve?
I think your main problem is this:
for(int i=0;i<2;i++)
{
list.add(new SingleProcess.MyThread(erastotenes,numbers.subList((numbers.size()/2)*i,(numbers.size()/2)*i+numbers.size()/2)));
list.get(list.size()-1).start();
list.get(list.size()-1).join();
}
You start a thread and then immediately wait for it to finish; that kills the parallelism entirely. You can start and wait in the end:
for(int i=0;i<2;i++)
{
list.add(new SingleProcess.MyThread(erastotenes,numbers.subList((numbers.size()/2)*i,(numbers.size()/2)*i+numbers.size()/2)));
list.get(list.size()-1).start();
}
for (Thread t : list) {
t.join();
}
But, there's also a problem with your semaphore tbh. Each thread blocks all other threads from doing anything as long as it's working on a number; that means that again, all parallelism is gone.
You can do away with the semaphore altogether IMO; there's not really a lot of danger in setting the same index to 0 several times, which is all that happens in this "critical section" - but it's not critical at all because no one ever reads the array value in question before all threads are finished.

How do I implement a reset for my loop counter?

I have an action listener that calls some methods and one of those methods counts the number of times that a loop inside of another method is run. The problem I am having is that the counter just adds to itself (I understand why I just don't know how to fix it) rather than resetting back to 0.
Here is my action listener code.
public double computeIterative(double n) throws InvalidInput {
int a=1, b=2;
int result = 0;
if (n>=0) {
if(n==0)return 0;
if(n==1)return 1;
if(n==2)return 2;
for(int i = 3; i <= n; i++) {
result = a+(2*b);
a=b;
b = result;
this.getEfficiency();
}
} else{
throw new InvalidInput();
}
return result;
}
ActionListener that calls methods and sets text:
public void actionPerformed(ActionEvent e) {
int n = Integer.parseInt(nField.getText());
//Try Catch for Iterate Radio Button
if (iterateBtn.isSelected()){
try {
double result = sequence.computeIterative(n);
int efficiency = sequence.getEfficiency();
rField.setText(Double.toString(result));
eField.setText(Integer.toString(efficiency));
}
catch (InvalidInput ex) {
}
}
The getEfficiency method counts how many times the loop inside computeIterative method is run and then sets it to a textField.
Here is my getEfficiency method:
public int getEfficiency() {
efficiency++;
return efficiency;
}
Now obviously this will just keep adding onto itself, and I am sure that I am looking way too hard for a solution but I just cant figure it out.
Basically, after the try, catch, I need to set efficiency to 0 so that the next time the computeIterative(n) method is called, I get a proper reading.
You could simply add a method resetEfficiency():
public int resetEfficiency() {
efficiency = 0;
}
And then call it at the beginning of computeIterative():
public double computeIterative(double n) throws InvalidInput {
this.resetEfficiency();
//rest of code goes here
//....
}
(Of course I'm assuming this is not multi-threaded or anything).
public double computeIterative(double n) throws InvalidInput {
int a=1, b=2;
int result = 0;
this.resetEfficiencyCounter(); //Call Reset if Number Got Invalid.
if (n>=0) {
if(n==0)return 0;
if(n==1)return 1;
if(n==2)return 2;
for(int i = 3; i <= n; i++) {
result = a+(2*b);
a=b;
b = result;
this.getEfficiency();
}
} else{
throw new InvalidInput();
}
return result;
}
add new Function Named resetEfficiencyCounter().
private void resetEfficiencyCounter(){
this.efficiency = 0;
}

how to spwan recursive calls and for loop iterations in multiple threads in java (if possible)?

I was wondering if it is possible to spawn each loop iteration (each iteration into a thread by itself) and finally collect the result. consider this example, nothing fancy in it at all. Just a simple for-loop, but the idea is to extend on it. The body of for loop does not matter, I just filled up with some code. but basically assume it has some expensive calculation which will take few minutes to complete for each iteration. so I want to do each loop calculation in a separate thread.
public class Threadspawns {
private double[] arr = new double[4];
public void calculations(){
for (int i =2; i < 6; i++){
//expensive calculation
arr[i-2]=Math.pow(i,500);
}
}
public static void main(String[] args){
Threadspawns t = new Threadspawns();
long start = System.currentTimeMillis();
t.calculations();
long end = System.currentTimeMillis();
System.out.println(Arrays.toString(t.arr));
System.out.println("time taken "+ (end-start));
}
}
on the same note,
if it is possible to actually split the recursive calls into multiple threads and collect them as they return.
Example is that of fibonacci
public static int fibonacci(int n){
if (n==0)
return 0;
if (n==1)
return 1;
return fibonacci(n-2)+fibonacci(n-1);
}
It is possible that it cannot be done for fibonacci recurive method. but any other example of paralleling recursive calls between threads IF POSSIBLE would be nice to know.
P.S: I have basic knowledge of Thread and Runnable, but wondering if the above is doable
Solution to your first requirement that is moving the expensive calculation into a Callable task. Hope it find it useful:
import java.util.Arrays;
import java.util.concurrent.*;
public class Threadspawns {
private final int THREAD_COUNT = 8;
private final int CALCULATION_COUNT = 60000;
private double[] arr = new double[CALCULATION_COUNT];
public void calculations() {
ExecutorService executorService = Executors.newFixedThreadPool(THREAD_COUNT);
ExecutorCompletionService<Double> completionService = new ExecutorCompletionService<Double>(executorService);
for (int i = 2; i < CALCULATION_COUNT; i++) {
completionService.submit(new Calculation(i));
}
//Get from all Future tasks till all tasks completed
for (int i = 2; i < CALCULATION_COUNT; i++) {
try {
arr[i] = completionService.take().get();
} catch (InterruptedException e) {
e.printStackTrace(); //do something
} catch (ExecutionException e) {
e.printStackTrace(); //do something
}
}
}
private static class Calculation implements Callable<Double> {
private final int num;
private Calculation(int num) {
this.num = num;
}
#Override
public Double call() throws Exception {
return Math.pow(num, 500);
}
}
public static void main(String[] args) {
Threadspawns t = new Threadspawns();
long start = System.currentTimeMillis();
t.calculations();
long end = System.currentTimeMillis();
System.out.println(Arrays.toString(t.arr));
System.out.println("time taken " + (end - start));
}
}

Categories