Currently, we have "root" (/) mapped to a static index.html page, but we want to upgrade to a jsp to have dynamic content. Trying to figure out how to do this. We have content that is mapped to the default content server (e.g. /css), so we don't want to change too much.
We tried:
Changing the .html to .jsp. This resulted in a blank page.
Changing the .html to .jsp and then moving the file into the WEB-INF directory. This resulted in a 404.
Trying to subclass the DefaultServlet class that content servlet is currently mapped to. This through a 500, with a class assertion error (it checked to see if it was the same class).
Adding another servlet to that url, but it overwrote the current one.
I've searched StackOverflow, but still haven't found an answer that works.
Thanks!
If I understand your question correctly, this is trivial using Spring MVC:
<mvc:default-servlet-handler/>
And in web.xml:
<servlet>
<servlet-name>spring-mvc</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<async-supported>true</async-supported>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/META-INF/spring/your-applicationContext-web.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-mvc</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Is this what you have tried already?
Just set up a controller method mapped to / that returns a view name, which is your jsp file. And make sure your view resolver is set up correctly. Any of the spring mac tutorial hellos world programs out there will show how.
I like to expose one JAVA method as a Web service that will accept POST ,strip the parameters out of it and reply accordingly. I read I have to use doPost(req,resp) , but How can I get to the servlet code? what should be in web.xml? there will not be a welcome-file ? After mapping the servlet, can I read it without the need for a index.html as start point?
create the doPost(req,resp) method in your servlet and map it to a url in web.xml
<servlet>
<servlet-name>HelloPost</servlet-name>
<servlet-class>packageName.HelloPost</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloPost</servlet-name>
<url-pattern>/post-url</url-pattern>
</servlet-mapping>
then you can post your request to /post-url .You don't need to use index.html.Any url can be put in welcome file to load for the url /
To set /post-url as landing page , use
<welcome-file-list>
<welcome-file>/post-url</welcome-file>
</welcome-file-list>
you can get started here https://developers.google.com/appengine/docs/java/gettingstarted/creating
If you want to know how to set the web.xml to start the servlet then may be this will help you.
I used to build my projects with maven. Now I want to do it 'manually'. But I struggle a little bit with directory order and other stuff. I first just created a new dynamic web project in eclipse and added JSF libraries. Now I tried to deploy a hello world page onto a tomcat 7. But jsf-tags are not getting rendered.
Here is my directory structure:
Anybody has an idea where the mistake is? Am I missing a library or is my structure wrong?
cheers
It finally works! thank's to balusc
But jsf-tags are not getting rendered.
This means that the FacesServlet isn't mapped in web.xml or you didn't make the URL in browser address bar to match the url-pattern of the FacesServlet. The FacesServlet is the one responsible for parsing JSF tags and doing all the JSF works.
Assuming that the url-pattern of the FacesServlet as definied in web.xml is *.jsf, then you need to open the start.xhtml by http://localhost:8080/fitnessverwaltung/start.jsf instead of http://localhost:8080/fitnessverwaltung/start.xhtml.
You can also change the url-pattern to *.xhtml, then you don't need to worry about this.
<servlet>
<servlet-name>facesServlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>facesServlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
I've mapped the Spring MVC dispatcher as a global front controller servlet on /*.
<servlet>
<servlet-name>home</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>home</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
However, this mapping stops the access to static files like CSS, JS, images etc which are all in the /res/ folder.
How can I access them anyway?
Map the controller servlet on a more specific url-pattern like /pages/*, put the static content in a specific folder like /static and create a Filter listening on /* which transparently continues the chain for any static content and dispatches requests to the controller servlet for other content.
In a nutshell:
<filter>
<filter-name>filter</filter-name>
<filter-class>com.example.Filter</filter-class>
</filter>
<filter-mapping>
<filter-name>filter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>controller</servlet-name>
<servlet-class>com.example.Controller</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>controller</servlet-name>
<url-pattern>/pages/*</url-pattern>
</servlet-mapping>
with the following in filter's doFilter():
HttpServletRequest req = (HttpServletRequest) request;
String path = req.getRequestURI().substring(req.getContextPath().length());
if (path.startsWith("/static")) {
chain.doFilter(request, response); // Goes to default servlet.
} else {
request.getRequestDispatcher("/pages" + path).forward(request, response);
}
No, this does not end up with /pages in browser address bar. It's fully transparent. You can if necessary make "/static" and/or "/pages" an init-param of the filter.
With Spring 3.0.4.RELEASE and higher you can use
<mvc:resources mapping="/resources/**" location="/public-resources/"/>
As seen in Spring Reference.
What you do is add a welcome file in your web.xml
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
And then add this to your servlet mappings so that when someone goes to the root of your application, they get sent to index.html internally and then the mapping will internally send them to the servlet you map it to
<servlet-mapping>
<servlet-name>MainActions</servlet-name>
<url-pattern>/main</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>MainActions</servlet-name>
<url-pattern>/index.html</url-pattern>
</servlet-mapping>
End result: You visit /Application, but you are presented with /Application/MainActions servlet without disrupting any other root requests.
Get it? So your app still sits at a sub url, but automatically gets presented when the user goes to the root of your site. This allows you to have the /images/bob.img still go to the regular place, but '/' is your app.
If you use Tomcat, you can map resources to the default servlet:
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/static/*</url-pattern>
</servlet-mapping>
and access your resources with url http://{context path}/static/res/...
Also works with Jetty, not sure about other servlet containers.
Serving static content with appropriate suffix in multiple servlet-mapping definitions solved the security issue which is mentioned in one of the comments in one of the answers posted. Quoted below:
This was a security hole in Tomcat (WEB-INF and META-INF contents are accessible this way) and it has been fixed in 7.0.4 (and will be ported to 5.x and 6.x as well). – BalusC Nov 2 '10 at 22:44
which helped me a lot.
And here is how I solved it:
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.js</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.css</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.jpg</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
I've run into this also and never found a great solution. I ended up mapping my servlet one level higher in the URL hierarchy:
<servlet-mapping>
<servlet-name>home</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
And now everything at the base context (and in your /res directory) can be served up by your container.
As of 3.0.4 you should be able to use mvc:resources in combination with mvc:default-servlet-handler as described in the spring documentation to achieve this.
http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/mvc.html#mvc-static-resources
The reason for the collision seems to be because, by default, the context root, "/", is to be handled by org.apache.catalina.servlets.DefaultServlet. This servlet is intended to handle requests for static resources.
If you decide to bump it out of the way with your own servlet, with the intent of handling dynamic requests, that top-level servlet must also carry out any tasks accomplished by catalina's original "DefaultServlet" handler.
If you read through the tomcat docs, they make mention that True Apache (httpd) is better than Apache Tomcat for handling static content, since it is purpose built to do just that. My guess is because Tomcat by default uses org.apache.catalina.servlets.DefaultServlet to handle static requests. Since it's all wrapped up in a JVM, and Tomcat is intended to as a Servlet/JSP container, they probably didn't write that class as a super-optimized static content handler. It's there. It gets the job done. Good enough.
But that's the thing that handles static content and it lives at "/". So if you put anything else there, and that thing doesn't handle static requests, WHOOPS, there goes your static resources.
I've been searching high and low for the same answer and the answer I'm getting everywhere is "if you don't want it to do that, don't do that".
So long story short, your configuration is displacing the default static resource handler with something that isn't a static resource handler at all. You'll need to try a different configuration to get the results you're looking for (as will I).
'Static' files in App Engine aren't directly accessible by your app. You either need to upload them twice, or serve the static files yourself, rather than using a static handler.
The best way to handle this is using some kind of URL re-writing. In this way, you can have clean restful URLs, and NOT with any extensions i.e abc.com/welcom/register as opposed to abc.com/welcome/resister.html
I use Tuckey URL which is pretty cool.
It's got instructions on how to set up your web app.I have set it up with my Spring MVC web app. Of course, everything was fine until I wanted to use annotations for Spring 3 validations like #Email or #Null for domain objects.
When I add the Spring mvc directives:
< mvc:annotation-driven />
< mvc:default-servlet-handler />
.. it breaks the good ol Tuckey code. Apparently, < mvc:default-servlet-handler /> replaces Tuckey, which I'm still trying to solve.
I'd recommend trying to use a Filter instead of a default servlet whenever possible.
Other two possibilities:
Write a FileServlet yourself. You'll find plenty examples, it should just open the file by URL and write its contents into output stream. Then, use it to serve static file request.
Instantiate a FileServlet class used by Google App Engine and call service(request, response) on that FileServlet when you need to serve the static file at a given URL.
You can map /res/* to YourFileServlet or whatever to exclude it from DispatcherServlets' handling, or call it directly from DispatcherServlet.
And, I have to ask, what does Spring documentation say about this collision? I've never used it.
Add the folders which you don't want to trigger servlet processing to the <static-files> section of your appengine-web.xml file.
I just did this and looks like things are starting to work ok. Here's my structure:
/
/pages/<.jsp files>
/css
I added "/pages/**" and "/css/**" to the <static-files> section and I can now forward to a .jsp file from inside a servlet doGet without causing an infinite loop.
After trying the filter approach without success (it did for some reason not enter the doFilter() function) I changed my setup a bit and found a very simple solution for the root serving problem:
Instead of serving " / * "
in my main Servlet, I now only listen to dedicated language prefixes
"EN", "EN/ *", "DE", "DE/ *"
Static content gets served by the default Servlet and the empty root requests go to the index.jsp which calls up my main Servlet with the default language:
< jsp:include page="/EN/" />
(no other content on the index page.)
I found that using
<mvc:default-servlet-handler />
in the spring MVC servlet bean definition file works for me. It passes any request that isn't handled by a registered MVC controller on to the container's original default handler, which should serve it as static content. Just make sure you have no controller registered that handles everything, and it should work just fine. Not sure why #logixplayer suggests URL rewriting; you can achieve the effect he's looking for just adequately using Spring MVC alone.
I found a simpler solution with a dummy index file.
Create a Servlet (or use the one you wanted to respond to "/") which maps to "/index.html"
(Solutions mentioned here use the mapping via XML, I used the 3.0 version with annotation #WebServlet)
Then create a static (empty) file at the root of the static content named "index.html"
I was using Jetty, and what happened was that the server recognized the file instead of listing the directory but when asked for the resource, my Servlet took control instead. All other static content remained unaffected.
In Embedded Jetty I managed to achieve something similar by adding a mapping for the "css" directory in web.xml. Explicitly telling it to use DefaultServlet:
<servlet>
<servlet-name>DefaultServlet</servlet-name>
<servlet-class>org.eclipse.jetty.servlet.DefaultServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>DefaultServlet</servlet-name>
<url-pattern>/css/*</url-pattern>
</servlet-mapping>
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<mvc:default-servlet-handler/>
</beans>
and if you want to use annotation based configuration use below code
#Override
public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
configurer.enable();
}
With regard to Tomcat, a lot depends on the particular version. There was a bug fix
https://bz.apache.org/bugzilla/show_bug.cgi?id=50026
which means the servlet-mapping (other than for '/') for the default servlet behaves differently in Tomcat 6.0.29 (and earlier) compared with later versions.
In section "12.2 Specification of Mappings" of the Servlet Specification, it says:
A string containing only the ’/’ character indicates the "default" servlet of the
application.
So in theory, you could make your Servlet mapped to /* do:
getServletContext().getNamedDispatcher("/").forward(req,res);
... if you didn't want to handle it yourself.
However, in practice, it doesn't work.
In both Tomcat and Jetty, the call to getServletContext().getNamedDispatcher('/') returns null if there is a servlet mapped to '/*'
I'm trying to write a web application using SpringMVC. Normally I'd just map some made-up file extension to Spring's front controller and live happily, but this time I'm going for REST-like URLs, with no file-name extensions.
Mapping everything under my context path to the front controller (let's call it "app") means I should take care of static files also, something I'd rather not do (why reinvent yet another weel?), so some combination with tomcat's default servlet (let's call it "tomcat") appears to be the way to go.
I got the thing to work doing something like
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>tomcat</servlet-name>
<url-pattern>*.ext</url-pattern>
</servlet-mapping>
and repeating the latter for each one of the file extensions of my static content. I'm just wondering why the following setups, which to me are equivalent to the one above, don't work.
<!-- failed attempt #1 -->
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>tomcat</servlet-name>
<url-pattern>*.ext</url-pattern>
</servlet-mapping>
<!-- failed attempt #2 -->
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>tomcat</servlet-name>
<url-pattern>/some-static-content-folder/*</url-pattern>
</servlet-mapping>
Can anyone shed some light?
I think I may know what is going on.
In your working web.xml you have set your servlet to be the default servlet (/ by itself is the default servlet called if there are no other matches), it will answer any request that doesn't match another mapping.
In Failed 1 your /* mapping does appear to be a valid path mapping. With the /* mapping in web.xml it answers all requests except other path mappings. According to the specification extension mappings are implicit mappings that are overwritten by explicit mappings. That's why the extension mapping failed. Everything was explicitly mapped to app.
In Failed 2, App is responsible for everything, except content that matches the static content mapping. To show what is happening in the quick test I set up. Here is an example. /some-static-content-folder/ contains test.png
Trying to access test.png I tried:
/some-static-content-folder/test.png
and the file was not found. However trying
/some-static-content-folder/some-static-content-folder/test.png
it comes up. So it seems that the Tomcat default servlet (6.0.16 at least) drops the servlet mapping and will try to find the file by using the remaining path. According to this post Servlet for serving static content Jetty gives the behavior you and I were expecting.
Is there some reason you can't do something like map a root directory for your rest calls. Something like app mapped to /rest_root/* than you are responsible for anything that goes on in the rest_root folder, but anywhere else should be handled by Tomcat, unless you make another explicit mapping. I suggest setting your rest servlet to a path mapping, because it declares the intent better. Using / or /* don't seem appropriate, since you have to map out the exceptions. Using SO as an example, my rest mappings would be something like
/users/* for the user servlet
/posts/* for the posts servlet
Mapping order
Explicit (Path mappings)
Implicit (Extension mappings)
Default (/)
Please correct anything that I got wrong.
For reference, the "failed attempt #2" is perfectly correct in version of Tomcat >= to 6.0.29.
It was the result of a Tomcat bug that get fixed in version 6.0.29:
https://issues.apache.org/bugzilla/show_bug.cgi?id=50026
<!-- Correct for Tomcat >= 6.0.29 or other Servlet containers -->
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/some-static-content-folder/*</url-pattern>
</servlet-mapping>
I've never tried to map a servlet like this, but I would argue that /* does technically both start with / and end with /*, even though the same character is used for both matches.