I have an method which writes data to an OutputStream but needs to return the contents of the OutputStream as an InputStream
public InputStream getInputStreamOfData(type param) {
// ..... data
OutputStreamWriter writer = new OutputStreamWriter();
writer.write(data);
// convert writer object to an InputStream
}
I came across some libraries to do this such as IOUtils and other thread based methods. Is there a simple way to achieve this using standard Java library ? I want to return the contents in the writer as an InputStream to be consumed by the calling method.
Thanks!
Write to a ByteArrayOutputStream, then get the byte array, and return a ByteArrayInputStream from this byte array.
I think the correct way to do it is using PipedInputStream. It's just like unix pipes (in highlevel). PipedInputStream constructor takes PipedOutputStream, so if you write to PipedOutputStream, you will get exactly what you want!
Good luck!
Related
I was trying to read from file and then write to other file. I use code bellow to do so.
byte[] bytes = Files.readAllBytes(file1);
Writer Writer = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(file2), "UTF-8"));
for(int i=0;i<bytes.length;i++)
Writer.write(bytes[i]);
Writer.close();
But when I change file1 to picture.png and file2 to picture2.png, this method doesn't work and I can't open picture2.png using image viewer.
What have I done wrong?
Writers are for writing text, possibly in different formats (ie utf-8 / 16, etc). For writing raw bytes, don't use writers. Just use (File)OutputStreams.
It is truly as simple as
byte[] bytes = ...;
FileOutputStream fos = ...;
fos.write(bytes);
The other answers explain why what you have potentially fails.
I'm curious why you're already using one Java NIO method, but not others? The library already has methods to do this for you.
byte[] bytes = Files.readAllBytes(file1);
Files.write(file2, bytes, StandardOpenOption.CREATE_NEW); // or relevant OpenOptions
or
FileOutputStream out = new FileOutputStream(file2); // or buffered
Files.copy(file1, out);
out.close();
or
Files.copy(file1, file2, options);
The problem is that Writer.write() doesn't take a byte. It takes a char, which is variable size, and often bigger than one byte.
But once you've got the whole thing read in as a byte[], you can just use Files.write() to send the whole array to a file in much the same way that you read it in:
Files.write(filename, bytes);
This is the more modern NIO idiom, rather than using an OutputStream.
It's worth reading the tutorial.
Good Evening, today i faced a strange situation when i used Print Writer in uploading files to a server, the file is transferred i tried to use FileOutPutStream instead and it solves the problem, my question is why PrintWriter does that strange behaviour, here's the code that i used in uploading a file and save it at the server:
public void doPost(HttpServletRequest request,HttpServletResponse response)throws IOException,ServletException{
int i;
if(request instanceof MultipartWrapper){
String DestinationPath="C:\\";
MultipartWrapper request1=(MultipartWrapper)request;
File f=request1.getFile("photo");
java.io.FileInputStream fis=new java.io.FileInputStream(f);
//PrintWriter out=new PrintWriter(DestinationPath+f.getName()); causes the problem mentioned above
java.io.FileOutputStream out=new java.io.FileOutputStream(DestinationPath+f.getName());
while((i=fis.read())!=-1){
out.write(i);
}
fis.close();
out.close();
}
}
You need to understand the difference between Writers and OutputStreams. PrintWriter.write(int) is writing a character, while FileOutputStream.write(int) is writing a byte. you were accidentally converting bytes to characters, which was corrupting your file. in general, when just copying streams around, you want to stick to bytes.
PrintWriter will create a Writer using the default encoding, while FileOutputStream will simply write raw bytes out. Provided that your original content and the server side use the same encoding, you won't have problems writing bytes and reinterpreting them. However, when you use the PrintWriter, the default system encoding is used, potentially mucking up your data.
I'm looking for an efficient way to transfer files between client and server processes using TCP in Java. My server code looks something like this:
socket = serverSocket.accept();
InputStream is = socket.getInputStream();
OutputStream os = socket.getOutputStream();
FileInputStream fis = new FileInputStream(new File(filename));
I'm just unsure of how to proceed. I know I want to read bytes from fis and then write them to os, but I'm unsure about the best way to read and write bytes using byte streams in Java. I'm only familiar with writing/reading text using Writers and Readers. Can anyone tell me the appropriate way to do this? What should I wrap os and fis in (if anything) and how do I keep reading bytes until the end of file without a hasNext() method (or equivalent)
You could do something like:
byte[] contents = new byte[BUFFER_SIZE];
int numBytes =0;
while((numBytes = is.read(contents))>0){
os.write(contents,0,numBytes);
}
You could use Apache's IOUtils.copy(in, out) or
import org.apache.commons.fileupload.util.Streams;
...
Streams.copy(in, out, false);
Inspecting the source might prove interesting. ( http://koders.com ?)
There is the java.nio.Channel with a transferTo method, with mixed opinions in the community wether better for smaller/larger files.
A simple block wise copy between Input/OutputStream would be okay. You could wrap it in buffered streams.
Consider these two functions:
Function A takes inputStream as parameter.
public void processStream(InputStream stream)
{
//Do process routine
}
Function B loads a file content to pass it to Function A as InputStream.
pulic void loadFile()
{
File file =new File("c:\\file.txt");
//Pass file as InputStream
}
How can I pass file from Function B to Function A as InputStream without reading it on first hand?
I did something like this:
File file = new File("c:\\file.txt");
DataInputStream stream= new DataInputStream(new FileInputStream(file));
This generated the exception below:
java.io.WriteAbortedException: writing aborted; java.io.NotSerializableException: java.io.DataInputStream
EDIT:
loadFile() is passing the InputStream as RMI response.
The following should work just fine
processStream(new FileInputStream(file));
You should only not attempt to serialize an InputStream instance by ObjectOutputStream like as
objectOutputStream.writeObject(inputStream);
which you're apparently doing in processStream() method. That's namely exactly what the exception is trying to tell you. How to solve it properly depends on the sole functional requirement which you omitted from the question.
Update as per the comment
I am passing the InputStream as an RMI response.
There's the problem. You cannot pass non-serializable objects around as RMI response, let alone unread streams. You need to read the InputStream into a ByteArrayOutputStream the usual IO way and then use its toByteArray() to get a byte[] out of it and pass that instead. Something like:
InputStream input = new FileInputStream(file);
ByteArrayOutputStream output = new ByteArrayOutputStream();
byte[] buffer = new byte[8192];
for (int length = 0; (length = input.read(buffer)) > 0;) {
output.write(buffer, 0, length);
}
byte[] bytes = output.toByteArray(); // Pass that instead to RMI response.
Be careful with large files though. Every byte of a byte[] eats one byte of JVM's memory.
That exception seems to indicate that you are calling the processStream method on a remote object using something like RMI? if that is the case, you will need to re-visit what you are doing. sending streams of data over RMI is not an easy thing to do. if you are guaranteed to be using small files, you could copy the file data to a byte[] and pass that to the remote method call. if you need to process larger files, however, that will most likely cause memory issues on the client and/or server. in that case, you should use something like rmiio, which provides utilities for streaming data over RMI.
You could just pass the FileInputStream ?
processStream(new FileInputStream(yourFile));
The reason you are getting the exception is because DataInputStream is intended to read primitive Java types
I was handed some data in a file with an .dat extension. I need to read this data in a java program and build the data into some objects we defined. I tried the following, but it did not work
FileInputStream fstream = new FileInputStream("news.dat");
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
Could someone tell me how to do this in java?
What kind of file is it? Is it a binary file which contains serialized Java objects? If so, then you rather need ObjectInputStream instead of DataInputStream to read it.
FileInputStream fis = new FileInputStream("news.dat");
ObjectInputStream ois = new ObjectInputStream(fis);
Object object = ois.readObject();
// ...
(don't forget to properly handle resources using close() in finally, but that's beyond the scope of this question)
See also:
Basic serialization tutorial
A .dat file is usually a binary file, without any specific associated format. You can read the raw bytes of the file in a manner similar to what you posted - but you will need to interpret these bytes according to the underlying format. In particular, when you say "open" the file, what exactly do you want to happen in Java? What kind of objects do you want to be created? How should the stream of bytes map to these objects?
Once you know this, you can either write this layer yourself or use an existing API (assuming it's a standard format).
For reference, your example doesn't work because it assumes that the binary format is a character representation in the platform's default charset (as per the InputStreamReader constructor). And as you say it's binary, this will fail to convert the binary to a stream of characters (since, after all, it's not).
// BufferedInputStream not strictly needed, but much more efficient than reading
// one byte at a time
BufferedInputStream in = new BufferedInputStream (new FileInputStream("news.dat"));
This will give you a buffered stream which will return the raw bytes of the file; you can now either read and process them yourself, or pass this input stream to some library API that will create appropriate objects for you (if such a library exists).
That entirely depends on what sort of file the .dat is. Unfortunately, .dat is often used as a generic extension for a data file. It could be binary, in which case you could use FileInputStream fstream = new FileInputStream(new File("news.dat")); and call read() to get bytes from the file, or text, in which case you could use BufferedReader buff = new BufferedInputReader(new FileInputStream(new File("news.dat"))); and call readLine() to get each line of text. [edit]Or it could be Java objects in which case what BalusC said.[/edit]
In both cases, you'd then need to know what format the file was in to divide things up and get meaning from it, although this would be much easier if it was text as it could be done by inspection.
Please try the below code:
FileReader file = new FileReader(new File("File.dat"));
BufferedReader br = new BufferedReader(file);
String temp = br.readLine();
while (temp != null) {
temp = br.readLine();
System.out.println(temp);
}
A better way would be to use try-with-resources so that you would not have to worry about closing the resources.
Here is the code.
FileInputStream fis = new FileInputStream("news.dat");
try(ObjectInputStream objectstream = new ObjectInputStream(fis)){
objectstream.readObject();
}
catch(IOException e){
//
}