From a long time i am struggling for with this program. I am having a shell script which accepts parameters as version number and path for the files. then that script creates Zip file with the name of version number congaing all file files to the folder.
I have installed Cygwin on following path D:/cygwin. I am coping required files to same location where cygwin is installed D:\cygwin\bin
Command
D:/cygwin/bin/bash -c '/bin/test/app.sh 04.10 D:\cygwin\bin\ Test_files
Or Can any one please suggest how to run shell script in java using Cygwin.
Rewriting the Problem:-
When i am trying to run following Command in command prompt it gives error
sh app.sh AK-RD 02.20 D:\cygwin\bin\Test_files
Error:-C:\Documents and Settings\sh app.sh AK-RD 02.20 D:\cygwin\bin\Test_files
/usr/bin/app.sh: line 51: lib/lib.sh: No such file or directory
But if i run the same command at
D:cygwin\bin\Test>sh app.sh AK-RD 02.20 D:\cygwin\bin\Test_files
It works fine. Can any one suggest me how to avoid this kind of errors.
Runtime run = Runtime.getRuntime();
Process p = run.exec("D:/cygwin/bin/bash -c \'/bin/test/app.sh 04.10 D:\cygwin\bin\ Test_files");
p.waitFor();
Related
shell script file directory: /some/location/myShellScript.sh
Properties-Type: shell script (application/x-shellscript)
EDIT
content of shell script:
#!/bin/bash
export LD_LIBRARY_PATH=`pwd`
echo `pwd`
./someExecutable ../input/cfg/test1.ini
The test1.ini is generated one step before in the java code,
it provides settings for some testing, which is done in the background. Then the shell script ends up with the file I need for further processing.
/EDIT
When I am running this shell script on linux terminal in its own directory just with "./myShellScript.sh" it works perfectly fine...
The part my shell script shall be executed:
//Do something before
//Shell scripts creates a file
String cmd = /some/location/myShellScript.sh;
ProcessBuilder pb = new ProcessBuilder(cmd);
Process process = pb.start();
int exitValue = process.waitFor();
System.out.println(exitValue);
//Afterwards I am processing the generated file
When running my java program as an executable .jar file, this process gets not executed and the exitValue is 127, but I don't know why...
I tried many things like:
using the Runtime to exec
adding #!/bin/bash or #!/bin/sh on top of the shell script
adding a "sh" parameter to the process command in form of String[]
In my execution directory, I changed the permission with chmod 755 -R * recursively so every associated library used by the shell script is indeed available (also due to the fact, that I can just execute it on the terminal).
I really tried to find a proper answer on the internet but I wasn't successful.
And no, I cannot just do everything in java, the shell script is mandatory and cannot be replaced in this case.
Thanks in advance for helpful suggestions!
The script you are executing is highly sensitive to its working directory. It uses pwd to set the LD_LIBRARY_PATH and it attempts to execute another program via a relative path to that program, providing a relative path as a command-line argument, as well.
The working directory for an execution of the script has no essential relationship with the directory in which the script resides -- it completely depends on how and in what context the script is launched. For example, you report that the script works as you expect "When I am running this shell script [...] in its own directory." But when you run the script from Java you very likely are not running it with its own directory as the working directory, and that will strongly affect this script's behavior.
One solution would be to hardcode the script's installation path into the script itself, and to express all your paths relative to that:
#!/bin/bash
installation_dir=/path/to/the/script/dir
export LD_LIBRARY_PATH=$installation_dir
"$installation_dir"/someExecutable "$installation_dir"/../input/cfg/test1.ini
It's a bit kludgy to hardcode the path, though. You could further improve it by having the script identify its own directory at runtime:
#!/bin/bash
installation_dir="$( cd "$( dirname "${BASH_SOURCE[0]}" )" >/dev/null && pwd )"
export LD_LIBRARY_PATH=$installation_dir
"$installation_dir"/someExecutable "$installation_dir"/../input/cfg/test1.ini
That's obviously Bash-specific, but you were using bash anyway. Alternatively, if the executable your script launches is also sensitive to its working directory, then perhaps you just want the script to change directory (which will be effective only for the script and processes downstream from it, not for its parent process):
#!/bin/bash
cd "$( dirname "${BASH_SOURCE[0]}" )"
export LD_LIBRARY_PATH=`pwd`
./someExecutable ../input/cfg/test1.ini
The 127 exit status means that a command used in the script is not found.
EDIT
Debug the script, when bash is used, add the line below on the second line:
exec > /tmp/debug.txt 2>&1 ; set -x
After the next attempt, analyze the traces generated into the /tmp/debug.txt file.
OLD INTRO
(the script content was not yet provided)
The Java program which executes the myShellScript.sh script has probably not the same PATH environment variable than the one which is set in your environment when you execute the script manually from a terminal.
I am using following working command for Windows batch file.
set projectLocation=E:\APPIUM\CXMFunctionalTest\LinuxAPITest
cd %projectLocation%
set classpath=%projectLocation%\bin;%projectLocation%\lib\*
java org.testng.TestNG %projectLocation%\testng.xml
pause
How i can convert this into Linux Shell Script? So i can run it in Linux machine.
cd /home/[[youruser]]/APPIUM;
java org.testng.TestNG /home/[[youruser]]/APPIUM/testng.xml;
This should be sufficient, considering that [[youruser]] is your users home folder, and the APPIUM folder is placed directly inside it. Then you can put this in a file called runappium.sh, and run it with the command sh appium.sh or mark it executable and run it directly.
I wrote a little java program and now I want to execute this .jar file from a .sh script.
my script:
#! /bin/bash
java -jar /var/spool/sms/sentSMS.jar
then i run the command: sudo bash sentSMS.sh
an get following error:
ERROR: Unable to access jarfile /var/spool/sms/sentSMS.jar
I am using a Raspberry with raspian-jessie, if this important to solve it.
Sorry, but I'm new in scripting with linux.
Take into account that the user must have at least READ permissions on that file.
Also, as you say you are new in linux, make sure the name is correct. sentSMS.jar is different from sentsms.jar
I'm trying to run a script from an Amazon Linux machine. The script invokes checkstyle like this (in a script called eval.sh):
CHECKSTYLE="java -jar /home/ec2-user/grader/ext/checkstyle-6.15-all.jar"
CHECKSTYLE_RULES="/home/ec2-user/grader/config/checks.xml"
CHECKSTYLE_OUT="quality.log"
"${CHECKSTYLE}" -c "${CHECKSTYLE_RULES}" -f xml -o "${CHECKSTYLE_OUT}" $(find "${_toCheck}" -name "*.java") 2>"quality.err"
When I run this, I get the following error in quality.err:
./grader/eval.sh: line 10: java -jar /home/ec2-user/grader/ext/checkstyle-6.15-all.jar: No such file or directory
I have tried to run the same command directly in the terminal and it is working. Both checkstyle-6.15-all.jar and checks.xml are where they should be.
What could cause this problem?
Change "${CHECKSTYLE}" to ${CHECKSTYLE} (without the quotes).
You are passing the entire value of the CHECKSTYLE variable as a single word (that's what the quotes do), so the shell is looking for a relative directory named java -jar, and is trying to find a file under that (nonexistent) directory with the path home/ec2-user/grader/ext/checkstyle-6.15-all.jar.
When you envoke "${CHECKSTYLE}" the shell thinks that is the command you are running. There is no such file name with the spaces and options have you have included there. If you envoke it simply as ${CHECKSTYLE} (drop the quotes) the shell will process it for whitespace as normal and split it into the appropriate pieces for creating the process.
I have a homework assignment in Java that is tested using the commands:
make
./<program_name> <arguments>
my make file compiles my java program successfully, but how can the program be run without using the command:
java <program_name>
I have investigated how to convert a .jar into an .exe but I am convinced that is not the answer I am looking for.
I believe the test is run on a Linux machine. Is there something I can include in the make file to cause the command
./<program_name>
to run a compiled java class?
Without converting the java program in a native executable file, that will be different for linux, for windows and any other platform (so you will loose Java portability), the only thing you can do is to create a launch script.
On *nix system you can create a bash script and on windows a batch script. Then in this script you have to call java <program_name>.
With the script you are now able to launch your application with a single command.
For example on unix you can create myapp.sh:
#!/bin/bash
java -classpath bin com.test.YourApp $*
and make this script runnable with command
chmod a+x myapp.sh
in this example when you write myapp.sh command you launch your Java class com.test.YourApp using the folder bin as classpath.