I've been trying to do a project using quick sort and bottom-up merge sort but I am stuck on quick sort. I've been able to come up with some code but whenever I try to run my program I get the error "quickSort(int[],int,int) in sort cannot be applied to (int[])" Any tips?
Here's code...
import java.util.Random;
public class main {
public static void main(String[] args) {
Random gen = new Random();
int[] a = new int[20];
for (int i = 0; i < a.length; i++)
a[i] = gen.nextInt(100);
printArray(a);
quickSort(a);
}
private static void printArray(int[] a){
for (int i : a)
System.out.print(i + " ");
System.out.println("");
}
private static void quickSort(int a[], int left, int right){
int i = left, j = right;
int tmp;
int pivot = a[(left + right) / 2];
while (i <= j) {
while (a[i] < pivot)
i++;
while (a[j] > pivot)
j--;
if (i <= j) {
tmp = a[i];
a[i] = a[j];
a[j] = tmp;
i++;
j--;
}
}
if (left < j)
quickSort(a, left, j);
if (i < right)
quickSort(a, i, right);
}
Your quickSort function takes three arguments, but you are calling it with only one.
your first call to quicksort doesn't have the right syntax. The method takes 3 parameters.
quickSort(a);
I think you want
quickSort(a, 0, 19); //might be 20 I don't know if it's size or last element index
Related
I'm trying to implement quicksort using the median of three algo and it fails a unit test I wrote related to a small partition. I changed my earlier partition and now it passes one of the tests it used to fail, but still fails the one at the bottom:
My code is:
public class QuickSort {
static void swap(int[] A, int i, int j) {
int tmp = A[i];
A[i] = A[j];
A[j] = tmp;
}
static final int LIMIT = 15;
static int partition(int[] a, int left, int right){
int center = (left + right) / 2;
if(a[center] < (a[left]))
swap(a,left,center);
if(a[right-1] < a[left])
swap(a,left,right);
if(a[right-1] < a[center])
swap(a,center,right);
swap(a,center,right - 1);
return a[right - 1];
}
static void quicksort(int[] a, int left, int right){
if(left + LIMIT <= right){
int pivot = partition(a,left,right);
int i = left;
int j = right - 1;
for(;;){
while(a[++i] < pivot){}
while(a[--j] > pivot){}
if(i < j)
swap(a,i,j);
else
break;
}
swap(a,i,right - 1);
quicksort(a,left,i-1);
quicksort(a,i+1,right);
}
else{
insertionSort(a);
}
}
public static void insertionSort(int[] a){
int j;
for(int p = 1; p < a.length; p++){
int tmp = a[p];
for(j = p; j > 0 && tmp < a[j-1]; j--)
a[j] = a[j-1];
a[j] = tmp;
}
}
}
This test fails:
public void smalltest() throws Exception {
int[] Arr_orig = {3,9,8,2,4,6,7,5};
int[] Arr = Arr_orig.clone();
int pivot = QuickSort.partition(Arr, 0, Arr.length);
for (int i = 0; i != pivot; ++i)
assertTrue(Arr[i] <= Arr[pivot]); //fails!
for (int i = pivot + 1; i != Arr.length; ++i)
assertTrue(Arr[pivot] < Arr[i]);
}
There is a conflict between using right-1 and right in this sequence:
if(a[right-1] < a[left])
swap(a,left,right);
You need to decide if right is going to be the index to the last element, or 1 + index to the last element (an "ending" index).
There may be other problems, but this is the first one I noticed.
I'm trying to implement a QuickSort algorithm as a homework at the university, but I just fail to understand where there is a mistake in my code. I suppose it's a logical mistake, I think I swap my pivot wrongly. I could really use some help, thank you in advance. There is the code:
public class QuickSort {
private int [] array;
public QuickSort(int [] array){
this.array = array;
}
public void sort(){
partition(0, array.length - 1);
}
public void partition(int start, int end){
if (end - start < 2){
return;
}
int pivot_index = end;
int i = start;
int j = end - 1;
while (i < j){
//both elements are not in the right place
if(array[i] > array[pivot_index] && array[j] <= array[pivot_index]){
swap(array, i, j);
i++;
j--;
}
//the element on the left is not in place
else if (array[i] > array[pivot_index] && array[j] > array[pivot_index]){
j--;
}
//the element on the right is not in place
else if (array[i] < array[pivot_index] && array[j] < array[pivot_index]){
i++;
}
//both elements are in place
else {
i++;
j--;
}
}
if (array[i] > array[pivot_index]){
swap(array, pivot_index, i);
pivot_index = i;
}
partition(start, pivot_index - 1);
partition(pivot_index + 1, end);
}
private static void swap(int [] tab, int index1, int index2){
int temp = tab[index1];
tab[index1] = tab[index2];
tab[index2] = temp;
}
}
Solution one
The idea is iterating through the array to check whether the current element is smaller than the last one (the pivot), if yes swap with the first one that is not (index is lastSmaller + 1).
private void partition(int start, int end) {
if (start >= end) {
return;
}
int lastSmallest = start - 1;
for (int i = start; i < end; i++) {
if (array[i] < array[end])
swap(++lastSmallest, i);
}
swap(++lastSmallest, end);
partition(start, lastSmallest - 1);
partition(lastSmallest + 1, end);
}
Solution two
I think this is what you want to implement. Iterate through the array, skip all the elements in good place on the left and right. Swap the two in wrong place.
private void partition(int start, int end) {
if (end <= start) {
return;
}
int k = end;
int i = start;
int j = end - 1;
while (i < j) {
// left is in place
while (i < j && array[i] < array[k]) {
i++;
}
// right is in place
while (i < j && array[j] >= array[k]) {
j--;
}
// both are not good
if (i < j) {
// swap
int temp = array[i];
array[i] = array[j];
array[j] = temp;
i++;
j--;
}
}
// swap left and pivot
if (array[i] >= array[k]) {
int temp = array[i];
array[i] = array[k];
array[k] = temp;
}
partition(start, i - 1);
partition(i + 1, end);
}
The reason why your solution does not work is that when you find both are not in place, you swap them and continue to partition the rest of the array. However, you can not guarantee what you have swapped does not violate the rule. Therefore, you need to skip all the elements in place on both side first then swap.
This is a quick sort as you know and I want to optimize it in itself arrayList and don't want to use another array or using linkedList. Suppose that the half numbers of array was sorted in ascending order and others are in among them.I mean optimization is less swap in code that depends on where does choose a pivot or change the partition function.if you know how I should optimize it please help me.total of count variable is a number of swap if I write it true. Thanks!
public class Quick {
public static void main(String[] args) {
int[] a = {4,6,0,7,1,12,2,18,4,9,4,13,5,6};
sort(a,0,a.length - 1);
for (int i = 0; i < a.length; i++) {
System.out.print(a[i] + " ");
}
}
static void sort(int[] a, int lo, int hi){
if(lo < hi){
int j = partiton(a ,lo ,hi);
sort(a, lo ,j - 1);
sort(a, j + 1, hi);
}
}
static int partiton(int[] a, int lo, int hi){
int i = lo; int j = hi + 1;
int v = a[lo];
int count = 0;
while(true){
while(a[++i] < v){
if (i == hi)
break;
}
while(v < a[--j]){
if (j == lo)
break;
}
if (i >= j){
break;
}
swap(a, i, j);
count = count + 1;
}
swap(a, lo, j);
count = count + 1;
System.out.println("swap : " + count);
return j;
}
static void swap(int[] a, int i, int j){
int temp = 0;
temp = a[j];
a[j] = a[i];
a[i] = temp;
}
}
I am working on a non recursive merge sort for my CS class and it is not exactly working. I know it is being called since when I run the test program it changes the array, just not into the correct order. Can someone please help? Thanks!
private static void mergeSort(int[] a, int left, int right)
{
int midPoint = ((right + left) / 2);
int[] buffer = new int[19];
selectionSort(a, left, midPoint);
selectionSort(a, midPoint-1, right);
merge(a, buffer, 0, 9, 19);
}
private static void selectionSort(int[] a, int beginning, int end)
{
int [] temp = new int[end-1];
for(int y = 0; y < end - 1; y++)
{
temp[y] = a[y];
}
for (int i = 0; i < temp.length - 1; i++)
{
int minIndex = findMinimum(temp, i);
if (minIndex != i)
swap (temp, i, minIndex);
}
}
private static int findMinimum(int[] a, int first)
{
int minIndex = first;
for (int i = first + 1; i < a.length; i++)
{
if (a[i] < a[minIndex])
minIndex = i;
}
return minIndex;
}
private static void swap(int []a, int x, int y)
{
int temp = a[x];
a[x] = a[y];
a[y] = temp;
}
private static void merge(int[] a, int[] temp, int left, int mid, int right) {
if (mid >= a.length) return;
if (right > a.length) right = a.length;
int i = left, j = mid+1;
for (int k = left; k < right; k++) {
if (i == mid)
temp[k] = a[j++];
else if (j == right)
temp[k] = a[i++];
else if (a[j] < a[i])
temp[k] = a[j++];
else
temp[k] = a[i++];
}
for (int k = left; k < right; k++)
a[k] = temp[k];
}
There may be other bugs, but one that sticks out is that selectionSort doesn't actually do anything to the array. You pass in an array reference as the a parameter:
private static void selectionSort(int[] a, int beginning, int end)
Since this is a reference, if selectionSort did anything to assign to any elements of a, like
a[x] = y;
it would change the element of the caller's array, like you want. But there is no statement in selectionSort that changes anything in a. The code copies elements to temp, works with temp--but then throws all the work away.
My code works properly (to my knowledge) up until my input array size (a.length) is around 62,000 at which time I consistently get a StackOverFlowError. I previously had used 2 recursive calls to quicksort (less than, and greater than the pivot q) and then I switched to tail recursion. As you can see, I'm selecting the pivot to be the value at the end of the array. I know this isn't the best way to choose a pivot, but I still shouldn't be seeing StackOverFlowErrors with an array size this small, right? What could be causing this? Thanks in advance! Here's my code:
public static void quicksort(int[] a, int p, int r)
{
int q;
while (p < r)
{
q = partition(a, p, r);
quicksort(a, p, q - 1);
p = q + 1;
}
}
public static int partition(int[] a, int p, int r)
{
int j = p - 1;
int x = a[r];
for (int i = p; i < r; i++)
{
if (a[i] <= x)
{
j++;
swap(a, i, j);
}
}
j++;
swap(a, j, r);
return j;
}
private static void swap(int[] a, int i, int j)
{
int tmp = a[i];
a[i] = a[j];
a[j] = tmp;
}
The worst-case input (sorted order) makes quicksort Θ(n^2). Partition always puts a single element on one side of the partition (Cormen et al.). By randomizing the sort (choosing a random pivot) no particular input elicits its worst-case behavior.
import java.util.Random;
public class Quicksort
{
private static Random rand = new Random();
public static void quicksort(int[] arr, int left, int right)
{
if (left < right)
{
int pivot = randomizedPartition(arr, left, right);
quicksort(arr, left, pivot);
quicksort(arr, pivot + 1, right);
}
}
private static int randomizedPartition(int[] arr, int left, int right)
{
int swapIndex = left + rand.nextInt(right - left) + 1;
swap(arr, left, swapIndex);
return partition(arr, left, right);
}
private static int partition(int[] arr, int left, int right)
{
int pivot = arr[left];
int i = left - 1;
int j = right + 1;
while (true)
{
do
j--;
while (arr[j] > pivot);
do
i++;
while (arr[i] < pivot);
if (i < j)
swap(arr, i, j);
else
return j;
}
}
private static void swap(int[] arr, int i, int j)
{
int tmp = arr[i];
arr[i] = arr[j];
arr[j] = tmp;
}
// Sort 100k elements that are in reversed sorted order
public static void main(String[] args)
{
int arr[] = new int[100000];
for (int i = 0; i < arr.length; i++)
arr[i] = arr.length - i;
System.out.println("First 20 elements");
System.out.print("Before sort: ");
for (int i = 0; i < 20; i++)
System.out.print(arr[i] + " ");
System.out.println();
quicksort(arr, 0, arr.length - 1);
System.out.print("After sort: ");
for (int i = 0; i < 20; i++)
System.out.print(arr[i] + " ");
System.out.println();
}
}
Given the right input, your implementation will recurse once for every single element of the array. 60,000 recursive calls could easily be enough to overflow the stack in Java in the default configuration.