public class SimpleHTTPRequest {
String envelope1="<?xml version=\"1.0\" encoding=\"utf-8\"?>" +
"<soap:Envelope xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:tns=\"urn:insertdata\"" +
" targetNamespace=\"urn:insertdata\">"+
"<soap:Body>"+
"<insertdata>"+
"<name xsi:type=\"xsd:string\">ghjghj</name>"+
"<phone xsi:type=\"xsd:string\">1111</phone>"+
"<email xsi:type=\"xsd:string\">ascom</email>"+
"<score xsi:type=\"xsd:string\">12</score>"+
"</insertdata>"+
"</soap:Body>"+
"</soap:Envelope>";
/**
* #param args
*/
public static void main(String[] args) {
String url="http://url/iphone_soap_server.php/insertdata";
String soapAction="http://urkl/iphone_soap_server.php/insertdata/insertdata";
HttpURLConnection connection = null;
OutputStreamWriter wr = null;
BufferedReader rd = null;
StringBuilder sb = null;
String line = null;
URL serverAddress = null;
String data = "width=50&height=100";
try {
serverAddress = new URL("http://url/soap-server.php?wsdl");
connection = null;
//Set up the initial connection
connection = (HttpURLConnection)serverAddress.openConnection();
connection.setRequestMethod("POST");
connection.setDoOutput(true);
connection.setDoOutput(true);
OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream());
writer.write(data);
writer.flush();
rd = new BufferedReader(new InputStreamReader(connection.getInputStream()));
sb = new StringBuilder();
while ((line = rd.readLine()) != null)
{
sb.append(line + '\n');
}
System.out.println(sb.toString());
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ProtocolException e1) {
e1.printStackTrace();
} catch (IOException e2) {
e2.printStackTrace();
}
finally
{
//close the connection, set all objects to null
connection.disconnect();
rd = null;
sb = null;
wr = null;
connection = null;
}
}
}
I want consume the soap web services From Java where can i put the Soap Action IN this code...
Thanks in Advance.....
When using SOAP over HTTP, in general the SOAP Action is inserted in the SOAPAction HTTP header in the request. See the standard here: http://www.w3.org/TR/2000/NOTE-SOAP-20000508/#_Toc478383528
The SOAPAction HTTP request header field can be used to indicate the
intent of the SOAP HTTP request. The value is a URI identifying the
intent. SOAP places no restrictions on the format or specificity of
the URI or that it is resolvable. An HTTP client MUST use this header
field when issuing a SOAP HTTP Request.
So what you want is (assuming soapAction is set to the correct value):
connection.setRequestProperty("SOAPAction", soapAction);
Related
I am trying to call an API that gives 400 on some requests.
But it has meaningful message that needs to be read.
Also i am passing a payload(json body) in the api call
My code(it takes a payload as json) and the 400 response is below
I am able to successfully read the response of 200 but issue is with 400
public static void blahblah (String input, String CustomerID, String endpoint, String dateNameFolder) throws UnknownHostException
{
try {
URL url = new URL(endpoint);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
OutputStream os = conn.getOutputStream();
os.write(input.getBytes());
os.flush();
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
StringBuilder sb = new StringBuilder();
String output;
while ((output = br.readLine()) != null) {
sb.append(output);
}
File fileObj = new File(CustomerID + ".json");
if (!fileObj.exists()) {
fileObj.createNewFile();
FileWriter dataWriter = new FileWriter(CustomerID + ".json");
dataWriter.write(sb.toString());
dataWriter.close();
} else {
FileWriter dataWriter = new FileWriter(CustomerID + ".json");
dataWriter.write(sb.toString());
dataWriter.close();
}
conn.disconnect();
}catch (MalformedURLException e) {
l
log.info(e);
}
catch (IOException e) {
log.error("Error in Validating Request to Catalog for Customer ID(400 Bad Request) : " + CustomerID ) ;
log.info(e);
}
}
Sample output of 400 bad request :
<Response>
<StatusCode>BadRequest</StatusCode>
<ErrorCode>OrderRequestInvalid.InvalidCharacteristicUse</ErrorCode>
<Message>Characteristic ID cannot be found in the specification: { EntityUniqueCode: CS_0aefdfec-022e-4ac9-a84b-83c8ea2e0fd0, CharacteristicID: 76c4e767-ce7b-4675-a178-d832839b322f}</Message>
<Context>
<EntityUniqueCode>CS_0aefdfec-022e-4ac9-a84b-83c8ea2e0fd0</EntityUniqueCode>
<CharacteristicID>76c4e767-ce7b-4675-a178-d832839b322f</CharacteristicID>
</Context>
</Response>
You need to choose correct stream depending on your response status. here is an example how you can do this:
BufferedReader br = null;
int statusCode = conn.getResponseCode();
if (statusCode>299){
br = new BufferedReared(new InputStreamReader(conn.getErrorStream()));
} else {
br = new BufferedReared(new InputStreamReader(conn.getInputStream()));
}
I want to get data from an web service and after that to display it in a listView. So I made a function that get the data from the service, but when I tested it I discovered something unexpectedly. When I tested it as a call in the main function of the java class, it works, it returns me the data, but when I use it in the listView class, it doesn't. After some debugging, I still don't get why it doesn't work, but I observed that the only difference is that when the function is called in the main function, the URLConnection begins with sun.net.www.protocol.http.Http.URLConnection:http://... and when it's called in the listView class it begins with com.android.okhttp.internal.huc.HttpURLConnectionImpl:http//.. .
public static String getDataFromServer(String url) {
BufferedReader inputStream = null;
URL dataUrl = null;
String data = null;
//handle url exception
try {
dataUrl = new URL(url);
try {
URLConnection dc = dataUrl.openConnection();
dc.setConnectTimeout(5000);
dc.setReadTimeout(5000);
try {
inputStream = new BufferedReader(new InputStreamReader(dc.getInputStream(), "UTF-8"));
} catch (UnsupportedEncodingException e) { System.out.println(e.getMessage());}
StringBuffer sb = new StringBuffer();
String line = "";
while ((line = inputStream.readLine())!=null)
sb.append(line + "\r\n");
data = sb.toString();
} catch (IOException e) { System.out.println(e.getMessage());
}
} catch (MalformedURLException e) { System.out.println(e.getMessage());}
return data;
}
do somthing like that :
String url = "http://youaddres.com/path";
URL object = new URL(url);
HttpURLConnection con = (HttpURLConnection) object.openConnection();
con.setDoOutput(true);
con.setDoInput(true);
con.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
//if it is post
con.setRequestMethod("POST");
String me = "{\"json\":\"" + json+ "\",\"json\":\"" + json+"\"}";
OutputStream os = con.getOutputStream();
os.write(me.getBytes());
os.flush();
InputStream inputStr = con.getInputStream();
reader = new BufferedReader(new InputStreamReader(inputStr));
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line);
}
String = response = sb.toString();
I need to send a post request to a https address. I have a function that sends post messages currectly but i cant seem to make it work for https.
public static String serverCall(String link, String data){
HttpURLConnection connection;
OutputStreamWriter request = null;
URL url = null;
String response = null;
String parameters = data;
try
{
url = new URL(link);
connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "text/xml");
connection.setRequestMethod("POST");
request = new OutputStreamWriter(connection.getOutputStream());
request.write(parameters);
request.flush();
request.close();
String line = "";
InputStreamReader isr = new InputStreamReader(connection.getInputStream());
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
// Response from server after process will be stored in response variable.
response = sb.toString();
isr.close();
reader.close();
}
catch(IOException e)
{
// Error
}
return response;
}
i have tryed using HttpsURLConnection insted of HttpURLConnection, i am still getting null from my server.
you should call connect();
....
connection.setRequestMethod("POST");
connection.connect();
....
I have a web application under test. Using Fiddler/Httpfox, I can see that on logging in to the web app, there are TWO 302 HTTP redirects before a 200 OK is response is received. Is it possible to observe the two redirects using Java code?
This is what I coded:
public class HttpReq {
HttpURLConnection con = null;
StringBuilder str = new StringBuilder();
BufferedReader br = null;
URL address = null;
String line = null;
HttpReq () {
try {
address = new URL("http://walhs24002v.us.oracle.com/t1mockapp1/");
con = (HttpURLConnection)address.openConnection();
con.setRequestMethod("GET");
con.setReadTimeout(60000);
con.setConnectTimeout(60000);
con.setDoOutput(true);
con.setInstanceFollowRedirects(true);
con.connect();
InputStreamReader is = new InputStreamReader(con.getInputStream());
br = new BufferedReader(is);
while((line = br.readLine()) != null)
{
str.append(line + '\n');
}
//System.out.println(str);
System.out.println(con.getResponseCode());
System.out.println(con.getResponseMessage());
}
catch (MalformedURLException m)
{
m.printStackTrace();
}
catch (IOException i)
{
i.printStackTrace();
}
finally
{
br = null;
str = null;
con = null;
}
}
public static void main(String[] args) {
HttpReq http = new HttpReq();
}
}
The program gives the output:
200
OK
No surprises there. Is there a way to capture the two 302 redirects before the 200 ok is received?
With defaulthttpclient you most certainly can:
http://hc.apache.org/httpcomponents-client-ga/tutorial/html/httpagent.html
ClientPNames.HANDLE_REDIRECTS='http.protocol.handle-redirects':
defines whether redirects should be handled automatically. This
parameter expects a value of type java.lang.Boolean. If this parameter
is not set HttpClient will handle redirects automatically.
I just try to post data to google by using the following code,but always got 405 error,can anybody tell me way?
package com.tom.labs;
import java.net.*;
import java.io.*;
public class JavaHttp {
public static void main(String[] args) throws Exception {
File data = new File("D:\\in.txt");
File result = new File("D:\\out.txt");
FileOutputStream out = new FileOutputStream(result);
OutputStreamWriter writer = new OutputStreamWriter(out);
Reader reader = new InputStreamReader(new FileInputStream(data));
postData(reader,new URL("http://google.com"),writer);//Not working
//postData(reader,new URL("http://google.com/search"),writer);//Not working
sendGetRequest("http://google.com/search", "q=Hello");//Works properly
}
public static String sendGetRequest(String endpoint,
String requestParameters) {
String result = null;
if (endpoint.startsWith("http://")) {
// Send a GET request to the servlet
try {
// Send data
String urlStr = endpoint;
if (requestParameters != null && requestParameters.length() > 0) {
urlStr += "?" + requestParameters;
}
URL url = new URL(urlStr);
URLConnection conn = url.openConnection();
// Get the response
BufferedReader rd = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
StringBuffer sb = new StringBuffer();
String line;
while ((line = rd.readLine()) != null) {
sb.append(line);
}
rd.close();
result = sb.toString();
} catch (Exception e) {
e.printStackTrace();
}
}
System.out.println(result);
return result;
}
/**
* Reads data from the data reader and posts it to a server via POST
* request. data - The data you want to send endpoint - The server's address
* output - writes the server's response to output
*
* #throws Exception
*/
public static void postData(Reader data, URL endpoint, Writer output)
throws Exception {
HttpURLConnection urlc = null;
try {
urlc = (HttpURLConnection) endpoint.openConnection();
try {
urlc.setRequestMethod("POST");
} catch (ProtocolException e) {
throw new Exception(
"Shouldn't happen: HttpURLConnection doesn't support POST??",
e);
}
urlc.setDoOutput(true);
urlc.setDoInput(true);
urlc.setUseCaches(false);
urlc.setAllowUserInteraction(false);
urlc.setRequestProperty("Content-type", "text/xml; charset=UTF-8");
OutputStream out = urlc.getOutputStream();
try {
Writer writer = new OutputStreamWriter(out, "UTF-8");
pipe(data, writer);
writer.close();
} catch (IOException e) {
throw new Exception("IOException while posting data", e);
} finally {
if (out != null)
out.close();
}
InputStream in = urlc.getInputStream();
try {
Reader reader = new InputStreamReader(in);
pipe(reader, output);
reader.close();
} catch (IOException e) {
throw new Exception("IOException while reading response", e);
} finally {
if (in != null)
in.close();
}
} catch (IOException e) {
e.printStackTrace();
throw new Exception("Connection error (is server running at "
+ endpoint + " ?): " + e);
} finally {
if (urlc != null)
urlc.disconnect();
}
}
/**
* Pipes everything from the reader to the writer via a buffer
*/
private static void pipe(Reader reader, Writer writer) throws IOException {
char[] buf = new char[1024];
int read = 0;
while ((read = reader.read(buf)) >= 0) {
writer.write(buf, 0, read);
}
writer.flush();
}
}
405 means "method not allowed". For example, if you try to POST to a URL that doesn't allow POST, then the server will return a 405 status.
What are you trying to do by making a POST request to Google? I suspect that Google's home page only allows GET, HEAD, and maybe OPTIONS.
Here's the body of a POST request to Google, containing Google's explanation.
405. That’s an error.
The request method POST is inappropriate for the URL /. That’s all we know.